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Winforms "Save" button (like we have in MS Word)

My point is to create a save button like we have in Microsoft Word, for example. I know that there is already a post about "Save As" button but here is a difference. You click "Save" and if your file has not been saved earlier, you will get a window with possibility to set a name, directory etc. But if you have already saved the file, you will not get that window (unlike with "Save As"), changes will be saved for the file and this is exactly what I need
So I have this event, can somebody help me what's next?
private void saveToolStripMenuItem_Click(object sender, EventArgs e)
{
}
P.S. Already tried this:
private void saveToolStripMenuItem_Click(object sender, EventArgs e)
{
SaveFileDialog saveFileDialog1 = new SaveFileDialog();
saveFileDialog1.InitialDirectory = #"C:\Documents";
saveFileDialog1.Title = "Saving files";
saveFileDialog1.CheckFileExists = true;
saveFileDialog1.CheckPathExists = true;
saveFileDialog1.DefaultExt = "";
saveFileDialog1.Filter = "All files (*.*)|*.*";
saveFileDialog1.FilterIndex = 1;
saveFileDialog1.RestoreDirectory = true;
if (saveFileDialog1.ShowDialog() == DialogResult.OK)
{
System.IO.StreamWriter file = new System.IO.StreamWriter(saveFileDialog1.FileName.ToString());
file.WriteLine(richTextBox1.Text);
file.Close();
}
}

It seems to me that you'd just need to track whether or not they've already saved the document, by capturing the file path in a variable. This way, if the value is not set you can show the dialog, and if it is set you just use the path to save the content.
You'd also want to update this variable in the SaveAs and Open events if you have them.
Here's an example:
// Stores the name and path of the current file
private string filePath = null;
// Enum to enable us to easily reuse the same method for getting a file path
// while still showing the appropriate dialog title (see 'UpdateFilePath')
private enum DialogType
{
Open,
Save,
SaveAs
}
// Shows a dialog (based on 'dialogType') and captures the path in our variable
private bool UpdateFilePath(DialogType dialogType)
{
FileDialog dialog;
if (dialogType == DialogType.Open)
{
dialog = new OpenFileDialog();
}
else
{
dialog = new SaveFileDialog();
}
dialog.Filter = "All Files (*.*)|*.*";
dialog.Title = dialogType == DialogType.SaveAs
? "Save File As"
: dialogType + " File";
if (dialog.ShowDialog() == DialogResult.OK && dialog.FileName.Length > 0)
{
filePath = dialog.FileName;
return true;
}
return false;
}
private void openToolStripMenuItem_Click(object sender, EventArgs e)
{
var originalPath = filePath;
if (UpdateFilePath(DialogType.Open))
{
try
{
richTextBox1.LoadFile(filePath);
}
catch
{
MessageBox.Show("Unable to load specified file.");
filePath = originalPath;
}
}
}
private void saveToolStripMenuItem_Click(object sender, EventArgs e)
{
if (string.IsNullOrEmpty(filePath))
{
if (UpdateFilePath(DialogType.Save))
{
richTextBox1.SaveFile(filePath);
}
}
else
{
richTextBox1.SaveFile(filePath);
}
}
private void saveAsToolStripMenuItem_Click(object sender, EventArgs e)
{
if (UpdateFilePath(DialogType.SaveAs))
{
richTextBox1.SaveFile(filePath);
}
}

Cant copy a png image in c#

I am creating an app that i need to copy some png files.
I already have searching with many keywords, finding many solutions and none of them worked, so i decided to ask here.
There is the code,it uses a windows forms and "this" refers to this window
private void button2_Click(object sender, EventArgs e)
{
//yes i commented them to solve why the file was not copying
//try
{
FileInfo x = new FileInfo(Environment.GetFolderPath(Environment.SpecialFolder.ApplicationData) + #"\some_location");
x.CopyTo(textBox1.Text);
}
//catch
{ }
this.Close();
}
private void button1_Click(object sender, EventArgs e)
{
OpenFileDialog openDialog = new OpenFileDialog();
openDialog.Title = "Select Image To Load";
openDialog.Filter = "Text Files (*.png)|*.png" + "|" + "All Files (*.*)|*.*";
if (openDialog.ShowDialog() == DialogResult.OK)
{
string PathData = openDialog.FileName;
textBox1.Text = PathData;
}
}
I have gotten several different errors, but most common there is:
System.UnauthorizedAccessException

It looks a bit weird to me that you're using an OpenFileDialog to select a destination. I'd assume you'd want to either do it the other way around:
private void button2_Click(object sender, EventArgs e)
{
//yes i commented them to solve why the file was not copying
//try
{
FileInfo x = new FileInfo(textBox1.Text);
x.CopyTo(Environment.GetFolderPath(Environment.SpecialFolder.ApplicationData) + #"\some_location");
}
//catch
{ }
this.Close();
}
private void button1_Click(object sender, EventArgs e)
{
OpenFileDialog openDialog = new OpenFileDialog();
openDialog.Title = "Select Image To Load";
openDialog.Filter = "Text Files (*.png)|*.png" + "|" + "All Files (*.*)|*.*";
if (openDialog.ShowDialog() == DialogResult.OK)
{
string PathData = openDialog.FileName;
textBox1.Text = PathData;
}
}
or use SaveFileDialog instead.

