I have the xml below in a c# class.
string xml =#"<?xml version='1.0' encoding='UTF-8'?>
<call method='importCube'>
<credentials login='sampleuser#company.com' password='my_pwd' instanceCode='INSTANCE1'/>
<importDataOptions version='Plan' allowParallel='false' moveBPtr='false'/>
I need to update the XML held within the node attributes i.e.
string xml =#"<?xml version='1.0' encoding='UTF-8'?>
<call method='importCube'>
<credentials login='testuser#test.com' password='userpassword' instanceCode='userinstance'/>
<importDataOptions version='Actual' allowParallel='true' moveBPtr='true'/>
I've written code to do this :
// instantiate XmlDocument and load XML from string
XmlDocument doc = new XmlDocument();
doc.LoadXml(xml);
// get a list of nodes
XmlNodeList aNodes = doc.SelectNodes("/call/credentials");
// loop through all nodes
foreach (XmlNode aNode in aNodes)
{
// grab the attribute
XmlAttribute idLogin = aNode.Attributes["login"];
XmlAttribute idPass = aNode.Attributes["password"];
XmlAttribute idInstance = aNode.Attributes["instanceCode"];
idLogin.Value = "myemail.com";
idPass.Value = "passtest";
idInstance.Value = "TestInstance";
}
It works but the issue at the minute is that I have to repeat the whole code block for each node path i.e.
XmlNodeList aNodes = doc.SelectNodes("/call/importDataOptions");
....
There has to be a better way. Any ideas how I can rip through the attributes in 1 pass?
Maybe just using a cast to XmlElement could help you to reduce your code:
XmlDocument doc = new XmlDocument();
doc.LoadXml(xml);
foreach (XmlElement credential in doc.SelectNodes("/call/credentials"))
{
credential.SetAttribute("login" , "myemail.com" );
credential.SetAttribute("password" , "passtest" );
credential.SetAttribute("instanceCode", "TestInstance");
}
Another option is to create an object structure which resembles your XML vocabulary and deserialize your input into that objects, but it seems overkill.
EDIT: Per your comment, you could go with:
foreach (XmlElement node in doc.SelectNodes("/call/*")) // it's case sensitive
{
switch(node.Name)
{
case "credentials":
node.SetAttribute("login" , "myemail.com" );
node.SetAttribute("password" , "passtest" );
node.SetAttribute("instanceCode", "TestInstance");
break;
case "importDataOptions":
// ...
break;
default:
throw new ArgumentOutOfRangeException("Unexpected node: "+node.Name);
}
}
Related
I am working on this since yesterday. I have an XML file which looks something like this
<catalog>
<captureInfo>
<row>5</row>
<col>5</col>
</captureInfo>
<patientInfo>
<name>XYZ</name>
<detail>details here</detail>
</patientInfo>
<imageData>
<r0c0>
<contrastFlag>true</contrastFlag>
</r0c0>
<r0c1>
<contrastFlag>true</contrastFlag>
</r0c1>
</imageData>
</catalog>
I need to update the value of contrastFlag in the XML file. This is the code I have written:
XmlDocument doc = new XmlDocument();
XmlNodeList imageData = doc.GetElementsByTagName("imageData");
foreach(XmlNode node in imageData)
{
foreach (XmlNode innernode in node)
{
if (innernode.Name == "r0c0")
{
innernode.InnerText = "false";
}
}
}
doc.Save("XMLFile1.xml");
Can anyone tell me where am I going wrong and also is there any better/faster approach for this?
Well first off, your XML is malformed, the closing should match "catalog". Why not just do this:
string xml = #"<catalog>
<captureInfo>
<row>5</row>
<col>5</col>
</captureInfo>
<patientInfo>
<name>XYZ</name>
<detail>details here</detail>
</patientInfo>
<imageData>
<r0c0>
<contrastFlag>true</contrastFlag>
</r0c0>
<r0c1>
<contrastFlag>true</contrastFlag>
</r0c1>
</imageData>
</catalog>";
XmlDocument xdoc = new XmlDocument();
xdoc.LoadXml(xml);
xdoc.SelectSingleNode("//catalog/imageData/r0c0/contrastFlag").InnerText = "false";
Here is a way to replace all of the instances using LINQ. I just wrote out to a new file to preserve the source.
