Hey there i started learning C# a few days ago and I'm trying to make a program that copies and pastes files (and replaces if needed) to a selected directory but I don't know how to get the directory and file paths from the openfiledialog and folderbrowserdialog
what am I doing wrong?
Here's the code:
namespace filereplacer
{
public partial class Form1 : Form
{
public Form1()
{
InitializeComponent();
}
private void direc_Click(object sender, EventArgs e)
{
string folderPath = "";
FolderBrowserDialog directchoosedlg = new FolderBrowserDialog();
if (directchoosedlg.ShowDialog() == DialogResult.OK)
{
folderPath = directchoosedlg.SelectedPath;
}
}
private void choof_Click(object sender, EventArgs e)
{
OpenFileDialog choofdlog = new OpenFileDialog();
choofdlog.Filter = "All Files (*.*)|*.*";
choofdlog.FilterIndex = 1;
choofdlog.Multiselect = true;
choofdlog.ShowDialog();
}
private void replacebtn_Click(object sender, EventArgs e)
{
// This is where i'm having trouble
}
public static void ReplaceFile(string FileToMoveAndDelete, string FileToReplace, string BackupOfFileToReplace)
{
File.Replace(FileToMoveAndDelete, FileToReplace, BackupOfFileToReplace, false);
}
}
For OpenFileDialog:
OpenFileDialog choofdlog = new OpenFileDialog();
choofdlog.Filter = "All Files (*.*)|*.*";
choofdlog.FilterIndex = 1;
choofdlog.Multiselect = true;
if (choofdlog.ShowDialog() == DialogResult.OK)
{
string sFileName = choofdlog.FileName;
string[] arrAllFiles = choofdlog.FileNames; //used when Multiselect = true
}
For FolderBrowserDialog:
FolderBrowserDialog fbd = new FolderBrowserDialog();
fbd.Description = "Custom Description";
if (fbd.ShowDialog() == DialogResult.OK)
{
string sSelectedPath = fbd.SelectedPath;
}
To access selected folder and selected file name you can declare both string at class level.
namespace filereplacer
{
public partial class Form1 : Form
{
string sSelectedFile;
string sSelectedFolder;
public Form1()
{
InitializeComponent();
}
private void direc_Click(object sender, EventArgs e)
{
FolderBrowserDialog fbd = new FolderBrowserDialog();
//fbd.Description = "Custom Description"; //not mandatory
if (fbd.ShowDialog() == DialogResult.OK)
sSelectedFolder = fbd.SelectedPath;
else
sSelectedFolder = string.Empty;
}
private void choof_Click(object sender, EventArgs e)
{
OpenFileDialog choofdlog = new OpenFileDialog();
choofdlog.Filter = "All Files (*.*)|*.*";
choofdlog.FilterIndex = 1;
choofdlog.Multiselect = true;
if (choofdlog.ShowDialog() == DialogResult.OK)
sSelectedFile = choofdlog.FileName;
else
sSelectedFile = string.Empty;
}
private void replacebtn_Click(object sender, EventArgs e)
{
if(sSelectedFolder != string.Empty && sSelectedFile != string.Empty)
{
//use selected folder path and file path
}
}
....
}
NOTE:
As you have kept choofdlog.Multiselect=true;, that means in the OpenFileDialog() you are able to select multiple files (by pressing ctrl key and left mouse click for selection).
In that case you could get all selected files in string[]:
At Class Level:
string[] arrAllFiles;
Locate this line (when Multiselect=true this line gives first file only):
sSelectedFile = choofdlog.FileName;
To get all files use this:
arrAllFiles = choofdlog.FileNames; //this line gives array of all selected files
Use the Path class from System.IO. It contains useful calls for manipulating file paths, including GetDirectoryName which does what you want, returning the directory portion of the file path.
Usage is simple.
string directoryPath = System.IO.Path.GetDirectoryName(choofdlog.FileName);
you can store the Path into string variable like
string s = choofdlog.FileName;
To get the full file path of a selected file or files, then you need to use FileName property for one file or FileNames property for multiple files.
var file = choofdlog.FileName; // for one file
or for multiple files
var files = choofdlog.FileNames; // for multiple files.
To get the directory of the file, you can use Path.GetDirectoryName
Here is Jon Keet's answer to a similar question about getting directories from path
Create this class as Extension:
public static class Extensiones
{
public static string FolderName(this OpenFileDialog ofd)
{
string resp = "";
resp = ofd.FileName.Substring(0, 3);
var final = ofd.FileName.Substring(3);
var info = final.Split('\\');
for (int i = 0; i < info.Length - 1; i++)
{
resp += info[i] + "\\";
}
return resp;
}
}
Then, you could use in this way:
//ofdSource is an OpenFileDialog
if (ofdSource.ShowDialog(this) == DialogResult.OK)
{
MessageBox.Show(ofdSource.FolderName());
}
Your choofdlog holds a FileName and FileNames (for multi-selection) containing the file paths, after the ShowDialog() returns.
A primitive quick fix that works.
