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Extract string from a pattern preceded by any length

I'm looking for a regular expression to extract a string from a file name
eg if filename format is "anythingatallanylength_123_TESTNAME.docx", I'm interested in extracting "TESTNAME" ... probably fixed length of 8. (btw, 123 can be any three digit number)
I think I can use regex match ...
".*_[0-9][0-9][0-9]_[A-Z][A-Z][A-Z][A-Z][A-Z][A-Z][A-Z][A-Z].docx$"
However this matches the whole thing. How can I just get "TESTNAME"?
Thanks

Use parenthesis to match a specific piece of the whole regex.
You can also use the curly braces to specify counts of matching characters, and \d for [0-9].
In C#:
var myRegex = new Regex(#"*._\d{3}_([A-Za-z]{8})\.docx$");
Now "TESTNAME" or whatever your 8 letter piece is will be found in the captures collection of your regex after using it.
Also note, there will be a performance overhead for look-ahead and look-behind, as presented in some other solutions.

You can use a look-behind and a look-ahead to check parts without matching them:
(?<=_[0-9]{3}_)[A-Z]{8}(?=\.docx$)
Note that this is case-sensitive, you may want to use other character classes and/or quantifiers to fit your exact pattern.

In your file name format "anythingatallanylength_123_TESTNAME.docx", the pattern you are trying to match is a string before .docx and the underscore _. Keeping the thing in mind that any _ before doesn't get matched I came up with following solution.
Regex: (?<=_)[A-Za-z]*(?=\.docx$)
Flags used:
g global search
m multi-line search.
Explanation:
(?<=_) checks if there is an underscore before the file name.
(?=\.docx$) checks for extension at the end.
[A-Za-z]* checks the required match.
Regex101 Demo

Thanks to #Lucero #noob #JamesFaix I came up with ...
#"(?<=.*[0-9]{3})[A-Z]{8}(?=.docx$)"
So a look behind (in brackets, starting with ?<=) for anything (ie zero or more any char (denoted by "." ) followed by an underscore, followed by thee numerics, followed by underscore. Thats the end of the look behind. Now to match what I need (eight letters). Finally, the look ahead (in brackets, starting with ?=), which is the .docx
Nice work, fellas. Thunderbirds are go.

Regex.Split command in c#

I am trying to use Regex.SPlit to split a a string in order to keep all of its contents, including the delimiters i use. The string is a math problem. For example, 5+9/2*1-1. I have it working if the string contains a + sign but I don't know how to add more then one to the delimiter list. I have looked online at multiple pages but everything I try gives me errors. Here is the code for the Regex.Split line I have: (It works for the plus, Now i need it to also do -,*, and /.
string[] everything = Regex.Split(inputBox.Text, #"(\+)");

Use a character class to match any of the math operations: [*/+-]
string input = "5+9/2*1-1";
string pattern = #"([*/+-])";
string[] result = Regex.Split(input, pattern);
Be aware that character classes allow ranges, such as [0-9], which matches any digit from 0 up to 9. Therefore, to avoid accidental ranges, you can escape the - or place it at either the beginning or end of the character class.

Regex - Get all words that are not wrapped with a "/"

Im really trying to learn regex so here it goes.
I would really like to get all words in a string which do not have a "/" on either side.
For example, I need to do this to:
"Hello Great /World/"
I need to have the results:
"Hello"
"Great"
is this possible in regex, if so, how do I do it? I think i would like the results to be stored in a string array :)
Thank you

Just use this regular expression \b(?<!/)\w+(?!/)\b:
var str = "Hello Great /World/ /I/ am great too";
var words = Regex.Matches(str, #"\b(?<!/)\w+(?!/)\b")
.Cast<Match>()
.Select(m=>m.Value)
.ToArray();
This will get you:
Hello
Great
am
great
too

var newstr = Regex.Replace("Hello Great /World/", #"/(\w+?)/", "");
If you realy want an array of strings
var words = Regex.Matches(newstr, #"\w+")
.Cast<Match>()
.Select(m => m.Value)
.ToArray();

I would first split the string into the array, then filter out matching words. This solution might also be cleaner than a big regexp, because you can spot the requirements for "word" and the filter better.
The big regexp solution would be something like word boundary - not a slash - many no-whitespaces - not a slash - word boundary.

I would use a regex replace to replace all /[a-zA-Z]/ with '' (nothing) then get all words

Try this one : (Click here for a demo)
(\s(?<!/)([A-Za-z]+)(?!/))|((?<!/)([A-Za-z]+)(?!/)\s)

Using this example excerpt:
The /character/ "_" (underscore/under-strike) can be /used/ in /variable/ names /in/ many /programming/ /languages/, while the /character/ "/" (slash/stroke/solidus) is typically not allowed.
...this expression matches any string of letters, numbers, underscores, or apostrophes (fairly typical idea of a "word" in English) that does not have a / character both before and after it - wrapped with a "/"
\b([\w']+)\b(?<=(?<!/)\1|\1(?!/))
...and is the purest form, using only one character class to define "word" characters. It matches the example as follows:
Matched Not Matched
------------- -------------
The character
_ used
underscore variable
under in
strike programming
can languages
be character
in stroke
names
many
while
the
slash
solidus
is
typically
not
allowed
If excluding /stroke/, is not desired, then adding a bit to the end limitation will allow it, depending upon how you want to define the beginning of a "next" word:
\b([\w']+)\b(?<=(?<!/)\1|\1(?!/([^\w]))).
changes (?!/) to (?!/([^\w])), which allows /something/ if it does have a letter, number, or underscore immediately after it. This would move stroke from the "Not Matched" to the "Matched" list, above.
note: \w matches uppercase or lowercase letters, numbers and the underscore character
If you want to alter your concept for "word" from the above, simply exchange the characters and shorthand character classes contained in the [\w'] part of the expression to something like [a-zA-Z'] to exclude digits or [\w'-] to include hyphens, which would capture under-strike as a single match, rather than two separate matches:
\b([\w'-]+)\b(?<=(?<!/)\1|\1(?!/([^\w])))
IMPORTANT ALTERNATIVE!!! (I think)
I just thought of an alternative to Matching any words that are not wrapped with / symbols: simply consume all of these symbols and words that are surrounded in them (splitting). This has a few benefits: no lookaround means this could be used in more contexts (JavaScript does not support lookbehind and some flavors of regex don't support lookaround at all) while increasing efficiency; also, using a split expression means a direct result of a String array:
string input = "The /character/ "_" (underscore/under-strike) can be..."; //etc...
string[] resultsArray = Regex.Split(input, #"([^\w'-]+?(/[\w]+/)?)+");
voila!

