WPF Change between 2 windows - c#

I have been searching everywhere for the answer to my problem but i cant seem to locate anything.
I am trying to open 2 different windows, that i have already created, after a button press. On the button press, i go to open the new window, but it just opens a blank window, not the window i want.
This is my function that i am trying to open my new window with, and it is inside my MainWindow, and i want to open my window i have created in Jobs (see image below).
void Jobs_Clicked(object sender, RoutedEventArgs e)
{
Window Jobs_Window = new Window();
App.Current.Jobs = Jobs_Window;
Jobs_Window.Show();
this.Close();
}
Solution Explorer

You are creating an instance of the standard Window class rather than your custom Window that you have made.
If you have added a Window, called JobsWindow for example, then create an instance of that rather than just the .NET built-in Window:
void Jobs_Clicked(object sender, RoutedEventArgs e)
{
Window Jobs_Window = new JobsWindow();
App.Current.Jobs = Jobs_Window;
Jobs_Window.Show();
this.Close();
}

Related

I minimize one Form and minimize several

I have a form and through this I press a button and a new form opens. If I click minimize this new form, the form I call this form from is minimized as well. How could I make sure the form from which I call the new form is not minimized?
Maybe I have to enable some property in the form or something.
Of course, I tried with the following code and with the form propety singleFixed but the two forms are minimized:
private void bminimize_Click(object sender, EventArgs e)
{
WindowState = FormWindowState.Minimized;
}
Maybe have I to create this new form as subform or something like this?
EDIT: How I call this new form:
private void Button_Click(object sender, EventArgs e)
{
DateTime rnow = DateTime.Now;
Chronometer chrono = new chronometer();
var resultchrono = chrono.ShowDialog();
if (resultchrono == DialogResult.OK)
{
...
}
You're using ShowDialog(), which is documented thus, emphasis mine:
This version of the ShowDialog method does not specify a form or control as its owner. When this version is called, the currently active window is made the owner of the dialog box. If you want to specify a specific owner, use the other version of this method.
If you need the dialog result, you'll need to use the ShowDialog(owner) form of the call with say, the desktop window handle.
Its because of: chrono.ShowDialog();. Show the dialog with chrono.Show(); . But you will have to handle returned values differently.
If you need the DialogResult in the same method in which you open the window, then use AKX´s answer.

Open and close forms through a menu c#

I've had a look around but none of the answers make any sense to me. I have a menu form which has buttons on; when users come to use the menu form, you can open other forms from the menu. Currently, I can get the form to open, but the menu form stays open too.
private void BtnAddNewCar_Click(object sender, EventArgs e)
{
AddCompanyCar carForm = new AddCompanyCar();
carForm.ShowDialog();
}
The code above opens the form AddCompanyCar from the menu. How do I add to this code so that the form 'Menu' closes when AddCompanyCar opens?
Are you sure want to do this as it impacts usability. If you're using WinForms, then just create a container window, and replace the panels instead. Might be easy and best way
If not and you wanna go-ahead, can take a look on this example
Why not just hide it, then show it again when ShowDialog() returns?
private void BtnAddNewCar_Click(object sender, EventArgs e)
{
this.Visible = false;
AddCompanyCar carForm = new AddCompanyCar();
carForm.ShowDialog(); // execution stops here until "carForm" is dismissed
this.Visible = true;
}
by closing the main window, you destroy the context in which you were previously working. As others suggest, simply hide the main window so you can return to it.

C# - How to close current window and get new window

I'm implementing a window form in C#. I want to close current window and open a new window. (Just like File->New function in applications)
This is my code
private void newToolStripMenuItem_Click(object sender, EventArgs e)
{
Image_Editor IE = new Image_Editor(); //Image_Editor is the name of window
IE.Show();
this.Close();
}
Images of what I want to achieve:
(source: infosight.com)
I want to implement the "new" function as shown in the above link. When executing given code, new window just appeared and both windows close at the same time.
What should I do to solve this?
if you mean that you want to close this windows and open a windows like your current windows use this
Myform frm; //thats name of the class of your form like Form1
frm = new Myform();
frm.Show(); // show the secend one
this.Close(); // and close the first one

WPF: window.ShowDialog() then window.Show() - application stopped

I try to show the authentication window, then open the main window,
but when you close the authorization window, application is stopped
private void App_OnStartup(object sender, StartupEventArgs e)
{
new LoginWindow().ShowDialog();
new MainWindow().Show();
// Then application stopped
}
BUT!
If the display window authentication by using method Show(), the application does not close after closing the authorization window
private void App_OnStartup(object sender, StartupEventArgs e)
{
new LoginWindow().Show();
new MainWindow().Show();
// Then application running
}
Why is this behavior???
Thanks to Eran Otzap!
Application.Current.ShutdownMode = ShutdownMode.OnExplicitShutdown;
Is working!
By default, when the main windows of the application is closed, then the application is closed.
According to the documentation, "Application.MainWindow is automatically set with a reference to the first Window object to be instantiated in the AppDomain."
To get around this, you can try to create first a MainWindow object (without calling Show()),
then create and show the login dialog, and then show the main window.

Properties Window in C#

I'm currently trying to create a Properties Window which is opened after a Button on the Outlook Toolbar is pressed, i now have:
1) the Button on the Toolbar (currently if pressed nothing occurs)
2) i know how to create the method which would hold the action after the Button is Pressed
-but, I am a beginner and i don't know how to create a window which would open after the button is pressed, the Window should be fairly big, and for now have nothing but a checkbox(which i later would like to apply some method to.
if you ever created a window which opens after a button is pressed, i would be really pleased to get your help.
All help is appreciated, thank you
Here's the recommended way of opening a dialog window when the user clicks a button:
Add a new form to your project (e.g. MyForm) and then you can use the following code in your button's click event handler:
private void OnMyButtonClicked(object sender, EventArgs e)
{
MyForm myForm = new MyForm();
if (myForm.ShowDialog() == DialogResult.OK)
{
// The code that should be executed when the dialog was closed
// with an OK dialog result
}
}
In case you do not want the new window to be modal (i.e. you want to allow the user use other parts of the application while the window is opened), the code gets even more simple:
private void OnMyButtonClicked(object sender, EventArgs e)
{
MyForm myForm = new MyForm();
myForm.Show();
}
You can also create your form on the fly without adding one to your project, which is a bit more complicated, but advanced developers prefer this approach instead of messing with the designer ;)
private void OnMyButtonClicked(object sender, EventArgs e)
{
Form myForm = new Form();
myForm.Text = "My Form Title";
// Add a checkbox
CheckBox checkBox = new CheckBox();
checkBox.Text = "Check me";
checkBox.Location = new Point(10, 10);
myForm.Controls.Add(checkBox);
// Show the form
myForm.Show();
}
Here is a small tutorial for you to follow..
http://msdn.microsoft.com/en-us/library/ws1btzy8%28v=vs.90%29.aspx
EDIT: I would also recommend you remember the msdn website because it will prove invaluable for other programming issues you come across..
you have to add a new form to your project. Then you call the constructor where you want to pop up the window.
like this
Form2 form2 = new Form2();
form2.showDialog();
Edit:
where form2 is not the "main" Form of you program.
This'll set your main window to the background as long as the newly popped up window is closed.

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