I need to search for a pattern within a string.
For eg:
string big = "Hello there, I need information for ticket XYZ12345. I also submitted ticket ZYX54321. Please update.";
Now I need to extract/find/seek words based on the pattern XXX00000 i.e. 3 ALPHA and than 5 numeric.
Is there any way to do this ?
Even extraction will be okay for me.
Please help.
foreach (Match m in Regex.Matches(big, "([A-Za-z]{3}[0-9]{5})"))
{
if (m.Success)
{
m.Groups[1].Value // -- here is your match
}
}
How about this one?
([XYZ]{3}[0-9]{5})
You can use Regex Tester to test your expressions.
You can use simple regular expression to match your following string
([A-Za-z]{3}[0-9]{5})
the full code will be:
string strRegex = #"([A-Za-z]{3}[0-9]{5})";
Regex myRegex = new Regex(strRegex, RegexOptions.IgnoreCase);
string strTargetString = #"Hello there, I need information for ticket XYZ12345. I also submitted ticket ZYX54321. Please update.";
foreach (Match myMatch in myRegex.Matches(strTargetString))
{
if (myMatch.Success)
{
// Add your code here
}
}
You could always use a chatbot extension for the requests.
as for extracting the required information out of a sentence without any context
you can use regex for that.
you can use http://rubular.com/ to test it,
an example would be
...[0-9]
that would find XXX00000
hope that helped.
Use a regex:
string ticketNumber = string.Empty;
var match = Regex.Match(myString,#"[A-Za-z]{3}\d{5}");
if(match.Success)
{
ticketNumber = match.Value;
}
Here's a regex:
var str = "ABCD12345 ABC123456 ABC12345 XYZ98765";
foreach (Match m in Regex.Matches(str, #"(?<![A-Z])[A-Z]{3}[0-9]{5}(?![0-9])"))
Console.WriteLine(m.Value);
The extra bits are the zero-width negative look-behind ((?<![A-Z])) and look-ahead ((?![0-9])) expressions to make sure you don't capture extra numbers or letters. The above example only catches the third and fourth parts, but not the first and second. A simple [A-Z]{3}[0-9]{5} catches at least the specified number of characters, or more.
Related
I have string like
"Augustin Ralf (050288)"
"45 Max Müller (4563)"
"Hans (Adam) Meider (056754)"
I am searching for a regex to extract the last part in the brackets, for example this results for the strings above:
"050288"
"4563"
"056754"
I have tried with
var match = Regex.Match(string, #".*(\(\d*\))");
But I get also the brackets with the result. Is there a way to extract the strings and get it without the brackets?
Taking your requirements precisely, you are looking for
\(([^()]+)\)$
This will capture anything between the parentheses (not nested!), may it be digits or anything else and anchors them to the end of the string. If you happen to have whitespace at the end, use
\(([^()]+)\)\s*$
In C# this could be
using System;
using System.Text.RegularExpressions;
public class Example
{
public static void Main()
{
string pattern = #"\(([^()]+)\)$";
string input = #"Augustin Ralf (050288)
45 Max Müller (4563)
Hans (Adam) Meider (056754)
";
RegexOptions options = RegexOptions.Multiline;
foreach (Match m in Regex.Matches(input, pattern, options))
{
Console.WriteLine("'{0}' found at index {1}.", m.Value, m.Index);
}
}
}
See a demo on regex101.com.
please use regex - \(([^)]*)\)[^(]*$. This is working as expected. I have tested here
You can extract the number between the parantheses without worring about extracting the capturing groups with following regex.
(?<=\()\d+(?=\)$)
demo
Explanation:
(?<=\() : positive look behind for ( meaning that match will start after a ( without capturing it to the result.
\d+ : captures all digits in a row until non digit character found
(?=\)$) : positive look ahead for ) with line end meaning that match will end before a ) with line ending without capturing ) and line ending to the result.
Edit: If the number can be within parantheses that is not at the end of the line, remove $ from the regex to fix the match.
var match = Regex.Match(string, #".*\((\d*)\)");
https://regex101.com/r/Wk9asY/1
Here are three options for you.
The first one uses the simplest pattern and in addition the Trim method.
The second one uses capturing the desired value to the group and then getting it from the group.
The third one uses Lookbehind and Lookahead.
var inputs = new string[] {
"Augustin Ralf (050288)", "45 Max Müller (4563)", "Hans (Adam) Meider (056754)"
};
foreach (var input in inputs)
{
var match = Regex.Match(input, #"\(\d+\)");
Console.WriteLine(match.Value.Trim('(', ')'));
}
Console.WriteLine();
foreach (var input in inputs)
{
var match = Regex.Match(input, #"\((\d+)\)");
Console.WriteLine(match.Groups[1]);
}
Console.WriteLine();
foreach (var input in inputs)
{
var match = Regex.Match(input, #"(?<=\()\d+(?=\))");
Console.WriteLine(match.Value);
}
Console.WriteLine();
I'm trying to find all instances of the substring EnemyType('XXXX') where XXXX is an arbitrary string and the instasnce of EnemyType('XXXX') can appear multiple times.
Right now I'm using a consortium of index of/substring functions in C# but would like to know if there's a cleaner way of doing it?
Use regex. Example:
using System.Text.RegularExpressions;
var inputString = " EnemyType('1234')abcdeEnemyType('5678')xyz";
var regex = new Regex(#"EnemyType\('\d{4}'\)");
var matches = regex.Matches(inputString);
foreach (Match i in matches)
{
Console.WriteLine(i.Value);
}
It will print:
EnemyType('1234')
EnemyType('5678')
The pattern to match is #"EnemyType\('\d{4}'\)", where \d{4} means 4 numeric characters (0-9). The parentheses are escaped with backslash.
