I'm working on my first WPF application, and I'm trying to copy the browsed image into designated folder, however I have problem with CopyTo function.
private void btnBrowse_Click(object sender, EventArgs e)
{
openFileDialog1.Filter = "Select image(*.JPG;*.PNG)|*.JPG;*.PNG";
openFileDialog1.Title = "Select your image";
openFileDialog1.InitialDirectory = #"C:\";
if (openFileDialog1.ShowDialog() == DialogResult.OK)
{
// The image to be shown into PictureBox
pictureBox1.Image = Image.FromFile(openFileDialog1.FileName);
// The Image
var theImg = Image.FromFile(openFileDialog1.FileName);
string fileName = openFileDialog1.FileName;
if(theImg != null)
{
string exePath = System.Environment.GetCommandLineArgs()[0];
string destinationFolder = Path.Combine(exePath, "Profiles");
if (!Directory.Exists(destinationFolder))
{
Directory.CreateDirectory(destinationFolder);
}
string filePath = Path.Combine(destinationFolder, fileName);
using(var fileStream = new FileStream(filePath, FileMode.Create))
{
theImg.CopyTo(theImg, fileStream);
}
}
}
}
Error: No overload for method 'CopyTo' takes 2 arguments
How can I solve this issue? Thank you in advance
I am trying to save my rich text box content to a a file. However I am getting the error when I am trying to save a new file. Save as works as expected. Any suggestions. Thank you
System.ArgumentException: 'Empty path name is not legal.'
My code for the save and save as button are as follows:
OpenFileDialog file_open = new OpenFileDialog();
private void saveToolStripMenuItem_Click(object sender, EventArgs e)
{
SaveFileDialog saveDlg = new SaveFileDialog();
string filename = "";
// To filter files from SaveFileDialog
saveDlg.Filter = "Rich Text File (*.rtf)|*.rtf|Plain Text File (*.txt)|*.txt";
saveDlg.DefaultExt = "*.rtf";
saveDlg.FilterIndex = 1;
saveDlg.Title = "Save the contents";
filename = file_open.FileName;
RichTextBoxStreamType stream_type;
// Checks the extension of the file to save
if (filename.Contains(".txt"))
stream_type = RichTextBoxStreamType.PlainText;
else
stream_type = RichTextBoxStreamType.RichText;
richTextBox1.SaveFile(filename, stream_type);
}
private void saveAsToolStripMenuItem_Click(object sender, EventArgs e)
{
SaveFileDialog saveDlg = new SaveFileDialog();
string filename = "";
// To filter files from SaveFileDialog
saveDlg.Filter = "Rich Text File (*.rtf)|*.rtf|Plain Text File (*.txt)|*.txt";
saveDlg.DefaultExt = "*.rtf";
saveDlg.FilterIndex = 1;
saveDlg.Title = "Save the contents";
DialogResult retval = saveDlg.ShowDialog();
if (retval == DialogResult.OK)
filename = saveDlg.FileName;
else
return;
RichTextBoxStreamType stream_type;
if (saveDlg.FilterIndex == 2)
stream_type = RichTextBoxStreamType.PlainText;
else
stream_type = RichTextBoxStreamType.RichText;
richTextBox1.SaveFile(filename, stream_type);
MessageBox.Show("File Saved");
}
I need help with this code. I want to create basic image convert program but this program is not working? What am I doing wrong. Thanks for answers.
private void button1_Click(object sender, EventArgs e)
{
OpenFileDialog file = new OpenFileDialog();
file.ShowDialog();
string DosyaYolu = file.FileName;
string DosyaAdi = file.SafeFileName;
if (file.ShowDialog() == DialogResult.OK)
{
System.Drawing.Image image = System.Drawing.Image.FromFile(DosyaYolu);
image.Save(DosyaYolu, System.Drawing.Imaging.ImageFormat.Png);
}
You choose the wrong target path to save the new image to. Also you invoked the ShowDialog() twice, which is not necessary. The following code will save the new file with the same name but a different extension.
var dialog = new OpenFileDialog();
if (dialog.ShowDialog() == DialogResult.OK)
{
string sourceFile = dialog.FileName;
string targetFile = Path.ChangeExtension(sourceFile, "png");
Image image = Image.FromFile(sourceFile);
image.Save(targetFile, ImageFormat.Png);
}
Hey there i started learning C# a few days ago and I'm trying to make a program that copies and pastes files (and replaces if needed) to a selected directory but I don't know how to get the directory and file paths from the openfiledialog and folderbrowserdialog
what am I doing wrong?
Here's the code:
namespace filereplacer
{
public partial class Form1 : Form
{
public Form1()
{
InitializeComponent();
}
private void direc_Click(object sender, EventArgs e)
{
string folderPath = "";
FolderBrowserDialog directchoosedlg = new FolderBrowserDialog();
if (directchoosedlg.ShowDialog() == DialogResult.OK)
{
folderPath = directchoosedlg.SelectedPath;
}
}
private void choof_Click(object sender, EventArgs e)
{
OpenFileDialog choofdlog = new OpenFileDialog();
choofdlog.Filter = "All Files (*.*)|*.*";
choofdlog.FilterIndex = 1;
choofdlog.Multiselect = true;
choofdlog.ShowDialog();
}
private void replacebtn_Click(object sender, EventArgs e)
{
// This is where i'm having trouble
}
public static void ReplaceFile(string FileToMoveAndDelete, string FileToReplace, string BackupOfFileToReplace)
{
File.Replace(FileToMoveAndDelete, FileToReplace, BackupOfFileToReplace, false);
}
}
For OpenFileDialog:
OpenFileDialog choofdlog = new OpenFileDialog();
choofdlog.Filter = "All Files (*.*)|*.*";
choofdlog.FilterIndex = 1;
choofdlog.Multiselect = true;
if (choofdlog.ShowDialog() == DialogResult.OK)
{
string sFileName = choofdlog.FileName;
string[] arrAllFiles = choofdlog.FileNames; //used when Multiselect = true
}
For FolderBrowserDialog:
FolderBrowserDialog fbd = new FolderBrowserDialog();
fbd.Description = "Custom Description";
if (fbd.ShowDialog() == DialogResult.OK)
{
string sSelectedPath = fbd.SelectedPath;
}
To access selected folder and selected file name you can declare both string at class level.
