Why don't interfaces act like classes? - c#

I have a few questions regarding interfaces.
Why we can't use virtual keyword with Interfaces members
Why we can't use override keyword in derived class from interfaces
Suppose
interface Iface
{
void Func();
}
class Program : Iface
{
static void Main(string[] args)
{
}
public void Func()
{
Console.WriteLine("In func");
}
}
Why I need to use public on member functions in derived class from interface i.e. in Func() definition? If I am not using public keyword it will result in a compile time error
Can we use static Members in Interface?

Marking a method virtual gives the inheriting class the option to override the respective method. But when inheriting from an interface the implementation is not optional but mandatory. Every interface method is abstract by definition.
You don't override the methods, you implement them. An interface method has no own implementation, there is nothing to override. It just wouldn't make any sense.
Why a C# interface method implemented in a class must be public
No we can't use static methods on an interface

Interfaces don't need that. The implementation can be virtual.
An implementation doesn't need that - there is nothing to override.
You will have to instantiate a Program to call Func. Also there is no concept of static interfaces.

Interfaces dont act like class because, we cant make an object of interfaces if we can make make an object of interfaces to achieve multiple inheritance then we can face diamond problem that occur in the case of multiple inheritance of classes.

Related

Can abstract class be used as non base class?

I am new to C# programming. I understand that it is necessary to modify the class as abstract if it contains any abstract methods, and its implementation must be provided in any of the child classes in class hierarchy.
But my question is whether can we have an abstract class without any abstract methods(so it is not necessary for it to be a base class), and if it is so, then what are the significance of the same. Please help in this regard. :)
Yes you can have an abstract base class without any abstract methods. The benefit is that you cannot create an instance of this class.
There is a consideration to replace that abstract class with an interface. The difference is that the interface may not contain any implementation, but in the abstract class you can provide some implementation for methods that any inheritor may use.
You cann't create instances of the abstract class, and if you are not use this class as base - it is useless (only possible for some tricky goals using reflection)
Yes, it can be used without having an implementing subclass. Basically you have three "ways" of defining and calling methods here:
static: Methods that can be called directly on the abstract class, because they do not require an instance at all.
abstract: Methods that must be implemented in a sub-class (note that the existance of one of these does not stop you from using any existing static methods directly!)
"Regular": Normal methods, implemented directly in the abstract class, and which can be called via an instance of a sub-class. Note that you can only call them via sub-classes, since you can only have instances of a subclass (not the abstract class itself). Such a sub-class must also by definition implement any abstract method(s) in the abstract class (otherwise you`ll get a compile time error).
The following simple console app gives a nice, concrete (no pun intended) example:
using System;
namespace ConsoleStuff
{
public abstract class MyAbstractClass
{
public abstract void DoSomethingAbs();
public void DoSomethingElse()
{
Console.WriteLine("Do something general...");
}
public static void TakeABreak()
{
Console.WriteLine("Take a break");
}
}
class MyImplementation : MyAbstractClass
{
public override void DoSomethingAbs()
{
Console.WriteLine("Do something Specific...");
}
}
class Program
{
static void Main(string[] args)
{
// Static method; no instance required
MyAbstractClass.TakeABreak();
var inst = new MyImplementation();
inst.DoSomethingAbs(); // Required implementation in subclass
inst.DoSomethingElse(); // Use method from the Abstract directly
Console.ReadKey();
}
}
}