StreamReader stream = new StreamReader(#"c:\test.xml");
XDocument doc = XDocument.Load(stream);
IEnumerable<XElement> flags = doc.Descendants("contrastFlag");
foreach (XElement e in flags)
{
e.Value = "false";
}
doc.Save(#"c:\test2.xml");
I have xml file:
<?xml version="1.0" encoding="UTF-8" standalone="yes"?><SENT_110 xmlns:ns2="http://www.mf.gov.pl/SENT/2017/01/18/STypes.xsd" xmlns="http://www.mf.gov.pl/SENT/2017/01/18/SENT_110.xsd"><SentNumber>SENT20180416000032</SentNumber><KeyNumber><ns2:SenderKey>KS-28YM</ns2:SenderKey><ns2:RecipientKey>KR-52DH</ns2:RecipientKey><ns2:CarrierKey>KD-48WW</ns2:CarrierKey></KeyNumber>
I want to read in separate SenderKey, RecipientKey & CarrierKey.
When i use this code:
XmlTextReader reader = new XmlTextReader(file);
XmlDocument xmlDoc = new XmlDocument();
xmlDoc.Load(reader);
XmlNamespaceManager nsmgr = new XmlNamespaceManager(xmlDoc.NameTable);
nsmgr.AddNamespace("ns", xmlDoc.DocumentElement.NamespaceURI);
XmlNodeList nodeList = xmlDoc.SelectNodes("/ns:SENT_110/ns:KeyNumber", nsmgr);
foreach (XmlNode node in nodeList)
{
key = node.InnerText;
MessageBox.Show(key);
}
i've got something like this: KS-28YMKR-52DHKD-48WW, without any separate between key.
How i could read only one key?
Use the following XPath:
"/ns:SENT_110/ns:KeyNumber/*"
It will return all nested nodes to you.
If the structure of the XML is fixed it is rather easy by using XDocument:
var xmlText = "<SENT_110 xmlns:ns2=\"http://www.mf.gov.pl/SENT/2017/01/18/STypes.xsd\" xmlns=\"http://www.mf.gov.pl/SENT/2017/01/18/SENT_110.xsd\"><SentNumber>SENT20180416000032</SentNumber><KeyNumber><ns2:SenderKey>KS-28YM</ns2:SenderKey><ns2:RecipientKey>KR-52DH</ns2:RecipientKey><ns2:CarrierKey>KD-48WW</ns2:CarrierKey></KeyNumber></SENT_110>";
var xml = XDocument.Parse(xmlText);
var nodes = xml.Descendants();
var senderKey = nodes.First(d => d.Name.ToString().EndsWith("SenderKey")).Value;
var recipientKey = nodes.First(d => d.Name.ToString().EndsWith("RecipientKey")).Value;
var carrierKey = nodes.First(d => d.Name.ToString().EndsWith("CarrierKey")).Value;
See HERE for a working snippet. If this is just a part of a bigger XML or the structure can be different maybe some more complex searching is needed.
Please, Help me Out Here
I Want to display the value of "email" from xml. my syntax works for now but it displays every value. i want to be able to display Individual (one) Values like
email: mail#mail.com
My scripts
var xml ="<?xml version='1.0' encoding='UTF-8'?>
<MemResponse>
<Phone>2554535</Phone>
<Email>mail#mail</Email>
<Number>we75546654</Number>
</MemResponse>";
XmlDocument doc = new XmlDocument();
doc.LoadXml(xml);
foreach(XmlNode n in doc.DocumentElement)
{
string q = n.FirstChild.InnerText;
Response.Write(q);
}
Simply you can select all element by tag name by GetElementsByTagName method.
Check this :
XmlDocument doc = new XmlDocument();
doc.LoadXml(xml);
var myEmails = doc.GetElementsByTagName("Email");
foreach (XmlNode mail in myEmails)
{
string mailText = mail.FirstChild.InnerText;
Response.Write(mailText);
}
I have got it from MSDN
Your code goes through each node and writes the contents of that node.
It seems like you want to match on the node name, and only write the value if its name is "email".
If thats the case, inside of your for each, try something like:
if(n.Name == "Email") {
string q = n.FirstChild.InnerText;
Response.Write(q);
}
Alternatively, you could just use a node list.
NodeList nl = doc.GetElementsByTagName("Email");
And write that.
When loading your XML Doc, use :
HttpWebRequest request = WebRequest.Create(requestUrl) as HttpWebRequest;
HttpWebResponse response = request.GetResponse() as HttpWebResponse;
XmlDocument xmlDoc = new XmlDocument();
xmlDoc.Load(response.GetResponseStream());
Please try this code:
XmlDocument doc = new XmlDocument();
doc.LoadXml("YOUR_XML_PATH");
XmlNodeList email_hd= doc.GetElementsByTagName("Email");
string email=email_hd[0].InnerText;
I want to create a routing(path) to xml element and assign it to a variable so i can access it
fast in the future.
