I have this XML file, I can read all the the nodes
<?xml version="1.0" encoding="UTF-8"?>
<cteProc xmlns="http://www.portalfiscal.inf.br/cte" versao="1.04">
<CTe xmlns="http://www.portalfiscal.inf.br/cte">
<infCte versao="1.04" ID="CTe3512110414557000014604"></infCte>
</CTe>
</cteProc>
I have tried reading this using C#
string chavecte;
string CaminhoDoArquivo = #"C:\Separados\13512004-procCTe.xml";
XmlDocument xmlDoc = new XmlDocument();
xmlDoc.Load(CaminhoDoArquivo); //Carregando o arquivo
chavecte = xmlDoc.SelectSingleNode("infCTe")
.Attributes.GetNamedItem("Id").ToString();
but something is wrong with this code.
If you want to use Linq To Xml
var xDoc = XDocument.Load(CaminhoDoArquivo);
XNamespace ns = "http://www.portalfiscal.inf.br/cte";
var chavecte = xDoc.Descendants(ns+"infCte").First().Attribute("id").Value;
PS: I am assuming your xml's invalid line is as
<infCte versao="1.04" id="CTe3512110414557000014604"></infCte>
replace
chavecte = xmlDoc.SelectSingleNode("infCTe").Attributes.GetNamedItem("Id").Value;
with
XmlNamespaceManager nsmgr = new XmlNamespaceManager(xmlDoc.NameTable);
nsmgr.AddNamespace("ab", "http://www.portalfiscal.inf.br/cte");
chavecte = xmlDoc.SelectSingleNode("//ab:infCte", nsmgr)
.Attributes.GetNamedItem("Id").Value;
I've also noticed that infCte doesn't have the ID attribute properly defined in your xml
Another possible solution is:
string CaminhoDoArquivo = #"C:\Separados\13512004-procCTe.xml";
XmlDocument xmlDoc = new XmlDocument();
xmlDoc.Load(CaminhoDoArquivo); //Carregando o arquivo
// Select the node you're interested in
XmlNode node = xmlDoc.SelectSingleNode("/cteProc/CTe/infCte");
// Read the value of the attribute "ID" of that node
string chavecte = node.Attributes["ID"].Value;
Related
I have xml file:
<?xml version="1.0" encoding="UTF-8" standalone="yes"?><SENT_110 xmlns:ns2="http://www.mf.gov.pl/SENT/2017/01/18/STypes.xsd" xmlns="http://www.mf.gov.pl/SENT/2017/01/18/SENT_110.xsd"><SentNumber>SENT20180416000032</SentNumber><KeyNumber><ns2:SenderKey>KS-28YM</ns2:SenderKey><ns2:RecipientKey>KR-52DH</ns2:RecipientKey><ns2:CarrierKey>KD-48WW</ns2:CarrierKey></KeyNumber>
I want to read in separate SenderKey, RecipientKey & CarrierKey.
When i use this code:
XmlTextReader reader = new XmlTextReader(file);
XmlDocument xmlDoc = new XmlDocument();
xmlDoc.Load(reader);
XmlNamespaceManager nsmgr = new XmlNamespaceManager(xmlDoc.NameTable);
nsmgr.AddNamespace("ns", xmlDoc.DocumentElement.NamespaceURI);
XmlNodeList nodeList = xmlDoc.SelectNodes("/ns:SENT_110/ns:KeyNumber", nsmgr);
foreach (XmlNode node in nodeList)
{
key = node.InnerText;
MessageBox.Show(key);
}
i've got something like this: KS-28YMKR-52DHKD-48WW, without any separate between key.
How i could read only one key?
Use the following XPath:
"/ns:SENT_110/ns:KeyNumber/*"
It will return all nested nodes to you.
