I have some int values that I want to convert to a string but in hex.
This hex value should be formatted always by 2 digits.
Example below:
int a = 10;
int b = 20;
//returns the value in hex
string c = a.toString("x"); // a
string d = b.toString("x"); // 14
What I want is that always that the hex value results in two digits. Shows like "0a", not only "a".
I'm using convert a int to a formatted string,
int e = 1;
string f = e.toString("D2"); // 01
Have a way to the two things together? To convert the int to a hex formatted string?
you can use this
int e = 1;
string f = e.toString("x2");
Have a way to the two things togheter?
Yes - you just use x2. You already have the hex bit with x and the "2 characters" part with D2 - you just need to combine them.
See the documentation for standard numeric format strings for more information.
Related
I am trying to get 11001 as 11001.000000 , I tried ToString("N6"), but it adds separator and output is as: 11,001.000000
How can get the value as a 6 floating digit without separator?
Use F6 instead of N6
int i = 11001;
string result = i.ToString("F6");
Reference: MSDN
To remove the comma separaytor use can use
System.Threading.Thread.CurrentThread.CurrentCulture.NumberFormat.NumberGroupSeparator
double d = 11001;
string result = d.ToString("F6").Replace(System.Threading.Thread.CurrentThread.CurrentCulture.NumberFormat.NumberGroupSeparator, "");
int i = 11001;
string result = i.ToString("F6");
Here F in ToString() method is fixed point format specifier.
Number next to F can be used accordingly.
ex if you want 11001.00000, then use ToString("F5");
I`m working with C# and I have a problem at converting a string array to a int array.
First I created a string number with the Console
Console.WriteLine("Geben Sie die Nummer ein:");
string wert = Console.ReadLine();
Then I converted the string to a array
char[] wertarray = wert.ToCharArray();
wertarray1 = new string(wertarray);*
And now comes the problem. I want to convert the string array to a int array, but e.g. for string wertarray1[0]=1, the int array has the value 49.
int wertarray2 = Convert.ToInt16(wertarray1[0]);
Normal the Int value should be 1, but I don`t know where the problem is.
I tried the solutions for "convert a string array to a int array" from this forum, but i still had the problem that the int value get a strange number.
I´m looking forward for help.
Thanks :-).
Convert.ToInt16(Char) takes the numeric value of the char (i.e. its Unicode code-point value) and returns that number. While you might think Convert.ToInt16('1') should return 1, consider what would happen if you tried Convert.ToInt16('#') for example.
Use Int16.Parse (or TryParse) to actually parse a string to numbers. As you're working with individual characters to represent 0-9 you might as well do it using simple arithmetic without the need to call any Parse function:
String line = Console.ReadLine();
List<Int16> numbers = new List<Int16>( line.Length );
foreach(Char c in line) {
Int16 charValue = (Int16)c;
if( charValue < 48 || charValue > 57 ) throw new Exception("char is not a digit");
Int16 value = charValue - 48;
numbers.Add( value );
}
Answers provided already explain your problem and provide solution too.
In general, you can convert the char to string and parse them to integer (not the best performance though).
If you have all numeric string
var numStr = "136";
var numbers = numStr.Select(n => int.Parse(n.ToString())).ToList(); // {1, 3, 6}
If your string contains non numbers too
var mixStr = "1.k78Tj_n";
int temp;
var numbers2 = new List<int>();
mixStr.ToList().ForEach(n =>
{
if (int.TryParse(n.ToString(), out temp))
numbers2.Add(temp);
}); //{ 1, 7, 8 }
You're getting the Unicode code point value of the characters in your input stream -- 49 is the unicode value for the character 1.
If you want to convert a unicode character that is a digit to the numeric value of that digit, you can use System.Globalization.CharUnicodeInfo.GetDecimalDigitValue(char c):
var wertarray2 = wert.Select(c => (short)CharUnicodeInfo.GetDecimalDigitValue(c)).ToArray();
This handles all digits (including superscripted numbers) not just the standard ASCII digits.
I need to use HEX() in MySQL to get data out of the database and process in C# WinForm code. The binary string needs to be decoded in C#, is there an equivalent UNHEX() function?
From MySQL Doc:
For a string argument str, HEX() returns a hexadecimal string
representation of str where each byte of each character in str is
converted to two hexadecimal digits. (Multi-byte characters therefore
become more than two digits.) The inverse of this operation is
performed by the UNHEX() function.
