Instead of doing this, I want to make use of string.format() to accomplish the same result:
if (myString.Length < 3)
{
myString = "00" + 3;
}
If you're just formatting a number, you can just provide the proper custom numeric format to make it a 3 digit string directly:
myString = 3.ToString("000");
Or, alternatively, use the standard D format string:
myString = 3.ToString("D3");
string.Format("{0:000}", myString);
It's called Padding:
myString.PadLeft(3, '0')
This is how it's done using string interpolation C# 7
$"{myString:000}"
(Can't comment yet with enough reputation , let me add a sidenote)
Just in case your output need to be fixed length of 3-digit , i.e. for number run up to 1000 or more (reserved fixed length), don't forget to add mod 1000 on it .
yourNumber=1001;
yourString= yourNumber.ToString("D3"); // "1001"
yourString= (yourNumber%1000).ToString("D3"); // "001" truncated to 3-digit as expected
Trail sample on Fiddler https://dotnetfiddle.net/qLrePt
This is a short hand string format Interpolation:
$"{value:D3}"
"How to: Pad a Number with Leading Zeros"
http://msdn.microsoft.com/en-us/library/dd260048.aspx
Does it have to be String.Format?
This looks like a job for String.Padleft
myString=myString.PadLeft(3, '0');
Or, if you are converting direct from an int:
myInt.toString("D3");
You can also do : string.Format("{0:D3}, 3);
Related
I use following code to convert input to comma separated string in INR:
decimal input = 1111111111.59m;
string result = input.ToString("C", new CultureInfo("EN-in"));
I want to remove the trailing 0s now, how do i do this?
for example:
decimal input = 1111111111.00m;
Output should be 1111111111
string result = input.ToString("c0", new CultureInfo("EN-in"));
Update:
So you want output "123.45" for input 123.45 and output "123" for input 123.00.
You can't achieve these 2 different formats without conditional operator, String.Format() will produce only one output format for you.
The code is simple though:
string format = Decimal.Round(input) == input ? "c0" : "c";
string output = input.ToString(format);
string output = input.ToString("0");
Following code should work :
string results = input.ToString("0.##");
The simplest thing to convert is convert into int.
int d = convert.toInt32(1111.00);
or use any math function as suggested.
How to remove decimal part from a number in C#
How do I format a C# decimal to remove extra following 0's?
Edit
As I understand just try
Console.WriteLine(d.ToString("0.#####"));
Seet this url :- Best way to display decimal without trailing zeroes
I need to display some numbers in a variable of type decimal.
I want to display them almost as they are, which ToString("G29") gives me.
However, I want to add a thousands separator. ToString("N") gives me the thousands separator but totally loses the "G29 goodness".
Is there a simple solution to get the display string I want?
value "N" "G29" What I Want
============= ========== ========== ==============
296018.413 296,018.41 296018.413 296,018.413
652609 652,609.00 652609 652,609
296.018413 296.02 296.018413 296.018413
326.305 326.31 326.305 326.305
Edit:
Another SO question/answer recently made me aware that "G29" returns values less than 0.0001 in scientific notation. So when I wrote the question I was unaware that the solution needed to handle special cases like these:
value What I Want
============ =============
0.00001 0.00001
12345.000067 12,345.000067
You might have to do a little bit of work around.
How about this?
decimal d = 34561.2223400M;
string decimalPart = (d - (int)d).ToString("G29");
string integerPart = d.ToString("##,###");
string finalNumber = integerPart + decimalPart.Substring(1,decimalPart.Length-1);;
There is a pretty simple solution to this, though it involves a fairly long format string.
decimal d = 12345.000067m;
string s = d.ToString("#,###0.############################"); // 28 #'s after the decimal
You have to format the string.
