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Regex - Extract string patterns

I have many strings like these
/test/v1/3908643GASF/item
/test/v1/343569/item/AAAS45663/document
/test/v2/field/1230FRE/item
...
For each one I need to extract the defined pattern like these
/test/v1/{Value}/item
/test/v1/{Value}/item/{Value}/document
/test/v2/field/{Value}/item
The value can be a guid or something else, Can I match the given string patterns with input paths with regex?
I wrote just this code but I don't konw how to match input paths with patterns. The result should be the pattern. Thank you
string pattern1 = "/test/v1/{Value}/item";
string pattern2 = "/test/v1/{Value}/item/{Value}/document";
string pattern3 = "/test/v2/field/{Value}/item";
List<string> paths = new List<string>();
List<string> matched = new List<string>();
paths.Add("/test/v1/3908643GASF/item");
paths.Add("/test/v1/343569/item/AAAS45663/document");
paths.Add("/test/v1/343569/item/AAAS45664/document");
paths.Add("/test/v1/123444/item/AAAS45688/document");
paths.Add("/test/v2/field/1230FRE/item");
foreach (var path in paths)
{
}

This can also be achieved using regex alone. You can probably try:
(\w+)\/\w+(?<=\/item)(\/(\w+)\/)?
Explanation of the above regex:
(\w+) - Represents a capturing group matching a word character one or more time. This group captures our required result.
\/\w+(?<=\/item) - Represents a positive look-behind matching the characters before \items.
$1 - Captured group 1 contains the required information you're expecting.
(\/(\w+)\/)? - Represents the second and third capturing group capturing if after item some other values is present or not.
You can find the demo of the above regex in here.
Sample implementation in C#:
using System;
using System.Text.RegularExpressions;
public class Example
{
public static void Main()
{
string pattern = #"(\w+)\/\w+(?<=\/item)(\/(\w+)\/)?";
string input = #"/test/v1/3908643GASF/item
/test/v1/343569/item/AAAS45663/document
/test/v2/field/1230FRE/item";
foreach (Match m in Regex.Matches(input, pattern))
{
Console.Write(m.Groups[1].Value + " ");
if(m.Groups[3].Value != null)
Console.WriteLine(m.Groups[3].Value);
}
}
}
You can find the sample run of the above implementation in here.

Split a string by Regex [duplicate]

This question already has answers here:
Regular expression to extract text between square brackets
(15 answers)
Closed 5 years ago.
I'm currently thinking of how to split this kind of string into regex using c#.
[01,01,01][02,03,00][03,07,00][04,06,00][05,02,00][06,04,00][07,08,00][08,05,00]
Can someone knowledgeable on regex can point me on how to achieved this goal?
sample regex pattern that don't work:
[\dd,\dd,\dd]
sample output:
[01,01,01]
[02,03,00]
[03,07,00]
[04,06,00]
[05,02,00]
[06,04,00]
[07,08,00]
[08,05,00]

This will do the job in C# (\[.+?\]), e.g.:
var s = #"[01,01,01][02,03,00][03,07,00][04,06,00][05,02,00][06,04,00][07,08,00][08,05,00]";
var reg = new Regex(#"(\[.+?\])");
var matches = reg.Matches(s);
foreach(Match m in matches)
{
Console.WriteLine($"{m.Value}");
}
EDIT This is how the expression (\[.+?\]) works
first the outter parenthesis, ( and ), means to capture whatever the inside pattern matched
then the escaped square brackets, \[ and \], is to match the [ and ] in the source string
finally the .+? means to match one or more characters, but as few times as possible, so that it won't match all the characters before the first [ and the last ]

I know you stipulated Regex, however it's worth looking at Split again, if for only for academic purposes:
Code
var input = "[01,01,01][02,03,00][03,07,00][04,06,00][05,02,00][06,04,00][07,08,00][08,05,00]";
var output = input.Split(']',StringSplitOptions.RemoveEmptyEntries)
.Select(x => x + "]") // the bracket back
.ToList();
foreach(var o in output)
Console.WriteLine(o);
Output
[01,01,01]
[02,03,00]
[03,07,00]
[04,06,00]
[05,02,00]
[06,04,00]
[07,08,00]
[08,05,00]

The Regex solution below is restricted to 3 values of only 2 digits seperated by comma. Inside the foreach loop you can access the matching value via match.Value. >> Refiddle example
Remember to include using System.Text.RegularExpressions;
var input = "[01,01,01][02,03,00][03,07,00][04,06,00][05,02,00][06,04,00][07,08,00][08,05,00]";
foreach(var match in Regex.Matches(input, #"(\[\d{2},\d{2},\d{2}\])+"))
{
// do stuff
}

Thanks all for the answer i also got it working by using this code
string pattern = #"\[\d\d,\d\d,\d\d]";
Regex rgx = new Regex(pattern, RegexOptions.IgnoreCase);
MatchCollection matches = rgx.Matches(myResult);
Debug.WriteLine(matches.Count);
foreach (Match match in matches)
Debug.WriteLine(match.Value);

Regex match and replace operators in math operation

Given an input string
12/3
12*3/12
(12*54)/(3/4)
I need to find and replace each operator with a string that contains the operator
some12text/some3text
some12text*some2text/some12text
(some12text*some54text)/(some3text/some4text)
practical application:
From a backend (c#), i have the following string
34*157
which i need to translate to:
document.getElementById("34").value*document.getElementById("157").value
and returned to the screen which can be run in an eval() function.
So far I have
var pattern = #"\d+";
var input = "12/3;
Regex r = new Regex(pattern);
var matches = r.Matches(input);
foreach (Match match in matches)
{
// im at a loss what to match and replace here
}
Caution: i cannot do a blanket input.Replace() in the foreach loop, as it may incorrectly replace (12/123) - it should only match the first 12 to replace
Caution2: I can use string.Remove and string.Insert, but that mutates the string after the first match, so it throws off the calculation of the next match
Any pointers appreciated

