Choose file C# and get directory - c#

I'm trying to open a file dialog box so the user can choose the location of an access database. Can someone explain how to add a file dialog when a button is clicked and also how to transform the user choice into a string that contains the file directory ( c:\abc\dfg\1234.txt)?
Thanks

As you did not state the technology you use (WPF or WinForms), I assume you use WinForms. In that case, use an OpenFileDialog in your code. After the dialog was closed, you can get the selected full file name using the FileName property.
There is the following example of how to use it on the documentation page I linked above, which I modified slightly as you want the file name, not the stream:
private void button1_Click(object sender, System.EventArgs e)
{
OpenFileDialog openFileDialog1 = new OpenFileDialog();
openFileDialog1.InitialDirectory = "c:\\" ;
openFileDialog1.Filter = "Database files (*.mdb, *.accdb)|*.mdb;*.accdb" ;
openFileDialog1.FilterIndex = 0;
openFileDialog1.RestoreDirectory = true ;
if(openFileDialog1.ShowDialog() == DialogResult.OK)
{
string selectedFileName = openFileDialog1.FileName;
//...
}
}

Based on your previous question I assume you are using WinForms.
You can use the OpenFileDialog Class for this purpose. See the code below which will run on your button Click event assuming your button id is button1:
private void button1_Click(object sender, System.EventArgs e)
{
OpenFileDialog openFileDialog1 = new OpenFileDialog();
openFileDialog1.InitialDirectory = "c:\\";
openFileDialog1.Filter = "Access files (*.accdb)|*.accdb|Old Access files (*.mdb)|*.mdb";
openFileDialog1.FilterIndex = 2;
openFileDialog1.RestoreDirectory = true;
if(openFileDialog1.ShowDialog() == DialogResult.OK)
{
var path = openFileDialog1.FileName;
}
}
More information.

Assuming that you actually have a form with button (button1)...
At the constructor hook into button1's click event
...
button1.Click += button1_Click;
...
Then define the handling function and use System.Windows.Forms.OpenFileDialog as you like.
void button1_Click(object sender, EventArgs e)
{
string oSelectedFile = "";
System.Windows.Forms.OpenFileDialog oDlg = new System.Windows.Forms.OpenFileDialog();
if (System.Windows.Forms.DialogResult.OK == oDlg.ShowDialog())
{
oSelectedFile = oDlg.FileName;
// Do whatever you want with oSelectedFile
}
}

It's actually fairly simple
namespace YourProgram
{
public partial class Form1 : Form
{
public Form1()
{
InitializeComponent();
}
string path = "";
//Declare the File Dialog
OpenFileDialog ofd = new OpenFileDialog();
private void button1_click(object sender, EventArgs e)
{
if (odf.ShowDialog() == DialogResult.OK)
{
path = ofd.FileName;
}
}
}
}

Related

how to access OpenFileDialog with Streamwrite?

i want to make a windows forms app with 2 buttons
1 Button to find a .wtf or .txt file
Second Button to write a line into selected file let`s say "example"
this is my first button
private void button5_Click_1(object sender, EventArgs e)
{
OpenFileDialog choofdlog = new OpenFileDialog();
choofdlog.Filter = "All Files (*.*)|*.*";
choofdlog.FilterIndex = 1;
choofdlog.Multiselect = false;
if (choofdlog.ShowDialog() == DialogResult.OK)
{
string sFileName = choofdlog.FileName;
}
}
now how do i make the second button write "example" into the file i selected with the first one ?
You can achieve this in two steps:
First, you have to store the file name in a member variable:
private string _fileName;
private void button5_Click_1(object sender, EventArgs e)
{
OpenFileDialog choofdlog = new OpenFileDialog();
choofdlog.Filter = "All Files (*.*)|*.*";
choofdlog.FilterIndex = 1;
choofdlog.Multiselect = false;
if (choofdlog.ShowDialog() == DialogResult.OK)
{
_fileName = choofdlog.FileName;
}
}
In the second step, you have to define the logic of button 2:
private void secondButton_Click_1(object sender, EventArgs e)
{
System.IO.File.WriteAllText( _fileName, "Example" );
}
"1 Button to find a .wtf or .txt file"
To look for specific file extensions you should change your filter a bit
openFileDialog.InitialDirectory = "c:\\";
openFileDialog.Filter = "txt files (*.txt)|*.txt|wtf files (*.wtf)|*.wtf";
openFileDialog.FilterIndex = 2;
openFileDialog.RestoreDirectory = true;
Microsoft docs

Winforms "Save" button (like we have in MS Word)