The element, which is a child of other elements, can change its position in the document
so i cant use methods like first child or indexing that rely on position.
The path to the element will always stay constant and there is no other path like it.
If we look at a short example so i want a path to level4 value(header4) so i can modify it.
<level1>
<level2>
<level3>header3</level3>
<level4>header4</level4>
<level3>header31</level31>
</level2>
<level2>
<level3>nnn</level3>
<level3>nnnnn</level31>
</level2>
</level1>
You've got to use XPath in that case.
XmlDocument xmlDoc = new XmlDocument();
xmlDoc.Load("Path of the xml");
XmlNode titleNode = xmlDoc.SelectSingleNode("//level1/level2/level3");
You can use XPath for this.
XmlDocument doc; // assuming the xml is already in doc
XmlNode node = doc.SelectSingleNode("/level1/level2/level3/level4");
if(node != null)
{
node.InnerText = "New value";
}
If there could be more than one level4 then you could do this:
XmlDocument doc; // assuming the xml is already in doc
XmlNodeList nodes = doc.SelectNodes("/level1/level2/level3/level4");
if(nodes != null)
{
foreach(XmlNode node in nodes)
{
node.InnerText = "New value";
}
}
I am trying to read the following file, I can read the attributes, but I can't go into the specific element (Address in this case) and read its elements based on the attribute of that (Address) element. Shortly I need to distinguish between work and home addresses. I need to do this with XMLReader class. Can you help?
<Address Label="Work">
<Name>Name1</Name>
<Street>PO 1</Street>
<City>City1</City>
<State>State 1</State>
</Address>
<Address Label="Home">
<Name>Name2</Name>
<Street>PO 2</Street>
<City>City2</City>
<State>State 2</State>
</Address>"
Okay, here are some notes to think about. XMLReader in the sense i understand you use it (with no code example) is that you iterate over the document, since the XMLReader is forward-only, and read-only.
Because of this you need to iterate until you find the node you need. In the example below i find the address element labeled "work" and extract that entire node. Then query on this node as you want.
using (var inFile = new FileStream(path, FileMode.Open))
{
using (var reader = new XmlTextReader(inFile))
{
while (reader.Read())
{
switch (reader.NodeType)
{
case XmlNodeType.Element:
if (reader.Name == "Address" && reader.GetAttribute(0) == "Work")
{
// Create a document, which will contain the address element as the root
var doc = new XmlDocument();
// Create a reader, which only will read the substree <Address> ... until ... </Address>
doc.Load(reader.ReadSubtree());
// Use XPath to query the nodes, here the "Name" node
var name = doc.SelectSingleNode("//Address/Name");
// Print node name and the inner text of the node
Console.WriteLine("Node: {0}, Inner text: {1}", name.Name, name.InnerText);
}
break;
}
}
}
}
Edit
Made an example that not uses LINQ
XML:
<Countries>
<Country name ="ANDORRA">
<state>Andorra (general)</state>
<state>Andorra</state>
</Country>
<Country name ="United Arab Emirates">
<state>Abu Z¸aby</state>
<state>Umm al Qaywayn</state>
</Country>
Java:
public void datass(string file)
{
string file = HttpContext.Current.Server.MapPath("~/App_Data/CS.xml");
XmlDocument doc = new XmlDocument();
if (System.IO.File.Exists(file))
{
//Load the XML File
doc.Load(file);
}
//Get the root element
XmlElement root = doc.DocumentElement;
XmlNodeList subroot = root.SelectNodes("Country");
for (int i = 0; i < subroot.Count; i++)
{
XmlNode elem = subroot.Item(i);
string attrVal = elem.Attributes["name"].Value;
Response.Write(attrVal);
XmlNodeList sub = elem.SelectNodes("state");
for (int j = 0; j < sub.Count; j++)
{
XmlNode elem1 = sub.Item(j);
Response.Write(elem1.InnerText);
}
}
}
Using XPath you can easily write concise expressions to navigate an XML document.
You would do something like
XmlDocument xDoc = new XmlDocument();
xDoc.LoadXml(myXMLString);
XmlNode homeAddress = xDoc.SelectSingleNode("//Address[#Label='Work']");
Then do whatever you want with homeAddress.
Read more here on w3schools on XPath.