Is there an easy way to show an dialog when the program is started for the first time (and only the first time), for some kind of instruction or specifying settings?
You could save it as a bool in your settings and you should check at load event of first form.
Your settings file should have a setting that I called "FirstRun" do this with following steps:
Right click your Project
Click "Properties"
Click "Settings" tabpage(probably on the left)
Add setting like I did as seen in image above
Note: The Scope can be changed to "Application", if that is your application's need, since you didn't mention in your question.
Your Settings file should look like image below:
public void Form1_Load(object sender, EventArgs e)
{
if((bool)Properties.Settings.Default["FirstRun"] == true)
{
//First application run
//Update setting
Properties.Settings.Default["FirstRun"] = false;
//Save setting
Properties.Settings.Default.Save();
//Create new instance of Dialog you want to show
FirstDialogForm fdf = new FirstDialogForm();
//Show the dialog
fdf.ShowDialog();
}
else
{
//Not first time of running application.
}
}
Note: wrote this from my phone, so I couldn't compile to test
Edit: Checked code and added image from desktop.
You can have bool value in your settings file which is a "user setting" which means you can change it to true save it for this specific user.
When your application starts just check that value. If it's false show your dialog and change it to true and it will stay true.
public void Form_Load(object sender, EventArgs e)
{
if(Settings.Default.ShowDialog)
{
Settings.Default.ShowDialog = false;
Settings.Default.Save();
// show first disalog
}
// rest of code if needed
}
Here's an MSDN link on user settings:
http://msdn.microsoft.com/en-us/library/bb397750(v=vs.110).aspx
Ok, so I assume you're creating WinForms application. First of all, locate the Load event in your main Form event lists (or simply double click your Form in Designer panel). The following method stub will pop up:
public void Form1_Load(object sender, EventArgs e)
{
}
And modify it like this:
public void Form1_Load(object sender, EventArgs e)
{
MessageBox.Show("Your message here");
}
Related
I have a Windows Form Application, where the User can input numbers into three different TextBoxes. I want to save these numbers by checking the Checkbox next to it, so when the Application gets closed and re-opened you don't have to put in the numbers again.
I have added the Properties to the User Settings and implemented the Code below, but when I input a number and re-open the Application, nothing is shown and they aren't saved in the user.config file.
Any help is greatly appreciated as I can't find my mistake.
private void MainForm_Load(object sender, EventArgs e)
{
Text = Properties.Settings.Default.title;
chkBox1.Checked = Properties.Settings.Default.checkBox;
chkBox2.Checked = Properties.Settings.Default.checkBox;
chkBox3.Checked = Properties.Settings.Default.checkBox;
txtBox1.Text = Properties.Settings.Default.textBox;
txtBox2.Text = Properties.Settings.Default.textBox;
txtBox3.Text = Properties.Settings.Default.textBox;
this.Location = new System.Drawing.Point(Properties.Settings.Default.PX, Properties.Settings.Default.PY);
}
private void MainForm_FormClosing(object sender, FormClosingEventArgs e)
{
Properties.Settings.Default.checkBox = chkBox1.Checked;
Properties.Settings.Default.checkBox = chkBox2.Checked;
Properties.Settings.Default.checkBox = chkBox3.Checked;
Properties.Settings.Default.textBox = txtBox1.Text;
Properties.Settings.Default.textBox = txtBox2.Text;
Properties.Settings.Default.textBox = txtBox3.Text;
Properties.Settings.Default.PX = this.Location.X;
Properties.Settings.Default.PY = this.Location.Y;
Properties.Settings.Default.Save();
}
private void chkBox1_Checked(object sender, EventArgs e)
{
this.Text = txtBox1.Text;
}
private void chkBox2_Checked(object sender, EventArgs e)
{
this.Text = txtBox2.Text;
}
private void chkBox3_Checked(object sender, EventArgs e)
{
this.Text = txtBox3.Text;
}
Why not use databinding to save changes automatically. You don't need to replicate the code on form_load and form_closing events.
The best explanation I have for control data binds is that they provide two way model update between a control properties and object properties.
