I've made a C# usercontrol with one textbox and one richtextbox.
How can I access the properties of the richtextbox from outside the usercontrol.
For example.. if i put it in a form, how can i use the Text propertie of the richtextbox???
thanks
Cleanest way is to expose the desired properties as properties of your usercontrol, e.g:
class MyUserControl
{
// expose the Text of the richtext control (read-only)
public string TextOfRichTextBox
{
get { return richTextBox.Text; }
}
// expose the Checked Property of a checkbox (read/write)
public bool CheckBoxProperty
{
get { return checkBox.Checked; }
set { checkBox.Checked = value; }
}
//...
}
In this way you can control which properties you want to expose and whether they should be read/write or read-only. (of course you should use better names for the properties, depending on their meaning).
Another advantage of this approach is that it hides the internal implementation of your user control. Should you ever want to exchange your richtext control with a different one, you won't break the callers/users of your control.
Change the access modifier ("Modifiers") of the RichTextBox in the property grid to Public.
Add a property to the usercontrol like this
public string TextBoxText
{
get
{
return textBox1.Text;
}
set
{
textBox1.Text = value;
}
}
I recently had some issues doing this with a custom class:
A user control had a public property which was of a custom class type. The designer by default tries to assign some value to it, so in the designer code, the line userControlThing.CustomClassProperty = null was being automatically added.
The intent was to be able to provide the user control with a custom class at any point while running the program (to change values visible to the user). Because the set {} portion did not check for null values, various errors were cropping up.
The solution was to change the property to a private one, and use two public methods to set and get the value. The designer will try to auto-assign properties, but leaves methods alone.
You need to make a public property for the richtextbox, or expose some other property that does the job of setting the richtextbox text like:
private RichTextBox rtb;
public string RichTextBoxText
{
get
{
return rtb.Text;
}
set
{
rtb.Text = value;
}
}
Related
I Created a custom UserControl using Windows Form Control Library.And I want to create a property of UserControlwhich I can add item to it, then I can select item like comboBox.
WinForms allows you to create a rich design-time environment as well as providing for customised editors at runtime for certain properties that you define.
For example, if I plonk a MessageQueue component onto my WinForms form and view the Properties window, I can see a property named Formatter.
Clicking on the Formatter property however displays a drop-down box showing a preset list of values. This is an example of a UI Type Editor.
One way to do this is to define an enum for your supported values (it could be a dynamic list if you wish).
public enum Muppets
{
Kermit,
MissPiggy,
Fozzie
}
...then after defining your own editor derived from UITypeEditor (see MSDN link below)
class MyMuppetEditor : UITypeEditor { ... }
...you attach it to your control's property that you wish to have a drop-down as so:
[Category("Marquee")]
[Browsable(true)]
[EditorAttribute(typeof(MyMuppetEditor),
typeof(System.Drawing.Design.UITypeEditor))]
public Muppets Muppet {get ; set; }
For more detailed information check out the link below.
More
Walkthrough: Implementing a UI Type Editor
Getting the Most Out of the .NET Framework PropertyGrid Control
EDIT: To allow for dynamic list, try making the property a string because that's what the selection will be bound to and during EditValue() when showing your SelectionControl just display a listbox of your dynamic items
You can do this by using the CategoryAttribute class.
Example:
[Description("Description of property here"), Category("Design")]
public bool my_property;
Check out the MSDN page for a more complete reference on how to use it.
EDIT: In the case of wanting to have a bool property, use this example.
private bool my_bool = true; // this is its default value
[PropertyTab("Property Tab Name")]
[Browsable(true)]
[Description("Description of Property"), Category("Data")]
public bool my_property
{
get { return my_bool; }
set { my_bool = value; }
}
I removed my last answer because I misunderstood your point.
An easy solution would require to make a Collection of enum as a property. The Designer property grid will automatically give you the choice among your initialized Collection with a ComboBox. The displayed names will also be the enum's name.
