This question already has answers here:
How to remove time portion of date in C# in DateTime object only?
(43 answers)
Closed 9 years ago.
The line of code DateTime d = DateTime.Today; results in 10/12/2011 12:00:00 AM. How can I get only the date part.I need to ignore the time part when I compare two dates.
DateTime is a DataType which is used to store both Date and Time. But it provides Properties to get the Date Part.
You can get the Date part from Date Property.
http://msdn.microsoft.com/en-us/library/system.datetime.date.aspx
DateTime date1 = new DateTime(2008, 6, 1, 7, 47, 0);
Console.WriteLine(date1.ToString());
// Get date-only portion of date, without its time.
DateTime dateOnly = date1.Date;
// Display date using short date string.
Console.WriteLine(dateOnly.ToString("d"));
// Display date using 24-hour clock.
Console.WriteLine(dateOnly.ToString("g"));
Console.WriteLine(dateOnly.ToString("MM/dd/yyyy HH:mm"));
// The example displays the following output to the console:
// 6/1/2008 7:47:00 AM
// 6/1/2008
// 6/1/2008 12:00 AM
// 06/01/2008 00:00
There is no way to "discard" the time component.
DateTime.Today is the same as:
DateTime d = DateTime.Now.Date;
If you only want to display only the date portion, simply do that - use ToString with the format string you need.
For example, using the standard format string "D" (long date format specifier):
d.ToString("D");
When comparing only the date of the datatimes, use the Date property. So this should work fine for you
datetime1.Date == datetime2.Date
DateTime d = DateTime.Today.Date;
Console.WriteLine(d.ToShortDateString()); // outputs just date
if you want to compare dates, ignoring the time part, make an use of DateTime.Year and DateTime.DayOfYear properties.
code snippet
DateTime d1 = DateTime.Today;
DateTime d2 = DateTime.Today.AddDays(3);
if (d1.Year < d2.Year)
Console.WriteLine("d1 < d2");
else
if (d1.DayOfYear < d2.DayOfYear)
Console.WriteLine("d1 < d2");
you can use a formatstring
DateTime time = DateTime.Now;
String format = "MMM ddd d HH:mm yyyy";
Console.WriteLine(time.ToString(format));
Related
I have a couple of DateTime startTime and endTime. I would like them to be in MMM yyyy format ("August 2017") but if I parse them ToString, i can't loop because, well, it's a string now, there is no AddMonths method. For exemple :
var formattedStartTime = startTime.ToString("MMMM yyyy");
var formattedEndTime = endTime.ToString("MMMM yyyy");
for (var date = formattedStartTime; date < formattedEndTime; date = date.AddMonths(1)) // nope
How can i parse my variables and loop through every month in between two dates ?
By calling ToString you are obviously converting your dates to a string, which know nothing about the original date they represent and as such also cannot perform any date related operations.
The solution is to simply convert to string only when you are actually displaying the object:
for (var date = startTime; date < endTime; date = date.AddMonths(1))
{
Console.WriteLine(date.ToString("MMM yyyy"));
}
Be careful with such date comparisons though, since depending on the actual days of the month and the time component in the startTime and endTime, you might skip or include a result you do not expect.
For example with startTime = new DateTime(2017, 1, 2) and endTime = new DateTime(2017, 2, 3) (February 3rd), you would get February in the result but with endTime = new DateTime(2017, 2, 1) (February 1st) you wouldn’t.
This question already has answers here:
extract the date part from DateTime in C# [duplicate]
(5 answers)
Closed 8 years ago.
I have a datetime value below,
23/07/2014 04:15:00
How can i get date as below string value
23/07/2014
How can i get hour as below string value
04:15 AM/PM (depends hour time)
Any help will be appreciated.
Thanks.
I'd parse the string to DateTime first to avoid string manipulation.
var str = "23/07/2014 04:15:00";
var dt = DateTime.ParseExact(str, "dd/MM/yyyy HH:mm:ss", CultureInfo.InvariantCulture);
var date = dt.ToString("dd/MM/yyyy", CultureInfo.InvariantCulture);//23/07/2014
var time = dt.ToString("hh:mm tt", CultureInfo.InvariantCulture);//04:15 AM
If you have the value as DateTime you can skip ParseExact part.
I'm not sure if you really use a DateTime instead of a string, but you should. If not, you can use DateTime.Parse/DateTime.TryParseExact to get a DateTime from a string.
DateTime has a method ToShortDateString
string dateOnly = dt.ToShortDateString();
// or to force / as separator even if current culture has different separator
dateOnly = dt.ToString("d", CultureInfo.InvariantCulture);
// hour+minute and AM/PM designator:
string hour = DateTime.Now.ToString("hh:mm tt", CultureInfo.InvariantCulture);
I strongly feel like taking a risk to answer your question but.. anyway.
How can i get date as below string value
DateTime dt = new DateTime(2014, 7, 23, 4, 15, 0);
Console.WriteLine(dt.ToString(#"dd\/MM\/yyyy")); // 23/07/2014
I escaped / character because it has a special meaning in custom date and time format strings. It means as; replace me with the current culture date separator. Take a look "/" Custom Format Specifier for more information.
How can i get hour as below string value
Console.WriteLine(dt.ToString("HH:mm tt", CultureInfo.InvariantCulture));
Output will be;
04:15 AM
This question already has answers here:
Combine two datetime variables into one (up to seconds precision)
(4 answers)
Closed 9 years ago.