Edit: Since you only want the string inside quotes, not the whole string, you can use named groups instead.
var inputString = " EnemyType('1234')abcdeEnemyType('5678')xyz";
var regex = new Regex(#"EnemyType\('(?<id>[^']+)'\)");
var matches = regex.Matches(inputString);
foreach (Match i in matches)
{
Console.WriteLine(i.Groups["id"].Value);
}
Now it prints:
1234
5678
Regex is a really nice tool for parsing strings. If you often parse strings, regex can make life so much easier.
I need a little help regarding Regular Expressions in C#
I have the following string
"[[Sender.Name]]\r[[Sender.AdditionalInfo]]\r[[Sender.Street]]\r[[Sender.ZipCode]] [[Sender.Location]]\r[[Sender.Country]]\r"
The string could also contain spaces and theoretically any other characters. So I really need do match the [[words]].
What I need is a text array like this
"[[Sender.Name]]",
"[[Sender.AdditionalInfo]]",
"[[Sender.Street]]",
// ... And so on.
I'm pretty sure that this is perfectly doable with:
var stringArray = Regex.Split(line, #"\[\[+\]\]")
I'm just too stupid to find the correct Regex for the Regex.Split() call.
Anyone here that can tell me the correct Regular Expression to use in my case?
As you can tell I'm not that experienced with RegEx :)
Why dont you split according to "\r"?
and you dont need regex for that just use the standard string function
string[] delimiters = {#"\r"};
string[] split = line.Split(delimiters,StringSplitOptions.None);
Do matching if you want to get the [[..]] block.
Regex rgx = new Regex(#"\[\[.*?\]\]");
foreach (Match m in rgx.Matches(input))
Console.WriteLine(m.Groups[0].Value);
IDEONE
The regex you are using (\[\[+\]\]) will capture: literal [s 2 or more, then 2 literal ]s.
A regex solution is capturing all the non-[s inside doubled [ and ]s (and the string inside the brackets should not be empty, I guess?), and cast MatchCollection to a list or array (here is an example with a list):
var str = "[[Sender.Name]]\r[[Sender.AdditionalInfo]]\r[[Sender.Street]]\r[[Sender.ZipCode]] [[Sender.Location]]\r[[Sender.Country]]\r";
var rgx22 = new Regex(#"\[\[[^]]+?\]\]");
var res345 = rgx22.Matches(str).Cast<Match>().ToList();
Output:
Well, I don't know how to explain that exactly, but I have this text:
abc=0;def=2;abc=1;ghi=4;jkl=2
The thing I want to do is select abc=0 and abc=1 but excluding abc part...
My regex is: abc=\d+, but it includes abc part...
I readed something about this, and the answer was this: (?!abc=)\d+ but It select all the numbers inside the text...
So, can somebody help me with this?
Thanks in advance.
If your language supports \K then you could use the below regex to matche the number which was just after to the string abc=,
abc=\K\d+
DEMO
OR
use a positive look-behind if your language didn't support \K,
(?<=abc=)\d+
DEMO
C# code would be,
{
string str = "abc=0;def=2;abc=1;ghi=4;jkl=2";
Regex rgx = new Regex(#"(?<=abc=)\d+");
foreach (Match m in rgx.Matches(str))
Console.WriteLine(m.Value);
}
IDEONE
Explanation:
(?<=abc=) Positive lookbehind which actually sets the matching marker just after to the string abc=.
\d+ Matches one or more digits.
You don't need a lookaround assertion here. You can simply use a capturing group to capture the matched context that you want and refer back to the matched group using the Match.Groups Property.
abc=(\d+)
Example:
string s = "abc=0;def=2;abc=1;ghi=4;jkl=2";
foreach (Match m in Regex.Matches(s, #"abc=(\d+)"))
Console.WriteLine(m.Groups[1].Value);
Output
0
1
Couldn't find better title but i need a Regex to extract link from sample below.
snip... flashvars.image_url = 'http://domain.com/test.jpg' ..snip
assuming regex is the best way.
thanks
Consider the following sample code. It shows how one might extract from your supplied string. But I have expanded upon the string some. Generally, the use of .* is too all inclusive (as the example below demonstrates).
The main point, is there are several ways to do what you are asking, the first answer given uses "look-around" while the second suggests the "Groups" approach. The choice mainly depend upon your actual data.
string[] tests = {
#"snip... flashvars.image_url = 'http://domain.com/test.jpg' ..snip",
#"snip... flashvars.image_url = 'http://domain.com/test.jpg' flashvars2.image_url = 'http://someother.domain.com/test.jpg'",
};
string[] patterns = {
#"(?<==\s')[^']*(?=')",
#"=\s*'(.*)'",
#"=\s*'([^']*)'",
};
foreach (string pattern in patterns)
{
Console.WriteLine();
foreach (string test in tests)
foreach (Match m in Regex.Matches(test, pattern))
{
if (m.Groups.Count > 1)
Console.WriteLine("{0}", m.Groups[1].Value);
else
Console.WriteLine("{0}", m.Value);
}
}
A simple regex for this would be #"=\s*'(.*)'".
Edit: New regex matching your edited question:
You need to match what's between quotes, after a =, right?
#"(?<==\s*')[^']*(?=')"
should do.
(?<==\s*') asserts that there is a =, optionally followed by whitespace, followed by a ', just before our current position (positive lookbehind).
[^']* matches any number of non-' characters.
(?=') asserts that the match stops before the next '.
This regex doesn't check if there is indeed a URL inside those quotes. If you want to do that, use
#"(?<==\s*')(?=(?:https?|ftp|mailto)\b)[^']*(?=')"