E.g. (something I made for a TextBox that only allows a certain type of value)
The enum :
enum EnumSupportedType
{
Integer = 1,
Double
}
The class where the property is located :
public class NumericTextBox : TextBoxBase, INumericControl
{
private EnumSupportedType _supportedType = EnumSupportedType.Integer;
public EnumSupportedType SupportedType {
get { return _supportedType; }
set { _supportedType = value; }
}
}
Then these items are suggested in a ComboBox (in the Designer property grid) :
Integer
Double
If you can't use enumerations, you can refer to Providing a Custom UI for Your Properties which seems to be a much harder solution to implement but will solve your problem.
I hope it will help you.
I have a ListView and a GridView that lists users in an application by names. Whenever the user selects an user to edit, I add a new tab to a TabControl, and bind all editable properties to the WPF controls.
However, when the user is editing in the Edit Tab, the information in the List (specifically, the name field) is also being updated.
Currently I'm making a copy of the object to be edited and leaving the original so it doesn't update the ListView, but isn't there a better/easier way to do this?
I've tried setting the Binding Mode=OneWay, didn't work, and also UpdateSourceTrigger=Explicit in the GridView but also didn't work.
Is there any easier way to do this?
Edit: The way I implemented my INotifyPropertyChanged class is part of the issue, since I have this:
public partial class MyTabControl : UserControl
{
public MyTabControl()
{
InitializeComponent();
//Here, DataContext is a List<Users>
//Users being my Model from the Database
//Some of it's properties are bound to a GridView
//User doesn't implement INPC
}
public void OpenTab(object sender, RoutedEventArgs e)
{
User original = (sender as Button).DataContext as User;
// - This will create a new ViewModel below with the User I'm sending
MyTabControl.AddTab(original);
}
}
And my ViewModel of Users is:
public class UserViewModel : INotifyPropertyChanged
{
public User Original { get; private set; }
public string Name { get { return Original.Name; } set { Original.Name = value; OnPropertyChanged("Name"); } }
public UserViewModel(User original)
{
Original = original ?? new User();
}
// - INPC implementation
}
Since my ViewModel is the one reporting the property changes, I didn't expect my original User to report it as well to the GridView.
The Mode=OneWay causes the information flow to go from the bound data entity to the target UI property only, any change to the UI property will not be bound back.
The reason why the UI content is changing is because the underlying property is read/write (i.e. has a getter and a setter) and is notifying any value change (due to the implementation of the INPC interface).
Presuming that it is a list of User objects you've bound to the GridView, you have two simple options to fix this. Which one is best depends on how much scope for change you have:
change the current Name property on the User object, remove the setter for it. Replace the setter with a method to set the property (i.e. SetUserName(string name)) which then sets the private member variable. Or pass the name as an argument to the constructor of the User entity.
create a new property with only a getter which returns the name and set your binding to that; i.e. public string UserName { get { return Name; }}. As there is only a getter there will be no notification of this property, so if the name does change it won't be propagated via this new property.
I have a custom control with a public collection marked as DesignerSerializationVisibility.Content.
When I add items to the collection using the designer, it adds them to the designer file and assigns all desired values but it gives each element of the collection a generic name, such as MyClass1, MyClass2, etc. I want the "Name" property of each item to become the code name of the item so that I can then access the item by its name in code.
This is the functionality of how a ContextMenuStrip and ToolStrip works. In those cases, the Name property shows up as (Name) in the property grid.
Is there an attribute or something I can use to gain this functionality? Or do I have to write a whole custom designer dialog? If so, what's an example of the simplest way I could go about achieving this?
You can try inheriting from Component to get that feature.
In this example, I created a class called PanelItem, which will be the class used in my collection by my own Panel class. I added DesignTimeVisible(false) so that it doesn't populate the component tray in the designer.
