I
open an Image i tried this methode but when i click on the button the window doesn't appear
so i cant load an image
private void button1_Click(object sender, EventArgs e)
{
OpenFileDialog open = new OpenFileDialog();
if (open.ShowDialog() == DialogResult.OK)
{
pictureBox1.ImageLocation = open.FileName;
}
Do this it will work perfectly and display full image.
private void button1_Click_1(object sender, EventArgs e)
{
OpenFileDialog open = new OpenFileDialog();
if (open.ShowDialog() == DialogResult.OK)
{
pictureBox1.ImageLocation = open.FileName;
pictureBox1.SizeMode = PictureBoxSizeMode.Zoom;
}
}
There are "Open" and "Cancel" Buttons on OpenfileDialog. So because there is no "OK" button on it, "if condition" will not be true. You should change it to:
Private void button1_Click(object sender, EventArgs e)
{
OpenFileDialog open = new OpenFileDialog();
if (open.ShowDialog() != DialogResult.Cancel)
{
pictureBox1.ImageLocation = open.FileName;
}
}
Related
i wanna make a button that opens a check file dialog and after that check if that file is the correct one,thanks. file name is key.txt,i already tried to get it but i have a way to check the path,i need help.
private void button5_Click(object sender, EventArgs e)
{
OpenFileDialog ofd = new OpenFileDialog();
ofd.ShowDialog();
if (System.IO.File.Exists("E:\\Key\\key.txt"))
{
MessageBox.Show("Injected");
}
else
{
MessageBox.Show("Wrong File");
}
}
This is what i have,any solution?
It sounds like you just want to filter the available files that someone can select to those which match a particular file name, but still allow users to find that file in any folder.
Use the Filter property on the OpenFileDialog.
var ofd = new OpenFileDialog();
ofd.Filter = "key files|key.txt";
var dialogResult = ofd.ShowDialog();
if (dialogResult == DialogResult.OK && ofd.CheckFileExists)
{
MessageBox.Show("Injected " + ofd.FileName);
}
else
{
MessageBox.Show("Cancelled");
}
private void button5_Click(object sender, EventArgs e)
{
var ofd = new OpenFileDialog
{
Filter = "Key files (key.txt)|key.txt",
};
if (ofd.ShowDialog() == DialogResult.OK && File.Exists(ofd.FileName))
{
MessageBox.Show("Injected");
}
else
{
MessageBox.Show("Wrong File");
}
}
but I strongly recommend you to add OpenFileDialog as a form control, so the code look like:
private void button5_Click(object sender, EventArgs e)
{
if (openFileDialog1.ShowDialog() == DialogResult.OK && File.Exists(openFileDialog1.FileName))
{
MessageBox.Show("Injected");
}
else
{
MessageBox.Show("Wrong File");
}
}
Configure filter in property window:
I'm trying to make a simple Windows Form Application that saves a text file. I'm having trouble with the following program, it gives me:
Empty path is not a legal
namespace Filing
{
public partial class Form1 : Form
{
public Form1()
{
InitializeComponent();
}
private void Form1_Load(object sender, EventArgs e)
{
}
private void button_Save_Click(object sender, EventArgs e)
{
SaveFileDialog file = new SaveFileDialog();
file.Filter = "Text (*.txt) | Word File *.doc";
file.Title = "Save a file";
File.WriteAllText(file.FileName, richTextBox1.Text);
file.ShowDialog();
}
private void button_exit_Click(object sender, EventArgs e)
{
this.Close();
}
}
}
Cause you didn't "show" the SaveFileDialog yet, so the fileName is empty.
Try moving the showDialog upward:
private void button_Save_Click(object sender, EventArgs e)
{
SaveFileDialog file = new SaveFileDialog();
file.Filter = "Text (*.txt) | Word File *.doc";
file.Title = "Save a file";
//Ask the user to select the file path and file name, don't forget to handle cancel button!
if(file.ShowDialog() != DialogResult.Cancel)
{
File.WriteAllText(file.FileName, richTextBox1.Text);
}
}
You should wrap the writing statement as the following.
if(file.ShowDialog()== DialogResult.OK)
File.WriteAllText(file.FileName, richTextBox1.Text);
I'm trying to open a file dialog box so the user can choose the location of an access database. Can someone explain how to add a file dialog when a button is clicked and also how to transform the user choice into a string that contains the file directory ( c:\abc\dfg\1234.txt)?
