I`m working with C# and I have a problem at converting a string array to a int array.
First I created a string number with the Console
Console.WriteLine("Geben Sie die Nummer ein:");
string wert = Console.ReadLine();
Then I converted the string to a array
char[] wertarray = wert.ToCharArray();
wertarray1 = new string(wertarray);*
And now comes the problem. I want to convert the string array to a int array, but e.g. for string wertarray1[0]=1, the int array has the value 49.
int wertarray2 = Convert.ToInt16(wertarray1[0]);
Normal the Int value should be 1, but I don`t know where the problem is.
I tried the solutions for "convert a string array to a int array" from this forum, but i still had the problem that the int value get a strange number.
I´m looking forward for help.
Thanks :-).
Convert.ToInt16(Char) takes the numeric value of the char (i.e. its Unicode code-point value) and returns that number. While you might think Convert.ToInt16('1') should return 1, consider what would happen if you tried Convert.ToInt16('#') for example.
Use Int16.Parse (or TryParse) to actually parse a string to numbers. As you're working with individual characters to represent 0-9 you might as well do it using simple arithmetic without the need to call any Parse function:
String line = Console.ReadLine();
List<Int16> numbers = new List<Int16>( line.Length );
foreach(Char c in line) {
Int16 charValue = (Int16)c;
if( charValue < 48 || charValue > 57 ) throw new Exception("char is not a digit");
Int16 value = charValue - 48;
numbers.Add( value );
}
Answers provided already explain your problem and provide solution too.
In general, you can convert the char to string and parse them to integer (not the best performance though).
If you have all numeric string
var numStr = "136";
var numbers = numStr.Select(n => int.Parse(n.ToString())).ToList(); // {1, 3, 6}
If your string contains non numbers too
var mixStr = "1.k78Tj_n";
int temp;
var numbers2 = new List<int>();
mixStr.ToList().ForEach(n =>
{
if (int.TryParse(n.ToString(), out temp))
numbers2.Add(temp);
}); //{ 1, 7, 8 }
You're getting the Unicode code point value of the characters in your input stream -- 49 is the unicode value for the character 1.
If you want to convert a unicode character that is a digit to the numeric value of that digit, you can use System.Globalization.CharUnicodeInfo.GetDecimalDigitValue(char c):
var wertarray2 = wert.Select(c => (short)CharUnicodeInfo.GetDecimalDigitValue(c)).ToArray();
This handles all digits (including superscripted numbers) not just the standard ASCII digits.
Related
I'm just starting with the c# programming and
as the heading describes, I'm looking for a way to convert a number passed to me as an ASCII character in a byte[] to an integer. I often find the way to convert a hex-byte to ASCII-char or string. I also find the other direction, get the hex-byte from a char. Maybe I should still say that I have the values displayed in a texbox for control.
as an example:
hex- code: 30 36 38 31
Ascii string: (0) 6 8 1
Integer (dez) should be: 681
so far I have tried all sorts of things. I also couldn't find it on the Microsoft Visual Studio website. Actually this should be relatively simple. I am sorry for my missing basics in c#.
Putting together this hex-to-string answer and this integer parsing answer, we get the following:
// hex -> byte array -> string
var hexBytes = "30 36 38 31";
var bytes = hexBytes.Split(' ')
.Select(hb => Convert.ToByte(hb, 16)) // converts string -> byte using base 16
.ToArray();
var asciiStr = System.Text.Encoding.ASCII.GetString(bytes);
// parse string as integer
int x = 0;
if (Int32.TryParse(asciiStr, out x))
{
Console.WriteLine(x); // write to console
}
else
{
Console.WriteLine("{0} is not a valid integer.", asciiStr); // invalid number, write error to console
}
Try it online
A typical solution of the problem is a Linq query. We should
Split initial string into items
Convert each item to int, treating item being hexadecimal. We should subtract '0' since we have not digit itself but its ascii code.