Also, I added a Name property that is hidden from the designer but can be used in code. It seemed to work in my tests:
[DesignTimeVisible(false)]
public class PanelItem : Component {
[DefaultValue(typeof(string), "")]
public string PanelText { get; set; }
private string name = string.Empty;
[Browsable(false)]
[DesignerSerializationVisibility(DesignerSerializationVisibility.Visible)]
public string Name {
get {
if (base.Site != null) {
name = base.Site.Name;
}
return name;
}
set {
name = value;
}
}
}
Then my custom panel control:
public class MyPanel : Panel {
private List<PanelItem> panelItems = new List<PanelItem>();
[DesignerSerializationVisibility(DesignerSerializationVisibility.Content)]
public List<PanelItem> PanelItems {
get { return panelItems; }
}
}
Resulted in:
I believe your custom control itself is going to require a DesignerSerializer, and that merely decorating the collection with the the DesignerSerializationVisibility.Content will not be sufficient.
I used ILSpy to check: ToolStrip has its DesignerSerializer set to an internal ToolStripCodeDomSerializer, which I think is responsible for generating all the code properties involved.
I think implementing this will be a bit of specialized work. Here's the MSDN article to get you started: http://msdn.microsoft.com/en-us/library/ms171834.aspx. You're looking for an implementation of the CodeDomSerializer, I believe: http://msdn.microsoft.com/en-us/library/system.componentmodel.design.serialization.codedomserializer.aspx.
class StyleProperty<T>
{
static readonly StyleProperty<Object> INHERIT ;
T value;
public T Value
{
get { return this.value; }
set { this.value = value; }
}
}
Hello..
The above class sometimes should have the value INHERIT when value should not be used.. As
c# doesnt allow overloading Properties i cant set Value=StyleProperty.Inherit. i must be of type T.
Any idea what to do there?
After reading your comments, what about this:
class StyleProperty<T>
{
T _Value;
public StyleProperty(T inheritedValue)
{
_Value = inheritedValue;
}
public T Value
{
get { return this._Value; }
set { this._Value = value; }
}
}
Your first problem is how should the inherited value flow into the concrete instance? The only way i can think of would be the constructor. If the user doesn't like this value he can simply change it (to maybe the same value).
If you would use for inheritance some kind of global variable (but that wouldn't be inheritance, that would be a default value) you could also think about using a boolean flag which will be checked in the getter to find out if the backing store or the default should be used and it will set always to the opposite of its initial state within the setter.
class StyleProperty<T>
{
T _Value;
bool _UseBackingStore;
public T Value
{
get { return _UseBackingStore ? this._Value : INHERIT; }
set { this._Value = value; _UseBackingStore = true; }
}
}
Update
To get a skin support into your application i think you need to take a different approach. All forms and gui controls you are using should implement some kind of interface (e.g. ISkin). Also your application should have some kind of SkinSelector. This one holds all informations about coloring, fonts, etc and it also gets a reference to the MainForm. Within the constructor it recursively runs through the Controls property of the form and checks if there are any controls implementing your interface (simply using as ISkin and check for null). If it is skinnable, simply set the colors, fonts, etc. of the control as defined within you SkinSelector. Sounds quite easy but the problem is, that you have to derive all gui controls and add your interface to them. So this is not such a complicated thing, but maybe a lot of work. Maybe you can test if Generics can help you out by using a SkinWrapper<T> where T : Control and an extension function like ISkin ToSkinnableControl(this Control control)). But this will only work if you need to change a few common properties, that are the same for all controls. If you need more skin control e.g. for the DataGridView or a ComboBox i think derivement is the only way to help you out.
Not exactly sure what you're asking for, but you can define a default value for a property like this:
[DefaultValue(<Value>)]
public T Value
{
get { return this.value; }
set { this.value = value; }
}
i want to remove unnecessary properties from user control. But I do not know what way?
You can remove inherited properties from the Properties window with the [Browsable] attribute:
[Browsable(false)]
public override bool AutoScroll {
get { return base.AutoScroll; }
set { base.AutoScroll = value; }
}
[Browsable(false)]
public new Size AutoScrollMargin {
get { return base.AutoScrollMargin; }
set { base.AutoScrollMargin = value; }
}
Note the difference between the two, you have to use the "new" keyword if the property isn't virtual. You can use the [EditorBrowsable(false)] attribute to also hide the property from IntelliSense.
You can't remove the properties your control inherits from UserControl.
You can, of course, remove properties you've created yourself. Just delete them from your source file.