This question have been answered. I recommend sumit_programmers solution below. For now, I've removed my code, thinking it's more confusing than helpful. When I've developed it a bit further, perhaps I'll post my code here, with some comments.
You may also be interested in the answer to the question Save text from rich text box with C#. There is an answer that reminds of the accepted answer to this question. The code should work, but it's written by me, so there may be some errors or missing information.
Update: I have improved the code a bit (at least I think so). "Encoding.Default" seems to work with most common encodings, like ANSI. If the encoding is UTF-8 without byte order mark (BOM), it seems "Encoding.Default" doesn't work, though. For more information, go to informit.com/guides. Here's the code I'm using right now:
private void fileOpen_Click(object sender, EventArgs e)
{
using (OpenFileDialog dlgOpen = new OpenFileDialog())
{
try
{
// Available file extensions
dlgOpen.Filter = "All files(*.*)|*.*";
// Initial directory
dlgOpen.InitialDirectory = "D:";
// OpenFileDialog title
dlgOpen.Title = "Open";
// Show OpenFileDialog box
if (dlgOpen.ShowDialog() == DialogResult.OK)
{
// Create new StreamReader
StreamReader sr = new StreamReader(dlgOpen.FileName, Encoding.Default);
// Get all text from the file
string str = sr.ReadToEnd();
// Close the StreamReader
sr.Close();
// Show the text in the rich textbox rtbMain
rtbMain.Text = str;
}
}
catch (Exception errorMsg)
{
MessageBox.Show(errorMsg.Message);
}
}
}
Yes, you are getting that error as you are trying to access file that can't be loaded in Rich Text Box. If you want to load a .rtf file you need to add this line
richTextBox1.LoadFile(dlg.FileName, RichTextBoxStreamType.RichText);
and if you want to load .txt file, you need to add this
richTextBox1.LoadFile(dlg.FileName, RichTextBoxStreamType.PlainText);
Sample Code:
using (OpenFileDialog ofd = new OpenFileDialog())
{
try
{
ofd.Filter = "Text files (*.txt)|*.txt|RTF files (*.rtf)|*.rtf";
if (ofd.ShowDialog() == DialogResult.OK)
{
if (Path.GetExtension(ofd.FileName) == ".rtf")
{
richTextBox1.LoadFile(ofd.FileName, RichTextBoxStreamType.RichText);
}
if (Path.GetExtension(ofd.FileName) == ".txt")
{
richTextBox1.LoadFile(ofd.FileName, RichTextBoxStreamType.PlainText);
}
}
}
catch (Exception ex)
{
}
}
Edit: Ok, if you want to open a plain text file, go back to my original solution.
You could just change the MessageBox.Show to the line:
rtfMain.Text = File.ReadAllText(dlg.FileName);
See the doc for ReadAllText for more info.
The try/catch bit is to avoid having your app crash due to unhandled errors (sometimes it might be the best thing to do to just let it crash, but even then you usually want to close it down in a somewhat controlled manner). Especially when working with files, there's a high risk that they'll fail to load for some reason so it might be useful to surround the code with some error handling, for example something like this:
try
{
rtfMain.Text = File.ReadAllText(dlg.FileName);
}
catch(Exception ex) // should try to avoid catching generic Exception here and use a more specialized one
{
MessageBox.Show("Failed to open file. Error: " + ex.Message);
}
Old answer below
Edit: I forgot that it's a RichTextBox, so my first answer wasn't as suitable, so it's probably better to do this instead:
You could just change the MessageBox.Show to the line:
rtfMain.LoadFile(dlg.FileName);
Probably adding in suitable try/catch to handle any errors in reading the file.
See the documentation for RichTextBox.LoadFile for a complete sample.
try
{
openFileDialog fd=new openFileDialog();
fd.showDialog();
richTextbox1.LoadFile(fd.FileName);
}
catch(Exception exc)
{
MessageBox.Show(exc.Message);
}
Related
In my C# project, i have to write some info to a file with streamwriter, and afterwards I want to call a method. But I have to be % 100 sure that the writing process has been finished, otherwise a data inconsistency can occure. How can I check this in my program?
After the dispose/using block of the StreamWriter object is called without an exception you can be sure that the string has been written to file.
https://learn.microsoft.com/en-us/dotnet/standard/io/how-to-write-text-to-a-file
try
{
using (StreamWriter outputFile = new StreamWriter(Path.Combine("C:\Temp", "WriteLines.txt"), true))
{
outputFile.WriteLine("Fourth Line");
}
//Text is 100% written
}
catch(Exception e)
{
//Text might not be written
}
I am trying to delete a folder but am getting the following error message:
The process cannot access the file .it is being used by another process.
string target_dir="D:\\projectpath\\page";
if (Directory.Exists(target_dir))
Directory.Delete(target_dir, false);
How can I resolve this error?