Aggregate items into the final integer
Code:
using System.Linq;
...
string source = "30 36 38 31";
int result = source
.Split(' ')
.Select(item => Convert.ToInt32(item, 16) - '0')
.Aggregate((sum, item) => sum * 10 + item);
If you want to obtain ascii string you can
Split the string
Convert each item into char
Join the chars back to string:
Code:
string source = "30 36 38 31";
string asciiString = string.Join(" ", source
.Split(' ')
.Select(item => (char)Convert.ToInt32(item, 16)));
To convert a byte array containing ASCII codes to an integer:
byte[] data = {0x30, 0x36, 0x38, 0x31};
string str = Encoding.ASCII.GetString(data);
int number = int.Parse(str);
Console.WriteLine(number); // Prints 681
To convert an integer to a 4-byte array containing ASCII codes (only works if the number is <= 9999 of course):
int number = 681;
byte[] data = Encoding.ASCII.GetBytes(number.ToString("D4"));
// data[] now contains 30h, 36h, 38h, 31h
Console.WriteLine(string.Join(", ", data.Select(b => b.ToString("x"))));
i been working on this "string to Binary" method for longer than usual and i have no idea where i m going wrong.
i have already searched the internet for solution but nothing seem to be working the way it supposed to do.
public static string hexToBin(string strValue)
{
byte[] hexThis = ASCIIEncoding.ASCII.GetBytes(strValue.ToString());
string thiI = ToHex(strValue);
ulong number = UInt64.Parse(*string*, System.Globalization.NumberStyles.HexNumber);
byte[] bytes = BitConverter.GetBytes(number);
string binaryString = string.Empty;
foreach (byte singleByte in bytes)
{
binaryString += Convert.ToString(singleByte, 2);
}
return binaryString;
}
ToHex(string) takes string and returns its hex representation.
but all i keep getting is "Input string was not in a correct format." at the ulong.Parse(string, NumberStyle); and no matter what are my inputs i keep getting the "FormatException" "Input string was not in a correct format." Error.
the inputs and its outputs
string: format exception - "Hello"
hex: format exception - "48 65 6C 6C 6F"
byte[]: format exception - { 72, 101, 108, 108, 111 }
i have also tried using the "Hello" string, but it threw me the same error.
would you please let me know what i m doing wrong in here?
i also have tried "Clean/build/rebuild" restart visual studio, but i keep getting the same format exception.
EDIT,, used UInt64.Parse() not ulong.Parse() and the used string is "Hello" w/o quotation.
EDIT #2,,
so i did this based on knittl suggestion and used the Convert.ToUInt64 instead of the parse, but still getting same error
ulong binary;
string binThis;
byte[] ByteThis;
binThis = "Hello";
ByteThis = ASCIIEncoding.ASCII.GetBytes(binThis);
binary = Convert.ToUInt64(ByteThis);
Console.WriteLine(binary);
the CurrentCulture is set to en-US and i m also using en-US keyboard
EDIT #3 - Solved
thanks to knittl
the solution is as follow:
string thestring = "example";
string[] finale = new string[thestring.Length];
foreach (var c in ByteThis)
{
for (int i = 0; i < ByteThis.Length; i++)
{
thestring = Convert.ToString(c, 2);
thestring = "0" + thestring;
if (thestring.Length == 9)
thestring.Remove(0, 1);
finale[i] = thestring;
Console.WriteLine(finale[i]);
}
}
the final for is to check on the solution.
this question aimed to get the binary representation of a given string.
Not totally clear, what your method should do (i.e. what format the input string is. Is it a bas10 number, or already a hexadecimal number?)
If it's a hexadecimal number, use ulong.Parse(inputStr, NumberStyles.HexNumber). If not, simply use ulong.Parse(inputStr). Note that NumberStyles.HexNumber does not allow the 0x prefix (Convert.ToUInt64(inputStr) does however).
Then, once you have your input string parsed to a number, simply use Convert.ToString(number, 2) to convert to base2. You will notice that there is no overload which takes an ulong and an int, but you can simply cast your number to a (signed) long, since the binary representation will be identical between the two (cf. two's complement). So, in effect Convert.ToString((long)number, 2).
No need for complicated loops and conversions to byte arrays.
Bonus answer.
If you are not too concerned with performance, you can even use a LINQ one-liner:
Encoding.ASCII.GetBytes(inputStr).Aggregate(
new StringBuilder(),
(sb, ch) => sb.Append(Convert.ToString(ch, 2).PadLeft(8, '0')),
sb => sb.ToString());
I have some int values that I want to convert to a string but in hex.
