I need to display a number with commas and a decimal point.
Eg:
Case 1 : Decimal number is 432324 (This does not have commas or decimal points).
Need to display it as: 432,324.00.
Not: 432,324
Case 2 : Decimal number is 2222222.22 (This does not have commas).
Need to display it as: 2,222,222.22
I tried ToString("#,##0.##"), but it is not formatting it correctly.
int number = 1234567890;
number.ToString("#,##0.00");
You will get the result 1,234,567,890.00.
Maybe you simply want the standard format string "N", as in
number.ToString("N")
It will use thousand separators, and a fixed number of fractional decimals. The symbol for thousands separators and the symbol for the decimal point depend on the format provider (typically CultureInfo) you use, as does the number of decimals (which will normally by 2, as you require).
If the format provider specifies a different number of decimals, and if you don't want to change the format provider, you can give the number of decimals after the N, as in .ToString("N2").
Edit: The sizes of the groups between the commas are governed by the
CultureInfo.CurrentCulture.NumberFormat.NumberGroupSizes
array, given that you don't specify a special format provider.
Try with
ToString("#,##0.00")
From MSDN
*The "0" custom format specifier serves as a zero-placeholder symbol. If the value that is being formatted has a digit in the position where the zero appears in the format string, that digit is copied to the result string; otherwise, a zero appears in the result string. The position of the leftmost zero before the decimal point and the rightmost zero after the decimal point determines the range of digits that are always present in the result string.
The "00" specifier causes the value to be rounded to the nearest digit preceding the decimal, where rounding away from zero is always used. For example, formatting 34.5 with "00" would result in the value 35.*
I had the same problem. I wanted to format numbers like the "General" format in spreadsheets, meaning show decimals if they're significant, but chop them off if not. In other words:
1234.56 => 1,234.56
1234 => 1,234
It needs to support a maximum number of places after the decimal, but don't put trailing zeros or dots if not required, and of course, it needs to be culture friendly. I never really figured out a clean way to do it using String.Format alone, but a combination of String.Format and Regex.Replace with some culture help from NumberFormatInfo.CurrentInfo did the job (LinqPad C# Program).
string FormatNumber<T>(T number, int maxDecimals = 4) {
return Regex.Replace(String.Format("{0:n" + maxDecimals + "}", number),
#"[" + System.Globalization.NumberFormatInfo.CurrentInfo.NumberDecimalSeparator + "]?0+$", "");
}
void Main(){
foreach (var test in new[] { 123, 1234, 1234.56, 123456.789, 1234.56789123 } )
Console.WriteLine(test + " = " + FormatNumber(test));
}
Produces:
123 = 123
1234 = 1,234
1234.56 = 1,234.56
123456.789 = 123,456.789
1234.56789123 = 1,234.5679
Try with
ToString("#,##0.###")
Produces:
1234.55678 => 1,234.556
1234 => 1,234
For Razor View:
$#string.Format("{0:#,0.00}",item.TotalAmount)
CultureInfo us = new CultureInfo("en-US");
TotalAmount.ToString("N", us)
Your question is not very clear but this should achieve what you are trying to do:
decimal numericValue = 3494309432324.00m;
string formatted = numericValue.ToString("#,##0.00");
Then formatted will contain: 3,494,309,432,324.00
All that is needed is "#,0.00", c# does the rest.
Num.ToString("#,0.00"")
The "#,0" formats the thousand separators
"0.00" forces two decimal points
If you are using string variables you can format the string directly using a : then specify the format (e.g. N0, P2, etc).
decimal Number = 2000.55512016465m;
$"{Number:N}" #Outputs 2,000.55512016465
You can also specify the number of decimal places to show by adding a number to the end like
$"{Number:N1}" #Outputs 2,000.5
$"{Number:N2}" #Outputs 2,000.55
$"{Number:N3}" #Outputs 2,000.555
$"{Number:N4}" #Outputs 2,000.5551
string Mynewcurrency = DisplayIndianCurrency("7743450.00");
private string DisplayIndianCurrency(string EXruppesformate)
{
string fare = EXruppesformate;
decimal parsed = decimal.Parse(fare, CultureInfo.InvariantCulture);
CultureInfo hindi = new CultureInfo("en-IN");
// string text = string.Format(hindi, "{0:c}", parsed);if you want <b>Rs 77,43,450.00</b>
string text = string.Format(hindi, "{0:N}", parsed); //if you want <b>77,43,450.00</b>
return ruppesformate = text;
}
For anyone looking at this now, and getting the "No overload for method 'ToString' takes 1 argument" when using:
TotalNumber.ToString("N")
My solution has been to use :
TotalNumber.Value.ToString("N")
I often get stuck on this when working directly inside an MVC View, the following wasn't working:
#Model.Sum(x => x.Number).ToString("N")
Whereas this works:
#Model.Sum(x => x.Number).Value.ToString("N")
Suppose I have a list of decimal numbers that I must format with a comma every three places, plus the appropriate number of digits after the decimal point. I want to use the .net string.Format method.