Regex Word splitting in C#

I know similar questions have been asked before, but I can't find one that is like mine, or enough like mine to help me out :). So essentially I want to split up a string which contains a bunch of words, and I don't want to return any characters that are not words (this is the key problem I am struggling with, ignoring characters). This is how I define the problem:
What constitutes a word is a string of any character a-zA-Z only
(no numbers or anything else)
In between any word, there can be any number of random other characters
I want to get back a string[] containing only the words
eg: text: "apple^&**^orange1247pear"
I want to return: apple, orange, pear in an array.
The closest I have found I suppose is this:
Regex.Split("apple^orange7pear",#"([a-zA-Z]*)")
Which splits out the apple/orange/pear, but also returns a bunch of other junk and blank strings.
Anyone know how to stop the split function from returning certain parts of the string, or is that not possible?
Thanks in advance for any help you give me :)

Split should match the tokens between your words. In your regex you've added a group around the word, so it is included in the result, but that isn't desired in this case. Note that this regex matches anything besides valid words - anything that isn't an ASCII letter:
string[] words = Regex.Split(str, "[^a-zA-Z]+");
Another option is to match the words directly:
MatchCollection matches = Regex.Matches(str, "[a-zA-Z]+");
string[] words2 = matches.Cast<Match>().Select(m => m.Value).ToArray();
The second option is probably clearer, and will not include blank elements on the start or end of the array.

var splits = Regex.Split("aaa $$$bbb ccc", #"[^A-Za-z]+");
But to include non-latin letters, I would use this:
var splits = Regex.Split("aaa $$$bbb ccc", #"\P{L}+");

Try this:
Regex.Matches("kalle kula(/()&//()nisse8978971", #"[A-Za-z]+")
Using Matches() will collect only the words, Split() will divide the string which is not what you want.

The second option Kobi listed is better and easier to control. I use the following regular expression to locate common entities such as words, numbers, email addresses in a string it will.
var regex = new Regex(#"[\p{L}\p{N}\p{M}]+(?:[-.'´_#][\p{L}|\p{N}|\p{M}]+)*", RegexOptions.Compiled);

C# reliable way to pattern match?

At the moment I am trying to match patterns such as
text text date1 date2
So I have regular expressions that do just that. However, the issue is for example if users input data with say more than 1 whitespace or if they put some of the text in a new line etc the pattern does not get picked up because it doesn't exactly match the pattern set.
Is there a more reliable way for pattern matching? The goal is to make it very simple for the user to write but make it easily matchable on my end. I was considering stripping out all the whitespace/newlines etc and then trying to match the pattern with no spaces i.e. texttextdate1date2.
Anyone got any better solutions?
Update
Here is a small example of the pattern I would need to match:
FIND me#test.com 01/01/2010 to 10/01/2010
Here is my current regex:
FIND [A-Z0-9._%+-]+#[A-Z0-9.-]+\.[A-Z]{2,4} [0-9]{1,2}/[0-9]{1,2}/[0-9]{2,4} to [0-9]{1,2}/[0-9]{1,2}/[0-9]{2,4}
This works fine 90% of the time, however, if users submit this information via email it can have all different kinds of formatting and HTML I am not interested in. I am using a combination of the HtmlAgilityPack and a HTML tag removing regex to strip all the HTML from the email, but even at that I can't seem to get a match on some occassions.
I believe this could be a more parsing related question than pattern matching, but I think maybe there is a better way of doing this...

To match at least one or more whitespace characters (space, tab, newline), use:
\s+
Substitute the above wherever you have the physical space in your pattern and you should be fine.

Example of matching multiple groups in a text with multiple whitespaces and/or newlines.
var txt = "text text date1\ndate2";
var matches = Regex.Match(txt, #"([a-z]+)\s+([a-z]+)\s+([a-z0-9]+)\s+([a-z0-9]+)", RegexOptions.Singleline);
matches.Groups[n].Value with n from 1 to 4 will contain your matches.

I would split the string into a string array and match each resulting string to the necessary Regular Expression.

\b(text)[\s]+(text)[\s]+(date1)[\s]+(date2)\b

Its a nasty expression but here is something that will work for the input you provided:
^(\w+)\s+([\w#.]+)\s+(\d{2}\/\d{2}\/\d{4})[^\d]+(\d{2}\/\d{2}\/\d{4})$
This will work with variable amounts of whitespace between the capture groups as well.

Through ORegex you can tokenize your string and just pattern match on token sequences:
var tokens = input.Split(new[]{' ','\t','\n','\r'}, StringSplitOptions.RemoveEmptyEntries);
var oregex = new ORegex<string>("{0}{0}{1}{1}", IsText, IsDate);
var matches = oregex.Matches(tokens); //here is your subsequence tokens.
...
public bool IsText(string str)
{
...
}
public bool IsDate(string str)
{
...
}