I have DateTimePicker on my form and I set a value to the custom format property to "dd/MM/yyyy" ant when I run this code:
MessageBox.Show(dateTimePicker1.Value.ToString());
I get this value : "3/26/2010 1:26 PM".
How I can remove the time part from value.
I know we can use this method
dateTimePicker1.Value.ToShortDateString();
but I want to set the value property to this format "dd/MM/yyyy" so the output will be like this "26/3/2010", because I want to store the value in my DB (SQL)
How I can do that?
Use dateTimePicker1.Value.Date to get the Date part of this DateTime value.
Do notice though, if you mean to parse into strings, that using dateTimePicker1.Value.Date.ToString will result with the "26/03/2010 00:00:00" string, while using something like MyString = CStr(dateTimePicker1.Value.Date) will result in MyString being "26/03/2010".
If you have string as datatype in database:
dateTimePicker1.Value.Date.ToString("d");
If datatype is DateTime:
dateTimePicker1.Value.Date;
Both will return date in dd/mm/yyyy format without time.
I assume you initialized the DateTimePicker with the current date and time:
dateTimePicker1.Value = DateTime.Now;
Instead, initialize it with the current date:
dateTimePicker1.Value = DateTime.Today;
What happens is as follows:
If the user selects a date, then the DateTimePicker.Value property will always return a date with no time of day component, and DateTime.Kind set to Unspecified.
If the user doesn't select a date, then the DateTimePicker.Value property will return the value used to initialize the DateTimePicker.Value property. If you initialize it with DateTime.Now, it will have a time of day component, and DateTime.Kind will be set to Local.
just MessageBox.Show(dateTimePicker1.Value.ToString("dd/MM/yyyy"));
dateTimePicker1.Value.ToString("dd-MM-yyyy")
This should work
You can set DateTimePicker "Format" to "Short" in Properties window (under Appearance)
Related
I have initialized an array for my DateTime.
DateTime[] departureCalcArray = new DateTime[10];
And then getting the value of the DateTimePicker that is formatted as h:mm tt(that is 8:30 AM with no preceeding zero) .
My code for storing the value of the DateTimePicker is as below.
departureCalcArray[i] = timeDeparture.Value.Date;
However, when I checked if the value is saved via MessageBox.Show();
I keep getting the date today and 12:00:00 AM. Although back in PHP, I use to convert the time to 24hour format so that I can use it in calculation. Any help please?
Change
departureCalcArray[i] = timeDeparture.Value.Date;
to
departureCalcArray[i] = timeDeparture.Value;
When you use the Date property of a DateTime instance, you get a new DateTime instance with the same date, but its Time component set to 12:00AM
I am not able to comment becos I just started this account.
This answer is related to a conversation in comments on how to change to HH:mm
DateTimePicker.ShowUpDown = true;
DateTimePicker.CustomFormat = "hh:mm";
DateTimePicker.Format = System.Windows.Forms.DateTimePickerFormat.Custom;
Credits to here: DateTime Picker In WinForm How To Pick Time?
I know this may be a duplicate but using the .NET framework I can't seem to get the date and not the time for a WPF DatePicker.
I have this:
DatePicker.SelectedDate.Value.Date
I believed using the "Date" property would only return the date, but it returns the time "12:00:00" as well.
I read https://learn.microsoft.com/en-us/dotnet/api/system.datetime.date so I'm not sure what I am doing wrong.
I'm sure it's something silly as always, but with no helpful eye with me to tell me, I thought I resort to SO!
DatePicker.SelectedDate.Value.Date is a DateTime Nullable property. So any DateTime Property has the date and time section. but in this case it is not fill with the correct value and it will gives you the default value. if you want to get the date only use following code,
DatePicker.SelectedDate.Value.Date.ToShortDateString()
SelectedDate property is of type Nullable<DateTime> it gives you the date however the time is reset as 12:00:00 midnight (00:00:00)
see more on DatePicker.SelectedDate Property
from MSDN: DateTime.Date Property
The value of the Kind property of the returned DateTime value is the same as that of the current instance.
Because the DateTime type represents both dates and times in a single type, it is important to avoid misinterpreting a date returned by the Date property as a date and time. For more information, see "Saving and Restoring DateTime Values" in the DateTime topic.
While selecting the date from the datepicker in you code you can do following:
DateTime from = From_Date_Picker.SelectedDate.Value.Date
The following example uses the Date property to extract the date component of a DateTime value with its time component set to zero (or 0:00:00, or midnight). It also illustrates that, depending on the format string used when displaying the DateTime value, the time component can continue to appear in formatted output.
That says that depending on the Format (in this case the DatePicker i think) the Time component can appear. Like in your link, the Output is 12:00 AM
So Check the Format / properties of the DatePicker.
in your code, you can do the following:
string shortDate = datePicker.SelectedDate.Value.ToShortDateString();
or, if you'd like to specify the format of the date:
string formatDate = datePicker.SelectedDate.Value.ToString("yyyy-MM-dd");
Here datePicker is object of DatePicker WPF
Check to make sure your Windows regional settings are set to a 24hr clock. I'm guessing its returning 12AM
I have a datetime variable like this:
DateTime date1 = DateTime.Now; // has 9.4.2014 01:12:35
I want to assign this to another datetime or change its value like this:
2014-04-09 13:12:35
How can I do?
Thanks.
