We Keep Coding

Automatically clicking OK button in c# app

Morning all,
I have a c# app where if you press a start button a dialog box will open and the OK button will be automatically pressed. The problem is I don't know how to do this.
The code is below:
private void Start_Click(object sender, EventArgs e)
{
if (captureDevice.ShowDialog(this) == DialogResult.OK)
{
var videoSource = captureDevice.VideoDevice;
FinalVideo = captureDevice.VideoDevice;
FinalVideo.NewFrame += new NewFrameEventHandler(FinalVideo_NewFrame);
FinalVideo.Start();
}
}
I have tried:
Removing the if statement to directly run whats inside it
Put DialogResult.OK = true before the if statement
CaptureDevice.DialogResult.OK = true before the if statement;
Image shows the dialogbox when start is pressed

This dialog let you select the source capturing device. If you want to bypass this dialog you should specify source device in your code. if you use AForge.Net this link help you. if not search for appropriate solution in documentation of component or library you use.

Add a new button to your form. Call it "Settings". In the event handler for this button, you roughly put the first half of what you have now for the Start button. Create a Settings object in your MainForm in which you will store the camera chosen.
private void Settings_Click(object sender, EventArgs e)
{
if (captureDevice.ShowDialog(this) == DialogResult.OK)
{
settings.VideoSource = captureDevice.VideoDevice;
}
}
private void Start_Click(object sender, EventArgs e)
{
FinalVideo = settings.VideoSource;
FinalVideo.NewFrame += new NewFrameEventHandler(FinalVideo_NewFrame);
FinalVideo.Start();
}
Hope this helps.

I have sort of found a solution to the question and it was to use:
SendKeys.Send("{ENTER}");
I used it before the if statement and it works with the Start_Click method but when i use it in a method called Start_Vid(), I get the error:
'SendKeys cannot run inside this application because the application is not handling Windows messages. Either change the application to handle messages, or use the SendKeys.SendWait method'
I have no idea why it should not work and what the error message means so should I be creating another question to have this answered or can it be solved in here do you think?

C# webbrower automatically clicking a menu button

I have seen a few of these questions on here but, none of them answered my question. I am looking to automatically click a button on the google fusion table page. I want to run this is in a windows form in visual studio 2015. I need to navigate to the file-geocode... button. I right clicked and hit the inspect button and this is the ID for the button I want
<td class="gwt-MenuItem" id="gwt-uid-209" role="menuitem" colspan="2">Geocode...</td>
is it possible to use a method similar to this?:
private void webBrowser1_DocumentCompleted(object sender, WebBrowserDocumentCompletedEventArgs e)
{
webBrowser1.Document
.GetElementById("gwt-uid-209")
.InvokeMember("Click");
}
Thank you for your help.

i used the same code that you mentioned in the question but be careful because the webBrowser may invoke more than 1 events while the document is completing.
i usually set a timer with 1000ms interval;
try this, it will take 1 second more but it will do the job.
private void webBrowser1_DocumentCompleted(object sender, WebBrowserDocumentCompletedEventArgs e)
{
timer1.Enabled = true;
}
private void timer1_Tick(object sender, EventArgs e)
{
timer1.Enabled = false;
webBrowser1.Document.GetElementById("gwt-uid-209").InvokeMember("Click");
}

If I use the geckobrowser how do I get it to autoclick? this is what I have now.
Xpcom.Initialize("Firefox");
var geckoWebBrowser = new GeckoWebBrowser { Dock = DockStyle.Fill };
Form f = new Form();
f.Controls.Add(geckoWebBrowser);
geckoWebBrowser.Navigate("https://www.google.com/fusiontables/data?docid=1FdRUOJ9YIXT81QdfS71qXWV3m7qmzF_4TLRrKh5r#rows:id=1");
Application.Run(f);

Show dialog on first start of application

Is there an easy way to show an dialog when the program is started for the first time (and only the first time), for some kind of instruction or specifying settings?

