var amount="0";
#String.Format("{0:0.00}", amount)
returns "0"
While I was expecting it to return
"0.00"
Formatting a string will just return the string itself, you have to format a number to get it formatted as a number:
var amount = 0;
A variable with implicit type which is assigned an integer value will be an integer, so it won't have a fractional part. You might want to specify the type:
double amount = 0;
Or use a double value:
var amount = 0.0;
Try:
String.Format("{0:#.##}", amount)
OR
String.Format("{0:N2}", amount)
Scratch this - Guffa's answer is correct...
Try this
.ToString("N2")
It will use the CultureInfo to format the number. This means that your thousands separator might be different depending on the used CultureInfo. You can also pass the desired CultureInfo if you want.
Related
I need to display a number with commas and a decimal point.
Eg:
Case 1 : Decimal number is 432324 (This does not have commas or decimal points).
Need to display it as: 432,324.00.
Not: 432,324
Case 2 : Decimal number is 2222222.22 (This does not have commas).
Need to display it as: 2,222,222.22
I tried ToString("#,##0.##"), but it is not formatting it correctly.
int number = 1234567890;
number.ToString("#,##0.00");
You will get the result 1,234,567,890.00.
Maybe you simply want the standard format string "N", as in
number.ToString("N")
It will use thousand separators, and a fixed number of fractional decimals. The symbol for thousands separators and the symbol for the decimal point depend on the format provider (typically CultureInfo) you use, as does the number of decimals (which will normally by 2, as you require).
If the format provider specifies a different number of decimals, and if you don't want to change the format provider, you can give the number of decimals after the N, as in .ToString("N2").
Edit: The sizes of the groups between the commas are governed by the
CultureInfo.CurrentCulture.NumberFormat.NumberGroupSizes
array, given that you don't specify a special format provider.
Try with
ToString("#,##0.00")
From MSDN
*The "0" custom format specifier serves as a zero-placeholder symbol. If the value that is being formatted has a digit in the position where the zero appears in the format string, that digit is copied to the result string; otherwise, a zero appears in the result string. The position of the leftmost zero before the decimal point and the rightmost zero after the decimal point determines the range of digits that are always present in the result string.
The "00" specifier causes the value to be rounded to the nearest digit preceding the decimal, where rounding away from zero is always used. For example, formatting 34.5 with "00" would result in the value 35.*
I had the same problem. I wanted to format numbers like the "General" format in spreadsheets, meaning show decimals if they're significant, but chop them off if not. In other words:
1234.56 => 1,234.56
1234 => 1,234
It needs to support a maximum number of places after the decimal, but don't put trailing zeros or dots if not required, and of course, it needs to be culture friendly. I never really figured out a clean way to do it using String.Format alone, but a combination of String.Format and Regex.Replace with some culture help from NumberFormatInfo.CurrentInfo did the job (LinqPad C# Program).
string FormatNumber<T>(T number, int maxDecimals = 4) {
return Regex.Replace(String.Format("{0:n" + maxDecimals + "}", number),
#"[" + System.Globalization.NumberFormatInfo.CurrentInfo.NumberDecimalSeparator + "]?0+$", "");
}
void Main(){
foreach (var test in new[] { 123, 1234, 1234.56, 123456.789, 1234.56789123 } )
Console.WriteLine(test + " = " + FormatNumber(test));
}
Produces:
123 = 123
1234 = 1,234
1234.56 = 1,234.56
123456.789 = 123,456.789
1234.56789123 = 1,234.5679
Try with
ToString("#,##0.###")
Produces:
1234.55678 => 1,234.556
1234 => 1,234
For Razor View:
$#string.Format("{0:#,0.00}",item.TotalAmount)
CultureInfo us = new CultureInfo("en-US");
TotalAmount.ToString("N", us)
Your question is not very clear but this should achieve what you are trying to do:
decimal numericValue = 3494309432324.00m;
string formatted = numericValue.ToString("#,##0.00");
Then formatted will contain: 3,494,309,432,324.00
All that is needed is "#,0.00", c# does the rest.