If you only use OpenFileDialog, you can capture the FileName, SafeFileName, then subtract to get folder path:
exampleFileName = ofd.SafeFileName;
exampleFileNameFull = ofd.FileName;
exampleFileNameFolder = ofd.FileNameFull.Replace(ofd.FileName, "");
I am sorry if i am late to reply here but i just thought i should throw in a much simpler solution for the OpenDialog.
OpenDialog ofd = new OpenDialog();
var fullPathIncludingFileName = ofd.Filename; //returns the full path including the filename
var fullPathExcludingFileName = ofd.Filename.Replace(ofd.SafeFileName, "");//will remove the filename from the full path
I have not yet used a FolderBrowserDialog before so i will trust my fellow coders's take on this. I hope this helps.
String fn = openFileDialog1.SafeFileName;
String path = openFileDialog1.FileName.ToString().Replace(fn, "");
Related
I have a listbox which i can fill trough openfiledialog, which works but not the way i want it. I need 2 columns in my listbox 1 for the filepath and 1 for the fileName next to each other.
also i have another button which inserts all fileNames into the database, which works also but i also need the second column to update the path column in my database
Ive tried to make 2 columns 1 for the filename and 1 for the filepath, unfortunately i could only make 1 column work for my filename.
This is the code for filling in the listbox
private void btnOpenFiles_Click(object sender, RoutedEventArgs e)
{
lbfiles.Items.Clear();
OpenFileDialog openFileDialog = new OpenFileDialog();
openFileDialog.Multiselect = true;
openFileDialog.Filter = "Text files (*.txt)|*.txt|All files (*.*)|*.*";
openFileDialog.InitialDirectory = Environment.GetFolderPath(Environment.SpecialFolder.Desktop);
if (openFileDialog.ShowDialog() == true)
{
foreach (string filename in openFileDialog.FileNames)
lbfiles.Items.Add(System.IO.Path.GetFileName(filename));
}
}
this is the code for inserting into the database
private void BtnToDatabase_Click(object sender, RoutedEventArgs e)
{
bool dupe = false;
foreach (String string2 in lbfiles.Items.Cast<String>().ToList())
{
{
string cat1 = string2.Substring(0, string2.Length);
using (SqlConnection sqlCon = new SqlConnection(connectionString))
{
String query = "INSERT INTO tblBestanden2 (BestandNaam,toegewezen,Username,Status) VALUES (#BestandNaam, #toegewezen, #username, #Status)";
using (SqlCommand command = new SqlCommand(query, sqlCon))
{
command.Parameters.AddWithValue("#BestandNaam", cat1);
command.Parameters.AddWithValue("#toegewezen", "1");
command.Parameters.AddWithValue("#username", "");
command.Parameters.AddWithValue("#Status", "0");
sqlCon.Open();
int result = command.ExecuteNonQuery();
if (!dupe)
{
if (result == 0)
{
sqlCon.Close();
MessageBox.Show("error");
}
else
{
sqlCon.Close();
MessageBox.Show("toegevoegd");
}
dupe = true;
}
}
}
}
}
}
If there is any confusion about my question please tell me and i will try my best to elaborate
Create a class with two properties:
public class File
{
public string Name { get; set; }
public string Path { get; set; }
}
And instances of this one to the ListBox:
private void btnOpenFiles_Click(object sender, RoutedEventArgs e)
{
lbfiles.Items.Clear();
OpenFileDialog openFileDialog = new OpenFileDialog();
openFileDialog.Multiselect = true;
openFileDialog.Filter = "Text files (*.txt)|*.txt|All files (*.*)|*.*";
openFileDialog.InitialDirectory = Environment.GetFolderPath(Environment.SpecialFolder.Desktop);
if (openFileDialog.ShowDialog() == true)
{
foreach (string filename in openFileDialog.FileNames)
lbfiles.Items.Add(new File() { Name = System.IO.Path.GetFileName(filename), Path = filename });
}
}
You would then get the values by casting the items to File objects in your BtnToDatabase_Click event handler:
private void BtnToDatabase_Click(object sender, RoutedEventArgs e)
{
bool dupe = false;
foreach (File file in lbfiles.Items.OfType<File>())
{
string name = file.Name;
string path = file.Path;
...
}
}
In foreach statement, filepath is not included when this condition openFileDialog.ShowDialog() gets true, you are getting only filename. To get filepath, use System.IO.Path.GetFullPath(FileName);, you could get filepath for the filename
I am trying to output the file address of an item selected in a combobox. But i keep getting the Directory address of the project and not the item itself. Please help. Here is my Code:
private void comboBox1_SelectedIndexChanged_1(object sender, EventArgs e)
{
if (availableSoftDropBox.SelectedItem.Equals("Choose Your Own..."))
