I am trying to convert a image in my image folder and the image name defaultImage and update into my database table.
But now I am having problem in this line of code:
I change the code using this:
Image uploaded6 = Image.FromFile("/image/defaultImage.jpg");
instead of this:
System.Drawing.Image uploaded = System.Drawing.Image.FromStream(~/images/defaultImage);
I now getting the error of FileNotFoundException was unhandled by user code
I have tried this method using fileupload control and it working fine but not sure how to convert image in a folder.
How do I get the image from the folder in order to convert it using the method shown below.
Image uploaded6 = Image.FromFile("/image/defaultImage.jpg");
//System.Drawing.Image uploaded = System.Drawing.Image.FromStream();
System.Drawing.Image newImage = new Bitmap(1024, 768);
using (Graphics g = Graphics.FromImage(newImage))
{
g.InterpolationMode = InterpolationMode.HighQualityBicubic;
g.DrawImage(uploaded, 0, 0, 1024, 768);
}
byte[] results;
using (MemoryStream ms = new MemoryStream())
{
ImageCodecInfo codec = ImageCodecInfo.GetImageEncoders().FirstOrDefault(c => c.FormatID == ImageFormat.Jpeg.Guid);
EncoderParameters jpegParms = new EncoderParameters(1);
jpegParms.Param[0] = new EncoderParameter(Encoder.Quality, 95L);
newImage.Save(ms, codec, jpegParms);
results = ms.ToArray();
}
string sqlImage = "update MemberReport set image1 = #Data where memberreportid = '" + Session["memberreportid"] + "'";
SqlCommand cmdImage = new SqlCommand(sqlImage);
cmdImage.Parameters.AddWithValue("#Data", results);
InsertUpdateData(cmdImage);
I guess your problem is with relative paths, instead of
Image uploaded6 = Image.FromFile("/image/defaultImage.jpg");
you should provide the local path, which you can get it this way:
Image uploaded6 = Image.FromFile(Server.MapPath("~/image/defaultImage.jpg"));
System.Drawing.Image.FromStream requires 'MemoryStream' as parameter.
byte[] file = null;
MemoryStream memoryStream = new MemoryStream();
memoryStream = new MemoryStream(file, false);
System.Drawing.Image objTempImg = System.Drawing.Image.FromStream(memoryStream)
byte[] file is based64 image
System.Drawing.Image.FromStream(Stream)
You must to send a Stream parameter in this method.
Related
//Retrieve an image in Jpg format and store it into a variable.
var imgFile = (ImageFile)ScanerItem.Transfer(FormatID.wiaFormatJPEG);
var Path = #"D:\ScanImg.jpg";
// save the image in some path with filename.
imgFile.SaveFile(Path);
pictureBox1.ImageLocation = Path;
Based on the following SO answer, you can get the byte[] of the image with (byte[])imgFile.FileData.get_BinaryData():
converting .__comobj WIA to byte[] in C# application
A bitmap can be put as source into the PictureBox.
Therefore the byte[] as to put into a MemoryStream and create a Bitmap:
var imgFile = (ImageFile)ScanerItem.Transfer(FormatID.wiaFormatJPEG);
byte[] imageBytes = (byte[])imgFile.FileData.get_BinaryData();
Bitmap image;
using (MemoryStream stream = new MemoryStream(imageBytes))
{
image = new Bitmap(stream);
}
pictureBox1.Image = image;
I have two functions: one to convert from image to byte and other to convert from byte to bitmapImage.
