I know this may be a duplicate but using the .NET framework I can't seem to get the date and not the time for a WPF DatePicker.
I have this:
DatePicker.SelectedDate.Value.Date
I believed using the "Date" property would only return the date, but it returns the time "12:00:00" as well.
I read https://learn.microsoft.com/en-us/dotnet/api/system.datetime.date so I'm not sure what I am doing wrong.
I'm sure it's something silly as always, but with no helpful eye with me to tell me, I thought I resort to SO!
DatePicker.SelectedDate.Value.Date is a DateTime Nullable property. So any DateTime Property has the date and time section. but in this case it is not fill with the correct value and it will gives you the default value. if you want to get the date only use following code,
DatePicker.SelectedDate.Value.Date.ToShortDateString()
SelectedDate property is of type Nullable<DateTime> it gives you the date however the time is reset as 12:00:00 midnight (00:00:00)
see more on DatePicker.SelectedDate Property
from MSDN: DateTime.Date Property
The value of the Kind property of the returned DateTime value is the same as that of the current instance.
Because the DateTime type represents both dates and times in a single type, it is important to avoid misinterpreting a date returned by the Date property as a date and time. For more information, see "Saving and Restoring DateTime Values" in the DateTime topic.
While selecting the date from the datepicker in you code you can do following:
DateTime from = From_Date_Picker.SelectedDate.Value.Date
The following example uses the Date property to extract the date component of a DateTime value with its time component set to zero (or 0:00:00, or midnight). It also illustrates that, depending on the format string used when displaying the DateTime value, the time component can continue to appear in formatted output.
That says that depending on the Format (in this case the DatePicker i think) the Time component can appear. Like in your link, the Output is 12:00 AM
So Check the Format / properties of the DatePicker.
in your code, you can do the following:
string shortDate = datePicker.SelectedDate.Value.ToShortDateString();
or, if you'd like to specify the format of the date:
string formatDate = datePicker.SelectedDate.Value.ToString("yyyy-MM-dd");
Here datePicker is object of DatePicker WPF
Check to make sure your Windows regional settings are set to a 24hr clock. I'm guessing its returning 12AM
Related
Firstly, I want to say that I read many questions about similar problem and I couldn't find anything.
The difference is that I can't use DateTime.Now property, and I can't choose any specific date.
It is on the user to choose one date from DatePicker
I have tried Convert, Parse, tryParse, but still couldn't solve it...
This code will work fine if I use String in my class instead of DateTime, but I need to use DateTime type. Also, I don't want to display time, that's why I have formated like this. Can I get value to string, so I can parse it later?
string chosenDate = datePicker.SelectedDate.GetValueOrDefault().ToString("dd/MM/yyyy"); //error
After that I thought to move value to my object. This is what I did:
newObject = new Classes.MyClass(DateTime.Parse(chosenDate));
I have lost all ideas...
Thank you in advance.
EDIT:
Sorry for too little information about problem.
The problem is that I have a DataGrid which has binding on DateTime date (in .cs). I tried this way because it won't show time, but if I apply the following it shows the time in my result as you can see.
If MyClass expects a DateTime, you should use the value from the DatePicker's SelectedDate property. It returns a Nullable<DateTime> that can be converted to a DateTime using the GetValueOrDefault() method:
newObject = new Classes.MyClass(datePicker.SelectedDate.GetValueOrDefault());
If there is no date selected, GetValueOrDefault() will return DateTime.MinValue.
The DatePicker doesn't store the date in any particular format. That's a formatting thing.
It doesn't set the time either. If you however set the time yourself, you could strip it away using the Date property of the Date time:
datePicker.SelectedDate.GetValueOrDefault().Date
I have a DataTable coming from a stored procedure which I'm writing to an excel file. There's a column with a DateTime datatype, and looking at the values in there, they're just generic dates with the time stamp.
I've tried using the DateTime.Date property, but that still gives me a time stamp. Further, I've tried to create a new DateTime object using the year,month,day constructor but it still adds a time stamp:
DateTime newDate = DateTime(oldDate.Year, oldDate.Month, oldDate.Day);
I'm trying to keep the column datatype to DateTime but remove the time stamp, so this rules out ToString("") formatting. Is there another way?
A DateTime always contains a date and a time portion. If you use the Date property it returns a new DateTime where the time is 0:00:00 so midnight at the same day. You want a string representation of the datetime without the time.
You can use DateTime.ToString:
string result = oldDate.ToString("d"); // uses current culture's date format
or
string result = oldDate.ToShortDateString(); // same as above
or
string result = oldDate.ToString("MM-dd-yyyy"); // custom format
Edit: "so this rules out ToString("") formatting. Is there another way?"
No, because of the reason mentioned above.
It's important to separate the data from how it is displayed. If you need to display it without time use the code above, you can store the original DateTime variable for future processing, select it again from database or use DateTime.Parse/DateTime.ParseExcact to get a DateTime from the string.
The 'problem' is that there is no Date struct in .NET, you only have a DateTime struct. That will always contain both date and time. You can only format it as date.
Or, you could of course write your own struct containing only the date part, or give up and use string.Format to format it as a date (possibly using the short date string d).
If you mean time part with timestamp, a DateTime instance always have both date and time part. DateTime.Date property just sets the time value set to midnight.
You can get it's string representation if you want only it's Date part. You can get standard date and time format or custom date and time format with DateTime.ToString() method.
