How to serialize object's property to XML element's attribute? - c#

I've created a object that is serializable and I want to serialize it to XML and then later deserialize back. What I want though is to save one property of this object as XML attribute. Here is what I mean:
[Serializable]
public class ProgramInfo
{
public string Name { get; set; }
public Version Version { get; set; }
}
public class Version
{
public int Major { get; set; }
public int Minor { get; set; }
public int Build { get; set; }
}
I want to save ProgramInfo to XML file that looks like this:
<?xml version="1.0" encoding="utf-8" ?>
<ProgramInfo Name="MyApp" Version="1.00.0000">
</ProgramInfo>
Notice the Version property and its corresponding attribute in XML. I already have parser that turns string "1.00.0000" to valid Version object and vice-versa, but I don't know how to put it to use with this XML serialization scenario.

What you need is a property for the string representation that gets serialized:
[Serializable]
public class ProgramInfo
{
[XmlAttribute]
public string Name { get; set; }
[XmlIgnore]
public Version Version { get; set; }
[XmlAttribute("Version")
public string VersionString
{
get { return this.Version.ToString(); }
set{ this.Version = Parse(value);}
}
}

What you could do is have a VersionValue and a VersionType Property
[Serializable]
public class ProgramInfo
{
private string _versionValue;
public string Name { get; set; }
public string VersionValue
{
get
{
return _versionValue;
}
set{
_versionValue = value;
//Private method to parse
VersonType = parseAndReturnVersionType(value);
}
}
public Version VersionType { get; set; }
}

Related

Json class saving a value while containing other default values

Hey all I am trying to figure out how to go about saving just one value in my JSON class instead of having to write the whole JSON out again with "New". I am using the Newton JSON.Net.
This is my JSON structure:
public class GV
{
public class Data
{
[JsonProperty("pathForNESPosters")]
public static string PathForNESPosters { get; set; }
[JsonProperty("pathForSNESPosters")]
public static string PathForSNESPosters { get; set; }
[JsonProperty("pathForSEGAPosters")]
public static string PathForSEGAPosters { get; set; }
[JsonProperty("pathToNESContent")]
public static string PathToNESContent { get; set; }
[JsonProperty("pathToSNESContent")]
public static string PathToSNESContent { get; set; }
[JsonProperty("pathToSEGAContent")]
public static string PathToSEGAContent { get; set; }
[JsonProperty("lastSavedVolume")]
public static double LastSavedVolume { get; set; }
}
public class Root
{
public Data data { get; set; }
}
And I have no issues with loading that data from a file into my class:
GV.Root myDeserializedClass = JsonConvert.DeserializeObject<GV.Root>(File.ReadAllText(
currentAssemblyPath + String.Format(#"\Resources\{0}", "dataForLinks.json")
));
But I have yet to find anything searching that will let me do one update to an object in the class without wiping it out doing a New statement.
What I am wanting to do is something like the following:
-Load the json into my class object [Done]
-Save a value thats in my class object [stuck here]
GV.pathToNESContent = "new value here";
-Save class object (with the one new value) back to the file for which it came from preserving the other original values. [not here yet]
When I update just that one class object I am wanting to contain the original values for all the other JSON data I read in from the file.
Anyone have a good example of the above you can share?
update
I'd ditch the inner class structure:
namespace GV
{
public class Data
{
[JsonProperty("pathForNESPosters")]
public string PathForNESPosters { get; set; }
[JsonProperty("pathForSNESPosters")]
public string PathForSNESPosters { get; set; }
[JsonProperty("pathForSEGAPosters")]
public string PathForSEGAPosters { get; set; }
[JsonProperty("pathToNESContent")]
public string PathToNESContent { get; set; }
[JsonProperty("pathToSNESContent")]
public string PathToSNESContent { get; set; }
[JsonProperty("pathToSEGAContent")]
public string PathToSEGAContent { get; set; }
[JsonProperty("lastSavedVolume")]
public double LastSavedVolume { get; set; }
}
public class Root
{
public Data Data { get; set; }
}
Deser (use Path.Combine to build paths, not string concat):
var x = JsonConvert.DeserializeObject<GV.Root>(File.ReadAllText(
Path.Combine(currentAssemblyPath, "Resources", "dataForLinks.json"))
));
Edit:
x.Data.PathToNESContent = "...";
and re-ser