Thanks
As you did not state the technology you use (WPF or WinForms), I assume you use WinForms. In that case, use an OpenFileDialog in your code. After the dialog was closed, you can get the selected full file name using the FileName property.
There is the following example of how to use it on the documentation page I linked above, which I modified slightly as you want the file name, not the stream:
private void button1_Click(object sender, System.EventArgs e)
{
OpenFileDialog openFileDialog1 = new OpenFileDialog();
openFileDialog1.InitialDirectory = "c:\\" ;
openFileDialog1.Filter = "Database files (*.mdb, *.accdb)|*.mdb;*.accdb" ;
openFileDialog1.FilterIndex = 0;
openFileDialog1.RestoreDirectory = true ;
if(openFileDialog1.ShowDialog() == DialogResult.OK)
{
string selectedFileName = openFileDialog1.FileName;
//...
}
}
Based on your previous question I assume you are using WinForms.
You can use the OpenFileDialog Class for this purpose. See the code below which will run on your button Click event assuming your button id is button1:
private void button1_Click(object sender, System.EventArgs e)
{
OpenFileDialog openFileDialog1 = new OpenFileDialog();
openFileDialog1.InitialDirectory = "c:\\";
openFileDialog1.Filter = "Access files (*.accdb)|*.accdb|Old Access files (*.mdb)|*.mdb";
openFileDialog1.FilterIndex = 2;
openFileDialog1.RestoreDirectory = true;
if(openFileDialog1.ShowDialog() == DialogResult.OK)
{
var path = openFileDialog1.FileName;
}
}
More information.
Assuming that you actually have a form with button (button1)...
At the constructor hook into button1's click event
...
button1.Click += button1_Click;
...
Then define the handling function and use System.Windows.Forms.OpenFileDialog as you like.
void button1_Click(object sender, EventArgs e)
{
string oSelectedFile = "";
System.Windows.Forms.OpenFileDialog oDlg = new System.Windows.Forms.OpenFileDialog();
if (System.Windows.Forms.DialogResult.OK == oDlg.ShowDialog())
{
oSelectedFile = oDlg.FileName;
// Do whatever you want with oSelectedFile
}
}
It's actually fairly simple
namespace YourProgram
{
public partial class Form1 : Form
{
public Form1()
{
InitializeComponent();
}
string path = "";
//Declare the File Dialog
OpenFileDialog ofd = new OpenFileDialog();
private void button1_click(object sender, EventArgs e)
{
if (odf.ShowDialog() == DialogResult.OK)
{
path = ofd.FileName;
}
}
}
}
I have a question about the opfiledialog function within c#. When i dont select a file with openfiledialog it put's a text automaticly in my textbox. That text will be "filedialog1". What can i do to fix this.
using System;
using System.Windows.Forms;
using System.IO;
namespace Flashloader
{
public partial class NewApplication : Form
{
private toepassinginifile _toepassinginifile;
private controllerinifile _controllerinifile;
//private controllerinifile _controlIniFile;
public NewApplication(toepassinginifile iniFile)
{
_controllerinifile = new controllerinifile();
_toepassinginifile = iniFile;
InitializeComponent();
controllerComboBox.DataSource = _controllerinifile.Controllers;
}
public bool Run()
{
var result = ShowDialog();
return result == System.Windows.Forms.DialogResult.OK;
}
private void button4_Click(object sender, EventArgs e)
{
this.Close();
}
private void button1_Click(object sender, EventArgs e)
{
openFileDialog1.Filter = "Srec Files (.a20; .a21; .a26; .a44)|*.a20; *.a21; *.a26; *.a44|All files (*.*)|*.*";
openFileDialog1.Title = ("Choose a file");
openFileDialog1.InitialDirectory = Path.Combine(Directory.GetCurrentDirectory());
openFileDialog1.RestoreDirectory = true;
if (openFileDialog1.ShowDialog() == DialogResult.OK)
{
fileBox.Text = (System.IO.Path.GetFileName(openFileDialog1.FileName));
}
}
private void button3_Click(object sender, EventArgs e)
{
Toepassing toepassing = new Toepassing();
toepassing.Name = nameBox.Text;
