I have XML-based config for application shortcuts bindings. i need to parse it.
<ShortcutBinding>
<ShortcutHandler Name ="Retail.Application.Documents.Outcome.Presentation.OutcomePresenter">
<Shortcut Name="EditHeader">
<Key>CTRL</Key>
<Key>F4</Key>
</Shortcut>
<Shortcut Name="EditItem">
<Key>F4</Key>
</Shortcut>
</ShortcutHandler>
</ShortcutBinding>
I know that .Net has attributes for deserializing XML into objects.
Can anyone write complete example for such deserialization, using attributes.
public class ShortcutBinding
{
public ShortcutHandler ShortcutHandler { get; set; }
}
public class ShortcutHandler
{
[XmlAttribute]
public string Name { get; set; }
[XmlElement("Shortcut")]
public List<Shortcut> Shortcuts { get; set; }
}
public class Shortcut
{
[XmlAttribute]
public string Name { get; set; }
[XmlElement("Key")]
public List<string> Keys { get; set; }
}
Deserializing:
XmlSerializer serializer = new XmlSerializer(typeof(ShortcutBinding));
var binding = (ShortcutBinding)serializer.Deserialize(XmlReader.Create(path));
Related
I have created a REST Service which sends a response in XML. I have set the response format as XML and created the following Data Contracts:
[DataContract]
public class AuthorisationResult
{
[DataMember]
public string Status { get; set; }
[DataMember]
public Variable[] Variables { get; set; }
}
[DataContract]
public class Variable
{
[DataMember]
public string Name { get; set; }
[DataMember]
public string Type { get; set; }
}
This works ok however the output of the XML is not formatted as I need it. It is showing like this:
<Variables>
<Variable>
<Name>SomeName1</Name>
<Type>SomeType1</Type>
</Variable>
</Variables>
But I want to show it like this:
<Variables>
<Variable Name="SomeName1" Type="SomeType1"/>
</Variables>
Can anyone advise what I change to structure it how I want.
Just add XmlAttribute to the properties
[DataContract]
public class Variable
{
[DataMember, XmlAttribute]
public string Name { get; set; }
[DataMember, XmlAttribute]
public string Type { get; set; }
}
I am trying to Deserialize a xml file of this type
<?xml version="1.0" encoding="UTF-8"?>
<Network>
<ROUTES>
<ROUTE ID="RT_BALA_GLNC_R_162_154_1" DIRECTION="LEFT" ZONE="Richmond_Hill">
<ENTRANCESIGNAL>BALA_GLNC_G162</ENTRANCESIGNAL>
<EXITSIGNAL>BALA_DONS_G154</EXITSIGNAL>
<POINTENDIDS>
<POINTENDID POS="N">PT_BALA_GLNC_W11.TrackPortionConnection</POINTENDID>
<POINTENDID POS="N">PT_BALA_GLNC_W23.TrackPortionConnection</POINTENDID>
</POINTENDIDS>
</ROUTE>
<ROUTE ID="RT_BALA_ORLS_R_111_119_1" DIRECTION="RIGHT" ZONE="Richmond_Hill">
<ENTRANCESIGNAL>BALA_ORLS_G111</ENTRANCESIGNAL>
<EXITSIGNAL>BALA_ORLN_G119</EXITSIGNAL>
<POINTENDIDS>
<POINTENDID POS="N">PT_BALA_ORLS_W1.TrackPortionConnection</POINTENDID>
</POINTENDIDS>
</ROUTE>
<ROUTE ID="RT_BALA_GLNC_R_162D_154_1" DIRECTION="LEFT" ZONE="Richmond_Hill">
<ENTRANCESIGNAL>BALA_GLNC_G162D</ENTRANCESIGNAL>
<EXITSIGNAL>BALA_DONS_G154</EXITSIGNAL>
<POINTENDIDS>
<POINTENDID POS="R">PT_BALA_GLNC_W11.TrackPortionConnection</POINTENDID>
<POINTENDID POS="N">PT_BALA_GLNC_W23.TrackPortionConnection</POINTENDID>
</POINTENDIDS>
</ROUTE>
</ROUTES>
</Network>
I have tried this
class Program
{
static void Main(string[] args)
{
XmlSerializer deserializer = new XmlSerializer(typeof(Network));
TextReader reader = new StreamReader(#"xml File Location");
object obj = deserializer.Deserialize(reader);
Network XmlData = (Network)obj;
reader.Close();
Console.ReadLine();
}
}
[XmlRoot("Network")]
public class Network
{
[XmlElement("ROUTES")]
public List<ROUTE> ROUTES { get; set; }
}
public class ROUTE
{
[XmlAttribute("ID")]
public string ID { get; set; }
[XmlAttribute("DIRECTION")]
public string DIRECTION { get; set; }
[XmlElement("ENTRANCESIGNAL")]
public string ENTRANCESIGNAL { get; set; }
[XmlElement("EXITSIGNAL")]
public string EXITSIGNAL { get; set; }
[XmlElement("POINTENDIDS")]
public POINTENDIDS POINTENDIDS { get; set; }
}
public class POINTENDIDS
{
[XmlElement("POINTENDID")]
public List<POINTENDID> POINTENDID { get; set; }
}
public class POINTENDID
{
[XmlAttribute("POS")]
public string POS { get; set; }
}
I am doing it in a console application,
I started Debugging and put breakpoint on Network XmlData = (Network)obj;
I've got only 1 ROUTES and the values of "ID", "DIRECTION", "ENTRANCESIGNAL" ...etc are set to Null
being beginner in c# programming , I don't really understand what should I do !