Xml Serialization for list Property doesn't work when one item in the list

<TotalRecords ItineraryCount='1' >
<Recs ItineraryNumber="1" >
<Amount>516.6</Amount>
<TravelTime>940</TravelTime>
<FSegment>
<OutProperty>
<Segment No="1">
<Name>Ronald</Name>
<City>London</City>
<Country>United Kingdom</Country>
</Segment>
<Segment No="2">
<Name>Richard</Name>
<City>
London
</City>
<Country>United Kingdom</Country>
</Segment>
</OutProperty>
</FSegment>
</Recs>
</TotalRecords >
I am serializing xml to object of TotalRecords Class. It works fine when there are more than one segment in the OutProperty but in case of one segment it doesn't serialize into list property.
I have also tried with [XmlArray("")] and [XMlArrayItem("")] but it doesn't work. Anyone have idea?
public class TotalRecords
{
public Recs recs { get; set; }
public string ItineraryCount { get; set; }
}
public partial class Recs
{
public string amountField { get; set; }
public string travelTimeField { get; set; }
public FSegment fSegmentField { get; set; }
public string itineraryNumberField { get; set; }
}
public class FSegment
{
public List<Segment> OutProperty {get;set;}
}
public class Segment
{
public string nameField { get; set; }
public string cityField { get; set; }
public string countryField { get; set; }
}
Try to use the following for your Classes and their Properties:
[DataContract]
public class Contact
{
[DataMember]
public int Id { get; set; }
[DataMember]
public string Name { get; set; }
}
Hacking like this helps in many cases, perhaps in your too (converting List to array):
public class FSegment
{
[XmlIgnore]
public List<Segment> OutProperty {get;set;}
[XmlArray("OutProperty");
public Segment[] _OutProperty
{
get { return OutProperty.ToArray(); }
set { OutProperty = new List<Segment>(value); }
}
}
I am not exactly sure how your provided class definition worked previously without any XML attribute/element definitions since your variable names are not the same as the XML identifiers, meaning that the serialization wouldn't populate the properties that it couldn't find a name for.
Nether the less, the main issue here is that you are trying to put a list into a normal property.
From the XML provided, OutProperty is a single sub element of FSegment and Segment is an array of sub elements of OutProperty, but in your provided code, you tried to make Segment an array sub element of FSegment.
The correct structure of the class definition should be as follows (also including the XML definitions)
[System.Xml.Serialization.XmlRoot(ElementName="TotalRecords")]
public class TotalRecords
{
[System.Xml.Serialization.XmlElement(ElementName="Recs")]
public Recs recs { get; set; }
[System.Xml.Serialization.XmlAttribute(AttributeName = "ItineraryCount")]
public string ItineraryCount { get; set; }
}
public partial class Recs
{
[System.Xml.Serialization.XmlElement(ElementName = "Amount")]
public string amountField { get; set; }
[System.Xml.Serialization.XmlElement(ElementName = "TravelTime")]
public string travelTimeField { get; set; }
[System.Xml.Serialization.XmlElement(ElementName = "FSegment")]
public FSegment fSegmentField { get; set; }
[System.Xml.Serialization.XmlAttribute(AttributeName = "ItineraryNumber")]
public string itineraryNumberField { get; set; }
}
public class FSegment
{
[System.Xml.Serialization.XmlElement(ElementName = "OutProperty")]
public SegmentList OutProperty { get; set; }
}
public class SegmentList
{
[System.Xml.Serialization.XmlElement(ElementName = "Segment")]
public List<Segment> segmentField { get; set; }
}
public class Segment
{
[System.Xml.Serialization.XmlElement(ElementName = "Name")]
public string nameField { get; set; }
[System.Xml.Serialization.XmlElement(ElementName = "City")]
public string cityField { get; set; }
[System.Xml.Serialization.XmlElement(ElementName = "Country")]
public string countryField { get; set; }
[System.Xml.Serialization.XmlAttribute(AttributeName = "No")]
public int segmentNoField { get; set; }
}
Please note that in the above structure, Segment is a list object under the OutProperty object, which resides under the FSegment object.
Using this class structure to load your XML produces the (assumed) correct data in the created objects.
Using the XML definitions allows you to decouple the actual names of class properties from what they are called in the XML data. This allows you to changes the one or the other without affecting the other one, which is useful when you don't control the creation of the XML data.
If you don't want all the XML definitions in your code, change the names of the classes so that you can name your properties the same as what they are called in the XML file. That will allow you couple everything directly

