In my current project I have to work alot with substring and I'm wondering if there is an easier way to get out numbers from a string.
Example:
I have a string like this:
12 text text 7 text
I want to be available to get out first number set or second number set.
So if I ask for number set 1 I will get 12 in return and if I ask for number set 2 I will get 7 in return.
Thanks!
This will create an array of integers from the string:
using System.Linq;
using System.Text.RegularExpressions;
class Program {
static void Main() {
string text = "12 text text 7 text";
int[] numbers = (from Match m in Regex.Matches(text, #"\d+") select int.Parse(m.Value)).ToArray();
}
}
Try using regular expressions, you can match [0-9]+ which will match any run of numerals within your string. The C# code to use this regex is roughly as follows:
Match match = Regex.Match(input, "[0-9]+", RegexOptions.IgnoreCase);
// Here we check the Match instance.
if (match.Success)
{
// here you get the first match
string value = match.Groups[1].Value;
}
You will of course still have to parse the returned strings.
Looks like a good match for Regex.
The basic regular expression would be \d+ to match on (one or more digits).
You would iterate through the Matches collection returned from Regex.Matches and parse each returned match in turn.
var matches = Regex.Matches(input, "\d+");
foreach(var match in matches)
{
myIntList.Add(int.Parse(match.Value));
}
You could use regex:
Regex regex = new Regex(#"^[0-9]+$");
you can split the string in parts using string.Split, and then travese the list with a foreach applying int.TryParse, something like this:
string test = "12 text text 7 text";
var numbers = new List<int>();
int i;
foreach (string s in test.Split(' '))
{
if (int.TryParse(s, out i)) numbers.Add(i);
}
Now numbers has the list of valid values
Related
I have string like
"Augustin Ralf (050288)"
"45 Max Müller (4563)"
"Hans (Adam) Meider (056754)"
I am searching for a regex to extract the last part in the brackets, for example this results for the strings above:
"050288"
"4563"
"056754"
I have tried with
var match = Regex.Match(string, #".*(\(\d*\))");
But I get also the brackets with the result. Is there a way to extract the strings and get it without the brackets?
Taking your requirements precisely, you are looking for
\(([^()]+)\)$
This will capture anything between the parentheses (not nested!), may it be digits or anything else and anchors them to the end of the string. If you happen to have whitespace at the end, use
\(([^()]+)\)\s*$
In C# this could be
using System;
using System.Text.RegularExpressions;
public class Example
{
public static void Main()
{
string pattern = #"\(([^()]+)\)$";
string input = #"Augustin Ralf (050288)
45 Max Müller (4563)
Hans (Adam) Meider (056754)
";
RegexOptions options = RegexOptions.Multiline;
foreach (Match m in Regex.Matches(input, pattern, options))
{
Console.WriteLine("'{0}' found at index {1}.", m.Value, m.Index);
}
}
}
See a demo on regex101.com.
please use regex - \(([^)]*)\)[^(]*$. This is working as expected. I have tested here
You can extract the number between the parantheses without worring about extracting the capturing groups with following regex.
(?<=\()\d+(?=\)$)
demo
Explanation:
(?<=\() : positive look behind for ( meaning that match will start after a ( without capturing it to the result.
\d+ : captures all digits in a row until non digit character found
(?=\)$) : positive look ahead for ) with line end meaning that match will end before a ) with line ending without capturing ) and line ending to the result.
Edit: If the number can be within parantheses that is not at the end of the line, remove $ from the regex to fix the match.
var match = Regex.Match(string, #".*\((\d*)\)");
https://regex101.com/r/Wk9asY/1
Here are three options for you.
The first one uses the simplest pattern and in addition the Trim method.
The second one uses capturing the desired value to the group and then getting it from the group.
The third one uses Lookbehind and Lookahead.
var inputs = new string[] {
"Augustin Ralf (050288)", "45 Max Müller (4563)", "Hans (Adam) Meider (056754)"
};
foreach (var input in inputs)
{
var match = Regex.Match(input, #"\(\d+\)");
Console.WriteLine(match.Value.Trim('(', ')'));
}
Console.WriteLine();
foreach (var input in inputs)
{
var match = Regex.Match(input, #"\((\d+)\)");
Console.WriteLine(match.Groups[1]);
}
Console.WriteLine();
foreach (var input in inputs)
{
var match = Regex.Match(input, #"(?<=\()\d+(?=\))");
Console.WriteLine(match.Value);
}
Console.WriteLine();
I'm trying to find all instances of the substring EnemyType('XXXX') where XXXX is an arbitrary string and the instasnce of EnemyType('XXXX') can appear multiple times.
Right now I'm using a consortium of index of/substring functions in C# but would like to know if there's a cleaner way of doing it?