Need help for this implementation
Fix you Network Class. The names in square brackets are case sensitive. You also need to add the Xml array attributes.
[XmlRoot("Network")]
public class Network
{
[XmlArrayItem("ROUTE")]
[XmlArray("ROUTES")]
public List<ROUTE> ROUTES { get; set; }
}
using System.Xml; //XmlDoc
using System.Xml.Linq;//XElement
using System.IO;//Path,File,Directory, Stream
Read and parse xml file:
XmlDocument XmlDoc = new XmlDocument();
XmlDoc.Load(XmlFilePath);
Another approach is using XElement instead:
XElement a = XElement.Load(#"c:\path\file");
Most often I prefer XElement over XmlDocument, but that's personal
If you are starting with C#, you'd need a book, and a simpler project. Streams and Xml are syntactically complex. Also, console apps are ugly, and Forms apps are not that hard to do with the graphical tools of VisualStudio.
Your C# classes are not exactly aligned with the XML file and the serializer returns only a partial result. What you can do instead if the XML structure is fixed is outlined here.
https://stackoverflow.com/a/17315863/99804
This then works as you want it to.
You will get the following auto-generated code.
Note: I have cleaned up the output to use auto-properties etc.
using System;
using System.Xml.Serialization;
// NOTE: Generated code may require at least .NET Framework 4.5 or .NET Core/Standard 2.0.
/// <remarks />
[Serializable]
[XmlType(AnonymousType = true)]
[XmlRoot(Namespace = "", IsNullable = false)]
public class Network
{
/// <remarks />
[XmlArrayItem("ROUTE", IsNullable = false)]
public NetworkROUTE[] ROUTES { get; set; }
}
[Serializable]
[XmlType(AnonymousType = true)]
public class NetworkROUTE
{
[XmlAttribute]
public string DIRECTION { get; set; }
public string ENTRANCESIGNAL { get; set; }
public string EXITSIGNAL { get; set; }
[XmlAttribute]
public string ID { get; set; }
[XmlArrayItem("POINTENDID", IsNullable = false)]
public NetworkROUTEPOINTENDID[] POINTENDIDS { get; set; }
[XmlAttribute]
public string ZONE { get; set; }
}
[Serializable]
[XmlType(AnonymousType = true)]
public class NetworkROUTEPOINTENDID
{
[XmlAttribute]
public string POS { get; set; }
[XmlText]
public string Value { get; set; }
}
<TotalRecords ItineraryCount='1' >
<Recs ItineraryNumber="1" >
<Amount>516.6</Amount>
<TravelTime>940</TravelTime>
<FSegment>
<OutProperty>
<Segment No="1">
<Name>Ronald</Name>
<City>London</City>
<Country>United Kingdom</Country>
</Segment>
<Segment No="2">
<Name>Richard</Name>
<City>
London
</City>
<Country>United Kingdom</Country>
</Segment>
</OutProperty>
</FSegment>
</Recs>
</TotalRecords >
I am serializing xml to object of TotalRecords Class. It works fine when there are more than one segment in the OutProperty but in case of one segment it doesn't serialize into list property.
I have also tried with [XmlArray("")] and [XMlArrayItem("")] but it doesn't work. Anyone have idea?
public class TotalRecords
{
public Recs recs { get; set; }
public string ItineraryCount { get; set; }
}
public partial class Recs
{
public string amountField { get; set; }
public string travelTimeField { get; set; }
public FSegment fSegmentField { get; set; }
public string itineraryNumberField { get; set; }
}
public class FSegment
{
public List<Segment> OutProperty {get;set;}
}
public class Segment
{
public string nameField { get; set; }
public string cityField { get; set; }
public string countryField { get; set; }
}
Try to use the following for your Classes and their Properties:
[DataContract]
public class Contact
{
[DataMember]
public int Id { get; set; }
[DataMember]
public string Name { get; set; }
}
Hacking like this helps in many cases, perhaps in your too (converting List to array):
public class FSegment
{
[XmlIgnore]
public List<Segment> OutProperty {get;set;}
[XmlArray("OutProperty");
public Segment[] _OutProperty
{
get { return OutProperty.ToArray(); }
set { OutProperty = new List<Segment>(value); }
}
}
I am not exactly sure how your provided class definition worked previously without any XML attribute/element definitions since your variable names are not the same as the XML identifiers, meaning that the serialization wouldn't populate the properties that it couldn't find a name for.
