I am trying to delete a whole XmlNode which matches a certain condition
The format of my xml file is as follows:
<?xml version="1.0" encoding="utf-8"?>
<Advertisements>
<Ad>
<ImageUrl>image/Hydrangeas.jpg</ImageUrl>
<NavigateUrl>www.google.com</NavigateUrl>
<AlternateText>nbfndbf</AlternateText>
<ID>0</ID>
<Impressions>1</Impressions>
</Ad>
</Advertisements>
My deleting code:
XElement x =
new XElement("Ad",
new XElement("ImageUrl", lblImageURL.Text),
new XElement("NavigateUrl", lblImageURL.Text),
new XElement("AlternateText", lblAlternateText.Text),
new XElement("ID", lblID.Text),
new XElement("Impressions", lblfrequency.Text));
string filepath = Request.PhysicalApplicationPath.ToString() + "Adrotator.xml";
XmlDocument xD = new XmlDocument();
xD.LoadXml(x.ToString());
XmlNode xN = xD.FirstChild;
xN.ParentNode.RemoveChild(xN);
**xD.Save(filepath);**
I am getting an error Invalid XML document. The document does not have a root element.
You can use linq to xml to achieve this here exmple how to remove node where value ID = 0
var q = (from c in doc.Descendants("Advertisements")
from v in c.Elements("Ad")
where (int) v.Element("ID") == 0
select v).Remove();
here is another example using xpath
doc.XPathSelectElement("Advertisements/Ad[ID = 0]").Remove();
You create a new XDocument (doc) with the following code:
XDocument doc = XDocument.Load(filepath);
Is there something in the Xml file (with a root element)? Also, you don't seem to use doc in the code, so it's at least not required.
Related
I have xml file:
<?xml version="1.0" encoding="UTF-8" standalone="yes"?><SENT_110 xmlns:ns2="http://www.mf.gov.pl/SENT/2017/01/18/STypes.xsd" xmlns="http://www.mf.gov.pl/SENT/2017/01/18/SENT_110.xsd"><SentNumber>SENT20180416000032</SentNumber><KeyNumber><ns2:SenderKey>KS-28YM</ns2:SenderKey><ns2:RecipientKey>KR-52DH</ns2:RecipientKey><ns2:CarrierKey>KD-48WW</ns2:CarrierKey></KeyNumber>
I want to read in separate SenderKey, RecipientKey & CarrierKey.
When i use this code:
XmlTextReader reader = new XmlTextReader(file);
XmlDocument xmlDoc = new XmlDocument();
xmlDoc.Load(reader);
XmlNamespaceManager nsmgr = new XmlNamespaceManager(xmlDoc.NameTable);
nsmgr.AddNamespace("ns", xmlDoc.DocumentElement.NamespaceURI);
XmlNodeList nodeList = xmlDoc.SelectNodes("/ns:SENT_110/ns:KeyNumber", nsmgr);
foreach (XmlNode node in nodeList)
{
key = node.InnerText;
MessageBox.Show(key);
}
i've got something like this: KS-28YMKR-52DHKD-48WW, without any separate between key.
How i could read only one key?
Use the following XPath:
"/ns:SENT_110/ns:KeyNumber/*"
It will return all nested nodes to you.
If the structure of the XML is fixed it is rather easy by using XDocument:
var xmlText = "<SENT_110 xmlns:ns2=\"http://www.mf.gov.pl/SENT/2017/01/18/STypes.xsd\" xmlns=\"http://www.mf.gov.pl/SENT/2017/01/18/SENT_110.xsd\"><SentNumber>SENT20180416000032</SentNumber><KeyNumber><ns2:SenderKey>KS-28YM</ns2:SenderKey><ns2:RecipientKey>KR-52DH</ns2:RecipientKey><ns2:CarrierKey>KD-48WW</ns2:CarrierKey></KeyNumber></SENT_110>";
var xml = XDocument.Parse(xmlText);
var nodes = xml.Descendants();
var senderKey = nodes.First(d => d.Name.ToString().EndsWith("SenderKey")).Value;
var recipientKey = nodes.First(d => d.Name.ToString().EndsWith("RecipientKey")).Value;
var carrierKey = nodes.First(d => d.Name.ToString().EndsWith("CarrierKey")).Value;
See HERE for a working snippet. If this is just a part of a bigger XML or the structure can be different maybe some more complex searching is needed.
I apologize if this question is too easy for you as I am just starting to learn how XML works. What I am trying to do is to append a new element to App/Library and for example I started with this.
<?xml version="1.0" encoding="utf-8"?>
<App>
<Library>
<Count>100</Count>
<Track>
<TrackID>1</TrackID>
<Name>New York</Name>
<Artist>Snow Patrol</Name>
</Track>
</Library>
</App>
what I am trying to do is to add another track to my existing XML.
<Track>
<TrackID>2</TrackID>
<Name>Chasing Cars</Name>
<Artist>Snow Patrol</Name>
</Track>
There are a couple of ways to deal with xml manipulation in .NET. The older style using System.Xml.XmlDocument or using System.Xml.Linq.XDocument approach.
Here is an example on how to do it using XmlDocument:
var xml = "Baz";
var doc = new XmlDocument();
doc.LoadXml(xml); //Load up the original xml string into XmlDocument object
var fooNode = doc.SelectSingleNode("//foo"); //use xpath to get to the top level foo element
var newBar = doc.CreateElement("bar"); //Create a new bar element and assign it's inner text
newBar.InnerText = "Baz2";
fooNode.AppendChild(newBar); //append the newly created bar element to foo
and here is an example on how to do it using XDocument (which is much more simpler):
var xml = "<?xml version=\"1.0\" encoding=\"utf-8\"?><foo><bar>Baz</bar></foo>";
var xdoc = XDocument.Parse(xml); //Load up the original xml string into Linq XDocument object
xdoc.Root.Add(new XElement("bar", "Bar2")); //Add <bar>Bar2</bar> to foo (which is root of the document)
Here is a running example:
https://dotnetfiddle.net/vY7Vag
how can i retrieve node out of xml document by inner text.
for example
<w:t>WARNING</w:t>
node consists multiple times with different values in xml document.