Here you go
string pattern = #"\d+"; //machtes 1-n consecutive digits
var input = "(12*54)/(3/4)";
string result = Regex.Replace(input, pattern, "some$0Text");
$0 is the character group matching the pattern \d+. You can also write
string result = Regex.Replace(input, pattern, m => "some"+ m.Groups[0]+ "Text");
Fiddle: https://dotnetfiddle.net/JUknx2

How do I extract a string of text that lies between *>...* using .NET C# regex or anything else?

I have a string like this.
*>-0.0532*>-0.0534*>-0.0534*>-0.0532*>-0.0534*>-0.0534*>-0.0532*>-0.0532*>-0.0534*>-0.0534*>-0.0534*>-0.0532*>-0.0534*
I wanna extract between *> and * characters.
I tried this pattern which is wrong here below:
string pattern = "\\*\\>..\\*";
Regex rgx = new Regex(pattern, RegexOptions.IgnoreCase);
MatchCollection matches = rgx.Matches(seriGelen);
if (matches.Count > 0)
{
foreach (Match match in matches)
MessageBox.Show("{0}", match.Value);
}

You can use simple regex:
(?<=\*>).*?(?=\*)
Sample code:
string text = "*>-0.0532*>-0.0534*>-0.0534*>-0.0532*>-0.0534*>-0.0534*>-0.0532*>-0.0532*>-0.0534*>-0.0534*>-0.0534*>-0.0532*>-0.0534*";
string[] values = Regex.Matches(text, #"(?<=\*>).*?(?=\*)")
.Cast<Match>()
.Select(m => m.Value)
.ToArray();

Looks like there are can be very different values (UPD: there was an integer positive value). So, let me to not check numbers format. Also I will consider that *> and >, and also * are just different variants of delimiters.
I'd like to suggest the following solution.
(?<=[>\*])([^>\*]+?)(?=[>\*]+)
(http://regex101.com/r/mM7nK1)
Not sure it is ideal. Will only works if your input starts and ends with delimiters, but will allow to you to use matches instead groups, as your code does.
========
But you know, why wouldn't you use String.Split function?
var toprint = seriGelen.Split(new [] {'>', '*'}, StringSplitOptions.RemoveEmptyEntries);

Is there an error at the beginning of the string? Missing an asterisk after first number? >-0.0532>-0.0534*>
If not try this.
>([-+]?[0-9]*\.?[0-9]+)\*
C# Code
string strRegex = #">([-+]?[0-9]*\.?[0-9]+)\*";
Regex myRegex = new Regex(strRegex, RegexOptions.IgnoreCase | RegexOptions.Singleline);
string strTargetString = #">-0.0532>-0.0534*>-0.0534*>-0.0532*>-0.0534*>-0.0534*>-0.0532*>-0.0532*>-0.0534*>-0.0534*>-0.0534*>-0.0532*>-0.0534*";
foreach (Match myMatch in myRegex.Matches(strTargetString))
{
if (myMatch.Success)
{
// Add your code here
}
}

Search string using Pattern within long string in C#

I need to search for a pattern within a string.
For eg:
string big = "Hello there, I need information for ticket XYZ12345. I also submitted ticket ZYX54321. Please update.";
Now I need to extract/find/seek words based on the pattern XXX00000 i.e. 3 ALPHA and than 5 numeric.
Is there any way to do this ?
Even extraction will be okay for me.
Please help.

foreach (Match m in Regex.Matches(big, "([A-Za-z]{3}[0-9]{5})"))
{
if (m.Success)
{
m.Groups[1].Value // -- here is your match
}
}

How about this one?
([XYZ]{3}[0-9]{5})
You can use Regex Tester to test your expressions.

You can use simple regular expression to match your following string
([A-Za-z]{3}[0-9]{5})
the full code will be:
string strRegex = #"([A-Za-z]{3}[0-9]{5})";
Regex myRegex = new Regex(strRegex, RegexOptions.IgnoreCase);
string strTargetString = #"Hello there, I need information for ticket XYZ12345. I also submitted ticket ZYX54321. Please update.";
foreach (Match myMatch in myRegex.Matches(strTargetString))
{
if (myMatch.Success)
{
// Add your code here
}
}

You could always use a chatbot extension for the requests.
as for extracting the required information out of a sentence without any context
you can use regex for that.
you can use http://rubular.com/ to test it,
an example would be
...[0-9]
that would find XXX00000
hope that helped.

Use a regex:
string ticketNumber = string.Empty;
var match = Regex.Match(myString,#"[A-Za-z]{3}\d{5}");
if(match.Success)
{
ticketNumber = match.Value;
}

Here's a regex:
var str = "ABCD12345 ABC123456 ABC12345 XYZ98765";
foreach (Match m in Regex.Matches(str, #"(?<![A-Z])[A-Z]{3}[0-9]{5}(?![0-9])"))
Console.WriteLine(m.Value);
The extra bits are the zero-width negative look-behind ((?<![A-Z])) and look-ahead ((?![0-9])) expressions to make sure you don't capture extra numbers or letters. The above example only catches the third and fourth parts, but not the first and second. A simple [A-Z]{3}[0-9]{5} catches at least the specified number of characters, or more.