I want to display 0.12345 as "+12.3%". Format string "P1" or "p1" gives "12.3%". I have tried both "+P1" and "+p1" to no avail.
string sFoo = 0.12345.ToString("P1");
Update
I should have emphasized that I always want the proper sign, not "+". If the number is -0.12345, "P1" works exactly as I want: "-12.3%".
Not quite using P1, but same result:
0.12345.ToString("+#.#%;-#.#%");
If you prefer at least one leading digit (e.g. "+0.23%" instead of "+.23%"):
0.12345.ToString("+0.#%;-0.#%"));
Same for trailing digits (e.g. "+14.0%" instead of "+14%"):
0.12345.ToString("+0.0%;-0.0%"));
Reference: https://learn.microsoft.com/en-us/dotnet/standard/base-types/custom-numeric-format-strings#the--section-separator
var num = 0.12345;
var sign = num > 0 ? "+" : "";
var output = $"{sign}{num.ToString("P1")}";
I'm afraid there is no format string to display the positive sign. I've searched in NumberFormatInfo if some custom format could accept this, but with no avail.
You can however build some extension methods to fit your needs :
public static string ToSignedPercent(this double input)
{
return $"{(input >= 0 ? "+" : "")}{input.ToString("P1")}";
}
// ...
Console.WriteLine((0.12345).ToSignedPercent()); // +12.3%
Console.WriteLine((-0.6789).ToSignedPercent()); // -67.9%
Fiddle
Put the following in your main method. basically this approaches just sets the variable sFoo to have format of percentage with two decimals.
string sFoo = String.Format("Value: {0:P2}.", 0.12345); // formats as 12.35%
Console.WriteLine(sFoo);
I need to display a number with commas and a decimal point.
Eg:
Case 1 : Decimal number is 432324 (This does not have commas or decimal points).
Need to display it as: 432,324.00.
Not: 432,324
Case 2 : Decimal number is 2222222.22 (This does not have commas).
Need to display it as: 2,222,222.22
I tried ToString("#,##0.##"), but it is not formatting it correctly.
int number = 1234567890;
number.ToString("#,##0.00");
You will get the result 1,234,567,890.00.
Maybe you simply want the standard format string "N", as in
number.ToString("N")
It will use thousand separators, and a fixed number of fractional decimals. The symbol for thousands separators and the symbol for the decimal point depend on the format provider (typically CultureInfo) you use, as does the number of decimals (which will normally by 2, as you require).
If the format provider specifies a different number of decimals, and if you don't want to change the format provider, you can give the number of decimals after the N, as in .ToString("N2").
Edit: The sizes of the groups between the commas are governed by the
CultureInfo.CurrentCulture.NumberFormat.NumberGroupSizes
array, given that you don't specify a special format provider.
Try with
ToString("#,##0.00")
From MSDN
*The "0" custom format specifier serves as a zero-placeholder symbol. If the value that is being formatted has a digit in the position where the zero appears in the format string, that digit is copied to the result string; otherwise, a zero appears in the result string. The position of the leftmost zero before the decimal point and the rightmost zero after the decimal point determines the range of digits that are always present in the result string.
The "00" specifier causes the value to be rounded to the nearest digit preceding the decimal, where rounding away from zero is always used. For example, formatting 34.5 with "00" would result in the value 35.*
I had the same problem. I wanted to format numbers like the "General" format in spreadsheets, meaning show decimals if they're significant, but chop them off if not. In other words:
1234.56 => 1,234.56
1234 => 1,234
It needs to support a maximum number of places after the decimal, but don't put trailing zeros or dots if not required, and of course, it needs to be culture friendly. I never really figured out a clean way to do it using String.Format alone, but a combination of String.Format and Regex.Replace with some culture help from NumberFormatInfo.CurrentInfo did the job (LinqPad C# Program).
string FormatNumber<T>(T number, int maxDecimals = 4) {
return Regex.Replace(String.Format("{0:n" + maxDecimals + "}", number),
#"[" + System.Globalization.NumberFormatInfo.CurrentInfo.NumberDecimalSeparator + "]?0+$", "");
}
void Main(){
foreach (var test in new[] { 123, 1234, 1234.56, 123456.789, 1234.56789123 } )
Console.WriteLine(test + " = " + FormatNumber(test));
}
Produces:
123 = 123
1234 = 1,234
1234.56 = 1,234.56
123456.789 = 123,456.789
1234.56789123 = 1,234.5679
Try with
ToString("#,##0.###")
Produces:
1234.55678 => 1,234.556
1234 => 1,234
For Razor View:
$#string.Format("{0:#,0.00}",item.TotalAmount)
CultureInfo us = new CultureInfo("en-US");
TotalAmount.ToString("N", us)
Your question is not very clear but this should achieve what you are trying to do:
decimal numericValue = 3494309432324.00m;
string formatted = numericValue.ToString("#,##0.00");
Then formatted will contain: 3,494,309,432,324.00
All that is needed is "#,0.00", c# does the rest.