If the structure of the XML is fixed it is rather easy by using XDocument:
var xmlText = "<SENT_110 xmlns:ns2=\"http://www.mf.gov.pl/SENT/2017/01/18/STypes.xsd\" xmlns=\"http://www.mf.gov.pl/SENT/2017/01/18/SENT_110.xsd\"><SentNumber>SENT20180416000032</SentNumber><KeyNumber><ns2:SenderKey>KS-28YM</ns2:SenderKey><ns2:RecipientKey>KR-52DH</ns2:RecipientKey><ns2:CarrierKey>KD-48WW</ns2:CarrierKey></KeyNumber></SENT_110>";
var xml = XDocument.Parse(xmlText);
var nodes = xml.Descendants();
var senderKey = nodes.First(d => d.Name.ToString().EndsWith("SenderKey")).Value;
var recipientKey = nodes.First(d => d.Name.ToString().EndsWith("RecipientKey")).Value;
var carrierKey = nodes.First(d => d.Name.ToString().EndsWith("CarrierKey")).Value;
See HERE for a working snippet. If this is just a part of a bigger XML or the structure can be different maybe some more complex searching is needed.
I'm loading a xml page from a secured website which i want to read with Xml Document.
A part of the xml:
<ActueleVertrekTijden>
<VertrekkendeTrein>
<RitNummer>5070</RitNummer>
<VertrekTijd>2015-03-20T19:42:00+0100</VertrekTijd>
<EindBestemming>Den Haag Centraal</EindBestemming>
<TreinSoort>Sprinter</TreinSoort>
<RouteTekst>Lage Zwaluwe, Dordrecht, Rotterdam C.</RouteTekst>
<Vervoerder>NS</Vervoerder>
<VertrekSpoor wijziging="false">6</VertrekSpoor>
</VertrekkendeTrein>
<VertrekkendeTrein>
<RitNummer>1971</RitNummer>
<VertrekTijd>2015-03-20T19:50:00+0100</VertrekTijd>
<EindBestemming>Venlo</EindBestemming>
<TreinSoort>Intercity</TreinSoort>
<RouteTekst>Tilburg, Eindhoven, Helmond</RouteTekst>
<Vervoerder>NS</Vervoerder>
<VertrekSpoor wijziging="false">4</VertrekSpoor>
<Opmerkingen> // This is not always available, but it is important and specific for a 'VertrekkendeTrein'
<Opmerking>Rijdt vandaag niet</Opmerking>
</Opmerkingen>
</VertrekkendeTrein>
Now i'm using the following code:
string urlo = "the website";
string resultje = HttpGeto(urlo);
XmlDocument xmlDoc = new XmlDocument();
xmlDoc.LoadXml(resultje);
XmlNodeList ns = xmlDoc.GetElementsByTagName("VertrekkendeTrein");
//MessageBox.Show(ns[0].InnerXml); //*This part works it shows the xml inside the first "VertrekkendeTrein"*
//*Now I want to read all the items of ns[0] and split it like: GetElementsByTagName("RouteTekst")*
XmlDocument xd1 = new XmlDocument();
xd1.LoadXml(ns[0].InnerXml);
XmlNodeList nsvertrektijdje = xd1.GetElementsByTagName("RouteTekst");
var vty1 = nsvertrektijdje[0].InnerText;
MessageBox.Show(vty1);
The problem which i'm having now is that I can't load ns[0].InnerXml in LoadXml. It gave no result.
Edit:
Now i'm using the following:
string urlo = "website";
string resultje = HttpGeto(urlo);
XmlDocument xmlDoc = new XmlDocument();
xmlDoc.LoadXml(resultje);
XmlNodeList ns = xmlDoc.GetElementsByTagName("VertrekkendeTrein");
var element = ns[0] as XmlElement;
XmlNodeList nsvertrektijdje = element.GetElementsByTagName("RouteTekst");
var vty1 = nsvertrektijdje[0].InnerText;
MessageBox.Show(vty1);
But it still doesn't work
The problem is that since the ns[0].InnerXml doesn't have a root node , you are unable to parse the inner xml.
try appending a temp node while you loading xml
xd1.LoadXml("<data>" + ns[0].InnerXml + "</data>");
You can't use InnerXml, as that does not include the VertrekkendeTrein node, so it is not a valid xml document (A document can only have a single root node). You could use OuterXml, but that is wasteful, as you have already parsed the XML.