Try:
string yourString = String.Format("{0:N29}", yourWeight);
Edit:
The above was pretty close. This gives exactly the desired results:
string yourString = String.Format("{0:N29}", yourWeight).Trim(new [] { '0', '.' });
Scenario: I'm creating a file thats need to be in this format https://www.rbcroyalbank.com/ach/file-451771.pdf . I need to be able to set the limit of the string length for certain fields.
Question: Is there an easy way to set the limit of the field so that if the string was larger then the limit then just take the substring and if smaller would add extra spaces?
Note: I was able to accomplish something similar to this with integers by just using .toString("00000").
You could use the PadRight in conjunction with the Substring methods (where 5 could of course be variablized according to your needs):
Console.WriteLine("'{0}'", "abcdefgh".PadRight(5).Substring(0, 5));
Console.WriteLine("'{0}'", "abc".PadRight(5).Substring(0, 5));
prints:
'abcde'
'abc '
You can use string.PadLeft or string.PadRight to pad your strings with a char, and string.Substring to limit it.
This is straightforward.
const int MaxStringLength = 100; /* set to your maximum length */
...
myString = (myString.Length >= MaxStringLength)
? myString.Substring(0, MaxStringLength)
: myString.PadRight(MaxStringLength);
I am getting the following values from database:
99, 12, 12.2222, 54.98, 56, 17.556
Now I want to show that values like below:
99%, 12%, 12.22% , 54.98% , 56%, 17.55%
Please give me any suggestion to acchive this.
Its very easy in C#:
[EDIT]
var val = 99.569;
string result = string.Format("{0:0.##}%", val);
You can take a look for Format method of string class:
http://msdn.microsoft.com/en-us/library/fht0f5be.aspx
and I recomend you to take a look on custom format strings:
http://msdn.microsoft.com/en-us/library/0c899ak8.aspx
Use the ToString method that takes a string format - the format you want is "P2" or the custom format #0.##%. Both of these formatting options multiply by 100, expecting your data to be in standard percent format so you will need to divide to accomadate and use it.
To use ToString without the divide you can use "#0.##\%" which will format the numeric part and include the percent sign as a literl, this is the equivilent for ToString as the format from Anton Semenov's answer using the string.Format function on this thread.
Msdn article - Standard Formats
Msdn article - Custom Formats
to formart 12.2222 use f
string.Format("{0:f}%", 12.2222); //output 12,22%
Try this Out
List<double> myList = new List<double>();
myList.Add(0.1234);
myList.Add(99);
myList.Add(12.1234);
myList.Add(54.98);
foreach (double d in myList)
{
string First = string.Format("{0:0.00%}", d); //Multiply value by 100
Console.WriteLine(First);
string Second = string.Format("{0:P}", d);//Multiply value by 100
Console.WriteLine(Second);
string Third = string.Format("{0:P}%", d.ToString());//Use this One
Console.WriteLine(Third);
string Four = d.ToString() + "%"; //Not a good idea but works
Console.WriteLine(Four);
Console.WriteLine("=====================");
}
Console.ReadLine();
I have made a little trick here {0:P} will multiply your given value by 100 and then show it but you just want to place a % sign after value so first convert the given value to TOString than apply {0:p}
If you want to specify the number of decimal places to 2 (ie. not 12.2222%, but 12.22%), then use:
val.ToString("0.00") + "%"
Note that this will round the number off, so 12.226 would be shown as 12.23%, etc.
Hi i have a int example as 3 i need to format it as 003 . is the only way is convert to a string and concat and convert back ?
I guess this is what you want:
int n = 3;
string formatted = n.ToString("000");
Alternatively:
string formatted = String.Format("{0:000}", n);
More info here.
You can apply the .ToString("000"); method.
Debug.WriteLine(3.ToString("000"));
You can parse the resulting string value by using int.Parse or int.TryParse:
Debug.WriteLine(int.Parse("003"));
See Custom Numeric Format Strings
If it's an int object, the leading zeros will always be removed, regardless if you convert it to a string and back.
use the pad functionint i = 1;
i.ToString().PadLeft(3, '0');