I want to retrieve only those w:t nodes with inner text contains "WARNING" .
how can it be done?
To query elements with prefix you have to register proper prefix-to-namespace-URI mapping using XmlNamespaceManager, then use that registered prefix in your XPath, for example :
var xml = #"<root xmlns:w=""test"">
<w:t>WARNING</w:t>
</root>";
var xmlDoc = new XmlDocument();
xmlDoc.LoadXml(xml);
var nsManager = new XmlNamespaceManager(xmlDoc.NameTable);
//register proper prefix-to-namespace-URI mapping
nsManager.AddNamespace("w", "test");
//following XPath used to select <w:t> nodes with inner text contains "WARNING"
var result = xmlDoc.DocumentElement.SelectSingleNode("//w:t[contains(., 'WARNING')]", nsManager);
//print result
Console.WriteLine(result.OuterXml);
Try this :
var wtNodes = elements.Where(e => e.Name.LocalName.Equals("w:t"));
var warningNodes = wtNodes.Where(node => node.Value.Contains("WARNING"));
Try this:
xmlNodeList xNlist= xDoc.selectNodes("//pre:t[.="WARNING"]",objXmlnsMgr);
Here:
xDoc is XmlDocument;
objXmlnsMgr is XmlNamespaceManager ('w' in your case) & pre is its prefix.
I'm really just trying to create a custom xml document for simple configuration processing.
XmlDocument xDoc = new XmlDocument();
string[] NodeArray = { "Fruits|Fruit", "Vegetables|Veggie"};
foreach (string node in NodeArray)
{
XmlNode xmlNode = xDoc.CreateNode(XmlNodeType.Element,node.Split('|')[0],null);
//xmlNode.Value = node.Split('|')[0];
xmlNode.InnerText = node.Split('|')[1];
xDoc.DocumentElement.AppendChild(xmlNode);
}
What i'm trying to get is this.
<?xml version="1.0" encoding="ISO-8859-1"?>
<Fruits>Fruit</Fruits>
<Vegetables>Veggie</Vegetables>
i get not set to value of an object at xDoc.DocumentElement.AppendChild(xmlNode);
Unfortunately, You can't make that XML structure.
All XML documents must have a single root node. You can't have more.
Try something like this
XmlDocument xDoc = new XmlDocument();
xDoc.AppendChild( xDoc.CreateElement("root"));
string[] NodeArray = { "Fruits|Fruit", "Vegetables|Veggie" };
foreach (string node in NodeArray)
{
XmlNode xmlNode = xDoc.CreateNode(XmlNodeType.Element, node.Split('|')[0], null);
//xmlNode.Value = node.Split('|')[0];
xmlNode.InnerText = node.Split('|')[1];
xDoc.DocumentElement.AppendChild(xmlNode);
}
It is not possible to have that XML structure as XML MUST have a single root element. You may want to try:
<?xml version="1.0" encoding="ISO-8859-1"?>
<items>
<Fruits>Fruit</Fruits>
<Vegetables>Veggie</Vegetables>
</items>
I have this XML file, I can read all the the nodes
<?xml version="1.0" encoding="UTF-8"?>
<cteProc xmlns="http://www.portalfiscal.inf.br/cte" versao="1.04">
<CTe xmlns="http://www.portalfiscal.inf.br/cte">
<infCte versao="1.04" ID="CTe3512110414557000014604"></infCte>
</CTe>
</cteProc>
I have tried reading this using C#
string chavecte;
string CaminhoDoArquivo = #"C:\Separados\13512004-procCTe.xml";
XmlDocument xmlDoc = new XmlDocument();
xmlDoc.Load(CaminhoDoArquivo); //Carregando o arquivo
chavecte = xmlDoc.SelectSingleNode("infCTe")
.Attributes.GetNamedItem("Id").ToString();
but something is wrong with this code.
If you want to use Linq To Xml
var xDoc = XDocument.Load(CaminhoDoArquivo);
XNamespace ns = "http://www.portalfiscal.inf.br/cte";
var chavecte = xDoc.Descendants(ns+"infCte").First().Attribute("id").Value;
PS: I am assuming your xml's invalid line is as
<infCte versao="1.04" id="CTe3512110414557000014604"></infCte>
replace
chavecte = xmlDoc.SelectSingleNode("infCTe").Attributes.GetNamedItem("Id").Value;
with
XmlNamespaceManager nsmgr = new XmlNamespaceManager(xmlDoc.NameTable);
nsmgr.AddNamespace("ab", "http://www.portalfiscal.inf.br/cte");
chavecte = xmlDoc.SelectSingleNode("//ab:infCte", nsmgr)
.Attributes.GetNamedItem("Id").Value;
I've also noticed that infCte doesn't have the ID attribute properly defined in your xml
Another possible solution is:
string CaminhoDoArquivo = #"C:\Separados\13512004-procCTe.xml";
XmlDocument xmlDoc = new XmlDocument();
xmlDoc.Load(CaminhoDoArquivo); //Carregando o arquivo
// Select the node you're interested in
XmlNode node = xmlDoc.SelectSingleNode("/cteProc/CTe/infCte");
// Read the value of the attribute "ID" of that node
string chavecte = node.Attributes["ID"].Value;