Your best route here is to cast the XmlNode to an XmlElement and use the GetElementsByTagName method from that.
var element = ns[0] as XmlElement;
XmlNodeList nsvertrektijdje = element.GetElementsByTagName("RouteTekst");
The full code now looks like this:
var xml = #"<ActueleVertrekTijden>
<VertrekkendeTrein>
<RitNummer>5070</RitNummer>
<VertrekTijd>2015-03-20T19:42:00+0100</VertrekTijd>
<EindBestemming>Den Haag Centraal</EindBestemming>
<TreinSoort>Sprinter</TreinSoort>
<RouteTekst>Lage Zwaluwe, Dordrecht, Rotterdam C.</RouteTekst>
<Vervoerder>NS</Vervoerder>
<VertrekSpoor wijziging=""false"">6</VertrekSpoor>
</VertrekkendeTrein>
<VertrekkendeTrein>
<RitNummer> 1971 </RitNummer>
<VertrekTijd> 2015 - 03 - 20T19: 50:00 + 0100 </VertrekTijd >
<EindBestemming> Venlo </EindBestemming>
<TreinSoort> Intercity </TreinSoort>
<RouteTekst> Tilburg, Eindhoven, Helmond </RouteTekst>
<Vervoerder> NS </Vervoerder>
<VertrekSpoor wijziging = ""false""> 4 </VertrekSpoor>
<Opmerkingen> // This is not always available, but it is important and specific for a 'VertrekkendeTrein'
<Opmerking> Rijdt vandaag niet</Opmerking>
</Opmerkingen>
</VertrekkendeTrein></ActueleVertrekTijden>";
XmlDocument xmlDoc = new XmlDocument();
xmlDoc.LoadXml(xml);
XmlNodeList ns = xmlDoc.GetElementsByTagName("VertrekkendeTrein");
var element = ns[0] as XmlElement;
XmlNodeList nsvertrektijdje = element.GetElementsByTagName("RouteTekst");
var vty1 = nsvertrektijdje[0].InnerText;
MessageBox.Show(vty1);
I am trying to delete a whole XmlNode which matches a certain condition
The format of my xml file is as follows:
<?xml version="1.0" encoding="utf-8"?>
<Advertisements>
<Ad>
<ImageUrl>image/Hydrangeas.jpg</ImageUrl>
<NavigateUrl>www.google.com</NavigateUrl>
<AlternateText>nbfndbf</AlternateText>
<ID>0</ID>
<Impressions>1</Impressions>
</Ad>
</Advertisements>
My deleting code:
XElement x =
new XElement("Ad",
new XElement("ImageUrl", lblImageURL.Text),
new XElement("NavigateUrl", lblImageURL.Text),
new XElement("AlternateText", lblAlternateText.Text),
new XElement("ID", lblID.Text),
new XElement("Impressions", lblfrequency.Text));
string filepath = Request.PhysicalApplicationPath.ToString() + "Adrotator.xml";
XmlDocument xD = new XmlDocument();
xD.LoadXml(x.ToString());
XmlNode xN = xD.FirstChild;
xN.ParentNode.RemoveChild(xN);
**xD.Save(filepath);**
I am getting an error Invalid XML document. The document does not have a root element.
You can use linq to xml to achieve this here exmple how to remove node where value ID = 0
var q = (from c in doc.Descendants("Advertisements")
from v in c.Elements("Ad")
where (int) v.Element("ID") == 0
select v).Remove();
here is another example using xpath
doc.XPathSelectElement("Advertisements/Ad[ID = 0]").Remove();
You create a new XDocument (doc) with the following code:
XDocument doc = XDocument.Load(filepath);
Is there something in the Xml file (with a root element)? Also, you don't seem to use doc in the code, so it's at least not required.