Xml Deserialize returms null values but xml has values

I saw few topics but no one looks like my problem.
Here is my class:
namespace Framework.Cielo.Models
{
[XmlRoot("transacao", Namespace = "http://ecommerce.cbmp.com.br")]
public class TransactionResponse
{
[XmlAttribute("id")]
public string ID { get; set; }
[XmlAttribute("versao")]
public string Version { get; set; }
[XmlElement("tid")]
public string tid { get; set; }
[XmlElement("pan")]
public string pan { get; set; }
[XmlElement("dados-pedido")]
public EstablishmentOrder Order { get; set; }
[XmlElement("forma-pagamento")]
public PaymentMethod PaymentMethod { get; set; }
[XmlElement("status")]
public TransactionStatusEnum Status { get; set; }
[XmlElement("url-retorno")]
public string ReturnUrl { get; set; }
[XmlElement("autenticacao")]
public Authentication Authentication { get; set; }
}
}
and here is the authentication class
namespace Framework.Cielo.Models
{
[XmlRoot("autenticacao")]
public class Authentication
{
[XmlElement("codigo")]
public int Code { get; set; }
[XmlElement("mensagem")]
public string Message { get; set; }
[XmlIgnore]
public DateTime Date { get; set; }
[XmlElement("data-hora")]
public string FormattedDate
{
get
{
return Date.ToString("yyyy-MM-ddTHH:mm:ss");
}
set
{
DateTime kdc = DateTime.MinValue;
DateTime.TryParse(value, out kdc);
Date = kdc;
}
}
[XmlElement("valor")]
public int Value { get; set; }
[XmlElement("lr")]
public int SecurityLevel { get; set; }
[XmlElement("arp")]
public object arp { get; set; }
[XmlElement("nsu")]
public object nsu { get; set; }
}
}
Here is how I deserialize:
string serializado = File.ReadAllText("req.xml");
var stringReader = new System.IO.StringReader(serializado);
var serializer = new XmlSerializer(typeof(TransactionResponse));
TransactionResponse preAuthResponse = serializer.Deserialize(stringReader) as TransactionResponse;
and here is my XML:
<?xml version="1.0" encoding="ISO-8859-1"?>
<transacao versao="1.3.0" id="100" xmlns="http://ecommerce.cbmp.com.br">
<tid>10069930690A16DF1001</tid>
<pan>b1SQ6jpKCDt3n9C0dgD/ZkPQ1Bh+7aJESqr/CwP64P0=</pan>
<dados-pedido>
<numero>100</numero>
<valor>29900</valor>
<moeda>986</moeda>
<data-hora>2013-10-15T00:57:19.032-03:00</data-hora>
<descricao/>
<idioma>PT</idioma>
<taxa-embarque>0</taxa-embarque>
</dados-pedido>
<forma-pagamento>
<bandeira>mastercard</bandeira>
<produto>1</produto>
<parcelas>1</parcelas>
</forma-pagamento>
<status>4</status>
<autenticacao>
<codigo>4</codigo>
<mensagem>Transacao sem autenticacao</mensagem>
<data-hora>2013-10-15T00:57:19.037-03:00</data-hora>
<valor>29900</valor>
<eci>0</eci>
</autenticacao>
<autorizacao>
<codigo>4</codigo>
<mensagem>Transação autorizada</mensagem>
<data-hora>2013-10-15T00:57:19.041-03:00</data-hora>
<valor>29900</valor>
<lr>00</lr>
<arp>123456</arp>
<nsu>661215</nsu>
</autorizacao>
</transacao>
When I run this code, all the elements get right, but not ARP and NSU elements (the last 2 of autorizacao tag)
I really don't know why. This XML comes from a web service and I can't figure out why my deserialize don't work with the 2 last items but works greater with any other element.
I have tried with your code and updated following and it works.
Commented second last <autenticacao> tag.
Rename last tag <autorizacao> to <autenticacao> . May be you are getting wrong xml & last two tags are confusing so I have tried with only one tag.
In Authentication class I have changed type of ARP and NSU otherwise we are getting XMlNode type while deserializing. You can also use string instead of int.
[XmlElement("arp")]
public int arp { get; set; }
[XmlElement("nsu")]
public int nsu { get; set; }