Num.ToString("#,0.00"")
The "#,0" formats the thousand separators
"0.00" forces two decimal points
If you are using string variables you can format the string directly using a : then specify the format (e.g. N0, P2, etc).
decimal Number = 2000.55512016465m;
$"{Number:N}" #Outputs 2,000.55512016465
You can also specify the number of decimal places to show by adding a number to the end like
$"{Number:N1}" #Outputs 2,000.5
$"{Number:N2}" #Outputs 2,000.55
$"{Number:N3}" #Outputs 2,000.555
$"{Number:N4}" #Outputs 2,000.5551
string Mynewcurrency = DisplayIndianCurrency("7743450.00");
private string DisplayIndianCurrency(string EXruppesformate)
{
string fare = EXruppesformate;
decimal parsed = decimal.Parse(fare, CultureInfo.InvariantCulture);
CultureInfo hindi = new CultureInfo("en-IN");
// string text = string.Format(hindi, "{0:c}", parsed);if you want <b>Rs 77,43,450.00</b>
string text = string.Format(hindi, "{0:N}", parsed); //if you want <b>77,43,450.00</b>
return ruppesformate = text;
}
For anyone looking at this now, and getting the "No overload for method 'ToString' takes 1 argument" when using:
TotalNumber.ToString("N")
My solution has been to use :
TotalNumber.Value.ToString("N")
I often get stuck on this when working directly inside an MVC View, the following wasn't working:
#Model.Sum(x => x.Number).ToString("N")
Whereas this works:
#Model.Sum(x => x.Number).Value.ToString("N")
Im having alot of problems trying to take out the decimal part of my string,
the string comes from a var type in my view like this:
var temp = dashList[index];
#PrintSection(actualDate, Model, String.Format("{0:0.000}", temp.Rubro))**
temp.Rubro is my String part that can be ".00" or ".XX"
however i need to take the decimal part of the string only when its value is ".00"
since i have some values of the dashlist have important decimal parts.
Is there a way to take the decimal part of a string only if it equals to ".00"???
The output im trying to get is:
From XX.00 -> XX
From XX.12 -> XX.12
both kinds are on my list
Try this:
var temp = dashList[index];
#PrintSection(actualDate, Model, String.Format("{0:0.000}", temp.Rubro).Replace(".00", ""))
You can try using
String.Format("{0:G29}", decimal.Parse(temp.Rubro)))
Whereas all the below formats achieve the same results.
string.Format("{0:G29}", decimal.Parse("2.00"))
decimal.Parse("2.00").ToString("G29")
2.0m.ToString("G29")
You can use ToString() with the General ("G") Format Specifier to achieve the desired result. Trailing zeros are truncated when using this format string with a precision specified. In order to prevent rounding in any situations, you will need to set the precision to the maximum allowed for decimals (29).
Simple trick...
You can parse the string and it will automatically remove the decimal places
try following
private static void ParseDouble()
{
string sDouble = "12.00";
double dValue = double.Parse(sDouble);
Console.WriteLine(dValue.ToString());
sDouble = "12.14";
dValue = double.Parse(sDouble);
Console.WriteLine(dValue.ToString());
}
Your output will be
12
12.14
Hope this helps.
I will suggest you to use accounting.js plugging which is pretty straightforward. I have used it in some projects and as of today I cannot complain. Otherwise, you could do something like this,
var x = temp.Replace(".00","").Trim();
This is probably dumb but it's giving me a hard time. I need to convert/format a double to string with a mandatory decimal point.
1 => 1.0
0.2423423 => 0.2423423
0.1 => 0.1
1234 => 1234.0
Basically, I want to output all decimals but also make sure the rounded values have the redundant .0 too. I am sure there is a simple way to achieve this.
Use double.ToString("N1"):
double d1 = 1d;
double d2 = 0.2423423d;
double d3 = 0.1d;
double d4 = 1234d;
Console.WriteLine(d1.ToString("N1"));
Console.WriteLine(d2.ToString("N1"));
Console.WriteLine(d3.ToString("N1"));
Console.WriteLine(d4.ToString("N1"));
Demo
Standard Numeric Format Strings
The Numeric ("N") Format Specifier
Update
(1.234).ToString("N1") produces 1.2 and in addition to removing additional decimal digits, it also adds a thousands separator
Well, perhaps you need to implement a custom NumberFormatInfo object which you can derive from the current CultureInfo and use in double.ToString:
var culture = CultureInfo.CurrentCulture;
var customNfi = (NumberFormatInfo)culture.NumberFormat.Clone();
customNfi.NumberDecimalDigits = 1;
customNfi.NumberGroupSeparator = "";
Console.WriteLine(d1.ToString(customNfi));
Note that you need to clone it since it's readonly by default.
Demo
There is not a built in method to append a mandatory .0 to the end of whole numbers with the .ToString() method, as the existing formats will truncate or round based on the number of decimal places you specify.