namespace filereplacer
{
public partial class Form1 : Form
{
string sSelectedFile;
string sSelectedFolder;
public Form1()
{
InitializeComponent();
}
private void direc_Click(object sender, EventArgs e)
{
FolderBrowserDialog fbd = new FolderBrowserDialog();
//fbd.Description = "Custom Description"; //not mandatory
if (fbd.ShowDialog() == DialogResult.OK)
sSelectedFolder = fbd.SelectedPath;
else
sSelectedFolder = string.Empty;
}
private void choof_Click(object sender, EventArgs e)
{
OpenFileDialog choofdlog = new OpenFileDialog();
choofdlog.Filter = "All Files (*.*)|*.*";
choofdlog.FilterIndex = 1;
choofdlog.Multiselect = true;
if (choofdlog.ShowDialog() == DialogResult.OK)
sSelectedFile = choofdlog.FileName;
else
sSelectedFile = string.Empty;
}
private void replacebtn_Click(object sender, EventArgs e)
{
if(sSelectedFolder != string.Empty && sSelectedFile != string.Empty)
{
//use selected folder path and file path
}
}
....
}
NOTE:
As you have kept choofdlog.Multiselect=true;, that means in the OpenFileDialog() you are able to select multiple files (by pressing ctrl key and left mouse click for selection).
In that case you could get all selected files in string[]:
At Class Level:
string[] arrAllFiles;
Locate this line (when Multiselect=true this line gives first file only):
sSelectedFile = choofdlog.FileName;
To get all files use this:
arrAllFiles = choofdlog.FileNames; //this line gives array of all selected files
Use the Path class from System.IO. It contains useful calls for manipulating file paths, including GetDirectoryName which does what you want, returning the directory portion of the file path.
Usage is simple.
string directoryPath = System.IO.Path.GetDirectoryName(choofdlog.FileName);
you can store the Path into string variable like
string s = choofdlog.FileName;
To get the full file path of a selected file or files, then you need to use FileName property for one file or FileNames property for multiple files.
var file = choofdlog.FileName; // for one file
or for multiple files
var files = choofdlog.FileNames; // for multiple files.
To get the directory of the file, you can use Path.GetDirectoryName
Here is Jon Keet's answer to a similar question about getting directories from path
Create this class as Extension:
public static class Extensiones
{
public static string FolderName(this OpenFileDialog ofd)
{
string resp = "";
resp = ofd.FileName.Substring(0, 3);
var final = ofd.FileName.Substring(3);
var info = final.Split('\\');
for (int i = 0; i < info.Length - 1; i++)
{
resp += info[i] + "\\";
}
return resp;
}
}
Then, you could use in this way:
//ofdSource is an OpenFileDialog
if (ofdSource.ShowDialog(this) == DialogResult.OK)
{
MessageBox.Show(ofdSource.FolderName());
}
Your choofdlog holds a FileName and FileNames (for multi-selection) containing the file paths, after the ShowDialog() returns.
A primitive quick fix that works.
If you only use OpenFileDialog, you can capture the FileName, SafeFileName, then subtract to get folder path:
exampleFileName = ofd.SafeFileName;
exampleFileNameFull = ofd.FileName;
exampleFileNameFolder = ofd.FileNameFull.Replace(ofd.FileName, "");
I am sorry if i am late to reply here but i just thought i should throw in a much simpler solution for the OpenDialog.
OpenDialog ofd = new OpenDialog();
var fullPathIncludingFileName = ofd.Filename; //returns the full path including the filename
var fullPathExcludingFileName = ofd.Filename.Replace(ofd.SafeFileName, "");//will remove the filename from the full path
I have not yet used a FolderBrowserDialog before so i will trust my fellow coders's take on this. I hope this helps.
String fn = openFileDialog1.SafeFileName;
String path = openFileDialog1.FileName.ToString().Replace(fn, "");
I couldn't find any method to add in the if statement to read a text file. Here is the code;
private void button1_Click(object sender, EventArgs e)
{
OpenFileDialog BrowseFile1 = new OpenFileDialog();
BrowseFile1.Title = "Select a text file";
BrowseFile1.Filter = "Text File |*.txt";
BrowseFile1.FilterIndex = 1;
string ContainingFolder = AppDomain.CurrentDomain.BaseDirectory;
BrowseFile1.InitialDirectory = #ContainingFolder;
//BrowseFile1.InitialDirectory = #"C:\";
BrowseFile1.RestoreDirectory = true;
if (BrowseFile1.ShowDialog() == DialogResult.OK)
{
}
I just wanna get whole text froma text file that I choose from this OpenFolderDialog window.
string text = System.IO.File.ReadAllText(BrowseFile1.FileName);
Another possibility is using a StreamReader:
http://msdn.microsoft.com/en-us/library/db5x7c0d(v=vs.110).aspx
Just Change the file locatations through BrowseFile1.FileName.