I have a question about the opfiledialog function within c#. When i dont select a file with openfiledialog it put's a text automaticly in my textbox. That text will be "filedialog1". What can i do to fix this.
using System;
using System.Windows.Forms;
using System.IO;
namespace Flashloader
{
public partial class NewApplication : Form
{
private toepassinginifile _toepassinginifile;
private controllerinifile _controllerinifile;
//private controllerinifile _controlIniFile;
public NewApplication(toepassinginifile iniFile)
{
_controllerinifile = new controllerinifile();
_toepassinginifile = iniFile;
InitializeComponent();
controllerComboBox.DataSource = _controllerinifile.Controllers;
}
public bool Run()
{
var result = ShowDialog();
return result == System.Windows.Forms.DialogResult.OK;
}
private void button4_Click(object sender, EventArgs e)
{
this.Close();
}
private void button1_Click(object sender, EventArgs e)
{
openFileDialog1.Filter = "Srec Files (.a20; .a21; .a26; .a44)|*.a20; *.a21; *.a26; *.a44|All files (*.*)|*.*";
openFileDialog1.Title = ("Choose a file");
openFileDialog1.InitialDirectory = Path.Combine(Directory.GetCurrentDirectory());
openFileDialog1.RestoreDirectory = true;
if (openFileDialog1.ShowDialog() == DialogResult.OK)
{
fileBox.Text = (System.IO.Path.GetFileName(openFileDialog1.FileName));
}
}
private void button3_Click(object sender, EventArgs e)
{
Toepassing toepassing = new Toepassing();
toepassing.Name = nameBox.Text;
toepassing.Controller = (Flashloader.Controller)controllerComboBox.SelectedItem;
toepassing.TabTip = descBox.Text;
toepassing.Lastfile = openFileDialog1.FileName;
fileBox.Text = openFileDialog1.FileName;
if (nameBox.Text == "")
MessageBox.Show("You haven't assigned a Name");
else if (controllerComboBox.Text == "")
MessageBox.Show("You haven't assigned a Controller");
else if (descBox.Text == "")
MessageBox.Show("You haven't assigned a Desciption");
else if (fileBox.Text == "")
MessageBox.Show("You haven't assigned a Applicationfile");
_toepassinginifile.ToePassingen.Add(toepassing);
_toepassinginifile.Save(toepassing);
MessageBox.Show("Save Succesfull");
DialogResult = DialogResult.OK;
this.Close();
}
private void button2_Click(object sender, EventArgs e)
{
var newcontroller = new Newcontroller(_controllerinifile);
newcontroller.ShowDialog();
controllerComboBox.DataSource = null;
controllerComboBox.DataSource = _controllerinifile.Controllers;
}
}
}
Thanks all for the help
private void button3_Click(object sender, EventArgs e)
{
toepassing.Lastfile = openFileDialog1.FileName;// Dont do this
fileBox.Text = openFileDialog1.FileName; //or this
Its unclear to me why you are holding onto an Open file dialog I would personally do the following
using(OpenFileDialog ofd = new OpenFileDialog())
{
if(ofd.ShowDialog() == DialogResult.OK)
{
classStringVariable = ofd.FileName;
fileBox.Text = ofd.FileName;
}
}
Then in button 3
toepassing.LastFile = classStringVariable ;
fileBox.Text = classStringVariable ;
When you use the Form Designer to add an OpenFileDialog control on you form, the designer assigns at the property FileName the value openFileDialog1.
I suppose you have set something as the initial value for the property FileName. Then in button_click3 you have no mean to check for the DialogResult and thus you get inconditionally this default back.
Fix it removing this default from the designer FileName property
Just add openFileDialog1.FileName= ""; before you show the dialog.
openFileDialog1.Filter = "Srec Files (.a20; .a21; .a26; .a44)|*.a20; *.a21; *.a26; *.a44|All files (*.*)|*.*";
openFileDialog1.Title = ("Choose a file");
openFileDialog1.InitialDirectory = Path.Combine(Directory.GetCurrentDirectory());
openFileDialog1.RestoreDirectory = true;
openFileDialog1.FileName = "";
if (openFileDialog1.ShowDialog() == DialogResult.OK && openFileDialog1.FileName != "")
{
fileBox.Text = (System.IO.Path.GetFileName(openFileDialog1.FileName));
}
In your button3_Click event you're checking for an empty string file name anyways, so they would get the correct error message and they wouldn't have some weird arbitrary default name show up when they open the dialog.