I have 2 values:
var dt1 = dtFromDate.Value;
var tm1 = tmFromTime.Value;
dt1 = 12/5/2013 12:00:00 AM
tm1 = 11/5/2013 9:00:00 AM
i want to make datetime as : 12/5/2013 9:00:00 AM
how can it be possible?
You can take the date part of dt1 by accessing Date, the time part of tm1 by accessing TimeOfDay and then combine them using +:
dt1.Date + tm1.TimeOfDay
You can create a new DateTime using overloaded constructor:
DateTime dt = new DateTime(
dt1.Year,
dt1.Month,
dt1.Day,
tm1.Hour,
tm2.Minute,
tm2.Second,
tm2.Millisecond);
You can use that code, using Date property to get just date part and Time property to get just time part:
var dt1 = DateTime.Parse("12/5/2013 12:00:00 AM"); // this is just a sample date
var tm1 = DateTime.Parse("11/5/2013 9:00:00 AM"); // this is just a sample date
var newDate = dt1.Date.Add(tm1.TimeOfDay); // the code to use
DateTime object is immutable so in order to get the date from one DateTime object, but the time from another - you must create new DateTime object.
There is two ways for doing it:
Create new DateTime with constructor overload:
DateTime date1 =
new DateTime(dt1.Year, dt1.Month, dt1.Day, tm1.Hour, tm1.Minute, tm1.Second);
Parse string to DateTime:
var dateToParse =
String.Concat(dt1.ToString("yyyy.MM.dd ", CultureInfo.InvariantCulture),
tm1.ToString("HH:mm:ss", CultureInfo.InvariantCulture));
var date1 =
DateTime.ParseExact(dateToParse, "yyyy.MM.dd HH:mm:ss", CultureInfo.InvariantCulture);
This question already has answers here:
Closed 10 years ago.
Possible Duplicate:
How to add days to a date in Java
Consider the date to be 19/05/2013 and the number to be 14. I would like to get the resulting date after adding the number to the month.
Expected result is: 19/07/2014.
In .NET you could do use the AddMonths method:
DateTime date = new DateTime(2013, 5, 19);
DateTime newDate = date.AddMonths(14);
As far as parsing a date from a string using a specified format you could use the TryParseExact method:
string dateStr = "19/05/2013";
DateTime date;
if (DateTime.TryParseExact(dateStr, "dd/MM/yyyy", CultureInfo.InvariantCulture, DateTimeStyles.None, out date))
{
// successfully parsed the string into a DateTime instance =>
// here we could add the desired number of months to it and construct
// a new DateTime
DateTime newDate = date.AddMonths(14);
}
else
{
// parsing failed => the specified string was not in the correct format
// you could inform the user about that here
}
You can DateTime.AddMonths to add months.
DateTime date = new DateTime(2013, 5, 19);
DateTime newDate = date.AddMonths(14);
In Java:
Calendar c = Calendar.getInstance();
c.setTime(new Date()); // today is the default
c.add(Calendar.DATE, 1); // number of days to add (1)
c.getTime(); // The new date
Just use AddMonths to add the specified number of months to the value of this instance.
DateTime date = new DateTime(2013, 5, 19); // (yyyy,MM,dd)
DateTime dt = date.AddMonths(14);
I have a varchar(5) column in a table which contains the hour and minutes in 24 hour format time. I want to convert this 24 hour format to 12 hour format and finally embed this 12 hour format time into a DateTime Variable along with a Date value. Below is an example of demonstration.
For Example
8:18 should be converted into 8:18:00 AM and then should be embedded
with a Date like 8/10/2012 8:18:50 AM to be able to store in DateTime
column of DB.
22:20......10:20:00 PM.......8/10/2012 10:20:00 PM
The Date will not be current date it can be any date value like 8/8/2012 or 7/8/2012
You can do something like this:
string input = "22:45";
var timeFromInput = DateTime.ParseExact(input, "H:m", null, DateTimeStyles.None);
string timeIn12HourFormatForDisplay = timeFromInput.ToString(
"hh:mm:ss tt",
CultureInfo.InvariantCulture);
var timeInTodayDate = DateTime.Today.Add(timeFromInput.TimeOfDay);
And now the important parts to take in consideration:
The format for parsing uses "H:m" so it assumes a 24H value that does not use a zero to prefix single digits hours or minutes;
The format for printing uses "hh:mm:ss tt" because it seems to be the format you desire, however you need to use CultureInfo.InvariantCulture to be certain that you get a AM/PM designator that is in fact AM or PM. If you use another culture, the AM/PM designator may change;
The full date and time is constructed based on DateTime.Today which returns the today date with a zeroed time and then we just add the time we read from input.
To create the final date and time from another date you can instead use:
var timeInAnotherDate = new DateTime(2000, 1, 1).Add(timeFromInput.TimeOfDay);
Reference material:
DateTime Structure;
Custom Date and Time Format Strings;
Standard DateTime Format Strings.
create function dbo.COMBINE_DATE_TIME(
#DatePart DateTime, -- DateTime
#TimePart varchar(5)) -- Time
returns DateTime
as begin
return DATEADD(day, DATEDIFF(day,0,#DatePart),
CONVERT(DateTime,ISNULL(#TimePart,''),14))
end
go
string strDate = DateTime.ParseExact("8:18","HHmm",CultureInfo.CurrentCulture).ToString("hh:mm tt");
string fromTime = Convert.ToStr(reader["TimeFrom"]);
string toTime = Convert.ToStr(reader["TimeTo"]);
item.Time=DateTime.Parse(fromTime,CultureInfo.CurrentCulture).ToString("hh:mm tt");
here the property of your model(item.Time here) should be the string.