My point is to create a save button like we have in Microsoft Word, for example. I know that there is already a post about "Save As" button but here is a difference. You click "Save" and if your file has not been saved earlier, you will get a window with possibility to set a name, directory etc. But if you have already saved the file, you will not get that window (unlike with "Save As"), changes will be saved for the file and this is exactly what I need
So I have this event, can somebody help me what's next?
private void saveToolStripMenuItem_Click(object sender, EventArgs e)
{
}
P.S. Already tried this:
private void saveToolStripMenuItem_Click(object sender, EventArgs e)
{
SaveFileDialog saveFileDialog1 = new SaveFileDialog();
saveFileDialog1.InitialDirectory = #"C:\Documents";
saveFileDialog1.Title = "Saving files";
saveFileDialog1.CheckFileExists = true;
saveFileDialog1.CheckPathExists = true;
saveFileDialog1.DefaultExt = "";
saveFileDialog1.Filter = "All files (*.*)|*.*";
saveFileDialog1.FilterIndex = 1;
saveFileDialog1.RestoreDirectory = true;
if (saveFileDialog1.ShowDialog() == DialogResult.OK)
{
System.IO.StreamWriter file = new System.IO.StreamWriter(saveFileDialog1.FileName.ToString());
file.WriteLine(richTextBox1.Text);
file.Close();
}
}
It seems to me that you'd just need to track whether or not they've already saved the document, by capturing the file path in a variable. This way, if the value is not set you can show the dialog, and if it is set you just use the path to save the content.
You'd also want to update this variable in the SaveAs and Open events if you have them.
Here's an example:
// Stores the name and path of the current file
private string filePath = null;
// Enum to enable us to easily reuse the same method for getting a file path
// while still showing the appropriate dialog title (see 'UpdateFilePath')
private enum DialogType
{
Open,
Save,
SaveAs
}
// Shows a dialog (based on 'dialogType') and captures the path in our variable
private bool UpdateFilePath(DialogType dialogType)
{
FileDialog dialog;
if (dialogType == DialogType.Open)
{
dialog = new OpenFileDialog();
}
else
{
dialog = new SaveFileDialog();
}
dialog.Filter = "All Files (*.*)|*.*";
dialog.Title = dialogType == DialogType.SaveAs
? "Save File As"
: dialogType + " File";
if (dialog.ShowDialog() == DialogResult.OK && dialog.FileName.Length > 0)
{
filePath = dialog.FileName;
return true;
}
return false;
}
private void openToolStripMenuItem_Click(object sender, EventArgs e)
{
var originalPath = filePath;
if (UpdateFilePath(DialogType.Open))
{
try
{
richTextBox1.LoadFile(filePath);
}
catch
{
MessageBox.Show("Unable to load specified file.");
filePath = originalPath;
}
}
}
private void saveToolStripMenuItem_Click(object sender, EventArgs e)
{
if (string.IsNullOrEmpty(filePath))
{
if (UpdateFilePath(DialogType.Save))
{
richTextBox1.SaveFile(filePath);
}
}
else
{
richTextBox1.SaveFile(filePath);
}
}
private void saveAsToolStripMenuItem_Click(object sender, EventArgs e)
{
if (UpdateFilePath(DialogType.SaveAs))
{
richTextBox1.SaveFile(filePath);
}
}

How do i read already opened file in a another button click event directly .(i.e without open file dialogue in button click)

void OpenWithDialog()
{
var ofd = new OpenFileDialog();
ofd.Filter = "Triangle polygon file|*.poly";
if (ofd.ShowDialog() == DialogResult.OK)
{
OpenPolyFile(ofd.FileName);
}
}
void OpenPolyFile(string file)
{
var geometry = TriangleNet.IO.FileReader.ReadPolyFile(file);
// ...
}
private void button1_Click(object sender, EventArgs e)
{
}
How to read files in button1 click directly?
what you want is that your geometry object be accessible in additional scopes besides OpenPolyFile(). So you can simply make the geometry declaration accessible to both methods, declaring it, say, in the form code behind
// class scoped variables
[ThePolyFileType] (pick the right one here :) geometry = null;
void OpenWithDialog()
{
var ofd = new OpenFileDialog();
ofd.Filter = "Triangle polygon file|*.poly";
if (ofd.ShowDialog() == DialogResult.OK)
{
OpenPolyFile(ofd.FileName);
}
}
void OpenPolyFile(string file)
{
geometry = TriangleNet.IO.FileReader.ReadPolyFile(file);
// ...
}
private void button1_Click(object sender, EventArgs e)
{
if (geometry != null)
{
//do your stuff
}
}
How do i read already opened file in a another button click event
directly .(i.e without open file dialogue in button click)
I'm not quite sure why you want to read it twice, but if that requirement says, make selected filename available globally and use it.
private string filename;
void OpenWithDialog()
{
var ofd = new OpenFileDialog();
ofd.Filter = "Triangle polygon file|*.poly";
if (ofd.ShowDialog() == DialogResult.OK)
{
OpenPolyFile(ofd.FileName);
filename = ofd.FileName
}
}
Now you have opened filename available in button_clcik you can use this file and read again.
private void button1_Click(object sender, EventArgs e)
{
// now you can read the file.
//File.ReadAllText(filename); //OR
TriangleNet.IO.FileReader.ReadPolyFile(file);
}