It looks like the file is locked by some other process. This could happen if when reading/writing to it you forgot to dispose the stream reader/writer and you leaked the unmanaged handler to the file.
For example if you used the following code to read from the file:
StreamReader reader = new StreamReader(fileName);
string contents = reader.ReadToEnd();
and you never release the reader, the file will be locked. The proper way is to wrap IDisposable resources such as Streams and StreamReaders in using statements:
using (StreamReader reader = new StreamReader(fileName))
{
string contents = reader.ReadToEnd();
}
If on the other hand the file is locked by some other external process to your application then there's very little you could do about it, other than killing this process.
I think on the surface, your problem should be apparent: the file is in use by something else, so you can't delete the directory it resides in. If there was a way to "force delete" the file, it could cause other programs to crash. I'd recommend catching the error and either logging it or displaying it to the user, so they can decide if they really want to delete the in-use file.
If you MUST delete the file, you could take a look at:
Using C#, how does one figure out what process locked a file?
And once you know what the process is, you can then kill it, which should free up the file. Again, this isn't a good practice and should only be used in exceptional circumstances.
To delete the diectory you must have the correct Permissions.
var target_dir = "D:\\projectpath\page";
var isWriteAccess = false;
try
{
var collection = Directory.GetAccessControl(target_dir)
.GetAccessRules(true, true, typeof(System.Security.Principal.NTAccount));
if (collection.Cast<FileSystemAccessRule>().Any(rule => rule.AccessControlType == AccessControlType.Allow))
{
isWriteAccess = true;
}
}
catch (UnauthorizedAccessException ex)
{
isWriteAccess = false;
}
catch (Exception ex)
{
isWriteAccess = false;
}
if (!isWriteAccess)
{
MessageBox.Show("no access to directory.");
// Handle here close and kill the blocking process
}
else
{
Directory.Delete(target_dir, false);
}
}
I have a rich text editor that I have created in C#. One of the features I am now trying to add is templates. I do not want the user to have to use an OpenFileDialog to navigate to the template and open the file. I would like to specify the filepath myself so that the user only has to click one button in order to open the template.
Currently, I am trying to achieve this using the following code:
private void formalLetterToolStripMenuItem_Click(object sender, EventArgs e)
{
try
{
FileStream fileStream = new FileStream(#".\templates\tmp1.rtf", FileMode.Open);
String str;
str = fileStream.ToString();
string fileContents = File.ReadAllText(filepath);
fileContents = fileStream.ToString();
try
{
if (richTextBoxPrintCtrl1.Modified == true);
{
NewFile();
}
richTextBoxPrintCtrl1.Rtf = fileContents;
}
catch (Exception exception)
{
MessageBox.Show("There was an error opening the template. " + exception, "Error", MessageBoxButtons.OK, MessageBoxIcon.Error);
}
}
catch (Exception exception)
{
MessageBox.Show("There was an error opening the template. " + exception, "Error", MessageBoxButtons.OK, MessageBoxIcon.Error);
}
However, whenever I try to open the template, I get an exception that is as follows:
System.ArgumentsException: File format is not valid.
However, I have tried to open the file using my OpenFileDialog and that works fine. Could somebody assist me in getting this working correctly?
Your problem is that you're trying to convert the file to a string using str = fileStream.ToString(); however, this converts the filestream to a string which is not the same thing.
Instead just do string fileContents = File.ReadAllText(filepath); to get all of the files contents into a string. You only need to use a FileStream/StreamReader if you're going to do some type of processing on the file.
Also, your use of the FileStream is a little off. I think what you really want is a StreamReader with something like this (example from msdn);
using (StreamReader sr = new StreamReader("TestFile.txt"))
{
string line;
// Read and display lines from the file until the end of
// the file is reached.
while ((line = sr.ReadLine()) != null)
{
Console.WriteLine(line);
}
}
A FileStream cannot be used to read a file. It must be passed to a StreamReader in order to actually read the file and in this case there is no point in doing that because there is an overload of the constructor which takes a filepath. It's only useful if you don't know what kind of stream the reader is going to be reading.
Where you have;
FileStream fileStream = new FileStream(#".\templates\tmp1.rtf", FileMode.Open);
String str;
str = fileStream.ToString();
string fileContents = File.ReadAllText(filepath);
fileContents = fileStream.ToString();
You actually just want thins line; string fileContents = File.ReadAllText(filepath); , nothing else. There is no need for a FileStream when you're just reading all the text into a string.
