This question already has answers here:
Combine two datetime variables into one (up to seconds precision)
(4 answers)
Closed 9 years ago.
I have 2 values:
var dt1 = dtFromDate.Value;
var tm1 = tmFromTime.Value;
dt1 = 12/5/2013 12:00:00 AM
tm1 = 11/5/2013 9:00:00 AM
i want to make datetime as : 12/5/2013 9:00:00 AM
how can it be possible?
You can take the date part of dt1 by accessing Date, the time part of tm1 by accessing TimeOfDay and then combine them using +:
dt1.Date + tm1.TimeOfDay
You can create a new DateTime using overloaded constructor:
DateTime dt = new DateTime(
dt1.Year,
dt1.Month,
dt1.Day,
tm1.Hour,
tm2.Minute,
tm2.Second,
tm2.Millisecond);
You can use that code, using Date property to get just date part and Time property to get just time part:
var dt1 = DateTime.Parse("12/5/2013 12:00:00 AM"); // this is just a sample date
var tm1 = DateTime.Parse("11/5/2013 9:00:00 AM"); // this is just a sample date
var newDate = dt1.Date.Add(tm1.TimeOfDay); // the code to use
DateTime object is immutable so in order to get the date from one DateTime object, but the time from another - you must create new DateTime object.
There is two ways for doing it:
Create new DateTime with constructor overload:
DateTime date1 =
new DateTime(dt1.Year, dt1.Month, dt1.Day, tm1.Hour, tm1.Minute, tm1.Second);
Parse string to DateTime:
var dateToParse =
String.Concat(dt1.ToString("yyyy.MM.dd ", CultureInfo.InvariantCulture),
tm1.ToString("HH:mm:ss", CultureInfo.InvariantCulture));
var date1 =
DateTime.ParseExact(dateToParse, "yyyy.MM.dd HH:mm:ss", CultureInfo.InvariantCulture);
Related
This question already has answers here:
How to remove time portion of date in C# in DateTime object only?
(43 answers)
Closed 3 years ago.
I am doing an asp.net mvc project and I need to convert the string of "06/22/2019 00:00:00" to a valid DateTime type in format of 2019/06/22 without the part of hour and minute and second
You can use DateTime.ParseExact, here is an example :
http://net-informations.com/q/faq/stringdate.html
Finally, it should look like this :
string s = "06/22/2019 00:00:00";
DateTime myDate = DateTime.ParseExact(s, "MM/dd/yyyy HH:mm:ss",System.Globalization.CultureInfo.InvariantCulture);
Debug.WriteLine(myDate.ToString("MM/dd/yyyy"));
You can do this:
var dateString = "06/22/2019 00:00:00";
var datePart = dateString.Split(' ')[0];
var date = DateTime.Parse(datePart);
Though remember that DateTime will still have a default value for the time (12:00 AM), if you want the Date part only from the object, use date.Date which will return an instance with the default time (mentioned earlier).
DateTime contains default Time even if you access DateTime.Date. You can achieve format of date by converting Date into string.
Something like,
DateTime myDate = DateTime.ParseExact("06/22/2019 00:00:00", "MM/dd/yyyy HH:mm:ss", System.Globalization.CultureInfo.InvariantCulture);
string dateInFormat = $"{myDate.Year}/{myDate.Month}/{myDate.Day}";
POC : .net Fiddle
You convert the string to a DateTime object and then to display just the date portion you can use ToShortDateString like this:
var myDateTime = DateTime.Parse( "06/22/2019 00:00:00") //presumably use a variable here instead.
var date = myDateTime.ToShortDateString();
How you want to display this can be done using the CultureInfo part as shown here: https://learn.microsoft.com/en-us/dotnet/api/system.datetime.toshortdatestring?view=netframework-4.8
This question already has answers here:
DateTime.Value.ToString(format) gives me 12 hour clock
(4 answers)
Closed 6 years ago.
I'm working with a project and one of its functional requirement is to create a datetime range in which I will select a set of data based on that.
This range should take today's datetime starting from 8:00:00 to 18:00:00, and then I want to convert the format to be yyyy-MM-ddThh:mm:ssZ, so I'm doing the following to approach that:
DateTime fromTime = DateTime.Now;
TimeSpan ts = new TimeSpan(8,0,0);
fromTime = fromTime.Date + ts;
string fromTimeFormat = fromTime.ToString("yyyy-MM-ddThh:mm:ssZ");
DateTime toTime = DateTime.Now;
TimeSpan tss = new TimeSpan(18, 0, 0);
toTime = toTime.Date + tss;
string toTimeFormat = toTime.ToString("yyyy-MM-ddThh:mm:ssZ");
The problem is that, the toTimeFormat is being converted to the 12h system, so when I use it later it's being considered as 6:00 AM.
Any ideas please?
Because you are using hh specifier which is for 12-hour clock format.
You need to use HH specifier which is for 24-hour clock format.
string toTimeFormat = toTime.ToString("yyyy-MM-ddTHH:mm:ssZ");
And you can simplify your code as;
string fromTimeFormat = DateTime.Today.AddHours(6).ToString("yyyy-MM-ddThh:mm:ssZ");
string toTimeFormat = DateTime.Today.AddHours(18).ToString("yyyy-MM-ddTHH:mm:ssZ");
This question already has answers here:
Closed 10 years ago.