Interface and abstract class protection level methods

I came across a bit of code and am not quite sure why it works or why you'd want to do it this way. I would love it if someone could tear it down for me. I do understand well OOP concepts, I simply have not seen this technique before. Thanks
Here is the example:
public interface IInterface
{
IEnumerable<object> DoSomething();
}
public abstract class MyBase : IInterface
{
protected MyBase()
{
}
IEnumerable<object> IInterface.DoSomething()
{
return DoSomething();
}
protected virtual IEnumerable<object> DoSomething()
{
return new List<object>();
}
}
public class MyClass : MyBase
{
internal MyClass() : base() {}
protected override IEnumerable<object> DoSomething()
{
return new List<object>();
}
}
If you're talking about this line of code:
IEnumerable<object> IInterface.DoSomething()
That's called explicit interface implementation.
That forces consumers to access this method only via the interface,
and not to your class directly.
The above method is not private, it's just not explicitly set as public in code. In fact, with explicit interface implementation, you can't even use access modifiers.
One of the reasons for taking this approach is to force better coding practices. If you're the developer of this class, and you know it should only be accessed via an interface, this is the way to force that to happen.
In C#, explicitly implementing an interface by using a sealed method which does nothing but call a protected virtual method allows derived-classes great flexibility with regard to what they want to do with the interface; the method should be given a name other than the name of the interface method (in the above example, it could perhaps be DoSomething_Prot). Explicit interface implementation makes it impossible for a derived class re-implementation to chain to the base-class implementation, but if the only thing the base-class implementation is doing is chaining to a protected virtual or abstract method, there's no need for a derived class to re-implement the interface. Further, even if the derived class were to re-implement the interface either deliberately or as a result of covariance it would still be able to invoke the "guts" of the base-class implementation using the protected method from the base class.
Putting all the code for the interface implementation in a public virtual method which implicitly implements the interface is better than putting code in an explicit implementation, since derived-class code can generally chain to the private member. Such an approach, however, requires that all derived classes publicly implement the method with the same signature. While it may seem like what one would naturally expect anyway, it isn't always. For example, in the above example a derived class may wish to have its DoSomething method return a type other than IEnumerable<object> (e.g. it might return an IList<Kangaroo>). The method which implements the interfae would still have to return precise type IList<Kangaroo>, but code that knew it was dealing with the derived type could use the return type as an IList<Kangaroo> without a typecast. If the actual code for the method were in a method called DoSomething_Prot(), the derived class could both override DoSomething_Prot and declare a new public IList<Kangaroo> DoSomething(). If the base-class method were called DoSomething(), there would be no way for the derived class to both override it and define a new method with a different return type.
Off the top of my head I'm having trouble of thinking of a practical use for this, but one thing that this accomplishes is that objects of type MyBase or its subclasses do not have a public or internally visible DoSomething() method:
MyClass a = new MyClass();
a.DoSomething(); // Compile error
but the DoSomething() method is visible when the object is used as an IInterface:
void AMethod(IInterface i)
{
i.DoSomething(); // compiles just fine
}
void AnotherMethod(MyBase a)
{
AMethod(a); // as does this
}
Making the non-explicit version protected virtual allows subclasses to override the behavior of the DoSomething() method.
This is a way of implementing a method that cannot be called directly when working with MyBases as MyBases, but can be used when they are being treated as IInterfaces. There's nothing to prevent someone from doing this: ((IInterface)a).DoSomething(); but it seems the hiding is done for semantic reasons.
My take on this is that it is an implementation of the template pattern as described here. Typically you see the template pattern used along with the strategy pattern. In your particular example, users of the IInterface could call the DoSomething
method without regard for how the concrete subclass implemented the method.
This kind of OO programming allows you to take advantage of quite a few other patterns such as the AbstractFactory for creating your concrete subclasses of MyBase which implement IInterface.
The important thing to note is that the two DoSomething methods have nothing to do with each other - they just happen to have the same name.
Basically, you've just got a normal interface that exposes a DoSomething method, so the caller who has a IInterface object can call it. It will then in turn pass the call on to the appropriate implementation of the protected DoSomething method, which can either be from the base class or the derived one.
Explicit implementation like this forces you to code by contract instead of implementation - doesn't really provide any actual protection, just makes it more difficult to accidentally use the wrong type when you declare your variable. They just as easily could have done:
public abstract class MyBase : IInterface {
public virtual IEnumerable<object> DoSomething() {
// blah
}
}
public class MyClass : MyBase {
public override IEnumerable<object> DoSomething() {
// blah
}
}
but that would let you call DoSomething on a variable declared as MyClass or MyBase, which you may not want them to do.

Is an interface and an abstract class with just virtual abstract methods the same thing?