toepassing.Controller = (Flashloader.Controller)controllerComboBox.SelectedItem;
toepassing.TabTip = descBox.Text;
toepassing.Lastfile = openFileDialog1.FileName;
fileBox.Text = openFileDialog1.FileName;
if (nameBox.Text == "")
MessageBox.Show("You haven't assigned a Name");
else if (controllerComboBox.Text == "")
MessageBox.Show("You haven't assigned a Controller");
else if (descBox.Text == "")
MessageBox.Show("You haven't assigned a Desciption");
else if (fileBox.Text == "")
MessageBox.Show("You haven't assigned a Applicationfile");
_toepassinginifile.ToePassingen.Add(toepassing);
_toepassinginifile.Save(toepassing);
MessageBox.Show("Save Succesfull");
DialogResult = DialogResult.OK;
this.Close();
}
private void button2_Click(object sender, EventArgs e)
{
var newcontroller = new Newcontroller(_controllerinifile);
newcontroller.ShowDialog();
controllerComboBox.DataSource = null;
controllerComboBox.DataSource = _controllerinifile.Controllers;
}
}
}
Thanks all for the help
private void button3_Click(object sender, EventArgs e)
{
toepassing.Lastfile = openFileDialog1.FileName;// Dont do this
fileBox.Text = openFileDialog1.FileName; //or this
Its unclear to me why you are holding onto an Open file dialog I would personally do the following
using(OpenFileDialog ofd = new OpenFileDialog())
{
if(ofd.ShowDialog() == DialogResult.OK)
{
classStringVariable = ofd.FileName;
fileBox.Text = ofd.FileName;
}
}
Then in button 3
toepassing.LastFile = classStringVariable ;
fileBox.Text = classStringVariable ;
When you use the Form Designer to add an OpenFileDialog control on you form, the designer assigns at the property FileName the value openFileDialog1.
I suppose you have set something as the initial value for the property FileName. Then in button_click3 you have no mean to check for the DialogResult and thus you get inconditionally this default back.
Fix it removing this default from the designer FileName property
Just add openFileDialog1.FileName= ""; before you show the dialog.
openFileDialog1.Filter = "Srec Files (.a20; .a21; .a26; .a44)|*.a20; *.a21; *.a26; *.a44|All files (*.*)|*.*";
openFileDialog1.Title = ("Choose a file");
openFileDialog1.InitialDirectory = Path.Combine(Directory.GetCurrentDirectory());
openFileDialog1.RestoreDirectory = true;
openFileDialog1.FileName = "";
if (openFileDialog1.ShowDialog() == DialogResult.OK && openFileDialog1.FileName != "")
{
fileBox.Text = (System.IO.Path.GetFileName(openFileDialog1.FileName));
}
In your button3_Click event you're checking for an empty string file name anyways, so they would get the correct error message and they wouldn't have some weird arbitrary default name show up when they open the dialog.
I have a windows form application I have a button that opens the SaveFileFrom dialog
private void button1_Click(object sender, EventArgs e)
{
SaveFileDialog savefileDialog1 = new SaveFileDialog();
savefileDialog1.ShowDialog();
}
I was wondering how I could put the file that is chosen in a text box even like so
private void textBox1_TextChanged(object sender, EventArgs e)
{
}
UPDATE* Ok, well since the user might want to open more than one file to save I wanted to take off my button SaveFileFrom and instead make the textbox run through the OpenFileDialog when clicked.
Also, is their a way to make a text link instead of a button?
Like I want a text link to add another text box/
Try this
private void button1_Click(object sender, EventArgs e)
{
SaveFileDialog savefileDialog1 = new SaveFileDialog();
if (savefileDialog1.ShowDialog() == DialogResult.OK)
{
textBox1.Text = savefileDialog1.Filename;
}
}
The filename selected will be saved in SaveFileDialog.FileName
example:
private void button1_Click(object sender, EventArgs e)
{
SaveFileDialog SvDlg = new SaveFileDialog();
if (SvDlg.ShowDialog() == DialogResult.OK)
{
textBox1.Text = SvDlg.FileName;
}
else
{
MessageBox.Show("No file selected.");
}
}