Related
i wanna make a button that opens a check file dialog and after that check if that file is the correct one,thanks. file name is key.txt,i already tried to get it but i have a way to check the path,i need help.
private void button5_Click(object sender, EventArgs e)
{
OpenFileDialog ofd = new OpenFileDialog();
ofd.ShowDialog();
if (System.IO.File.Exists("E:\\Key\\key.txt"))
{
MessageBox.Show("Injected");
}
else
{
MessageBox.Show("Wrong File");
}
}
This is what i have,any solution?
It sounds like you just want to filter the available files that someone can select to those which match a particular file name, but still allow users to find that file in any folder.
Use the Filter property on the OpenFileDialog.
var ofd = new OpenFileDialog();
ofd.Filter = "key files|key.txt";
var dialogResult = ofd.ShowDialog();
if (dialogResult == DialogResult.OK && ofd.CheckFileExists)
{
MessageBox.Show("Injected " + ofd.FileName);
}
else
{
MessageBox.Show("Cancelled");
}
private void button5_Click(object sender, EventArgs e)
{
var ofd = new OpenFileDialog
{
Filter = "Key files (key.txt)|key.txt",
};
if (ofd.ShowDialog() == DialogResult.OK && File.Exists(ofd.FileName))
{
MessageBox.Show("Injected");
}
else
{
MessageBox.Show("Wrong File");
}
}
but I strongly recommend you to add OpenFileDialog as a form control, so the code look like:
private void button5_Click(object sender, EventArgs e)
{
if (openFileDialog1.ShowDialog() == DialogResult.OK && File.Exists(openFileDialog1.FileName))
{
MessageBox.Show("Injected");
}
else
{
MessageBox.Show("Wrong File");
}
}
Configure filter in property window:
I'm trying to open a file dialog box so the user can choose the location of an access database. Can someone explain how to add a file dialog when a button is clicked and also how to transform the user choice into a string that contains the file directory ( c:\abc\dfg\1234.txt)?
Thanks
As you did not state the technology you use (WPF or WinForms), I assume you use WinForms. In that case, use an OpenFileDialog in your code. After the dialog was closed, you can get the selected full file name using the FileName property.
There is the following example of how to use it on the documentation page I linked above, which I modified slightly as you want the file name, not the stream:
private void button1_Click(object sender, System.EventArgs e)
{
OpenFileDialog openFileDialog1 = new OpenFileDialog();
openFileDialog1.InitialDirectory = "c:\\" ;
openFileDialog1.Filter = "Database files (*.mdb, *.accdb)|*.mdb;*.accdb" ;
openFileDialog1.FilterIndex = 0;
openFileDialog1.RestoreDirectory = true ;
if(openFileDialog1.ShowDialog() == DialogResult.OK)
{
string selectedFileName = openFileDialog1.FileName;
//...
}
}
Based on your previous question I assume you are using WinForms.
You can use the OpenFileDialog Class for this purpose. See the code below which will run on your button Click event assuming your button id is button1:
private void button1_Click(object sender, System.EventArgs e)
{
OpenFileDialog openFileDialog1 = new OpenFileDialog();
openFileDialog1.InitialDirectory = "c:\\";
openFileDialog1.Filter = "Access files (*.accdb)|*.accdb|Old Access files (*.mdb)|*.mdb";
openFileDialog1.FilterIndex = 2;
openFileDialog1.RestoreDirectory = true;
if(openFileDialog1.ShowDialog() == DialogResult.OK)
{
var path = openFileDialog1.FileName;
}
}
More information.
Assuming that you actually have a form with button (button1)...
At the constructor hook into button1's click event
...
button1.Click += button1_Click;
...
Then define the handling function and use System.Windows.Forms.OpenFileDialog as you like.
void button1_Click(object sender, EventArgs e)
{
string oSelectedFile = "";
System.Windows.Forms.OpenFileDialog oDlg = new System.Windows.Forms.OpenFileDialog();
if (System.Windows.Forms.DialogResult.OK == oDlg.ShowDialog())
{
oSelectedFile = oDlg.FileName;
// Do whatever you want with oSelectedFile
}
}
It's actually fairly simple
namespace YourProgram
{
public partial class Form1 : Form
{
public Form1()
{
InitializeComponent();
}
string path = "";
//Declare the File Dialog
OpenFileDialog ofd = new OpenFileDialog();
private void button1_click(object sender, EventArgs e)
{
if (odf.ShowDialog() == DialogResult.OK)
{
path = ofd.FileName;
}
}
}
}
I am programming in Visual Studio 2013, c# winform. Im trying to make something like Steam Library, but I don't know how to save FlowLayoutPanel that I have in tab1 (Library).