More Info https://learn.microsoft.com/en-us/dotnet/api/system.windows.forms.control.databindings?view=netcore-3.1
private void Form1_Load(object sender, EventArgs e)
{
chkBox1.DataBindings.Add("Checked", Properties.Settings.Default, "Checked1",true, DataSourceUpdateMode.OnPropertyChanged);
chkBox2.DataBindings.Add("Checked", Properties.Settings.Default, "Checked2",true, DataSourceUpdateMode.OnPropertyChanged);
chkBox3.DataBindings.Add("Checked", Properties.Settings.Default, "Checked3",true, DataSourceUpdateMode.OnPropertyChanged);
//you can others
}
private void Form1_FormClosing(object sender, FormClosingEventArgs e)
{
//don't forget to call save on form closing
Properties.Settings.Default.Save();
}
The first part of my answer, regarding to the fact that nothing is saved when you close your application, is based on the assumption that when testing, you leave the third textbox empty
Why is nothing saved
First is why you are seeing nothing when opening your application, leading you to believe nothing was saved when closing it.
You are in the part of your code handling what happens when your application is closing, saving all of the textboxes (and checkboxes states) in the same setting
Which leads to the following
txtBox1 contains a
txtbox2 contains nothing (or an empty string if you prefer)
When saving, what is happening with your code is that in a first step, you are putting "a" into your textbox setting.
Then, you are replacing this vlue with the content of the second textbox, which is empty
(repeat for the third textbox)
The you are saving.... An empty value.
If you wish to fix this in a "naive" way, you would need a setting per textbox and checkbox.
Which would lead to code ressembling this in your Closing event handler
private void MainForm_FormClosing(object sender, FormClosingEventArgs e)
{
Properties.Settings.Default.checkBox1 = chkBox1.Checked;
Properties.Settings.Default.checkBox2 = chkBox2.Checked;
Properties.Settings.Default.checkBox3 = chkBox3.Checked;
Properties.Settings.Default.textBox1 = txtBox1.Text;
Properties.Settings.Default.textBox2 = txtBox2.Text;
Properties.Settings.Default.textBox3 = txtBox3.Text;
Properties.Settings.Default.PX = this.Location.X;
Properties.Settings.Default.PY = this.Location.Y;
Properties.Settings.Default.Save();
}
Why do I say "naive", because as you've surely understood, this approach is not sustainable for a huge number of controls, but this is not the scope of the question, I'll let you research a solution on your own for this particular point.
Why are the checkbox doing nothing to determine what is saved
First, with the events available on Winforms (at least with the .NET Framework 4.5 which I used to reproduce what you had) the only events available to be notified of the checkbox state change are :
CheckedChanged
CheckStateChanged
The first is used on a binary Checkbox (checked or not)
The second on a checkbox with an uncertain state added to both of the other states.
I imagine you used the first of the two (because that is the one used by default by Visual Studio when double clicking on it in the designer).
The first issue here is that it notifiesyou that the state changed not only that it went from unchecked to checked, but the other way around too.
That means if you only want an action to be done when checking, you need to add a.... check (an if block) to skip the cases you're not interest into.
Next is the actual saving.
What you are doing in your code is just copying the textbox values in a property in your class, and that will NOT persist after closing the application.
Now there is two approach you could use to save those values into the settings, the first is to do it as soon as you check the boxes.
What you would need to do then is for each event handler to copy the value of the textbox.... directly into the settings
An example for the first textbox and checkbox :
private void chkBox1_Checked(object sender, EventArgs e)
{
if(chkBox1.Checked)
{
Properties.Settings.Default.checkBox1 = chkBox1.Checked;
}
}
I'm not a huge fan though, and would prefer the second solution => to check in the closing event, before copying the value from the textbox into the settings, if the corresponding checkbox is closed.
private void Form1_FormClosing(object sender, FormClosingEventArgs e)
{
if (this.chkBox1.Checked)
{
Properties.Settings.Default.textBox = txtBox1.Text;
}
[...]
}
Now that a little better, and should be working as intended.
Please note that this answer is oriented towards correcting the problem whilst using solutions that are the closest possible of your original code.
I'm working on a WinForms project where I'm trying to create an ON/OFF toggle button that uses two separate images (both located in project resources) for both the "ON" setting, and the "OFF" setting.
Based on what I've found online, I've used a CheckBox with its appearance set to "Button".
Here is the code I've got so far for my button:
private void ToggleButton_CheckedChanged(object sender, EventArgs e)
{
if (ToggleButton.Checked)
{
ToggleButton.BackgroundImage.Equals(Properties.Resources.ToggleButton_ON);
}
else
{
ToggleButton.BackgroundImage.Equals(Properties.Resources.ToggleButton_OFF);
}
}
For some reason nothing happens when I click on the button, and I'm not sure what I've done wrong here.
Basically, I'd like the background image to cycle back and fourth between ToggleButton_ON and ToggleButton_OFF when the user clicks on the button.