This hex value should be formatted always by 2 digits.
Example below:
int a = 10;
int b = 20;
//returns the value in hex
string c = a.toString("x"); // a
string d = b.toString("x"); // 14
What I want is that always that the hex value results in two digits. Shows like "0a", not only "a".
I'm using convert a int to a formatted string,
int e = 1;
string f = e.toString("D2"); // 01
Have a way to the two things together? To convert the int to a hex formatted string?
you can use this
int e = 1;
string f = e.toString("x2");
Have a way to the two things togheter?
Yes - you just use x2. You already have the hex bit with x and the "2 characters" part with D2 - you just need to combine them.
See the documentation for standard numeric format strings for more information.
I would like to parse a string to return only a value that is in between bracket symbols, such as [10.2%]. Then I would need to strip the "%" symbol and convert the decimal to a rounded up/down integer. So, [10.2%] would end up being 10. And, [11.8%] would end up being 12.
Hopefully I have provided sufficient information.
Math.Round(
double.Parse(
"[11.8%]".Split(new [] {"[", "]", "%"},
StringSplitOptions.RemoveEmptyEntries)[0]))
Why not use Regex?
In this example, I am assuming that your value inside the brackets always are a double with decimals.
string WithBrackets = "[11.8%]";
string AsDouble = Regex.Match(WithBrackets, "\d{1,9}\.\d{1,9}").value;
int Out = Math.Round(Convert.ToDouble(AsDouble.replace(".", ","));
var s = "[10.2%]";
var numberString = s.Split(new char[] {'[',']','%'},StringSplitOptions.RemoveEmptyEntries).First();
var number = Math.Round(Covnert.ToDouble(numberString));
If you can ensure that the content between the brackets is of the form <decimal>%, then this little function will return the value between the fist set of brackets. If there are more than one values you need to extract then you will need to modify it somewhat.
public decimal getProp(string str)
{
int obIndex = str.IndexOf("["); // get the index of the open bracket
int cbIndex = str.IndexOf("]"); // get the index of the close bracket
decimal d = decimal.Parse(str.Substring(obIndex + 1, cbIndex - obIndex - 2)); // this extracts the numerical part and converts it to a decimal (assumes a % before the ])
return Math.Round(d); // return the number rounded to the nearest integer
}
For example getProp("I like cookies [66.7%]") gives the Decimal number 67
Use regular expressions (Regex) to find the required words within one bracket.
This is the code you need:
Use an foreach loop to remove the % and convert to int.
List<int> myValues = new List<int>();
foreach(string s in Regex.Match(MYTEXT, #"\[(?<tag>[^\]]*)\]")){
s = s.TrimEnd('%');
myValues.Add(Math.Round(Convert.ToDouble(s)));
}
I have an integer variable .if its 1-9 it only displays as "1" or "9", I'm looking to convert the variable to save as 3 digits, ie. "001", or "009", etc. any ideas?
I am using C#,ASP.Net
use
int X = 9;
string PaddedResult = X.ToString().PadLeft (3, '0'); // results in 009
see MSDN references here and here.
What about
var result = String.Format("{0:000}", X);
var result2 = X.ToString("000");
int i = 5;
string tVal=i.ToString("000");
From: https://learn.microsoft.com/en-us/dotnet/standard/base-types/standard-numeric-format-strings#DFormatString
The "D" (or decimal) format specifier converts a number to a string of decimal digits (0-9), prefixed by a minus sign if the number is negative.
The precision specifier indicates the minimum number of digits desired in the resulting string. If required, the number is padded with zeros to its left to produce the number of digits given by the precision specifier.
Like:
int value;
value = 12345;
Console.WriteLine(value.ToString("D"));
// Displays 12345
Console.WriteLine(value.ToString("D8"));
// Displays 00012345
value = -12345;
Console.WriteLine(value.ToString("D"));
// Displays -12345
Console.WriteLine(value.ToString("D8"));
// Displays -00012345
int i = 5;
string retVal = i.ToString().PadLeft(3, '0');
you can use this code also
int k = 5;
string name = $"name-{k++:D3}.ext";