Okay firstly I just started C# so I'm not exactly the most skilled programmer out there. Okay so here's my problem that may seem stupid to you guys ;)
I have a simple enough app that a friend asked me to do. So far I have managed with a bit of Google but I'm stuck with this. The app runs fine and minimizes to the system tray and maximizes from the system tray which is good. However, when I open a second form from that application it creates another icon in the system tray and starts duplicating every time I open another form. So eventually I have lots of icons and all of them are seperate instances of the main form. System Tray events
private void notifyIcon_systemTray_MouseDoubleClick(object sender, MouseEventArgs e)
{
if (FormWindowState.Minimized == WindowState)
{
Show();
WindowState = FormWindowState.Normal;
}
}
private void CronNecessityForm_Resize(object sender, EventArgs e)
{
notifyIcon_systemTray.Visible = true;
if (FormWindowState.Minimized == WindowState)
Hide();
}
private void restoreContextMenuItem_Click(object sender, EventArgs e)
{
Show();
WindowState = FormWindowState.Normal;
}
To open the Form:
private void preferencesToolStripMenuItem_Click(object sender, EventArgs e)
{
CronPreferences.formPreferences CronPreferences = new CronPreferences.formPreferences();
CronPreferences.Show();
}
Close it:
private void button2_Click(object sender, EventArgs e)
{
this.Hide();
}
How can I have all Forms map to the same icon in the System Tray?
You will need a single global tray icon that they all access. Do this by using a static variable that stays the same throughout different instances of the class.
Then, if you want to:
Open one form: keep a reference to the latest form in a variable and open it.
Open all minimised forms: iterate through each form and open them again.
If I got it right, you want to keep only a single instance of your application running. In that case, your title is a bit misleading since your problem has nothing to do with tray icons or multiple forms.
Code Project: A Single Instance Application which Minimizes to the System Tray when Closed
On the other hand, if you really have a main form in your app, which opens the second form (which creates a tray icon), in that case you simply need to make sure your second form is instantiated only once:
public class MainForm
{
private SecondForm _secondForm;
public void OpenSecondForm()
{
// create it only once
if (_secondForm == null)
_secondForm = new SecondForm();
// otherwise just show it
_secondForm.Show();
}
}
Related
I made this simple little application which goes in the notification area (the little arrow on the taskbar which holds a few applications that run in the background).
I have a button made where I can minimize it using:
this.WindowState = FormWindowState.Minimized;
and I can put the WindowState back to normal mode with:
this.WindowState = FormWindowState.Normal;
This all works fine however when I try to click outside the application to minimize it, instead of pressing the button for it, it doesn't wanna go back to the normal state, even if I use the statement mentioned before.
Is there any setting I can use to toggle this behaviour, or do I need to change something inside the script and if so, what?
I've tried searching through the different settings on both the NotifyIcon and the ContextMenuStrip but couldn't find anything relevant but I might have also just missed it.
I've also tried to search through stackoverflow, but I'm not really sure what to search for, since nothing really popped up when trying to search for almost the same thing as the title on this thread.
Current Code:
private void button1_Click(object sender, EventArgs e)
{
File.WriteAllText("count.txt", count.ToString()); // Ignore this
this.WindowState = FormWindowState.Minimized;
}
private void notifyIcon1_MouseDoubleClick(object sender, MouseEventArgs e)
{
this.WindowState = FormWindowState.Normal;
}
private void exitToolStripMenuItem_Click(object sender, EventArgs e)
{
this.Close();
}
private void showToolStripMenuItem_Click(object sender, EventArgs e)
{
this.WindowState = FormWindowState.Normal;
}
Figured out that the issue was not about it minimizing the form, however it was prioritizing the window I was clicking on. To fix this and change it to the top I used
this.TopMost = true
Which worked perfectly.
I have a form and through this I press a button and a new form opens. If I click minimize this new form, the form I call this form from is minimized as well. How could I make sure the form from which I call the new form is not minimized?
Maybe I have to enable some property in the form or something.
Of course, I tried with the following code and with the form propety singleFixed but the two forms are minimized:
private void bminimize_Click(object sender, EventArgs e)
{
WindowState = FormWindowState.Minimized;
}
Maybe have I to create this new form as subform or something like this?
EDIT: How I call this new form:
private void Button_Click(object sender, EventArgs e)
{
DateTime rnow = DateTime.Now;
Chronometer chrono = new chronometer();
var resultchrono = chrono.ShowDialog();
if (resultchrono == DialogResult.OK)
{
...
}
You're using ShowDialog(), which is documented thus, emphasis mine:
This version of the ShowDialog method does not specify a form or control as its owner. When this version is called, the currently active window is made the owner of the dialog box. If you want to specify a specific owner, use the other version of this method.
If you need the dialog result, you'll need to use the ShowDialog(owner) form of the call with say, the desktop window handle.
Its because of: chrono.ShowDialog();. Show the dialog with chrono.Show(); . But you will have to handle returned values differently.
If you need the DialogResult in the same method in which you open the window, then use AKX´s answer.
I have been searching everywhere for the answer to my problem but i cant seem to locate anything.