This is how it looks (Library)
This is how it looks (Adding a new game)
This is how it looks (Deleting a new game): http:// oi62.tinypic.com/2uzfc3k.jpg
(sorry, im not able to add images and more than 2 links)
Here is my code:
private void btnTest_Click_1(object sender, EventArgs e)
{
if (textBox1.Text != "")
{
if (textBox2.Text != "")
{
if (textBox3.Text != "")
{
Button btn = sender as Button;
Button btnNew = new Button();
btnNew.Text = "";
btnNew.Height = 108;
btnNew.Width = 230;
btnNew.Name = textBox3.Text;
comboBox1.Items.Add(textBox3.Text);
btnNew.BackgroundImage = new Bitmap(textBox1.Text);
btnNew.BackgroundImageLayout = ImageLayout.Stretch;
btnNew.FlatStyle = FlatStyle.Flat;
flpContainer.Controls.Add(btnNew);
btnNew.Click += btnNew_Click;
btnNew.Tag = textBox2.Text;
counter1+=+1;
label1.Text = counter1.ToString();
System.Windows.Forms.MessageBox.Show("Game " + textBox3.Text + " was successfully added to library!");
textBox1.Text = "";
textBox2.Text = "";
textBox3.Text = "";
}
else if (textBox3.Text == "")
{
MessageBox.Show("You didn't wrote name!");
}
}
else if (textBox2.Text == "")
{
System.Windows.Forms.MessageBox.Show("You didn't choose exe file!");
}
}
else if (textBox1.Text == "")
{
System.Windows.Forms.MessageBox.Show("You didn't choose image!");
}
}
private void btnNew_Click(object sender, EventArgs e)
{
Button clickedButton = (Button)sender;
Process.Start((string)clickedButton.Tag);
}
private void ZvolitObrazek_Click(object sender, EventArgs e)
{
openFileDialog1.Title = "Open Image";
openFileDialog1.FileName = "Image file";
openFileDialog1.Filter = "Image files (*.jpg, *.img, *.png, *.jpeg)|*.jpg; *.img; *.png; *.jpeg|All files (*.*)|*.*";
if (openFileDialog1.ShowDialog() == DialogResult.OK)
{
textBox1.Text = openFileDialog1.FileName;
}
}
private void button1_Click(object sender, EventArgs e)
{
openFileDialog2.Title = "Open exe";
openFileDialog2.FileName = "Exe file";
openFileDialog2.Filter = "Exe files (*.exe)|*.exe|All files(*.*)|*.*";
if (openFileDialog2.ShowDialog() == DialogResult.OK)
{
textBox2.Text = openFileDialog2.FileName;
}
}
private void flpContainer_Paint(object sender, PaintEventArgs e)
{
flpContainer.AutoScroll = true;
}
private void button2_Click(object sender, EventArgs e)
{
if (comboBox1.Text == "")
{
MessageBox.Show("You didn't choose game that you want delete!");
}
else if (comboBox1.Text != "")
{
Control foundControl = null;
foreach (Control c in flpContainer.Controls)
{
c.Name = comboBox1.Text;
foundControl = c;
}
flpContainer.Controls.Remove(foundControl);
counter1 = counter1 - 1;
label1.Text = counter1.ToString();
MessageBox.Show("Game " + comboBox1.Text + " was successfully deleted");
comboBox1.Items.Remove(comboBox1.Text);
comboBox1.Text = "";
}
}
}
FlowLayoutPanel=flpContainter.
So, my question is, how can i save items (buttons) in FlowLayoutPanel and how to load them later?
Thank you for your answers!
You should create a class for your items (game buttons), including their Title, Image etc. Then you can save them using XML.
class Game
{
// Properties here
}
This link will provide you with a quick How-to on how to accomplish this.
For saving images you can convert the image to base64 and convert it back to an image when loading the XML file again.