Nether the less, the main issue here is that you are trying to put a list into a normal property.
From the XML provided, OutProperty is a single sub element of FSegment and Segment is an array of sub elements of OutProperty, but in your provided code, you tried to make Segment an array sub element of FSegment.
The correct structure of the class definition should be as follows (also including the XML definitions)
[System.Xml.Serialization.XmlRoot(ElementName="TotalRecords")]
public class TotalRecords
{
[System.Xml.Serialization.XmlElement(ElementName="Recs")]
public Recs recs { get; set; }
[System.Xml.Serialization.XmlAttribute(AttributeName = "ItineraryCount")]
public string ItineraryCount { get; set; }
}
public partial class Recs
{
[System.Xml.Serialization.XmlElement(ElementName = "Amount")]
public string amountField { get; set; }
[System.Xml.Serialization.XmlElement(ElementName = "TravelTime")]
public string travelTimeField { get; set; }
[System.Xml.Serialization.XmlElement(ElementName = "FSegment")]
public FSegment fSegmentField { get; set; }
[System.Xml.Serialization.XmlAttribute(AttributeName = "ItineraryNumber")]
public string itineraryNumberField { get; set; }
}
public class FSegment
{
[System.Xml.Serialization.XmlElement(ElementName = "OutProperty")]
public SegmentList OutProperty { get; set; }
}
public class SegmentList
{
[System.Xml.Serialization.XmlElement(ElementName = "Segment")]
public List<Segment> segmentField { get; set; }
}
public class Segment
{
[System.Xml.Serialization.XmlElement(ElementName = "Name")]
public string nameField { get; set; }
[System.Xml.Serialization.XmlElement(ElementName = "City")]
public string cityField { get; set; }
[System.Xml.Serialization.XmlElement(ElementName = "Country")]
public string countryField { get; set; }
[System.Xml.Serialization.XmlAttribute(AttributeName = "No")]
public int segmentNoField { get; set; }
}
Please note that in the above structure, Segment is a list object under the OutProperty object, which resides under the FSegment object.
Using this class structure to load your XML produces the (assumed) correct data in the created objects.
Using the XML definitions allows you to decouple the actual names of class properties from what they are called in the XML data. This allows you to changes the one or the other without affecting the other one, which is useful when you don't control the creation of the XML data.
If you don't want all the XML definitions in your code, change the names of the classes so that you can name your properties the same as what they are called in the XML file. That will allow you couple everything directly
I've created a object that is serializable and I want to serialize it to XML and then later deserialize back. What I want though is to save one property of this object as XML attribute. Here is what I mean:
[Serializable]
public class ProgramInfo
{
public string Name { get; set; }
public Version Version { get; set; }
}
public class Version
{
public int Major { get; set; }
public int Minor { get; set; }
public int Build { get; set; }
}
I want to save ProgramInfo to XML file that looks like this:
<?xml version="1.0" encoding="utf-8" ?>
<ProgramInfo Name="MyApp" Version="1.00.0000">
</ProgramInfo>
Notice the Version property and its corresponding attribute in XML. I already have parser that turns string "1.00.0000" to valid Version object and vice-versa, but I don't know how to put it to use with this XML serialization scenario.
What you need is a property for the string representation that gets serialized:
[Serializable]
public class ProgramInfo
{
[XmlAttribute]
public string Name { get; set; }
[XmlIgnore]
public Version Version { get; set; }
[XmlAttribute("Version")
public string VersionString
{
get { return this.Version.ToString(); }
set{ this.Version = Parse(value);}
}
}
What you could do is have a VersionValue and a VersionType Property
[Serializable]
public class ProgramInfo
{
private string _versionValue;
public string Name { get; set; }
public string VersionValue
{
get
{
return _versionValue;
}
set{
_versionValue = value;
//Private method to parse
VersonType = parseAndReturnVersionType(value);
}
}
public Version VersionType { get; set; }
}
I want to deserialize the following xml into my class, i can't change the xml because it commes from a device over tcp/ip.