My suggestion is to just roll your own implementation with an extension method
public static String ToDecmialString(this double source)
{
if ((source % 1) == 0)
return source.ToString("f1");
else
return source.ToString();
}
And the usage:
double d1 = 1;
double d2 = 0.2423423;
double d3 = 0.1;
double d4 = 1234;
Console.WriteLine(d1.ToDecimalString());
Console.WriteLine(d2.ToDecimalString());
Console.WriteLine(d3.ToDecimalString());
Console.WriteLine(d4.ToDecimalString());
Results in this output:
1.0
0.2423423
0.1
1234.0
You could do something like this: if the number doesn't have decimal points you can format its output to enforce one decimal 0 and if it has decimal places, just use ToString();
double a1 = 1;
double a2 = 0.2423423;
string result = string.Empty;
if(a1 - Math.Floor(a1) >0.0)
result = a1.ToString();
else
result = a1.ToString("F1");
if (a2 - Math.Floor(a2) > 0.0)
result = a2.ToString();
else
result = a2.ToString("F1");
When you use "F" as formatting, the output won't contain thousands separator and the number that follows it specifies the number of decimal places.
Use ToString("0.0###########################").
It does work. I found it in duplicate of your question decimal ToString formatting which gives at least 1 digit, no upper limit
Double provides a method ToString() where you can pass an IFormatProvider-object stating how you want your double to be converted.
Additionally, it should display trailing 0 at all costs.
value = 16034.125E21;
// Display value using the invariant culture.
Console.WriteLine(value.ToString(CultureInfo.InvariantCulture));
// Display value using the en-GB culture.
Console.WriteLine(value.ToString(CultureInfo.CreateSpecificCulture("en-GB")));
// Display value using the de-DE culture.
Console.WriteLine(value.ToString(CultureInfo.CreateSpecificCulture("de-DE")));
// This example displays the following output to the console:
// -16325.62015
// -16325.62015
// -16325,62015
// 1.6034125E+25
// 1.6034125E+25
// 1,6034125E+25
Here is the documentation from MSDN.
You can cast to string and then appen ".0" if there was no decimal point given
string sValue=doubleValue.ToString();
if(!sValue.Contains('.'))
sValue+=".0";
EDIT:
As mentioned in the comments '.' may not be the decimal seperator in the current culture. Refer to this article to retrieve the actual seperator if you want make your code save for this case.
As I'm working on C#, I have one field named 'Amount'.
double amount = 10.0;
So, I want the result like '10.0' after converting it to string.
If my value
amount = 10.00, then I want result '10.00' after converting it to string.
So, Basically I want exact result in string as it is in double type. (With precisions).
Thanks in advance.
string result = string.Format( "{0:f2}", amount );
What you ask is not possible. A double in C# is a simple 64-bit floating-point value. It doesn't store precision. You can print your value with one decimal places, or two, as other answers describe, but not in a way that's "preserves" the variable's original precision.
string amountString = amount.ToString("N2");
"N2" is the format string used as the first parameter to the .ToString() method.
"N" stands for number, and 2 stands for the number of decimal places.
More on string format's here:
http://msdn.microsoft.com/en-us/library/dwhawy9k.aspx
As #Michael Petratta points out, double doesn't carry with it the precision of the input. If you need that information, you will need to store it yourself. Then you could reconstuct the input string doing something like:
static public string GetPrecisionString( double doubleValue, int precision)
{
string FormattingString = "{0:f" + precision + "}";
return string.Format( FormattingString, doubleValue);
}
I have a decimal number like this:
62.000,0000000
I need to cast that decimal into int; it will always have zero decimal numbers; so I wont loose any precision. What I want is this:
62.000
Stored on an int variable in c#.
I try many ways but it always give me an error, that the string isn't in the correct format, this is one of the ways i tryied:
int.Parse("62.000,0000000");
Hope you can help me, thanks.
You need to parse it in the right culture. For example, the German culture uses "." as a group separator and "," as the decimal separator - so this code works:
CultureInfo german = new CultureInfo("de-DE");
decimal d = decimal.Parse("62.000,0000000", german);
int i = (int) d;
Console.WriteLine(i); // Prints 62000
Is that what you're after? Note that this will then fail if you present it with a number formatted in a different culture...
EDIT: As Reed mentions in his comment, if your real culture is Spain, then exchange "de-DE" for "es-ES" for good measure.
You need to specify your culture correctly:
var ci = CultureInfo.CreateSpecificCulture("es-ES");
int value = (int) decimal.Parse("60.000,000000", ci);
If you do this, it will correctly convert the number.
Why don't you just cast it to int instead of parsing?