Use regex. Example:
using System.Text.RegularExpressions;
var inputString = " EnemyType('1234')abcdeEnemyType('5678')xyz";
var regex = new Regex(#"EnemyType\('\d{4}'\)");
var matches = regex.Matches(inputString);
foreach (Match i in matches)
{
Console.WriteLine(i.Value);
}
It will print:
EnemyType('1234')
EnemyType('5678')
The pattern to match is #"EnemyType\('\d{4}'\)", where \d{4} means 4 numeric characters (0-9). The parentheses are escaped with backslash.
Edit: Since you only want the string inside quotes, not the whole string, you can use named groups instead.
var inputString = " EnemyType('1234')abcdeEnemyType('5678')xyz";
var regex = new Regex(#"EnemyType\('(?<id>[^']+)'\)");
var matches = regex.Matches(inputString);
foreach (Match i in matches)
{
Console.WriteLine(i.Groups["id"].Value);
}
Now it prints:
1234
5678
Regex is a really nice tool for parsing strings. If you often parse strings, regex can make life so much easier.
I have a string in this format:
ABCD_EFDG20120700.0.xml
This has a pattern which has three parts to it:
First is the set of chars before the '_', the 'ABCD'
Second are the set of chars 'EFDG' after the '_'
Third are the remaining 20120700.0.xml
I can split the original string and get the number(s) from the second element in the split result using this switch:
\d+
Match m = Regex.Match(splitname[1], "\\d+");
That returns only '20120700'. But I need '20120700.0'.
How do I get the required string?
You can extend your regex to look for any number of digits, then period and then any number of digits once again:
Match m = Regex.Match(splitname[1], "\\d+\\.\\d+");
Although with such regular expression you don't even need to split the string:
string s = "ABCD_EFDG20120700.0.xml";
Match m = Regex.Match(s, "\\d+\\.\\d+");
string result = m.Value; // result is 20120700.0
I can suggest you to use one regex operation for all you want like this:
var rgx = new Regex(#"^([^_]+)_([^\d.]+)([\d.]+\d+)\.(.*)$");
var matches = rgx.Matches(input);
if (matches.Count > 0)
{
Console.WriteLine("{0}", matches[0].Groups[0]); // All input string
Console.WriteLine("{0}", matches[0].Groups[1]); // ABCD
Console.WriteLine("{0}", matches[0].Groups[2]); // EFGH
Console.WriteLine("{0}", matches[0].Groups[3]); // 20120700.0
Console.WriteLine("{0}", matches[0].Groups[4]); // xml
}
I have the following string:
String myNarrative = "ID: 4393433 This is the best narration";
I want to split this into 2 strings;
myId = "ID: 4393433";
myDesc = "This is the best narration";
How do I do this in Regex.Split()?
Thanks for your help.
If it is a fixed format as shown, use Regex.Match with Capturing Groups (see Matched Subexpressions). Split is useful for dividing up a repeating sequence with unbound multiplicity; the input does not represent such a sequence but rather a fixed set of fields/values.
var m = Regex.Match(inp, #"ID:\s+(\d+)\s+(.*)\s+");
if (m.Success) {
var number = m.Groups[1].Value;
var rest = m.Groups[2].Value;
} else {
// Failed to match.
}
Alternatively, one could use Named Groups and have a read through the Regular Expression Language quick-reference.
I need to extract a substring from an existing string. This String starts with uninteresting characters (include "," "space" and numbers) and ends with ", 123," or ", 57," or something like this where the numbers can change. I only need the Numbers.
Thanks
public static void Main(string[] args)
{
string input = "This is 2 much junk, 123,";
var match = Regex.Match(input, #"(\d*),$"); // Ends with at least one digit
// followed by comma,
// grab the digits.
if(match.Success)
Console.WriteLine(match.Groups[1]); // Prints '123'
}
Regex to match numbers: Regex regex = new Regex(#"\d+");
Source (slightly modified): Regex for numbers only
I think this is what you're looking for:
Remove all non numeric characters from a string using Regex
using System.Text.RegularExpressions;
...
string newString = Regex.Replace(oldString, "[^.0-9]", "");
(If you don't want to allow the decimal delimiter in the final result, remove the . from the regular expression above).
Try something like this :
String numbers = new String(yourString.TakeWhile(x => char.IsNumber(x)).ToArray());
You can use \d+ to match all digits within a given string
So your code would be
var lst=Regex.Matches(inp,reg)
.Cast<Match>()
.Select(x=x.Value);
lst now contain all the numbers
But if your input would be same as provided in your question you don't need regex
input.Substring(input.LastIndexOf(", "),input.LastIndexOf(","));