public partial class Form1 : Form
{
SaveFileDialog sfd = new SaveFileDialog();
OpenFileDialog ofd = new OpenFileDialog();
public string contents = string.Empty;
public Form1()
{
InitializeComponent();
this.Text = "Untitled";
}
private void newToolStripMenuItem_Click(object sender, EventArgs e)
{
if (richTextBox1.Text != contents)
{
DialogResult dr = MessageBox.Show("Do You want to save the changes made to " + this.Text, "Save", MessageBoxButtons.YesNoCancel);
if (dr == DialogResult.Yes)
{
sfd.Title = "Save";
if (SaveFile() == 0)
return;
else
{
richTextBox1.Text = "";
this.Text = "Untitled";
}
contents = "";
}
else if (dr == DialogResult.No)
{
richTextBox1.Text = "";
this.Text = "Untitled";
contents = "";
}
else
{
richTextBox1.Focus();
}
}
else
{
this.Text = "Untitled";
richTextBox1.Text = "";
contents = "";
}
}
private int SaveFile()
{
sfd.Filter = "Text Documents|*.txt";
sfd.DefaultExt = "txt";
if (sfd.ShowDialog() == DialogResult.Cancel)
{
richTextBox1.Focus();
return 0;
}
else
{
contents = richTextBox1.Text;
if (this.Text == "Untitled")
richTextBox1.SaveFile(sfd.FileName,RichTextBoxStreamType.PlainText);
else
{
sfd.FileName = this.Text;
richTextBox1.SaveFile(sfd.FileName,RichTextBoxStreamType.PlainText);
}
this.Text = sfd.FileName;
return 1;
}
}
private void OpenFile()
{
ofd.Filter = "Text Documents|*.txt";
if (ofd.ShowDialog() == DialogResult.Cancel)
richTextBox1.Focus();
else
{
richTextBox1.LoadFile(ofd.FileName, RichTextBoxStreamType.PlainText);
this.Text = ofd.FileName;
contents = richTextBox1.Text;
}
}
private void openToolStripMenuItem_Click(object sender, EventArgs e)
{
if (richTextBox1.Text != contents)
{
DialogResult dr = MessageBox.Show("Do You want to save the changes made to " + this.Text, "Save", MessageBoxButtons.YesNoCancel);
if (dr == DialogResult.Yes)
{
SaveFile();
OpenFile();
}
else if (dr == DialogResult.No)
{
OpenFile();
}
else
{
richTextBox1.Focus();
}
}
else
OpenFile();
}
private void saveToolStripMenuItem_Click(object sender, EventArgs e)
{
SaveFile();
}
private void saveAsToolStripMenuItem_Click(object sender, EventArgs e)
{
sfd.Filter = "Text Documents|*.txt";
sfd.DefaultExt = "txt";
if (sfd.ShowDialog() == DialogResult.Cancel)
{
richTextBox1.Focus();
}
else
{
contents = richTextBox1.Text;
richTextBox1.SaveFile(sfd.FileName, RichTextBoxStreamType.PlainText);
this.Text = sfd.FileName;
}
}
When we open Windows notepad application then open a file, changes it contents and save it, it simply gets saved without opening the Save File dialog. But in the notepad program I have created above the Save File dialog opens on clicking 'Save' after changing the contents of saved file. Although the same file name appears in the save file dialog but on clicking 'Save' it gives a message "The same file name already exists. Do you want to replace it?". That is what I want to remove and make the changed contents saved directly to the opened file without opening the save file dialog.
Set sfd.OverwritePrompt = false any time after construction and before ShowDialog to suppress the overwrite warning.
You want to have two choices to save: A 'Save As..' button and a 'Save' button. You can create a string to hold the path of the opened file. The location may also change if the user specifies a new location when they save the file. If the user did not open the file, the 'Save As...' button would open the regular Save File Dialog. Once the user specifies the location of their document, you can save the file path to that string and use a `StreamWriter' to save it without the dialog:
...
using System.IO;
...