Load Image using C#

I
open an Image i tried this methode but when i click on the button the window doesn't appear
so i cant load an image
private void button1_Click(object sender, EventArgs e)
{
OpenFileDialog open = new OpenFileDialog();
if (open.ShowDialog() == DialogResult.OK)
{
pictureBox1.ImageLocation = open.FileName;
}

Do this it will work perfectly and display full image.
private void button1_Click_1(object sender, EventArgs e)
{
OpenFileDialog open = new OpenFileDialog();
if (open.ShowDialog() == DialogResult.OK)
{
pictureBox1.ImageLocation = open.FileName;
pictureBox1.SizeMode = PictureBoxSizeMode.Zoom;
}
}

There are "Open" and "Cancel" Buttons on OpenfileDialog. So because there is no "OK" button on it, "if condition" will not be true. You should change it to:
Private void button1_Click(object sender, EventArgs e)
{
OpenFileDialog open = new OpenFileDialog();
if (open.ShowDialog() != DialogResult.Cancel)
{
pictureBox1.ImageLocation = open.FileName;
}
}

SaveFileDialog Error

I'm trying to make a simple Windows Form Application that saves a text file. I'm having trouble with the following program, it gives me:
Empty path is not a legal
namespace Filing
{
public partial class Form1 : Form
{
public Form1()
{
InitializeComponent();
}
private void Form1_Load(object sender, EventArgs e)
{
}
private void button_Save_Click(object sender, EventArgs e)
{
SaveFileDialog file = new SaveFileDialog();
file.Filter = "Text (*.txt) | Word File *.doc";
file.Title = "Save a file";
File.WriteAllText(file.FileName, richTextBox1.Text);
file.ShowDialog();
}
private void button_exit_Click(object sender, EventArgs e)
{
this.Close();
}
}
}

Cause you didn't "show" the SaveFileDialog yet, so the fileName is empty.
Try moving the showDialog upward:
private void button_Save_Click(object sender, EventArgs e)
{
SaveFileDialog file = new SaveFileDialog();
file.Filter = "Text (*.txt) | Word File *.doc";
file.Title = "Save a file";
//Ask the user to select the file path and file name, don't forget to handle cancel button!
if(file.ShowDialog() != DialogResult.Cancel)
{
File.WriteAllText(file.FileName, richTextBox1.Text);
}
}

You should wrap the writing statement as the following.
if(file.ShowDialog()== DialogResult.OK)
File.WriteAllText(file.FileName, richTextBox1.Text);

Choose file C# and get directory

I'm trying to open a file dialog box so the user can choose the location of an access database. Can someone explain how to add a file dialog when a button is clicked and also how to transform the user choice into a string that contains the file directory ( c:\abc\dfg\1234.txt)?
Thanks

As you did not state the technology you use (WPF or WinForms), I assume you use WinForms. In that case, use an OpenFileDialog in your code. After the dialog was closed, you can get the selected full file name using the FileName property.
There is the following example of how to use it on the documentation page I linked above, which I modified slightly as you want the file name, not the stream:
private void button1_Click(object sender, System.EventArgs e)
{
OpenFileDialog openFileDialog1 = new OpenFileDialog();
openFileDialog1.InitialDirectory = "c:\\" ;
openFileDialog1.Filter = "Database files (*.mdb, *.accdb)|*.mdb;*.accdb" ;
openFileDialog1.FilterIndex = 0;
openFileDialog1.RestoreDirectory = true ;
if(openFileDialog1.ShowDialog() == DialogResult.OK)
{
string selectedFileName = openFileDialog1.FileName;
//...
}
}

Based on your previous question I assume you are using WinForms.
You can use the OpenFileDialog Class for this purpose. See the code below which will run on your button Click event assuming your button id is button1:
private void button1_Click(object sender, System.EventArgs e)
{
OpenFileDialog openFileDialog1 = new OpenFileDialog();
openFileDialog1.InitialDirectory = "c:\\";
openFileDialog1.Filter = "Access files (*.accdb)|*.accdb|Old Access files (*.mdb)|*.mdb";
openFileDialog1.FilterIndex = 2;
openFileDialog1.RestoreDirectory = true;
if(openFileDialog1.ShowDialog() == DialogResult.OK)
{
var path = openFileDialog1.FileName;
}
}
More information.

Assuming that you actually have a form with button (button1)...
At the constructor hook into button1's click event
...
button1.Click += button1_Click;
...
Then define the handling function and use System.Windows.Forms.OpenFileDialog as you like.
void button1_Click(object sender, EventArgs e)
{
string oSelectedFile = "";
System.Windows.Forms.OpenFileDialog oDlg = new System.Windows.Forms.OpenFileDialog();
if (System.Windows.Forms.DialogResult.OK == oDlg.ShowDialog())
{
oSelectedFile = oDlg.FileName;
// Do whatever you want with oSelectedFile
}
}

It's actually fairly simple
namespace YourProgram
{
public partial class Form1 : Form
{
public Form1()
{
InitializeComponent();
}
string path = "";
//Declare the File Dialog
OpenFileDialog ofd = new OpenFileDialog();
private void button1_click(object sender, EventArgs e)
{
if (odf.ShowDialog() == DialogResult.OK)
{
path = ofd.FileName;
}
}
}
}