XML parsing using attributes

I have XML-based config for application shortcuts bindings. i need to parse it.
<ShortcutBinding>
<ShortcutHandler Name ="Retail.Application.Documents.Outcome.Presentation.OutcomePresenter">
<Shortcut Name="EditHeader">
<Key>CTRL</Key>
<Key>F4</Key>
</Shortcut>
<Shortcut Name="EditItem">
<Key>F4</Key>
</Shortcut>
</ShortcutHandler>
</ShortcutBinding>
I know that .Net has attributes for deserializing XML into objects.
Can anyone write complete example for such deserialization, using attributes.
public class ShortcutBinding
{
public ShortcutHandler ShortcutHandler { get; set; }
}
public class ShortcutHandler
{
[XmlAttribute]
public string Name { get; set; }
[XmlElement("Shortcut")]
public List<Shortcut> Shortcuts { get; set; }
}
public class Shortcut
{
[XmlAttribute]
public string Name { get; set; }
[XmlElement("Key")]
public List<string> Keys { get; set; }
}
Deserializing:
XmlSerializer serializer = new XmlSerializer(typeof(ShortcutBinding));
var binding = (ShortcutBinding)serializer.Deserialize(XmlReader.Create(path));

Serialize Property as Xml Attribute in Element

I have the following class:
[Serializable]
public class SomeModel
{
[XmlElement("SomeStringElementName")]
public string SomeString { get; set; }
[XmlElement("SomeInfoElementName")]
public int SomeInfo { get; set; }
}
Which (when populated with some test data) and Serialized using XmlSerializer.Serialize() results in the following XML:
<SomeModel>
<SomeStringElementName>testData</SomeStringElementName>
<SomeInfoElementName>5</SomeInfoElementName>
</SomeModel>
What I need to have is:
<SomeModel>
<SomeStringElementName Value="testData" />
<SomeInfoElementName Value="5" />
</SomeModel>
Is there a way to specify this as attributes without writing my own custom serialization code?
You will need wrapper classes:
public class SomeIntInfo
{
[XmlAttribute]
public int Value { get; set; }
}
public class SomeStringInfo
{
[XmlAttribute]
public string Value { get; set; }
}
public class SomeModel
{
[XmlElement("SomeStringElementName")]
public SomeStringInfo SomeString { get; set; }
[XmlElement("SomeInfoElementName")]
public SomeIntInfo SomeInfo { get; set; }
}
or a more generic approach if you prefer:
public class SomeInfo<T>
{
[XmlAttribute]
public T Value { get; set; }
}
public class SomeModel
{
[XmlElement("SomeStringElementName")]
public SomeInfo<string> SomeString { get; set; }
[XmlElement("SomeInfoElementName")]
public SomeInfo<int> SomeInfo { get; set; }
}
And then:
class Program
{
static void Main()
{
var model = new SomeModel
{
SomeString = new SomeInfo<string> { Value = "testData" },
SomeInfo = new SomeInfo<int> { Value = 5 }
};
var serializer = new XmlSerializer(model.GetType());
serializer.Serialize(Console.Out, model);
}
}
will produce:
<?xml version="1.0" encoding="ibm850"?>
<SomeModel xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema">
<SomeStringElementName Value="testData" />
<SomeInfoElementName Value="5" />
</SomeModel>
Kind of, use the XmlAttribute instead of XmlElement, but it won't look like what you want. It will look like the following:
<SomeModel SomeStringElementName="testData">
</SomeModel>
The only way I can think of to achieve what you want (natively) would be to have properties pointing to objects named SomeStringElementName and SomeInfoElementName where the class contained a single getter named "value". You could take this one step further and use DataContractSerializer so that the wrapper classes can be private. XmlSerializer won't read private properties.
// TODO: make the class generic so that an int or string can be used.
[Serializable]
public class SerializationClass
{
public SerializationClass(string value)
{
this.Value = value;
}
[XmlAttribute("value")]
public string Value { get; }
}
[Serializable]
public class SomeModel
{
[XmlIgnore]
public string SomeString { get; set; }
[XmlIgnore]
public int SomeInfo { get; set; }
[XmlElement]
public SerializationClass SomeStringElementName
{
get { return new SerializationClass(this.SomeString); }
}
}

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