Usually, you can use ShortDatePattern to get only string representation of Date part which uses standard "d" format of your CurrentCulture.
DateTime.Now.ToString("d");
There is a proposal for System.Date and System.Time types for .NET Framework in dotnet/corefx on GitHub page by the way.
Proposal: System.Date type
You should use DateTime.Now.ToShortDateString();
I know such questions are in ton in SO but my situation seems little weird to me.
I have a textbox with a calendar extender control on my aspx page
Default format is "d" in extenders date format property.
When I choose my date say 15th May 2012 from the calendar,it gives me 5/15/2012, which is fine.
Since its a string and my db field is oftype datetime, so I am using
Convert.ToDateTime(TextBox.Text); // TextBox.Text = 5/15/2012
But it throws the exception,
string was not recognized as valid datetime.
I then Change the code and used DateTime.Parse() but the issue remains. Then i tried to reformat the date something like this,
Convert.ToDateTime(string.Format("0:MM-dd-yyyy",TextBox.Text)).Date
but still its throwing exceptions..
Please help me.
Use the following,
DateTime dt = DateTime.ParseExact(TextBox.Text, "dd/MM/yyyy",
CultureInfo.InvariantCulture);
There's probably a difference between your system's DateTime format and the DateTiem format the extender uses.
I suppose that your dev machine date-time format is not equal to MM/DD/YYYY, but something else (for example DD/MM/YYYY). Have a look on your computer Regional settings to see your system date time format.
I have DateTimePicker on my form and I set a value to the custom format property to "dd/MM/yyyy" ant when I run this code:
MessageBox.Show(dateTimePicker1.Value.ToString());
I get this value : "3/26/2010 1:26 PM".
How I can remove the time part from value.
I know we can use this method
dateTimePicker1.Value.ToShortDateString();
but I want to set the value property to this format "dd/MM/yyyy" so the output will be like this "26/3/2010", because I want to store the value in my DB (SQL)
How I can do that?
Use dateTimePicker1.Value.Date to get the Date part of this DateTime value.
Do notice though, if you mean to parse into strings, that using dateTimePicker1.Value.Date.ToString will result with the "26/03/2010 00:00:00" string, while using something like MyString = CStr(dateTimePicker1.Value.Date) will result in MyString being "26/03/2010".
If you have string as datatype in database:
dateTimePicker1.Value.Date.ToString("d");
If datatype is DateTime:
dateTimePicker1.Value.Date;
Both will return date in dd/mm/yyyy format without time.
I assume you initialized the DateTimePicker with the current date and time:
dateTimePicker1.Value = DateTime.Now;
Instead, initialize it with the current date:
dateTimePicker1.Value = DateTime.Today;
What happens is as follows:
If the user selects a date, then the DateTimePicker.Value property will always return a date with no time of day component, and DateTime.Kind set to Unspecified.
If the user doesn't select a date, then the DateTimePicker.Value property will return the value used to initialize the DateTimePicker.Value property. If you initialize it with DateTime.Now, it will have a time of day component, and DateTime.Kind will be set to Local.
just MessageBox.Show(dateTimePicker1.Value.ToString("dd/MM/yyyy"));
dateTimePicker1.Value.ToString("dd-MM-yyyy")
This should work
You can set DateTimePicker "Format" to "Short" in Properties window (under Appearance)
I'm trying to store a shortened date (mm/dd/yyyy) into a DateTime object. The following code below is what I am currently trying to do; this includes the time (12:00:00 AM) which I do not want :(
DateTime goodDateHolder = Convert.ToDateTime(DateTime.Now.ToShortDateString());
Result will be 10/19/2009 12:00:00 AM
DateTime is an integer interpreted to represent both parts of DateTime (ie: date and time). You will always have both date and time in DateTime. Sorry, there's nothing you can do about it.
You can use .Date to get the date part. In these cases, the time will always be 12:00 but you can just ignore that part if you don't want it.
You only have two options in this situation.
1) Ignore the time part of the value.
2) Create a wrapper class.
Personally, I am inclined to use option 1.
A DateTime will always have a time component - even if it is 12:00:00 AM. You just need to format the DateTime when you display it (e.g. goodDateHolder.ToShortDateString()).
Instead of .Now you can use .Today which will not remove the time part, but will only fill the date part and leave time to the default value.
Later on, as others pointed out, you should try to get the date part ignoring the time part, depending on the situation.
You'll always get the time portion in a DateTime type.
DateTime goodDateHolder = Convert.ToDateTime(DateTime.Now.ToShortDateString());
will give you today's date but will always show the time to be midnight.
If you're worried about formatting then you would try something like this
goodDateHolder.ToString("mm/dd/yyyy")
to get the date in the format that you want.
This is a good resource msdn-dateformat
You can also check out Noda Time based off the Java Joda Time library.
DateTime object stores both the date and the time. To display only the date, you would use the DateTime.ToString(string) method.
DateTime goodDateHolder = DateTime.Now;
// outputs 10/19/2009
Console.WriteLine(goodDateHolder.ToString("MM/dd/yyyy"));
For more information on the ToString method, follow this link
You might not be able to get it as a DateTime object...but when you want to display it you can format it in the way you want by doing something like.
myDateTime.ToString("M/d/yyyy") which gives 10/19/2009 for your example.
DateTime is merely a UInt64 with useful and clever formatting wrapped around it to make it appear like a date plus a time. You cannot eliminate the time element.