The following is the XML file read into XmlDocument
<Test xmlns="http://api.test.com/v2" xmlns:i="http://www.w3.org/2001/XMLSchema-instance">
<Result id="2015" description="Invalid Token" />
</Test >
What I need is the 'id' attribute value ("2015") stored in some TextBox
This is how XmlDocument is loaded
XmlDocument updateUser = new XmlDocument();
updateUser.Load(response.GetResponseStream());
Works well till here.
Then, create namespace and search for node
XmlNamespaceManager nsmgr = new XmlNamespaceManager(updateUser.NameTable);
nsmgr.AddNamespace("restup", "http://api.test.com/v2");
XmlNodeList locationElements1 = updateUser.SelectNodes("//restup:Test", nsmgr);
foreach (XmlNode Test in locationElements1)
{
//What DO I do here to get the value of 'id' attribute from the 'Result' node and save it in txtTest Textbox.
}
var id = Test.FirstChild.Attributes["id"].Value;
string idString = Test.FirstChild.Attributes["id"].ToString();
hello this is another method that can be useful
XmlTextReader reader = new XmlTextReader(fileLocation); //fileLocation is the Path of the XML file
while (reader.Read())
{
if (reader.NodeType == XmlNodeType.Element) //if the node is an element (not a comment, CDATA, or text)
if (reader.Name == "Result")
textBox1.Text = reader.GetAttribute("id");
}
reader.Close();
Related
hey guys I had XML file and I was using XDocument to write on it and using the next void remove the namespace
string path = Server.MapPath(xmlpath);
XDocument doc = XDocument.Load(path)
XElement root = new XElement("url");
foreach (var node in doc.Root.Descendants()
.Where(n => n.Name.NamespaceName == ""))
{
node.Attributes("xmlns").Remove();
node.Name = node.Parent.Name.Namespace + node.Name.LocalName;
}
this function works 100% with the XDocument now I changed
XDocument oldDoc = XDocument.Load(path);// the old doucument
XmlDocument newDoc = new XmlDocument();//the new document
I need a function that allows me to make loping and remove the namespace xmlns from my nodes the same one like above thanks a lot for your time's guys and thanks a lot for reading my question
You were very close, just had to use XMLDocument.CreateElement(string Name) overload which returns a XMLNode and then use .InnerText property to set your value
var mainRoot = doc.DocumentElement; //urlset element
var urlRoot = doc.CreateElement("url"); //create url element
var VidooTree = urlRoot.AppendChild(doc.CreateElement(a, ""));
urlRoot.AppendChild(doc.CreateElement("loc", "http:/domain/site.com"));
VidooTree.AppendChild(doc.CreateElement(b)).InnerText="imgur";
VidooTree.AppendChild(doc.CreateElement(c)).InnerText= "videoTitle";
VidooTree.AppendChild(doc.CreateElement("video:description")).InnerText= "videoDec";
VidooTree.AppendChild(doc.CreateElement(d)).InnerText= "VideoApi";
VidooTree.AppendChild(doc.CreateElement(m)).InnerText= "duration";
VidooTree.AppendChild(doc.CreateElement(nn)).InnerText= "2050-11-05T19:20:30+08:00";
VidooTree.AppendChild(doc.CreateElement(e)).InnerText= "watched";
VidooTree.AppendChild(doc.CreateElement(k)).InnerText= "date";
VidooTree.AppendChild(doc.CreateElement(f)).InnerText= "yes";
VidooTree.AppendChild(doc.CreateElement(g)).InnerText="No";
VidooTree.AppendChild(doc.CreateElement(h)).InnerText= "VideoKindName";
urlRoot.AppendChild(VidooTree);
mainRoot.AppendChild(urlRoot);
Output
<url xmlns="">
<loc xmlns="http:/domain/site.com" />
<video>
<thumbnail_loc>imgur</thumbnail_loc>
<title>videoTitle</title>
<description>videoDec</description>
<content_loc>VideoApi</content_loc>
<duration>duration</duration>
<expiration_date>2050-11-05T19:20:30+08:00</expiration_date>
<view_count>watched</view_count>
<publication_date>date</publication_date>
<family_friendly>yes</family_friendly>
<live>No</live>
<category>VideoKindName</category>
</video>
</url>
I am working on this since yesterday. I have an XML file which looks something like this
<catalog>
<captureInfo>
<row>5</row>
<col>5</col>
</captureInfo>
<patientInfo>
<name>XYZ</name>
<detail>details here</detail>
</patientInfo>
<imageData>
<r0c0>
<contrastFlag>true</contrastFlag>
</r0c0>
<r0c1>
<contrastFlag>true</contrastFlag>
</r0c1>
</imageData>
</catalog>
I need to update the value of contrastFlag in the XML file. This is the code I have written:
XmlDocument doc = new XmlDocument();
XmlNodeList imageData = doc.GetElementsByTagName("imageData");
foreach(XmlNode node in imageData)
{
foreach (XmlNode innernode in node)
{
if (innernode.Name == "r0c0")
{
innernode.InnerText = "false";
}
}
}
doc.Save("XMLFile1.xml");
Can anyone tell me where am I going wrong and also is there any better/faster approach for this?