If I have a project that contains similar classes and some may use the same implementation, but in most cases they implement their own way of handling the methods defined in an interface or abstract class. I am trying to figure out if an interface/abstract class is better or not. I don't get the point of an interface if you can just use an abstract class with virtual abstract methods.
Here is an interface:
public interface IAthlete
{
void Run();
}
Here is an abstract class:
public abstract class Athlete
{
public abstract void Run();
}
Here is an implementation of the interface:
public class Sprinter : IAthlete
{
public void Run()
{
Console.WriteLine("Running Fast....");
}
}
Here is an extension of the abstract class:
public class MarathonRunner : Athlete
{
public override void Run()
{
Console.Write("Jogging....");
}
}
Now if I decide to add a method called Stop to either the interface or abstract method, Sprinter and MarathonRunner both break and because I can provide some default implementation to abstract, it seems like a better choice. Am I missing something?
There are 2 main differences between Interfaces and abstract super-classes:
Abstract Classes
code reuse is possible by using an abstract super-class
you can only inherit one super-class
Interfaces
every method has to be implemented in each sub-class
a class can inherit more than 1 interface (multiple inheritance)
In the case where all you have is one piece of commonality to extract, you're quite right that there isn't a substantive difference between the two. But this is rather like saying "in the case of adding 1 to 2, there's no difference between an int and a double" - it's technically true, but not a particularly useful guide to how to think.
In case with any more complexity than this (that is, in most cases) there will be more classes, and pieces of common baheaviour to extract. Then you have to start making a significant choice between class inheritance and interface implementation, taking into account things like:
you only get one shot at choosing a base class, but you can implement as many interfaces as you like
if you want your 'parent' to do any work, it needs to be a class not an interface
and so on.
In general, the semantics of your classes should guide you - where the 'things' have an "IS A" relationship (like MarathonRunner to Athlete), inheritance is suggested; where the 'things' have an "I CAN FULFIL THE CONTRACT OF A" (like, say, Person to Runner), interface implementation is suggested.
Interfaces are a btter way to go as the current consensus amongst the .NET developer comunity is that you should favour composition over inheritance, so Interfaces are a much better strategy (think of Injection Containers and how usefull they are as well, and lets not get started on unit testing).
also, classes can implement many interfaces but can only inherit from one class (abstract or otherwise). also structs can implement interfaces but not inherit from another class.
At the runtime level, interfaces are more efficient as the runtime doesnt have to walk the inheritance stack in order to work out the polymorphic implications of calling a specific member.
Interfaces are a very useful feature, and are very similar to abstract classes, and in some circumstances, exchangable with abstract classes.
But, don't jump straight to interfaces, unleass you have to (very common antipattern in Java developers). I suggest, by reading your example, to stick to abstract classes.
Most of the times I only use interfaces, when I have several non related classes, and I need them to have common members, as If these classes came from the same base class.
In your example, you are trying to find what happen if you need a new stop method, when adding a base virtual method. These can be solved in a different approach, that is not Abstract Classes versus interfaces.
There are 3 choices:
(1) Add an abstract method that coerce the programmer to override it, in order to instantiate objects.
(2) Add a new virtual method that does something, but doesn't have to be overriden.
(3) Add a new method that does nothing, maybe applies to your case.
// cannot instantiate an abstract class
public abstract class Athlete
{
// helper method:
public /* non-abstract */ void DoNothing()
{
// does nothing on purpouse !!!
}
// (1) virtual & abstract method, must be overriden
public abstract void Run();
// (2) new virtual method, doesn't need to be overriden,
// but, maybe you dont like what it does
public virtual void Stop()
{
Message.Show("Stop !!!");
}
// (3) new virtual method, doesn't need to be overriden,
// its safe to be called
public virtual void TakeBreak()
{
// works like an abstract virtual method, but, you don't need to override
DoNothing();
}
} // class Athlete
// in a non abstract class, you must override all abstract methods
public /* non-abstract */ class Runner: Athlete
{
public override void Run()
{
DoNothing();
}
public override void Stop()
{
DoNothing();
}
// don't need to override this method
// public virtual void TakeBreak();
} // class Trekker
// ...
Runner ARunner = new Runner();
ARunner.Run();
ARunner.Stop();
ARunner.TakeBreak();
The third kind of virtual method, that may apply to your example, doesnt' have a special name, I already post a question about it on stackoverflow, but, nobody knew an special name for this case.
Cheers.
An important difference between interfaces and abstract classes is how their members handle multi-generational inheritance. Suppose there's an abstract class BaseFoo with abstract method Bar and interface IFoo with method Boz; class Foo inherits BaseFoo and implements IFoo, and class DerivedFoo inherits from Foo.
If DerivedFoo needs to override BaseFoo.Bar, it may do so, and its override may call base.Bar() if it needs to use its parent's implementation. If Foo implements Boz implicitly using a virtual method, then DerivedFoo may override that method and call base.Boz() (the override being a function of the class rather than the interface) but if Foo explicitly implements IFoo.Boz, then the only way for DerivedFoo to change the behavior of IFoo.Boz will be to re-implement it. If it does so, then Foo's implementation of IFoo.Boz will become inaccessible, even within DerivedFoo's implementation of the same interface member.