public partial class Form1 : Form
{
SaveFileDialog sfd = new SaveFileDialog();
OpenFileDialog ofd = new OpenFileDialog();
public string contents = string.Empty;
//string to hold file location
string currentFileLoc;
public Form1()
{
InitializeComponent();
this.Text = "Untitled";
}
private void newToolStripMenuItem_Click(object sender, EventArgs e)
{
if (richTextBox1.Text != contents)
{
DialogResult dr = MessageBox.Show("Do You want to save the changes made to " + this.Text, "Save", MessageBoxButtons.YesNoCancel);
if (dr == DialogResult.Yes)
{
sfd.Title = "Save";
if (SaveFile() == 0)
return;
else
{
richTextBox1.Text = "";
this.Text = "Untitled";
}
contents = "";
}
else if (dr == DialogResult.No)
{
richTextBox1.Text = "";
this.Text = "Untitled";
contents = "";
}
else
{
richTextBox1.Focus();
}
}
else
{
this.Text = "Untitled";
richTextBox1.Text = "";
contents = "";
}
}
private int SaveFile()
{
sfd.Filter = "Text Documents|*.txt";
sfd.DefaultExt = "txt";
if (sfd.ShowDialog() == DialogResult.Cancel)
{
richTextBox1.Focus();
return 0;
}
else
{
contents = richTextBox1.Text;
if (this.Text == "Untitled")
richTextBox1.SaveFile(sfd.FileName,RichTextBoxStreamType.PlainText);
else
{
sfd.FileName = this.Text;
richTextBox1.SaveFile(sfd.FileName,RichTextBoxStreamType.PlainText);
}
this.Text = sfd.FileName;
//
currentFileLoc = sfd.FileName;
return 1;
}
}
private void OpenFile()
{
ofd.Filter = "Text Documents|*.txt";
if (ofd.ShowDialog() == DialogResult.Cancel)
richTextBox1.Focus();
else
{
richTextBox1.LoadFile(ofd.FileName, RichTextBoxStreamType.PlainText);
this.Text = ofd.FileName;
contents = richTextBox1.Text;
}
currentFileLoc = ofd.FileName;
this.Text = currentFileLoc;
}
private void openToolStripMenuItem_Click(object sender, EventArgs e)
{
if (richTextBox1.Text != contents)
{
DialogResult dr = MessageBox.Show("Do You want to save the changes made to " + this.Text, "Save", MessageBoxButtons.YesNoCancel);
if (dr == DialogResult.Yes)
{
SaveFile();
OpenFile();
}
else if (dr == DialogResult.No)
{
OpenFile();
}
else
{
richTextBox1.Focus();
}
}
else
OpenFile();
}
private void saveToolStripMenuItem_Click(object sender, EventArgs e)
{
Save();
}
private void saveAsToolStripMenuItem_Click(object sender, EventArgs e)
{
SaveFile();
}
//new method
private void Save()
{
if (currentFileLoc != null)
{
using (StreamWriter writer = new StreamWriter(currentFileLoc))
{
writer.WriteLine(richTextBox1.Text);
}
}
else
saveFile();
}
}
I suggest you also enclose the using(...){ } block in a try/catch statement and handle any exceptions.
What you need to do is save the filename entered, then, when the save option is pressed, check for a previously entered filename. If you have one, skip showing the dialog and just execute the save code.
I have made a method so that when you click on Browse From File the openDialogBox appear. But it does not . What is wrong ?
This is the method that I made to Open the OpenFileDialog:
public void Lista()
{
string[] col2 = new string[dataGridView1.Rows.Count];
for (int i = 0; i < dataGridView1.Rows.Count; i++)
if (col2[i] == "Browse From File...")
{
DialogResult result2 = openFileDialog2.ShowDialog();
if (result2 == DialogResult.OK)
{
// filename = openFileDialog1.FileName;
}
}
}
This is the method where I call the method Lista.
private void button1_Click(object sender, EventArgs e)
{
// opens window **BROWSE**
openFileDialog1.Title = "Choose File CSV ";
string filename = "";
DialogResult result = openFileDialog1.ShowDialog();
if (result == DialogResult.OK)
{
filename = openFileDialog1.FileName;
textBox1.Text = filename;
string line;
// Read the file and display it line by line.
System.IO.StreamReader file = new System.IO.StreamReader(textBox1.Text);
stringforData = file.ReadLine();
while ((line = file.ReadLine()) != null)
{
//read inside the table
fileList.Add(line.Split(';'));
}
file.Close();
this.ToDataGrid();
this.Lista();
}
}
DataGridView by only having one editing control for all the rows. Here's how I handled a similar situation, First try a delegate to the EditControlShowing event
namespace WindowsFormsApplication1
{
public partial class Form1 : Form
{
public Form1()
{
InitializeComponent();
}
OpenFileDialog ofd = new OpenFileDialog();
private void Form1_Load(object sender, EventArgs e)
{
dataGridView1.Columns.Add("ID", "Product ID");
DataGridViewComboBoxColumn comboxboxCol = new DataGridViewComboBoxColumn();
comboxboxCol.HeaderText = "Type";
comboxboxCol.Items.Add("Obj1");
comboxboxCol.Items.Add("Obj2");
comboxboxCol.Items.Add("Obj3");
dataGridView1.Columns.Add(comboxboxCol);
dataGridView1.EditingControlShowing += new DataGridViewEditingControlShowingEventHandler(Grid_EditingControlShowing);
}
void Grid_EditingControlShowing(object sender, DataGridViewEditingControlShowingEventArgs e)
{
ComboBox combo = e.Control as ComboBox;
if (combo != null)
{
// the event to handle combo changes
EventHandler comboDelegate = new EventHandler(
(cbSender, args) =>
{
ofd.ShowDialog();
});
// register the event with the editing control
combo.SelectedValueChanged += comboDelegate;
}
}
}
}
Hope this will solve your Issue