I am trying to open 2 different windows, that i have already created, after a button press. On the button press, i go to open the new window, but it just opens a blank window, not the window i want.
This is my function that i am trying to open my new window with, and it is inside my MainWindow, and i want to open my window i have created in Jobs (see image below).
void Jobs_Clicked(object sender, RoutedEventArgs e)
{
Window Jobs_Window = new Window();
App.Current.Jobs = Jobs_Window;
Jobs_Window.Show();
this.Close();
}
Solution Explorer
You are creating an instance of the standard Window class rather than your custom Window that you have made.
If you have added a Window, called JobsWindow for example, then create an instance of that rather than just the .NET built-in Window:
void Jobs_Clicked(object sender, RoutedEventArgs e)
{
Window Jobs_Window = new JobsWindow();
App.Current.Jobs = Jobs_Window;
Jobs_Window.Show();
this.Close();
}
This is probably going to be a standard question. I have read lots of articles on this but none point out the issue i am having specifically.
I am developing a WinForm and have a "Main Menu" form that is loaded on startup. Within this main are several buttons which open up individual modules (other forms) of the program.
I can open up the form no problem and can close it and re-show the main form no problem. The problem lies when a user hits the (X) in the control box, the application doesnt exit because the main form is still there, but hidden. I know that i could put an application.exit() in the close event of the form. However, then if i have a button that closes the form and wants to unhide the main form, the application will close due to the formclosing event.
Can someone help me understand this principle. I dont think it should be as hard as it seems to me and i dont really want to use Panels.
Thanks in advance.
-Joseph
the following code solved the issue based on the answer provided below
private void btnHome_Click(object sender, EventArgs e)
{
Form f1 = Application.OpenForms[0];
f1.Visible=true;
this.Close();
}
private void frmCostControlMain_FormClosed(object sender, FormClosedEventArgs e)
{
Form f = Application.OpenForms[0]; // The main form
if (f.Visible==true)
{
f.BringToFront();
}
else
{
Application.Exit();
}
}
You can check the Application.OpenForms and see whether some non-hidden forms other than the current form are around. If you only want to check the main form, you can check Application.OpenForms[0]. Since it was opened first, it will always be at index 0. From memory:
Form_Closed(object sender, EventArgs e)
{
Form f = Application.OpenForms[0]; // The main form
if (f.Visible) {
f.BringToFront();
} else {
Application.Exit();
}
}
When the close button is clicked you would first unhide the main form and then close the current form.
I still don't understand your question, but I guess you could use the
Application.Exit().
You should then check the arguments of your FormClosed event.
The Close reason is as follows:
Click on [X]:
CloseReason = UserClosing
Application Exit:
CloseReason = ApplicationExitCall
You could then handle it properly
private void Form1_FormClosed(object sender, FormClosedEventArgs e)
{
if (e.CloseReason == CloseReason.ApplicationExitCall)
{
//Application.Exit();
}
else if (e.CloseReason == CloseReason.UserClosing)
{
//[X] was pressed
}
else
{
//Many other reasons
}
}
I guess there is a much cleaner way of handling your problem. If you provide a bit more details, I think someone would be able to help you along.
Problem: I have created a program that has two forms. When a button is pressed on Form1, the program "hides" Form1 and "shows" Form2. The issue is, when I close Form2, the program continues to run in the background, I believe this is because the program needs Form1 to be closed, not hidden in order for the program to end.
My Question is how do I override the Second Form to close the program and not hide?
private void btnCreate_Click(object sender, EventArgs e)
{
Form2.Show();
Form1.Hide();
}
I know I could show Form1 again from Form2, and then close, but I would really like to avoid that.
You have few options to do that, according to how your application is.
First and intuitive solution is to call Close() instead of Hide() for Form1. This works only if Form1 is not the main form of your application (the one inside main message loop started with Application.Run()).
Second solution is to add an event handler for the FormClosed event of Form2 and to close first form when second one is closed:
private void btnCreate_Click(object sender, EventArgs e)
{
Form2.Show();
Form2.FormClosed += new FormClosedEventHandler(delegate { Close(); });
Form1.Hide();
}
You can directly close Form1 or call Application.Exit() (in case you did open multiple forms you want to close all together).
Last solution is to make second form the owner of first one:
private void btnCreate_Click(object sender, EventArgs e)
{
Form2.Show();
Form1.Owner = Form2;
Form1.Hide();
}
This will close automatically the owned form when owner is closed. This is the solution I prefer but it works only for one form (an owner can own only one form).
You can use the FormClosed event:
private void btnCreate_Click(object sender, EventArgs e)
{
Form2.Show();
Form2.FormClosed += new FormClosedEventHandler(form2_FormClosed);
Form1.Hide();
}
void Form2_FormClosed(object sender, FormClosedEventArgs e)
{
Form1.Close();
}
In application development especially for winforms for the sake of your users, always have a main form (whether an mdiparent or a single parent) that will always be the main form that all other forms show from.
Giving an answer to the question will be encouraging bad programming practice.
Let the mainform close and the application will end. Hiding form1 will not end the application.