EDIT : I don't want string variable. I want it Datetime format.
try this :
date1.ToString("yyyy-MM-dd HH:mm:ss")
Also look at the table below here http://msdn.microsoft.com/en-us/library/8kb3ddd4(v=vs.110).aspx
edit :
As Jon said (and which I didn't mention) :
you should add InvariantCulture ( if you dont want it to be used with current thread culture ) :
CultureInfo heIL = new CultureInfo("he-IL");
heIL.DateTimeFormat.Calendar = new HebrewCalendar();
CultureInfo dft = Thread.CurrentThread.CurrentCulture;
Thread.CurrentThread.CurrentCulture = heIL;
Check these :
DateTime.Now.ToString("yyyy-MM-dd HH:mm:ss")
DateTime.Now.ToString("yyyy-MM-dd HH:mm:ss",CultureInfo.InvariantCulture);
result ( I live in israel) :
תשע"ד-ח'-ט' 13:32:31
2014-04-09 13:32:31
The code you've written just assigns a value to a variable. It doesn't return anything, and it doesn't have any inherent string representation. A DateTime value is just a date/time. It can be displayed in whatever format you want, but that's not part of the value of the variable.
It sounds like you're wanting to convert it to a string in a particular format, which you should do with DateTime.ToString - but only when you really need to. Try to keep the value as a DateTime for as long as possible. Typically you only need to convert to a string in order to display the value to a user, or possibly to use it in something like JSON. (If you find yourself converting it to a string for database usage, you're doing it wrong - make sure your schema has an appropriate data type for the field, use a parameterized query, and set the parameter value to just the DateTime - nor formatting required.)
The format you've specified looks like it's meant to be a machine-readable one rather than a culture-specific one, so I'd suggest:
string text = date1.ToString("yyyy-MM-dd HH:mm:ss",
CultureInfo.InvariantCulture);
By specifying the invariant culture, we've said that the result shouldn't depend on the current culture (which otherwise it would) - this can make a big difference if the current culture uses a different calendar system, for example.
Something like the following, which is one of the constructors of the DateTime object:
d = new DateTime(2014, 5, 6, 5, 4, 30);
Which will set d to 06/05/2014 05:04:30. Its parameters are in descending size order, so Year, Month, Day, Hour, Minute then Seconds.
If you want to adjust the time by an amount, look at the add methods, or TimeSpans.
you can just use something like this to format the date:
date1.ToString("dd/MM/yyyy HH:mm:ss")
By using "HH" instead of "hh" you will get 24hour format on the hour.
Hope that helps.
Try this
DateTime date1 = DateTime.Now;
string datestring=date1.ToString("yyyy-MM-dd HH:mm:ss",CultureInfo.InvariantCulture)
http://msdn.microsoft.com/en-us/library/8kb3ddd4(v=vs.110).aspx
As a guess, the "returned" value of your DateTime object is seen by you, by hoovering over the variable in the IDE while debugging.
This is just another form of calling internally the default ToString() method of your DateTime object by the debugger. The value is the same.
See: system.datetime
DateTime Values and their string representations
Internally, all DateTime values are represented as the number of ticks (the number of 100-nanosecond intervals) that have elapsed since 12:00:00 midnight, January 1, 0001. The actual DateTime value is independent of the way in which that value appears when displayed in a user interface element or when written to a file. The appearance of a DateTime value is the result of a formatting operation. Formatting is the process of converting a value to its string representation.
Because the appearance of date and time values is dependent on such factors as culture, international standards, application requirements, and personal preference, the DateTime structure offers a great deal of flexibility in formatting date and time values through the overloads of its ToString method. The default DateTime.ToString() method returns the string representation of a date and time value using the current culture's short date and long time pattern.
i have date stored in a string format as follows: "2014-03-12"
im passing this to a database which accepts the date as datetime.
im converting the string date to datetime format as follows:
DateTime StartDates = Convert.ToDateTime(StartDate);
but the time gets appended along with the date as "2014-03-12 12:00:00:00"
can anyone tel me how to send only the date leaving out the time.
i want the final date to be still in datetime format only but with time part cut off
DateTime is irrespective of the format. Formatting is only useful for presentation purpose. A DateTime object will have a Date part and Time part. When you try parsing your string "2014-03-12", it doesn't have a Time part, so in the parsed object, Time is set to 00:00:00.
If you just want to to display date then you can use DateTime.ToShortDateString method or use a custom format like:
string formattedDateString = StartDates.ToString("yyyy-MM-dd", CultureInfo.InvariantCulture);
If you're happy with the date part, you may simply return the Date property of the DateTime conversion result:
DateTime StartDates = Convert.ToDateTime(StartDate).Date;
I should mention that using Convert.ToDateTime puts you at the mercy of the process current culture date format though, so you probably want to use the ParseExact or ToString method like the other answers suggests, with the appropriate format and culture instance.
i have a TextBox which displays this format '01/01/1999 00:00:00' but my record has a date type not a datetime.
Thank you
my recors have a date type not datetime
.Net DateTime has Date and Time together. If your record has only date then you will see the time set at 00:00:00. To display only date you can use:
textBox.Text = yourDateObject.ToShortDateString();
Or you can pass custom format to ToString like:
textBox.Text = yourDateObject.ToString("dd/MM/yyyy", CultureInfo.InvariantCulture);
For more info see: Custom Date and Time Format Strings