You could save it as a bool in your settings and you should check at load event of first form.
Your settings file should have a setting that I called "FirstRun" do this with following steps:
Right click your Project
Click "Properties"
Click "Settings" tabpage(probably on the left)
Add setting like I did as seen in image above
Note: The Scope can be changed to "Application", if that is your application's need, since you didn't mention in your question.
Your Settings file should look like image below:
public void Form1_Load(object sender, EventArgs e)
{
if((bool)Properties.Settings.Default["FirstRun"] == true)
{
//First application run
//Update setting
Properties.Settings.Default["FirstRun"] = false;
//Save setting
Properties.Settings.Default.Save();
//Create new instance of Dialog you want to show
FirstDialogForm fdf = new FirstDialogForm();
//Show the dialog
fdf.ShowDialog();
}
else
{
//Not first time of running application.
}
}
Note: wrote this from my phone, so I couldn't compile to test
Edit: Checked code and added image from desktop.

You can have bool value in your settings file which is a "user setting" which means you can change it to true save it for this specific user.
When your application starts just check that value. If it's false show your dialog and change it to true and it will stay true.
public void Form_Load(object sender, EventArgs e)
{
if(Settings.Default.ShowDialog)
{
Settings.Default.ShowDialog = false;
Settings.Default.Save();
// show first disalog
}
// rest of code if needed
}
Here's an MSDN link on user settings:
http://msdn.microsoft.com/en-us/library/bb397750(v=vs.110).aspx

Ok, so I assume you're creating WinForms application. First of all, locate the Load event in your main Form event lists (or simply double click your Form in Designer panel). The following method stub will pop up:
public void Form1_Load(object sender, EventArgs e)
{
}
And modify it like this:
public void Form1_Load(object sender, EventArgs e)
{
MessageBox.Show("Your message here");
}

block a popup visual studio

I am using the below code in visual studio to make an auto login software . The software is working fine, But the page that is displayed after login has a popup script. This forces the opening of popup url in internet explorer. I want to block the internet explorer getting opened. Can i solve this ?
private void webBrowser1_DocumentCompleted_1(object sender, WebBrowserDocumentCompletedEventArgs e)
{
webBrowser1.Navigate("https://mwcp-ekm-04.adlkerala.com:8001/");
webBrowser1.Document.GetElementById("name").InnerText = "name";
webBrowser1.Document.GetElementById("id").InnerText = "66491";
webBrowser1.Document.GetElementById("accept").InvokeMember("click");
}

You can prevent the opening of a new window (popup) by subscribing to the NewWindow event and then cancel the event itself:
private void webBrowser1_NewWindow(object sender, CancelEventArgs e)
{
e.Cancel = true;
}

ToggleButton in C# WinForms

Is it possible to create a toggle button in C# WinForms? I know that you can use a CheckBox control and set it's Appearance property to "Button", but it doesn't look right. I want it to appear sunken, not flat, when pressed. Any thoughts?

You can just use a CheckBox and set its appearance to Button:
CheckBox checkBox = new System.Windows.Forms.CheckBox();
checkBox.Appearance = System.Windows.Forms.Appearance.Button;

Check FlatStyle property. Setting it to "System" makes the checkbox sunken in my environment.

You may also consider the ToolStripButton control if you don't mind hosting it in a ToolStripContainer. I think it can natively support pressed and unpressed states.