So, when I open the window with that images, I convert from byte to bitmapImage and it works great, but when I close and open it again it just keeps on memory and if I continue to do that time and time again it just throws an exception Out Of Memory exception
Image to byte->
private byte[] ConvertImageToBinary(Image img)
{
using (MemoryStream ss = new MemoryStream())
{
img.Save(ss, System.Drawing.Imaging.ImageFormat.Jpeg);
var s = ss.ToArray();
var jpegQuality = 50;
Image image;
using (var inputStream = new MemoryStream(s))
{
image = Image.FromStream(inputStream);
var jpegEncoder = System.Drawing.Imaging.ImageCodecInfo.GetImageDecoders()
.First(c => c.FormatID == System.Drawing.Imaging.ImageFormat.Jpeg.Guid);
var encoderParameters = new System.Drawing.Imaging.EncoderParameters(1);
encoderParameters.Param[0] = new System.Drawing.Imaging.EncoderParameter(System.Drawing.Imaging.Encoder.Quality, jpegQuality);
Byte[] outputBytes;
using (var outputStream = new MemoryStream())
{
image.Save(outputStream, jpegEncoder, encoderParameters);
return outputBytes = outputStream.ToArray();
}
}
}
}
Byte to bitmap ->
public BitmapImage ConvertBinaryToImage(byte[] array)
{
var image = new BitmapImage();
using (var ms = new MemoryStream(array))
{
image.BeginInit();
image.CacheOption = BitmapCacheOption.OnLoad; // here
image.StreamSource = ms;
image.EndInit();
image.Freeze();
}
return image;
}
When I open the WindowDragAndDrop it loads all the images
But when I close it it still uses the same amount of memory
Image is indeed disposable (https://learn.microsoft.com/en-us/dotnet/api/system.drawing.image?view=netframework-4.8), so you also need:
using (var image = Image.FromStream(inputStream)){
}
Around everywhere you use Image objects.
Hello friends i want to "convert a system.windows.control.image" to "System.Drawing.Image",but i am unable to do so.I am using below code for this
var e = (MouseButtonEventArgs)sender;
var device = e.MouseDevice.DirectlyOver;
System.Windows.Controls.Image img = (System.Windows.Controls.Image)device;
I have "img" i.e of type "system.windows.control.image" i need to convert it to bitmap or drawing type.
Try this....
Use your img variable in this code...
MemoryStream ms = new MemoryStream();
System.Windows.Media.Imaging.BmpBitmapEncoder bbe = new BmpBitmapEncoder();
bbe.Frames.Add(BitmapFrame.Create(new Uri(img.Source.ToString(),UriKind.RelativeOrAbsolute)));
bbe.Save(ms);
System.Drawing.Image img2 = System.Drawing.Image.FromStream(ms);
button1.Image = img2;
convert from byte[] to image
MemoryStream ms = new MemoryStream(imageByte);
Image image = Image.FromStream(ms);
it may help you..
I have an operation on the site that takes crops an image, however the resultant, cropped image is coming out significantly larger in terms of file size (original is 24k and the cropped image is like 650k). So I found that I need to apply some compression to the image before saving it. I came up with the following:
public static System.Drawing.Image CropImage(System.Drawing.Image image, Rectangle cropRectangle, ImageFormat format)
{
var croppedImage = new Bitmap(cropRectangle.Width, cropRectangle.Height);
using (var g = Graphics.FromImage(croppedImage))
{
g.InterpolationMode = InterpolationMode.HighQualityBicubic;
g.DrawImage(
image,
new Rectangle(new Point(0,0), new Size(cropRectangle.Width, cropRectangle.Height)),
cropRectangle,
GraphicsUnit.Pixel);
return CompressImage(croppedImage, format);
}
}
public static System.Drawing.Image CompressImage(System.Drawing.Image image, ImageFormat imageFormat)
{
var bmp = new Bitmap(image);
var codecInfo = EncoderFactory.GetEncoderInfo(imageFormat);
var encoder = System.Drawing.Imaging.Encoder.Quality;
var parameters = new EncoderParameters(1);
var parameter = new EncoderParameter(encoder, 10L);
parameters.Param[0] = parameter;
using (var ms = new MemoryStream())
{
bmp.Save(ms, codecInfo, parameters);
var resultImage = System.Drawing.Image.FromStream(ms);
return resultImage;
}
}
I set the quality low just to see if there was any change at all. There isn't. The crop is being saved correctly appearance-wise but compression is a no joy. If I bypass CompressImage() altogether, neither the file size nor the image quality appear to be any different.
So, 2 questions. Why is nothing happening? Is there a simpler way to compress the resultant image to "web-optimize" similar to how photoshop saves web images (I thought it just stripped a lot of info out of it to reduce the size).
Your problem is you must 'compress' (really encode) the image as you save it, not before you save it. An Image object in your program is always uncompressed.
By saving to the MemoryStream and reading back out from the stream will encode the image and then decode it back to the same size again (with some quality loss in the process if you are using JPEG). However, if you save it to a file with the compression parameters, you will get a compressed image file.