abstract method use vs regular methods

I would like to know the difference between two conventions:
Creating an abstract base class with an abstract method
which will be implemented later on the derived classes.
Creating an abstract base class without abstract methods
but adding the relevant method later on the level of the derived classes.
What is the difference?
Much like interfaces, abstract classes are designed to express a set of known operations for your types. Unlike interfaces however, abstract classes allow you to implement common/shared functionality that may be used by any derived type. E.g.:
public abstract class LoggerBase
{
public abstract void Write(object item);
protected virtual object FormatObject(object item)
{
return item;
}
}
In this really basic example above, I've essentially done two things:
Defined a contract that my derived types will conform to.
Provides some default functionality that could be overriden if required.
Given that I know that any derived type of LoggerBase will have a Write method, I can call that. The equivalent of the above as an interface could be:
public interface ILogger
{
void Write(object item);
}
As an abstract class, I can provide an additional service FormatObject which can optionally be overriden, say if I was writing a ConsoleLogger, e.g.:
public class ConsoleLogger : LoggerBase
{
public override void Write(object item)
{
Console.WriteLine(FormatObject(item));
}
}
By marking the FormatObject method as virtual, it means I can provide a shared implementation. I can also override it:
public class ConsoleLogger : LoggerBase
{
public override void Write(object item)
{
Console.WriteLine(FormatObject(item));
}
protected override object FormatObject(object item)
{
return item.ToString().ToUpper();
}
}
So, the key parts are:
abstract classes must be inherited.
abstract methods must be implemented in derived types.
virtual methods can be overriden in derived types.
In the second scenario, because you wouldn't be adding the functionality to the abstract base class, you couldn't call that method when dealing with an instance of the base class directly. E.g., if I implemented ConsoleLogger.WriteSomethingElse, I couldn't call it from LoggerBase.WriteSomethingElse.
The idea of putting abstract methods in a base class and then implementing them in subclasses is that you can then use the parent type instead of any specific subclass. For example say you want to sort an array. You can define the base class to be something like
abstract class Sorter {
public abstract Array sort(Array arr);
}
Then you can implement various algorithms such as quicksort, mergesort, heapsort in subclasses.
class QuickSorter {
public Array sort(Array arr) { ... }
}
class MergeSorter {
public Array sort(Array arr) { ... }
}
You create a sorting object by choosing an algorithm,
Sorter sorter = QuickSorter();
Now you can pass sorter around, without exposing the fact that under the hood it's a quicksort. To sort an array you say
Array sortedArray = sorter.sort(someArray);
In this way the details of the implementation (which algorithm you use) are decoupled from the interface to the object (the fact that it sorts an array).
One concrete advantage is that if at some point you want a different sorting algorithm then you can change QuickSort() to say MergeSort in this single line, without having to change it anywhere else. If you don't include a sort() method in the parent, you have to downcast to QuickSorter whenever calling sort(), and then changing the algorithm will be more difficult.
In the case 1) you can access those methods from the abstract base type without knowing the exact type (abstract methods are virtual methods).
The point of the abstract classes is usually to define some contract on the base class which is then implemented by the dervied classes (and in this context it is important to recognize that interfaces are sort of "pure abstract classes").
Uhm, well, the difference is that the base class would know about the former, and not about the latter.
In other words, with an abstract method in the base class, you can write code in other methods in the base class that call that abstract method.
Obviously, if the base class doesn't have those methods... you can't call them...
An abstract function can have no functionality. You're basically saying, any child class MUST give their own version of this method, however it's too general to even try to implement in the parent class. A virtual function, is basically saying look, here's the functionality that may or may not be good enough for the child class. So if it is good enough, use this method, if not, then override me, and provide your own functionality...
And of course, if you override a virtual method, you can always refer to the parent method by calling base.myVirtualMethod()
Okay, when you see a method like this:
A.Foo();
What you really have (behind the scenes) is a signature like this.
Foo(A x);
And when you call A.Foo() you're really calling Foo(this) where this is a reference to an object of type A.
Now, sometimes you'd like to have Foo(A|B|C|D...) where Foo is a method that can take either a type A, or B, or C, or D. But you don't want to worry about what type you're passing, you just want it to do something different based on the type that was passed in. Abstract methods let you do that, that's their only purpose.