I want it to work like this:
string format = ???;
string s1 = string.Format(format, "1500"); // "1,500"
string s2 = string.Format(format, "1500.25"); // "1,500.25"
string s3 = string.Format(format. "3.1415926358979"); // "3.1415926358979"
I have seen other answers where the digits after the decimal are either limited to a fixed number of digits or truncated entirely, but this doesn't work for my application. I want to add the comma-separator to the whole part of the number, but keep the digits after the decimal exactly as they are.
First problem, you need to parse your strings before you can format them. There maybe some lose of precision. Then you need to decide what your maximum amount of precision you need is. Then you can do something like this:
string format = "{0:#,##0.#############}";
string s1 = string.Format(format, double.Parse("1500")); // "1,500"
string s2 = string.Format(format, double.Parse("1500.25")); // "1,500.25"
string s3 = string.Format(format, double.Parse("3.1415926358979")); // "3.1415926358979"
The # after the decimal place is a place holder for a decimal digit. If there are no more digits it won't show trailing zeros.
If being limited to a number of decimal places or possibly losing precision when converting to double. You could do something really cludgy like this:
public static string DecimalFormatCludge(string original)
{
var split = original.Split('.');
return string.Join(".", (new [] { int.Parse(split[0]).ToString("#,##0")}).Concat(split.Skip(1)));
}
This will split on the . in the string, parse the first part as an int, convert it back to a string correctly formatted and then just stick the decimal part back on (if there is one)
something like this?
string s1 = format.ToString("#,##0.00");
The format is something like this:
string format = "{0:#,##.##################}";
I need to display some numbers in a variable of type decimal.
I want to display them almost as they are, which ToString("G29") gives me.
However, I want to add a thousands separator. ToString("N") gives me the thousands separator but totally loses the "G29 goodness".
Is there a simple solution to get the display string I want?
value "N" "G29" What I Want
============= ========== ========== ==============
296018.413 296,018.41 296018.413 296,018.413
652609 652,609.00 652609 652,609
296.018413 296.02 296.018413 296.018413
326.305 326.31 326.305 326.305
Edit:
Another SO question/answer recently made me aware that "G29" returns values less than 0.0001 in scientific notation. So when I wrote the question I was unaware that the solution needed to handle special cases like these:
value What I Want
============ =============
0.00001 0.00001
12345.000067 12,345.000067
You might have to do a little bit of work around.
How about this?
decimal d = 34561.2223400M;
string decimalPart = (d - (int)d).ToString("G29");
string integerPart = d.ToString("##,###");
string finalNumber = integerPart + decimalPart.Substring(1,decimalPart.Length-1);;
There is a pretty simple solution to this, though it involves a fairly long format string.
decimal d = 12345.000067m;
string s = d.ToString("#,###0.############################"); // 28 #'s after the decimal
You have to format the string.
Try:
string yourString = String.Format("{0:N29}", yourWeight);
Edit:
The above was pretty close. This gives exactly the desired results:
string yourString = String.Format("{0:N29}", yourWeight).Trim(new [] { '0', '.' });
I need help converting a string to double with 7 decimals. I have a string "00000827700000" and need it converted to 82.77
Tried using String.Format() with {0:N7} without success.
It looks like you could use:
decimal x = decimal.Parse(text.Substring(0, 7) + "." +
text.Substring(7),
CultureInfo.InvariantCulture);
That would actually parse it to 82.7700000, as decimal preserves trailing zeroes (to an extent) but maybe that's good enough? It not, you could change the second argument to
text.Substring(7).TrimEnd('0')
Note that I'd strongly recommend you to at least consider using decimal instead of double. You haven't explained what this value represents, but if it's stored as decimal figures which you need to preserve, it smells more like a decimal to me.
Based on the edit, it could be simplified as
var text = "00000827700000";
var x = decimal.Parse(text, CultureInfo.InvariantCulture) / 10000000;
Console.Write(String.Format("{0:N7}", x));
As I'm working on C#, I have one field named 'Amount'.
double amount = 10.0;
So, I want the result like '10.0' after converting it to string.
If my value
amount = 10.00, then I want result '10.00' after converting it to string.
So, Basically I want exact result in string as it is in double type. (With precisions).
Thanks in advance.
string result = string.Format( "{0:f2}", amount );
What you ask is not possible. A double in C# is a simple 64-bit floating-point value. It doesn't store precision. You can print your value with one decimal places, or two, as other answers describe, but not in a way that's "preserves" the variable's original precision.
string amountString = amount.ToString("N2");
"N2" is the format string used as the first parameter to the .ToString() method.
"N" stands for number, and 2 stands for the number of decimal places.
More on string format's here:
http://msdn.microsoft.com/en-us/library/dwhawy9k.aspx
As #Michael Petratta points out, double doesn't carry with it the precision of the input. If you need that information, you will need to store it yourself. Then you could reconstuct the input string doing something like:
static public string GetPrecisionString( double doubleValue, int precision)
{
string FormattingString = "{0:f" + precision + "}";
return string.Format( FormattingString, doubleValue);
}