thers is a simple way to create toggle button. I test it in vs2010. It's perfect.
ToolStripButton has a "Checked" property and a "CheckOnClik" property. You can use it to act as a toggle button
tbtnCross.CheckOnClick = true;
OR
tbtnCross.CheckOnClick = false;
tbtnCross.Click += new EventHandler(tbtnCross_Click);
.....
void tbtnCross_Click(object sender, EventArgs e)
{
ToolStripButton target = sender as ToolStripButton;
target.Checked = !target.Checked;
}
also, You can create toggle button list like this:
private void Form1_Load(object sender, EventArgs e)
{
arrToolView[0] = tbtnCross;
arrToolView[1] = tbtnLongtitude;
arrToolView[2] = tbtnTerrain;
arrToolView[3] = tbtnResult;
for (int i = 0; i<arrToolView.Length; i++)
{
arrToolView[i].CheckOnClick = false;
arrToolView[i].Click += new EventHandler(tbtnView_Click);
}
InitTree();
}
void tbtnView_Click(object sender, EventArgs e)
{
ToolStripButton target = sender as ToolStripButton;
if (target.Checked) return;
foreach (ToolStripButton btn in arrToolView)
{
btn.Checked = false;
//btn.CheckState = CheckState.Unchecked;
}
target.Checked = true;
target.CheckState = CheckState.Checked;
}

How about this?
Assuming you have System.Windows.Forms referenced.
var cbtnToggler = new CheckBox();
cbtnToggler.Appearance = Appearance.Button;
cbtnToggler.TextAlign = ContentAlignment.MiddleCenter;
cbtnToggler.MinimumSize = new Size(75, 25); //To prevent shrinkage!
Hope this helps ;)

This is my simple codes I hope it can help you
private void button2_Click(object sender, EventArgs e)
{
if (button2.Text == "ON")
{
panel_light.BackColor = Color.Yellow; //symbolizes light turned on
button2.Text = "OFF";
}
else if (button2.Text == "OFF")
{
panel_light.BackColor = Color.Black; //symbolizes light turned off
button2.Text = "ON";
}
}

When my button's FlatStyle is set to system, it looks flat. And when it's set to popup, it only pops up when mouses over. Either is what I want. I want it to look sunken when checked and raised when unchecked and no change while mousing over (the button is really a checkbox but the checkbox's appearance property is set to button).
I end up setting the FlatStyle to flat and wrote a new Paint event handler.
private void checkbox_paint(object sender, PaintEventArgs e)
{
CheckBox myCheckbox = (CheckBox)sender;
Rectangle borderRectangle = myCheckbox.ClientRectangle;
if (myCheckbox.Checked)
{
ControlPaint.DrawBorder3D(e.Graphics, borderRectangle,
Border3DStyle.Sunken);
}
else
{
ControlPaint.DrawBorder3D(e.Graphics, borderRectangle,
Border3DStyle.Raised);
}
}
I give a similar answer to this question:
C# winforms button with solid border, like 3d
Sorry for double posting.

You can always code your own button with custom graphics and a PictureBox, though it won't necessarily match the Windows theme of your users.

I ended up overriding the OnPaint and OnBackgroundPaint events and manually drawing the button exactly like I need it. It worked pretty well.

use if command to check status and let operate as a toggle button
private void Protection_ON_OFF_Button_Click(object sender, EventArgs e)
{
if (FolderAddButton.Enabled == true)
{
FolderAddButton.Enabled = false;
}
else
{
FolderAddButton.Enabled = true;
}
}

You should look into Siticone I use it and I love it. It works exactly like a checkbox but is a toggle button. Its downside is a message box will come up every time you open Visual Studios so I just installed a tool that disables it. You can also look into Guana but I found that to have a few bugs :)

Changing a CheckBox appearance to Button will give you difficulty in adjustments. You cannot change its dimensions because its size depends on the size of your text or image.
You can try this: (initialize the count variable first to 1 | int count = 1)
private void settingsBtn_Click(object sender, EventArgs e)
{
count++;
if (count % 2 == 0)
{
settingsPanel.Show();
}
else
{
settingsPanel.Hide();
}
}
It's very simple but it works.
Warning: This will work well with buttons that are occasionally used (i.e. settings), the value of count in int/long may be overloaded when used more than it's capacity without closing the app's process. (Check data type ranges: http://msdn.microsoft.com/en-us/library/s3f49ktz.aspx)
The Good News: If you're running an app that is not intended for use 24/7 all-year round, I think this is helpful. Important thing is that when the app's process ended and you run it again, the count will reset to 1.