Change your code to:
private void ToggleButton_CheckedChanged(object sender, EventArgs e)
{
if (ToggleButton.Checked)
ToggleButton.BackgroundImage = Properties.Resources.ToggleButton_ON;
else
ToggleButton.BackgroundImage = Properties.Resources.ToggleButton_OFF;
}
The .Equals is for checking equality which you can override in your own classes.
so I am writing a program in C# and I need it to save to custom Setting I made in the Settings designer. Here is a screenshot of the settings I have and here are a few examples of the way I am writing to the Settings.
private void txtUsername_TextChanged(object sender, EventArgs e)
{
Properties.Settings.Default.username = txtUsername.Text;
}
private void cbUpdate_CheckedChanged(object sender, EventArgs e)
{
Properties.Settings.Default.autoCheck = cbUpdate.Checked;
}
//In another method \/\/
if (Properties.Settings.Default.launchNumber == 0)
{
Settings form2 = new Settings();
form2.Show();
Properties.Settings.Default.launchNumber++;
}
So I'm pretty stumped right now, it is reading the settings I manually set in the designer normal, it just won't write over them when I set the setting to another value. I'm pretty much just trying to find where I went wrong in changing the settings. Thanks for the help.
You're not calling Save after updating settings:
Settings.Default.Save()
I have inherited some Windows Phone code that I must change. I need to show the user a tutorial about how to use the application when he first launches it. However, I cannot manage to change the current view...
Here is my code:
public LoginView()
{
InitializeComponent();
this.DataContext = new LoginViewModel();
if (ApplicationFirstLaunched() == true)
{
NavigationManager.Current.Navigate(ApplicationView.DemoView);
}
}
The ApplicationFirstLaunched function works fine (I use IsolatedStorageSettings to store a boolean value), but the view never changes.. I thought that maybe the Navigate call was wrong so I created a button in my view and assigned its Click property to this function:
private void demoBtn_Click(object sender, RoutedEventArgs e)
{
NavigationManager.Current.Navigate(ApplicationView.DemoView);
}
When I click the button, the view changes and the tutorial pops up. What to do to show another view at first launch? Thanks
Navigate in the OnNavigatedTo method.
protected override void OnNavigatedTo(System.Windows.Navigation.NavigationEventArgs e)
{
if (ApplicationFirstLaunched() == true)
{
NavigationManager.Current.Navigate(ApplicationView.DemoView);
}
}
I am working on a personal project in winforms just to gain some experience in it since I've never had the chance to work with it before. So, I'm quite the n00b when it comes to Winforms. This is the error I'm encountering:
In form BudgetTracker, I have a button called 'AddCat'. Below is the form's constructor and the button's click eventHandler:
public form_BudgetTracker()
{
InitializeComponent();
setEvents();
}
public void setEvents()
{
this.btn_AddCat.Click += new System.EventHandler(this.btn_AddCat_Click);
}
private void btn_AddCat_Click(object sender, EventArgs e)
{
form_NewCat NewCatForm = new form_NewCat();
var NewCatFormResult = NewCatForm.ShowDialog();
NewCatForm.Show();
}
In the NewCat form that comes up, I have a Cancel button. Code:
public form_NewCat()
{
InitializeComponent();
SetEvents();
}
private void SetEvents()
{
this.btn_Add.Click += new System.EventHandler(this.btn_Add_Click);
this.btn_Cancel.Click += new System.EventHandler(this.btn_Cancel_Click);
}
private void btn_Cancel_Click(object sender, EventArgs e)
{
this.Close();
}
The problem I'm facing is, when I click Add, the new form comes up. At this point, if I click Cancel, the form disappears but instantly a new instance of the form appears. I then click cancel again, and the form disappears.
What part of my code is making the form appear twice. I checked the contructors etc, but couldn't figure it out. Any help or pointers would be appreciated.
PS - As I mentioned, I'm new to winforms programming, so any cues or pointers would be appreciated as well.
private void btn_AddCat_Click(object sender, EventArgs e)
{
form_NewCat NewCatForm = new form_NewCat();
var NewCatFormResult = NewCatForm.ShowDialog(); // <-- opens the first time
NewCatForm.Show(); // <-- opens the second time
}
Judging from your code, you're simply showing the form twice!!!
form_NewCat NewCatForm = new form_NewCat();
var NewCatFormResult = NewCatForm.ShowDialog();
NewCatForm.Show();
The second line shows the form and blocks the method until DialogResult is set, then the third line shows the form without blocking the method.
Simply remove the third line!
Try stepping through the code using the F8 key instead of running it, or hitting F5. It will show you line by line what it's about to execute.
delete NewCatForm.Show();