Using this routine with JPEG quality level 90 on a 153 KB source image gives an output image of 102 KB. If you want a smaller file size (with more encoding artifacts) change the encoder parameter to something smaller than 90.
public static void SaveJpegImage(System.Drawing.Image image, string fileName)
{
ImageCodecInfo codecInfo = ImageCodecInfo.GetImageEncoders()
.Where(r => r.CodecName.ToUpperInvariant().Contains("JPEG"))
.Select(r => r).FirstOrDefault();
var encoder = System.Drawing.Imaging.Encoder.Quality;
var parameters = new EncoderParameters(1);
var parameter = new EncoderParameter(encoder, 90L);
parameters.Param[0] = parameter;
using (FileStream fs = new FileStream(fileName, FileMode.Create))
{
image.Save(fs, codecInfo, parameters);
}
}
I believe you shouldn't dispose of the MemoryStream while you are using an image created using Image.FromStream that refers to the stream. Creating a Bitmap directly from the stream also doesn't work.
Try this:
private static Image CropAndCompressImage(Image image, Rectangle rectangle, ImageFormat imageFormat)
{
using(Bitmap bitmap = new Bitmap(image))
{
using(Bitmap cropped = bitmap.Clone(rectangle, bitmap.PixelFormat))
{
using (MemoryStream memoryStream = new MemoryStream())
{
cropped.Save(memoryStream, imageFormat);
return new Bitmap(Image.FromStream(memoryStream));
}
}
}
}
I am using visual studio 2010, (desktop application) and using LINQ to SQL to save image/video or audio files to database in dataType VarBinary (MAX). This I can do... Problem is, I can't get them and display them in xaml because I can't get the converting part correct. Here is what I have so far (though its not working);
private void bt_Click (object sender, RoutedEventArgs e)
{
databaseDataContext context = new databaseDataContext();
var imageValue = from s in context.Images
where s.imageID == 2
select s.imageFile;
value = imageValue.Single().ToString();
//convert to string and taking down to next method to get converted in image
}
public string value { get; set; }
public object ImageSource //taking from http://stackoverflow.com/
{
get
{
BitmapImage image = new BitmapImage();
try
{
image.BeginInit();
image.CacheOption = BitmapCacheOption.OnLoad;
image.CreateOptions = BitmapCreateOptions.IgnoreImageCache;
image.UriSource = new Uri(value, UriKind.Absolute);
image.EndInit();
Grid.Children.Add(image);
}
catch { return DependencyProperty.UnsetValue; } return image;
}
}
I not even sure if I am on the correct track? And I am assuming that video or audio is quite similar methods?
Since your image is stored in binary format in the database, you want to "stream" this into an image object by leveraging the MemoryStream object.
Looking at your code, your solution will look something like this:
BitmapImage bmpImage = new BitmapImage();
MemoryStream msImageStream = new MemoryStream();
msImageStream.Write(value, 0, value.Length);
bmpCardImage.BeginInit();
bmpCardImage.StreamSource = new MemoryStream(msImageStream.ToArray());
bmpCardImage.EndInit();
image.Source = bmpCardImage;
It's very easy, if you have a binary data and want to create an Image object, use this code:
public Image BinaryToImage(byte[] binaryData)
{
MemoryStream ms = new MemoryStream(binaryData);
Image img = Image.FromStream(ms);
return img;
}
If you already have the bytes, to verify that what you saved is correct you can save the bytes to a file and open it....
string tempFile = Path.GetTempFileName();
MemoryStream ms = new MemoryStream(bytes); //bytes that was read from the db
//Here I assume that you're reading a png image, you can put any extension you like is a file name
FileStream stream = new FileStream(tempFile + ".png", FileMode.Create);
ms.WriteTo(stream);
ms.Close();
stream.Close();
//And here we open the file with the default program
Process.Start(tempFile + ".png");
And later you can use the answer of Dillie-O and stream....
Dillie-O's code makes for a very nice extension method:
// from http://stackoverflow.com/questions/5623264/how-to-convert-varbinary-into-image-or-video-when-retrieved-from-database-in-c:
public static BitmapImage ToImage(this Binary b)
{
if (b == null)
return null;
var binary = b.ToArray();
var image = new BitmapImage();
var ms = new MemoryStream();
ms.Write(binary, 0, binary.Length);
image.BeginInit();
image.StreamSource = new MemoryStream(ms.ToArray());
image.EndInit();
return image;
}