<?xml version="1.0" encoding="utf-8"?>
<CONTACTINFORMATION UID="1234">
<LoginId><![CDATA[1234]]></LoginId>
<ContactId><![CDATA[2134]]></ContactId>
<ContactType>CCININTERN</ContactType>
<Status>CONVERSATION</Status>
<From><![CDATA[123]]></From>
<To><![CDATA[123]]></To>
<WaitTime><![CDATA[123]]></WaitTime>
<ContactPropertySummary>
<ContactProperty>
<Name><![CDATA[13]]></Name>
<Value><![CDATA[13]]></Value>
<Hidden>NO</Hidden>
<Url><![CDATA[13]]></Url>
</ContactProperty>
</ContactPropertySummary>
<SkillSummary>
<Skill>
<Name><![CDATA[123]]></Name>
<Mandatory>YES</Mandatory>
</Skill>
<Skill>
<Name><![CDATA[124]]></Name>
<Mandatory>YES</Mandatory>
</Skill>
</SkillSummary>
<ContactCodeSummary>
<ContactCode>
<Id>123</Id>
<Hidden>NO</Hidden>
<Assigned>YES</Assigned>
</ContactCode>
</ContactCodeSummary>
<GroupSummary>
<Group>
<Name><![CDATA[123]]></Name>
<Mandatory>YES</Mandatory>
</Group>
</GroupSummary>
<PreviousAgent><![CDATA[2]]></PreviousAgent>
<ScratchPadId><![CDATA[2]]></ScratchPadId>
<ScratchPadData><![CDATA[2]]></ScratchPadData>
<FaxSpecific>
<NbrOfPages>2</NbrOfPages>
</FaxSpecific>
</CONTACTINFORMATION>
My class:
[Serializable]
[XmlRoot("CONTACTINFORMATION")]
public class Contact
{
#region :: PROPERTIES ::
public string LoginId { get; set; }
public string ContactId { get; set; }
public ContactType ContactType { get; set; }
public ContactStatus Status { get; set; }
[XmlElement("From")]
public string ContactFrom { get; set; }
[XmlElement("To")]
public string ContactTo { get; set; }
public int WaitTime { get; set; }
[XmlElement("SkillSummary", Form = System.Xml.Schema.XmlSchemaForm.Unqualified)]
[XmlArray("Skill")]
//[XmlElement("SkillSummary", Form = System.Xml.Schema.XmlSchemaForm.Unqualified)]
public Skill[] Skills { get; set; }
[XmlArray("ContactPropertySummary")]
public ContactProperty[] Properties { get; set; }
[XmlArray("GroupSummary", Form = System.Xml.Schema.XmlSchemaForm.Unqualified)]
[XmlArrayItem("Group", typeof(Group), Form = System.Xml.Schema.XmlSchemaForm.Unqualified)]
public Group[] Groups { get; set; }
}
The arry of skills has 2 skills, after deserializing there is only 1 skill in the arry, the groups and properties array is null...
What i'm doing wrong?
You should properly decorate array properties with XmlArray and XmlArrayItem attributes. For e.g. for skills property you are using XmlElement with XmlArray which is not permitted.
[XmlArrayItem("Skill", typeof(Skill), Form = System.Xml.Schema.XmlSchemaForm.Unqualified)]
[XmlArray("SkillSummary", Form = System.Xml.Schema.XmlSchemaForm.Unqualified)]
public Skill[] Skills
{
get;
set;
}
[XmlArray("ContactPropertySummary")]
[XmlArrayItem("ContactProperty", typeof(ContactProperty), Form = System.Xml.Schema.XmlSchemaForm.Unqualified)]
public ContactProperty[] Properties
{
get;
set;
}
[XmlArray("GroupSummary", Form = System.Xml.Schema.XmlSchemaForm.Unqualified)]
[XmlArrayItem("Group", typeof(Group), Form = System.Xml.Schema.XmlSchemaForm.Unqualified)]
public Group[] Groups
{
get;
set;
}
Make Sure that xmlArrayItem 'types' have proper read/write properties
public class Skill
{
public string Name
{
get;
set;
}
public string Mandatory
{
get;
set;
}
}
I recommend you to provide as much information to the XMLSerializer, through attributes, as you can.
You don't seem to be too off the mark. Using the above definitions I was able to successfully deserialize the XML you provided.
Start by defining a class Skill and then using this class in your Contract class.
// We're going to define a class called Skill
[Serializable()]
public class Skill
{
[System.Xml.Serialization.XmlElement("Name")]
public string Name { get; set; }
[System.Xml.Serialization.XmlElement("Mandatory")]
public string Mandatory { get; set; }
}
[Serializable]
[XmlRoot("CONTACTINFORMATION")]
public class Contact
{
// ...... Rest of your elements
[XmlArray("SkillSummary")]
[XmlArrayItem("Skill", typeof(Skill))]
public Skills[] Skill { get; set; }
}
Please do the same for Groups and Properties as well.