Well first off, your XML is malformed, the closing should match "catalog". Why not just do this:
string xml = #"<catalog>
<captureInfo>
<row>5</row>
<col>5</col>
</captureInfo>
<patientInfo>
<name>XYZ</name>
<detail>details here</detail>
</patientInfo>
<imageData>
<r0c0>
<contrastFlag>true</contrastFlag>
</r0c0>
<r0c1>
<contrastFlag>true</contrastFlag>
</r0c1>
</imageData>
</catalog>";
XmlDocument xdoc = new XmlDocument();
xdoc.LoadXml(xml);
xdoc.SelectSingleNode("//catalog/imageData/r0c0/contrastFlag").InnerText = "false";
Here is a way to replace all of the instances using LINQ. I just wrote out to a new file to preserve the source.
StreamReader stream = new StreamReader(#"c:\test.xml");
XDocument doc = XDocument.Load(stream);
IEnumerable<XElement> flags = doc.Descendants("contrastFlag");
foreach (XElement e in flags)
{
e.Value = "false";
}
doc.Save(#"c:\test2.xml");
Please, Help me Out Here
I Want to display the value of "email" from xml. my syntax works for now but it displays every value. i want to be able to display Individual (one) Values like
email: mail#mail.com
My scripts
var xml ="<?xml version='1.0' encoding='UTF-8'?>
<MemResponse>
<Phone>2554535</Phone>
<Email>mail#mail</Email>
<Number>we75546654</Number>
</MemResponse>";
XmlDocument doc = new XmlDocument();
doc.LoadXml(xml);
foreach(XmlNode n in doc.DocumentElement)
{
string q = n.FirstChild.InnerText;
Response.Write(q);
}
Simply you can select all element by tag name by GetElementsByTagName method.
Check this :
XmlDocument doc = new XmlDocument();
doc.LoadXml(xml);
var myEmails = doc.GetElementsByTagName("Email");
foreach (XmlNode mail in myEmails)
{
string mailText = mail.FirstChild.InnerText;
Response.Write(mailText);
}
I have got it from MSDN
Your code goes through each node and writes the contents of that node.
It seems like you want to match on the node name, and only write the value if its name is "email".
If thats the case, inside of your for each, try something like:
if(n.Name == "Email") {
string q = n.FirstChild.InnerText;
Response.Write(q);
}
Alternatively, you could just use a node list.
NodeList nl = doc.GetElementsByTagName("Email");
And write that.
When loading your XML Doc, use :
HttpWebRequest request = WebRequest.Create(requestUrl) as HttpWebRequest;
HttpWebResponse response = request.GetResponse() as HttpWebResponse;
XmlDocument xmlDoc = new XmlDocument();
xmlDoc.Load(response.GetResponseStream());
Please try this code:
XmlDocument doc = new XmlDocument();
doc.LoadXml("YOUR_XML_PATH");
XmlNodeList email_hd= doc.GetElementsByTagName("Email");
string email=email_hd[0].InnerText;
I have the xml below in a c# class.
string xml =#"<?xml version='1.0' encoding='UTF-8'?>
<call method='importCube'>
<credentials login='sampleuser#company.com' password='my_pwd' instanceCode='INSTANCE1'/>
<importDataOptions version='Plan' allowParallel='false' moveBPtr='false'/>
I need to update the XML held within the node attributes i.e.
string xml =#"<?xml version='1.0' encoding='UTF-8'?>
<call method='importCube'>
<credentials login='testuser#test.com' password='userpassword' instanceCode='userinstance'/>
<importDataOptions version='Actual' allowParallel='true' moveBPtr='true'/>
I've written code to do this :
// instantiate XmlDocument and load XML from string
XmlDocument doc = new XmlDocument();
doc.LoadXml(xml);
// get a list of nodes
XmlNodeList aNodes = doc.SelectNodes("/call/credentials");
// loop through all nodes
foreach (XmlNode aNode in aNodes)
{
// grab the attribute
XmlAttribute idLogin = aNode.Attributes["login"];
XmlAttribute idPass = aNode.Attributes["password"];
XmlAttribute idInstance = aNode.Attributes["instanceCode"];
idLogin.Value = "myemail.com";
idPass.Value = "passtest";
idInstance.Value = "TestInstance";
}
It works but the issue at the minute is that I have to repeat the whole code block for each node path i.e.