Num.ToString("#,0.00"")
The "#,0" formats the thousand separators
"0.00" forces two decimal points
If you are using string variables you can format the string directly using a : then specify the format (e.g. N0, P2, etc).
decimal Number = 2000.55512016465m;
$"{Number:N}" #Outputs 2,000.55512016465
You can also specify the number of decimal places to show by adding a number to the end like
$"{Number:N1}" #Outputs 2,000.5
$"{Number:N2}" #Outputs 2,000.55
$"{Number:N3}" #Outputs 2,000.555
$"{Number:N4}" #Outputs 2,000.5551
string Mynewcurrency = DisplayIndianCurrency("7743450.00");
private string DisplayIndianCurrency(string EXruppesformate)
{
string fare = EXruppesformate;
decimal parsed = decimal.Parse(fare, CultureInfo.InvariantCulture);
CultureInfo hindi = new CultureInfo("en-IN");
// string text = string.Format(hindi, "{0:c}", parsed);if you want <b>Rs 77,43,450.00</b>
string text = string.Format(hindi, "{0:N}", parsed); //if you want <b>77,43,450.00</b>
return ruppesformate = text;
}
For anyone looking at this now, and getting the "No overload for method 'ToString' takes 1 argument" when using:
TotalNumber.ToString("N")
My solution has been to use :
TotalNumber.Value.ToString("N")
I often get stuck on this when working directly inside an MVC View, the following wasn't working:
#Model.Sum(x => x.Number).ToString("N")
Whereas this works:
#Model.Sum(x => x.Number).Value.ToString("N")
Im having alot of problems trying to take out the decimal part of my string,
the string comes from a var type in my view like this:
var temp = dashList[index];
#PrintSection(actualDate, Model, String.Format("{0:0.000}", temp.Rubro))**
temp.Rubro is my String part that can be ".00" or ".XX"
however i need to take the decimal part of the string only when its value is ".00"
since i have some values of the dashlist have important decimal parts.
Is there a way to take the decimal part of a string only if it equals to ".00"???
The output im trying to get is:
From XX.00 -> XX
From XX.12 -> XX.12
both kinds are on my list
Try this:
var temp = dashList[index];
#PrintSection(actualDate, Model, String.Format("{0:0.000}", temp.Rubro).Replace(".00", ""))
You can try using
String.Format("{0:G29}", decimal.Parse(temp.Rubro)))
Whereas all the below formats achieve the same results.
string.Format("{0:G29}", decimal.Parse("2.00"))
decimal.Parse("2.00").ToString("G29")
2.0m.ToString("G29")
You can use ToString() with the General ("G") Format Specifier to achieve the desired result. Trailing zeros are truncated when using this format string with a precision specified. In order to prevent rounding in any situations, you will need to set the precision to the maximum allowed for decimals (29).
Simple trick...
You can parse the string and it will automatically remove the decimal places
try following
private static void ParseDouble()
{
string sDouble = "12.00";
double dValue = double.Parse(sDouble);
Console.WriteLine(dValue.ToString());
sDouble = "12.14";
dValue = double.Parse(sDouble);
Console.WriteLine(dValue.ToString());
}
Your output will be
12
12.14
Hope this helps.
I will suggest you to use accounting.js plugging which is pretty straightforward. I have used it in some projects and as of today I cannot complain. Otherwise, you could do something like this,
var x = temp.Replace(".00","").Trim();
Suppose I have a list of decimal numbers that I must format with a comma every three places, plus the appropriate number of digits after the decimal point. I want to use the .net string.Format method.
I want it to work like this:
string format = ???;
string s1 = string.Format(format, "1500"); // "1,500"
string s2 = string.Format(format, "1500.25"); // "1,500.25"
string s3 = string.Format(format. "3.1415926358979"); // "3.1415926358979"
I have seen other answers where the digits after the decimal are either limited to a fixed number of digits or truncated entirely, but this doesn't work for my application. I want to add the comma-separator to the whole part of the number, but keep the digits after the decimal exactly as they are.
First problem, you need to parse your strings before you can format them. There maybe some lose of precision. Then you need to decide what your maximum amount of precision you need is. Then you can do something like this:
string format = "{0:#,##0.#############}";
string s1 = string.Format(format, double.Parse("1500")); // "1,500"
string s2 = string.Format(format, double.Parse("1500.25")); // "1,500.25"
string s3 = string.Format(format, double.Parse("3.1415926358979")); // "3.1415926358979"
The # after the decimal place is a place holder for a decimal digit. If there are no more digits it won't show trailing zeros.
If being limited to a number of decimal places or possibly losing precision when converting to double. You could do something really cludgy like this:
public static string DecimalFormatCludge(string original)
{
var split = original.Split('.');
return string.Join(".", (new [] { int.Parse(split[0]).ToString("#,##0")}).Concat(split.Skip(1)));
}
This will split on the . in the string, parse the first part as an int, convert it back to a string correctly formatted and then just stick the decimal part back on (if there is one)
something like this?
string s1 = format.ToString("#,##0.00");
The format is something like this:
string format = "{0:#,##.##################}";
Hi i have a int example as 3 i need to format it as 003 . is the only way is convert to a string and concat and convert back ?
I guess this is what you want:
int n = 3;
string formatted = n.ToString("000");
Alternatively:
string formatted = String.Format("{0:000}", n);
More info here.
You can apply the .ToString("000"); method.
Debug.WriteLine(3.ToString("000"));
You can parse the resulting string value by using int.Parse or int.TryParse:
Debug.WriteLine(int.Parse("003"));
See Custom Numeric Format Strings
If it's an int object, the leading zeros will always be removed, regardless if you convert it to a string and back.
use the pad functionint i = 1;
i.ToString().PadLeft(3, '0');