For a numeric argument N, HEX() returns a hexadecimal string
representation of the value of N treated as a longlong (BIGINT)
number. This is equivalent to CONV(N,10,16). The inverse of this
operation is performed by CONV(HEX(N),16,10).
mysql> SELECT 0x616263, HEX('abc'), UNHEX(HEX('abc'));
-> 'abc', 616263, 'abc' mysql> SELECT HEX(255), CONV(HEX(255),16,10);
-> 'FF', 255
You can use this not-widely-known SoapHexBinary class to parse hex string
string hex = "616263";
var byteArr = System.Runtime.Remoting.Metadata.W3cXsd2001.SoapHexBinary.Parse(hex).Value;
var str = Encoding.UTF8.GetString(byteArr);
After fetching the binary string from the database, you can "unhex" it this way:
public static string Hex2String(string input)
{
var builder = new StringBuilder();
for(int i = 0; i < input.Length; i+=2){ //throws an exception if not properly formatted
string hexdec = input.Substring(i, 2);
int number = Int32.Parse(hexdec, NumberStyles.HexNumber);
char charToAdd = (char)number;
builder.Append(charToAdd);
}
return builder.ToString();
}
The method builds a string from the hexadecimal format of the numbers, their char representation being concatenated to the builder branch.
I have an integer variable .if its 1-9 it only displays as "1" or "9", I'm looking to convert the variable to save as 3 digits, ie. "001", or "009", etc. any ideas?
I am using C#,ASP.Net
use
int X = 9;
string PaddedResult = X.ToString().PadLeft (3, '0'); // results in 009
see MSDN references here and here.
What about
var result = String.Format("{0:000}", X);
var result2 = X.ToString("000");
int i = 5;
string tVal=i.ToString("000");
From: https://learn.microsoft.com/en-us/dotnet/standard/base-types/standard-numeric-format-strings#DFormatString
The "D" (or decimal) format specifier converts a number to a string of decimal digits (0-9), prefixed by a minus sign if the number is negative.
The precision specifier indicates the minimum number of digits desired in the resulting string. If required, the number is padded with zeros to its left to produce the number of digits given by the precision specifier.
Like:
int value;
value = 12345;
Console.WriteLine(value.ToString("D"));
// Displays 12345
Console.WriteLine(value.ToString("D8"));
// Displays 00012345
value = -12345;
Console.WriteLine(value.ToString("D"));
// Displays -12345
Console.WriteLine(value.ToString("D8"));
// Displays -00012345
int i = 5;
string retVal = i.ToString().PadLeft(3, '0');
you can use this code also
int k = 5;
string name = $"name-{k++:D3}.ext";
i am making application in c#. In that implication i have string which contain decimal value as
string number="12000";
The Hex equivalent of 12000 is 0x2EE0.
Here i want to assign that hex value to integer variable as
int temp=0x2EE0.
Please help me to convert that number.
Thanks in advance.
string input = "Hello World!";
char[] values = input.ToCharArray();
foreach (char letter in values)
{
// Get the integral value of the character.
int value = Convert.ToInt32(letter);
// Convert the decimal value to a hexadecimal value in string form.
string hexOutput = String.Format("{0:X}", value);
Console.WriteLine("Hexadecimal value of {0} is {1}", letter, hexOutput);
}
/* Output:
Hexadecimal value of H is 48
Hexadecimal value of e is 65
Hexadecimal value of l is 6C
Hexadecimal value of l is 6C
Hexadecimal value of o is 6F
Hexadecimal value of is 20
Hexadecimal value of W is 57
Hexadecimal value of o is 6F
Hexadecimal value of r is 72
Hexadecimal value of l is 6C
Hexadecimal value of d is 64
Hexadecimal value of ! is 21
*/
SOURCE: http://msdn.microsoft.com/en-us/library/bb311038.aspx
An int contains a number, not a representation of the number. 12000 is equivalent to 0x2ee0:
int a = 12000;
int b = 0x2ee0;
a == b
You can convert from the string "12000" to an int using int.Parse(). You can format an int as hex with int.ToString("X").
Well you can use class String.Format to Convert a Number to Hex
int value = Convert.ToInt32(number);
string hexOutput = String.Format("{0:X}", value);
If you want to Convert a String Keyword to Hex you can do it
string input = "Hello World!";
char[] values = input.ToCharArray();
foreach (char letter in values)
{
// Get the integral value of the character.
int value = Convert.ToInt32(letter);
// Convert the decimal value to a hexadecimal value in string form.
string hexOutput = String.Format("{0:X}", value);
Console.WriteLine("Hexadecimal value of {0} is {1}", letter, hexOutput);
}
If you want to convert it to hex string you can do it by
string hex = (int.Parse(number)).ToString("X");
If you want to put only the number as hex. Its not possible. Becasue computer always keeps number in binary format so When you execute int i = 1000 it stores 1000 as binary in i. If you put hex it'll be binary too. So there is no point.
you can try something like this if its going to be int
string number = "12000";
int val = int.Parse(number);
string hex = val.ToString("X");