Possible Duplicate:
How to add days to a date in Java
Consider the date to be 19/05/2013 and the number to be 14. I would like to get the resulting date after adding the number to the month.
Expected result is: 19/07/2014.
In .NET you could do use the AddMonths method:
DateTime date = new DateTime(2013, 5, 19);
DateTime newDate = date.AddMonths(14);
As far as parsing a date from a string using a specified format you could use the TryParseExact method:
string dateStr = "19/05/2013";
DateTime date;
if (DateTime.TryParseExact(dateStr, "dd/MM/yyyy", CultureInfo.InvariantCulture, DateTimeStyles.None, out date))
{
// successfully parsed the string into a DateTime instance =>
// here we could add the desired number of months to it and construct
// a new DateTime
DateTime newDate = date.AddMonths(14);
}
else
{
// parsing failed => the specified string was not in the correct format
// you could inform the user about that here
}
You can DateTime.AddMonths to add months.
DateTime date = new DateTime(2013, 5, 19);
DateTime newDate = date.AddMonths(14);
In Java:
Calendar c = Calendar.getInstance();
c.setTime(new Date()); // today is the default
c.add(Calendar.DATE, 1); // number of days to add (1)
c.getTime(); // The new date
Just use AddMonths to add the specified number of months to the value of this instance.
DateTime date = new DateTime(2013, 5, 19); // (yyyy,MM,dd)
DateTime dt = date.AddMonths(14);
This question already has answers here:
How to remove time portion of date in C# in DateTime object only?
(43 answers)
Closed 9 years ago.
The line of code DateTime d = DateTime.Today; results in 10/12/2011 12:00:00 AM. How can I get only the date part.I need to ignore the time part when I compare two dates.
DateTime is a DataType which is used to store both Date and Time. But it provides Properties to get the Date Part.
You can get the Date part from Date Property.
http://msdn.microsoft.com/en-us/library/system.datetime.date.aspx
DateTime date1 = new DateTime(2008, 6, 1, 7, 47, 0);
Console.WriteLine(date1.ToString());
// Get date-only portion of date, without its time.
DateTime dateOnly = date1.Date;
// Display date using short date string.
Console.WriteLine(dateOnly.ToString("d"));
// Display date using 24-hour clock.
Console.WriteLine(dateOnly.ToString("g"));
Console.WriteLine(dateOnly.ToString("MM/dd/yyyy HH:mm"));
// The example displays the following output to the console:
// 6/1/2008 7:47:00 AM
// 6/1/2008
// 6/1/2008 12:00 AM
// 06/01/2008 00:00
There is no way to "discard" the time component.
DateTime.Today is the same as:
DateTime d = DateTime.Now.Date;
If you only want to display only the date portion, simply do that - use ToString with the format string you need.
For example, using the standard format string "D" (long date format specifier):
d.ToString("D");
When comparing only the date of the datatimes, use the Date property. So this should work fine for you
datetime1.Date == datetime2.Date
DateTime d = DateTime.Today.Date;
Console.WriteLine(d.ToShortDateString()); // outputs just date
if you want to compare dates, ignoring the time part, make an use of DateTime.Year and DateTime.DayOfYear properties.
code snippet
DateTime d1 = DateTime.Today;
DateTime d2 = DateTime.Today.AddDays(3);
if (d1.Year < d2.Year)
Console.WriteLine("d1 < d2");
else
if (d1.DayOfYear < d2.DayOfYear)
Console.WriteLine("d1 < d2");
you can use a formatstring
DateTime time = DateTime.Now;
String format = "MMM ddd d HH:mm yyyy";
Console.WriteLine(time.ToString(format));
This question already has answers here:
How to change time in DateTime?
(29 answers)
Closed 9 years ago.
I have a DateTime variable:
DateTime date = DateTime.Now;
I want to change the time part of a DateTime variable. But when I tried to access time part (hh:mm:ss) these fields are readonly.
Can't I set these properties?
Use the constructor that allows you to specify the year, month, day, hours, minutes, and seconds:
var dateNow = DateTime.Now;
var date = new DateTime(dateNow.Year, dateNow.Month, dateNow.Day, 4, 5, 6);
you can't change the DateTime object, it's immutable. However, you can set it to a new value, for example:
var newDate = oldDate.Date + new TimeSpan(11, 30, 55);
date = new DateTime(date.year, date.month, date.day, HH, MM, SS);
I'm not sure exactly what you're trying to do but
you can set the date/time to exactly what you want in a number of ways...
You can specify 12/25/2010 4:58 PM by using
DateTime myDate = Convert.ToDateTime("2010-12-25 16:58:00");
OR if you have an existing datetime construct , say 12/25/2010 (and any random time) and you want to set it to 12/25/2010 4:58 PM, you could do so like this:
DateTime myDate = ExistingTime.Date.AddHours(16).AddMinutes(58);
The ExistingTime.Date will be 12/25 at midnight, and you just add hours and minutes to get it to the time you want.
It isn't possible as DateTime is immutable. The same discussion is available here: How to change time in datetime?