How to partially implement a contract in an abstract base class?

I have a interface as follows
public interface IX
{
void MethodA();
void MethodB();
}
I have two method contracts in the interface MethodA and MethodB. I will define set of classes that will implement the above interface. Out of these two methods MethodA is common for all the types that will implement the interface. I can define a abstract class as follows
public abstract class XBase:IX
{
public void MethodA()
{
// Common behaviour implementation
}
public abstract void MethodB();
}
And inherit this class to all the types that need to implement the above interface. It works.
But here in the abstract class i add 'public abstract void MethodB();'. It looks like repetition of the MethodB contract.
Why C# does not permit partial interface implementation if the class is abstract?. The above interface has only two methods. suppose one interface has 10 methods and 5 are common functionality and 5 are not, we are forced to add the 5 methods that are not common in the abstract class?
Because the C# language specification says so. Chapter 13.4.7:
Like a non-abstract class, an abstract class must provide implementations of all members of the interfaces that are listed in the base class list of the class.
Why the C# designers chose to specify the language like this is probably best answered by Eric Lippert. I'd personally guess at reducing the odds that unintended method hiding occurs, producing error messages that are very hard to interpret. I would personally have been more comfortable requiring the use of the overrides keyword for the interface method implementation. But they chose not to.
The reason it doesn't support this is because your superclass doesn't fulfil the contract. The only way for an abstract class to force implementation on its subclasses is to define abstract methods.
If you don't want the abstract class to have those abstract methods defined then you have to tell the subclasses to implement the interface instead.
Question would have to be, why would it be a problem having 5 abstract methods on your superclass?
Interfaces do pass along the contract requirement to each other, so as far as you have IFoo and IBar : IFoo, then classes inheriting from IBar must implement both interfaces, as clearly IBar cannot implement the members of IFoo itself. Why this behavior could not be extended to abstract base classes, I don't know. I'm sure there is a good reason, and since Hans posted the spec, it's obviously intentional.
As a please do not try this at home approach, you could do something like
class Derived : Base, IFoo
{
public void MethodB()
{
}
}
abstract class Base
{
public Base()
{
if (!(this is IFoo))
throw new InvalidOperationException("must implement IFoo");
}
public void MethodA() { }
}
interface IFoo
{
void MethodA();
void MethodB();
}
Which has the abstract base implement the methods it wants and then force the derived classes to implement the rest by enforcing that the derived classes implement the interface. The derived classes would then be responsible for implementing the methods that are not already in the base class. The problem with this approach is that this is a runtime requirement, not compile time.
How would you handle a situation where you have
interface IFoo {
void MethodA();
void MethodB();
}
abstract class Base: IFoo {
public void MethodA() {}
// MethodB gets implicitly generated
}
class Derived: Base {
public void MethodB() {}
}
Could you then do this:
Base myBase = ...
myBase.MethodB();
Ok you could, since MethodB is implicit. But what if you would later decide to remove the interface IFoo from the Base class? You just broke the Base's contract..Solution would be that generated methods would be explicit interface implementations, but that brings another kind of pain.
You can switch from 'abstract' to 'virtual' in the method declaration and provide an assertion:
public abstract void MethodB();
becomes
public virtual void MethodB()
{
Contract.Require( your condition );
}
I don't think abstract class or interface is doing any injustice in your scenario rather as per SOLID principles (specifically: Interface Segregation Principle) : https://msdn.microsoft.com/en-us/library/dn178470(v=pandp.30).aspx
It says large interfaces should be split into smaller and more specific ones so that client classes are not forced to implement methods they do not use at all. Utilizing this principle would solve your problem.

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