Consider the following XML:
<SomeRoot>
<SomeElement>
<SomeThing>25</SomeThing>
<SomeOther>Cat</SomeOther>
</SomeElement>
<SomeElement>
<SomeThing>46</SomeThing>
<SomeOther>Dog</SomeOther>
</SomeElement>
<SomeElement>
<SomeThing>83</SomeThing>
<SomeOther>Bat</SomeOther>
</SomeElement>
<SomethingElse>Unrelated to the SomeElements above</SomethingElse>
</SomeRoot>
I want to select SomeThing where SomeOther = 'Cat'. The following C# code throws a null reference exception:
xmlDoc = new XmlDocument();
this.path = path;
// Path is passed elsewhere
Console.WriteLine(xmlDoc.SelectSingleNode("/SomeRoot/SomeElement/SomeThing[../SomeOther='Cat']").InnerText);
What is the correct XPath syntax to use here?
You are missing the load
var xmlDoc = new XmlDocument();
xmlDoc.Load(path);
Console.WriteLine(xmlDoc.SelectSingleNode("/SomeRoot/SomeElement/SomeThing[../SomeOther='Cat']").InnerText);
Here's what I did and it works;
XmlDocument xDoc = new XmlDocument();
xDoc.LoadXml(#"<SomeRoot><SomeElement><SomeThing>25</SomeThing><SomeOther>Cat</SomeOther></SomeElement></SomeRoot>");
var x = xDoc.SelectSingleNode("/SomeRoot/SomeElement/SomeThing[../SomeOther= 'Cat']").InnerText;
You can avoid using any reverse axis:
/*/SomeElement[SomeOther='Cat']/SomeThing
I've tried several methods, from Linq to loading the data to an XML document, but i can't seem to be able to return the result that i need.
here's the example XML:
<serv:message xmlns:serv="http://www.webex.com/schemas/2002/06/service" xmlns:com="http://www.webex.com/schemas/2002/06/common" xmlns:event="http://www.webex.com/schemas/2002/06/service/event"><serv:header><serv:response><serv:result>SUCCESS</serv:result><serv:gsbStatus>PRIMARY</serv:gsbStatus></serv:response></serv:header><serv:body><serv:bodyContent xsi:type="event:createEventResponse" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"><event:sessionKey>11111111</event:sessionKey><event:guestToken>111111111111111111111</event:guestToken></serv:bodyContent></serv:body></serv:message>
And, here's what i've tried to do:
StreamReader reader = new StreamReader(dataStream);
XmlDocument doc = new XmlDocument();
doc.LoadXml(reader.ReadToEnd());
XmlNamespaceManager ns = new XmlNamespaceManager(doc.NameTable);
XmlNamespaceManager ns2 = new XmlNamespaceManager(doc.NameTable);
XmlNamespaceManager ns3 = new XmlNamespaceManager(doc.NameTable);
ns.AddNamespace("serv", "http://www.webex.com/schemas/2002/06/service");
ns2.AddNamespace("com", "http://www.webex.com/schemas/2002/06/common");
ns3.AddNamespace("event", "http://www.webex.com/schemas/2002/06/service/event");
XmlNode node = doc.SelectSingleNode("result",ns);
Yet, for some reason i cannot ever seem to return the actual result, which should be either 'SUCCESS' or 'FAILURE' based on the actual xml above.
How can i do this?
your xpath query is not correct.
try this one :
XmlNode node = doc.SelectSingleNode("//serv:result",ns);
or
XmlNode node = doc.SelectSingleNode("serv:message/serv:header/serv:response/serv:result",ns);
This works:
XDocument doc = XDocument.Load(#"test.xml");
XNamespace serv = "http://www.webex.com/schemas/2002/06/service";
var result = doc.Descendants(serv + "result").First().Value;