You are making very heavy weather of loading RTF. Your code to read a file into a string will never work, as #evanmcdonnal explained. Did your file dialog based code that succeeded really do it like that? Remember that a file dialog is just UI that generates a file name in a string. If your code with a file dialog works, then it will work when the file dialog is replaced with a hard coded string.
I suspect that some part of your problem is that you are using a relative path. Perhaps the working directory is not what you expect it to be. You should specify the full path to the file.
In any case, to load RTF simply call the LoadFile method of the control. But I strongly recommend passing the full path to the file.
richTextBoxPrintCtrl1.LoadFile(fullPathToRtfFile);
I write some codes for simple text editor in C# and I use rich text box control, I found a problem that I can't solve. The problem is when I save a file in my text editor and then try to reopen it using windows notepad, it become in one line, this is the example
This is when I write and save from my app
After I save it and open in windows notepad it becomes like this
here are my code for saving a fie
try
{
saveFileDialog1.ShowDialog();
this.Text = file = toolStripTextBox1.Text = saveFileDialog1.FileName;
isi = richTextBox1.Text;
write = new System.IO.StreamWriter(file);
write.WriteLine(isi);
write.Close();
toolStripStatusLabel2.Text = "Saved";
}
catch (Exception)
{
toolStripStatusLabel2.Text = "Save cancelled by user";
}
do you have any idea how to fix it?
You are probably getting this because you are trying to save richTextBox1.Text (the whole text) in one line only using the following code
isi = richTextBox1.Text;
write = new System.IO.StreamWriter(file);
write.WriteLine(isi);
write.Close();
It's recommended to use write.WriteLine() on a specific line number in richTextBox1 then move to another line.
Example
for (int i = 0; i < richTextBox1.Lines.Length; i++)
{
write.WriteLine(richTextBox1.Lines[i]);
}
write.Close();
Another Solution
There's already a built-in function for RichTextBox to save a file with a specific encoding. You may use RichTextBox.SaveFile() for this purpose.
Example
RichTextBox.SaveFile(string path, RichTextBoxStreamType);
Where path represents saveFileDialog1.FileName in your code. For RichTextBoxStreamType, it's best to set it as RichTextBoxStreamType.PlainText as long as you do not use RTF such as Color/Font/Protection/Indent/etc...
Then, you may read the file again using the following method
RichTextBox.LoadFile(string path, RichTextBoxStreamType);
NOTICE: If the file is not in RTF and you try to read it in RTF (RichTextBox.LoadFile(string path, RichTextBoxStreamType.RichText);)
you may encounter formatting errors. In this case, you'll need to catch the exception and read the file in a Plain or Unicode encoding.
Example
RichTextBox _RichTextBox = new RichTextBox();
try
{
_RichTextBox.LoadFile(#"D:\Resources\text.txt", RichTextBoxStreamType.RichText);
}
catch (Exception EX)
{
if (EX.Message.ToLower().Contains("format is not valid"))
{
_RichTextBox.LoadFile(#"D:\Resources\text.txt", RichTextBoxStreamType.PlainText);
}
}
Thanks,
I hope you find this helpful :)
Saves the contents of the RichTextBox to a file by using richtextbox 's own save method: SaveFile(string, RichTextBoxStreamType);
you can refer this : http://msdn.microsoft.com/en-us/library/system.windows.forms.richtextbox.savefile%28VS.71%29.aspx
load the content of file by LoadFile(Stream, RichTextBoxStreamType);, refer this: http://msdn.microsoft.com/en-us/library/system.windows.forms.richtextbox.loadfile(v=vs.71).aspx
I would like to tag some existing mp3 with taglib#.
I have the following error message:
"The process cannot access the file because it is being used by another process."
I don't know what kind of process it can be. I can access any mp3 files on any of my hard drives, I also can use the properties of the file, but I cannot save changes.
This is the code.
OpenFileDialog f = new OpenFileDialog();
if ((bool)f.ShowDialog())
{
try
{
if ( f.OpenFile() != null)
{
TagLib.File file = TagLib.File.Create(f.FileName);
file.Tag.Album = "Album1";
file.Save();
}
}
catch (Exception ex)
{
MessageBox.Show("Error: Could not read file from disk. Original error: " + ex.Message);
}
}
else
{
MessageBox.Show("Problem occured, try again later");
}
Could you help me?
Thanks
f.OpenFile() creates a FileStream around the file.
Since you never close this stream, the file remains open.
Don't do that.