How do you use an specific file from a C# multiselection dialog?

I need to use an specific file from the ones you select from a file dialog.
OpenFileDialog ofd = new OpenFileDialog();
private void pictureBox23_Click(object sender, EventArgs e)
{
ofd.Filter = "WAV|*.wav";
this.ofd.Multiselect = true;
if (ofd.ShowDialog() == DialogResult.OK)
{
label23.Text = ofd.SafeFileName;
}
else
{
label23.Text = "No files selected...";
}
}
What i need to do is select and use the files I pre-define, so if I define an event with 01.wav if the user selects a file named 01.wav, that one will be used like so:
using (SoundPlayer player = new SoundPlayer(Beatpadpc.Properties.Resources._01))
{
player.Play();
}
I currently have it adapted as it will play it from the resources, what i need to do is to play the file from the file selecion, but only if the file is named "01".wav
Is there a way for doing it?
Well, just filter the ofd property called Filenames.
OpenFileDialog ofd = new OpenFileDialog();
string strAudioFilePath = String.Empty;
private void pictureBox23_Click(object sender, EventArgs e)
{
ofd.Filter = "WAV|*.wav";
this.ofd.Multiselect = true;
if (ofd.ShowDialog() == DialogResult.OK)
{
// Here you make a small filter with linq
label23.Text = strAudioFilePath = ofd.FileNames.FirstOrDefault(x => x.EndsWith("01.wav")); // you change 01.wav to something that make more sense to you
}
else
{
label23.Text = "No files selected...";
}
}
Then if you want to get rid of your resource file, just give your sound player the path of the file and that's all.
SoundPlayer simpleSound = new SoundPlayer(strAudioFilePath);
simpleSound.Play();

How do I show the filename in listbox but keep the relative path using openfiledialog?

I am making a program in which the user needs to load in multiple files. However, in the ListBox I need to show only file names of the files they loaded but still be able to use the files loaded. So I want to hide the full path. This is how I load a file into the ListBox now, but it shows the whole path:
private void browseBttn_Click(object sender, EventArgs e)
{
OpenFileDialog OpenFileDialog1 = new OpenFileDialog();
OpenFileDialog1.Multiselect = true;
OpenFileDialog1.Filter = "DLL Files|*.dll";
OpenFileDialog1.Title = "Select a Dll File";
if (OpenFileDialog1.ShowDialog() == System.Windows.Forms.DialogResult.OK)
{
dllList.Items.AddRange(OpenFileDialog1.FileNames);
}
}
// Set a global variable to hold all the selected files result
List<String> fullFileName;
// Browse button handler
private void button1_Click(object sender, EventArgs e)
{
OpenFileDialog OpenFileDialog1 = new OpenFileDialog();
OpenFileDialog1.Multiselect = true;
OpenFileDialog1.Filter = "DLL Files|*.dll";
OpenFileDialog1.Title = "Seclect a Dll File";
if (OpenFileDialog1.ShowDialog() == System.Windows.Forms.DialogResult.OK)
{
// put the selected result in the global variable
fullFileName = new List<String>(OpenFileDialog1.FileNames);
// add just the names to the listbox
foreach (string fileName in fullFileName)
{
dllList.Items.Add(fileName.Substring(fileName.LastIndexOf(#"\")+1));
}
}
}
// handle the selected change if you wish and get the full path from the selectedIndex.
private void dllList_SelectedIndexChanged(object sender, EventArgs e)
{
// check to make sure there is a selected item
if (dllList.SelectedIndex > -1)
{
string fullPath = fullFileName[dllList.SelectedIndex];
// remove the item from the list
fullFileName.RemoveAt(dllList.SelectedIndex);
dllList.Items.Remove(dllList.SelectedItem);
}
}
You can extract the fileName of the absolute path using the static Class Path in the System.IO namespace
//returns only the filename of an absolute path.
Path.GetFileName("FilePath");

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