XmlNodeList aNodes = doc.SelectNodes("/call/importDataOptions");
....
There has to be a better way. Any ideas how I can rip through the attributes in 1 pass?
Maybe just using a cast to XmlElement could help you to reduce your code:
XmlDocument doc = new XmlDocument();
doc.LoadXml(xml);
foreach (XmlElement credential in doc.SelectNodes("/call/credentials"))
{
credential.SetAttribute("login" , "myemail.com" );
credential.SetAttribute("password" , "passtest" );
credential.SetAttribute("instanceCode", "TestInstance");
}
Another option is to create an object structure which resembles your XML vocabulary and deserialize your input into that objects, but it seems overkill.
EDIT: Per your comment, you could go with:
foreach (XmlElement node in doc.SelectNodes("/call/*")) // it's case sensitive
{
switch(node.Name)
{
case "credentials":
node.SetAttribute("login" , "myemail.com" );
node.SetAttribute("password" , "passtest" );
node.SetAttribute("instanceCode", "TestInstance");
break;
case "importDataOptions":
// ...
break;
default:
throw new ArgumentOutOfRangeException("Unexpected node: "+node.Name);
}
}
I am trying to read the following file, I can read the attributes, but I can't go into the specific element (Address in this case) and read its elements based on the attribute of that (Address) element. Shortly I need to distinguish between work and home addresses. I need to do this with XMLReader class. Can you help?
<Address Label="Work">
<Name>Name1</Name>
<Street>PO 1</Street>
<City>City1</City>
<State>State 1</State>
</Address>
<Address Label="Home">
<Name>Name2</Name>
<Street>PO 2</Street>
<City>City2</City>
<State>State 2</State>
</Address>"
Okay, here are some notes to think about. XMLReader in the sense i understand you use it (with no code example) is that you iterate over the document, since the XMLReader is forward-only, and read-only.
Because of this you need to iterate until you find the node you need. In the example below i find the address element labeled "work" and extract that entire node. Then query on this node as you want.
using (var inFile = new FileStream(path, FileMode.Open))
{
using (var reader = new XmlTextReader(inFile))
{
while (reader.Read())
{
switch (reader.NodeType)
{
case XmlNodeType.Element:
if (reader.Name == "Address" && reader.GetAttribute(0) == "Work")
{
// Create a document, which will contain the address element as the root
var doc = new XmlDocument();
// Create a reader, which only will read the substree <Address> ... until ... </Address>
doc.Load(reader.ReadSubtree());
// Use XPath to query the nodes, here the "Name" node
var name = doc.SelectSingleNode("//Address/Name");
// Print node name and the inner text of the node
Console.WriteLine("Node: {0}, Inner text: {1}", name.Name, name.InnerText);
}
break;
}
}
}
}
Edit
Made an example that not uses LINQ
XML:
<Countries>
<Country name ="ANDORRA">
<state>Andorra (general)</state>
<state>Andorra</state>
</Country>
<Country name ="United Arab Emirates">
<state>Abu Z¸aby</state>
<state>Umm al Qaywayn</state>
</Country>
Java:
public void datass(string file)
{
string file = HttpContext.Current.Server.MapPath("~/App_Data/CS.xml");
XmlDocument doc = new XmlDocument();
if (System.IO.File.Exists(file))
{
//Load the XML File
doc.Load(file);
}
//Get the root element
XmlElement root = doc.DocumentElement;
XmlNodeList subroot = root.SelectNodes("Country");
for (int i = 0; i < subroot.Count; i++)
{
XmlNode elem = subroot.Item(i);
string attrVal = elem.Attributes["name"].Value;
Response.Write(attrVal);
XmlNodeList sub = elem.SelectNodes("state");
for (int j = 0; j < sub.Count; j++)
{
XmlNode elem1 = sub.Item(j);
Response.Write(elem1.InnerText);
}
}
}
Using XPath you can easily write concise expressions to navigate an XML document.
You would do something like
XmlDocument xDoc = new XmlDocument();
xDoc.LoadXml(myXMLString);
XmlNode homeAddress = xDoc.SelectSingleNode("//Address[#Label='Work']");
Then do whatever you want with homeAddress.
Read more here on w3schools on XPath.