{
if (openFileDialog1.ShowDialog() == DialogResult.OK)
txtFlashFile.Text = openFileDialog1.FileName;
}
else
{
string fileName;
fileName = Path.GetFullPath((string)availableSoftDropBox.SelectedItem);
string fullPath = #"C:\Program Files (x86)\yeet-n . master\yeet-
master\src\yeet\System\Products\" + (fileName);
txtFlashFile.Text = fullPath;
I'm not quite sure what you want to achieve, but using FileInfo instead of Path.GetFullPath might help.
private void comboBox1_SelectedIndexChanged_1(object sender, EventArgs e)
{
const string fullPath = #"C:\Program Files (x86)\yeet-n . master\yeet-
master\src\yeet\System\Products\";
string selection = (string)availableSoftDropBox.SelectedItem;
var fileInfo = new FileInfo(fullPath + selection);
string text = fileInfo.FullName;
if (selection.Equals("Choose Your Own..."))
{
if (openFileDialog1.ShowDialog() == DialogResult.OK)
{
text = openFileDialog1.FileName;
}
}
txtFlashFile.Text = text;
}
I need to use an specific file from the ones you select from a file dialog.
OpenFileDialog ofd = new OpenFileDialog();
private void pictureBox23_Click(object sender, EventArgs e)
{
ofd.Filter = "WAV|*.wav";
this.ofd.Multiselect = true;
if (ofd.ShowDialog() == DialogResult.OK)
{
label23.Text = ofd.SafeFileName;
}
else
{
label23.Text = "No files selected...";
}
}
What i need to do is select and use the files I pre-define, so if I define an event with 01.wav if the user selects a file named 01.wav, that one will be used like so:
using (SoundPlayer player = new SoundPlayer(Beatpadpc.Properties.Resources._01))
{
player.Play();
}
I currently have it adapted as it will play it from the resources, what i need to do is to play the file from the file selecion, but only if the file is named "01".wav
Is there a way for doing it?
Well, just filter the ofd property called Filenames.
OpenFileDialog ofd = new OpenFileDialog();
string strAudioFilePath = String.Empty;
private void pictureBox23_Click(object sender, EventArgs e)
{
ofd.Filter = "WAV|*.wav";
this.ofd.Multiselect = true;
if (ofd.ShowDialog() == DialogResult.OK)
{
// Here you make a small filter with linq
label23.Text = strAudioFilePath = ofd.FileNames.FirstOrDefault(x => x.EndsWith("01.wav")); // you change 01.wav to something that make more sense to you
}
else
{
label23.Text = "No files selected...";
}
}
Then if you want to get rid of your resource file, just give your sound player the path of the file and that's all.
SoundPlayer simpleSound = new SoundPlayer(strAudioFilePath);
simpleSound.Play();
I am making a program in which the user needs to load in multiple files. However, in the ListBox I need to show only file names of the files they loaded but still be able to use the files loaded. So I want to hide the full path. This is how I load a file into the ListBox now, but it shows the whole path:
private void browseBttn_Click(object sender, EventArgs e)
{
OpenFileDialog OpenFileDialog1 = new OpenFileDialog();
OpenFileDialog1.Multiselect = true;
OpenFileDialog1.Filter = "DLL Files|*.dll";
OpenFileDialog1.Title = "Select a Dll File";
if (OpenFileDialog1.ShowDialog() == System.Windows.Forms.DialogResult.OK)
{
dllList.Items.AddRange(OpenFileDialog1.FileNames);
}
}
// Set a global variable to hold all the selected files result
List<String> fullFileName;
// Browse button handler
private void button1_Click(object sender, EventArgs e)
{
OpenFileDialog OpenFileDialog1 = new OpenFileDialog();
OpenFileDialog1.Multiselect = true;
OpenFileDialog1.Filter = "DLL Files|*.dll";
OpenFileDialog1.Title = "Seclect a Dll File";
if (OpenFileDialog1.ShowDialog() == System.Windows.Forms.DialogResult.OK)
{
// put the selected result in the global variable
fullFileName = new List<String>(OpenFileDialog1.FileNames);
// add just the names to the listbox
foreach (string fileName in fullFileName)
{
dllList.Items.Add(fileName.Substring(fileName.LastIndexOf(#"\")+1));
}
}
}
// handle the selected change if you wish and get the full path from the selectedIndex.
private void dllList_SelectedIndexChanged(object sender, EventArgs e)
{
// check to make sure there is a selected item
if (dllList.SelectedIndex > -1)
{
string fullPath = fullFileName[dllList.SelectedIndex];
// remove the item from the list
fullFileName.RemoveAt(dllList.SelectedIndex);
dllList.Items.Remove(dllList.SelectedItem);
}
}
You can extract the fileName of the absolute path using the static Class Path in the System.IO namespace
//returns only the filename of an absolute path.
Path.GetFileName("FilePath");
i have application with Listbox and files, each time i press on Add button the default C drive open and i want the application to remember the last path i used
private void btnAdd_Click(object sender, EventArgs e)
{
System.IO.Stream myStream;
OpenFileDialog thisDialog = new OpenFileDialog();
thisDialog.InitialDirectory = "c:\\";
thisDialog.Filter = "(*.snoop, *.pcap, *.cap, *.net)|*.snoop; *.pcap; *.cap; *.net|" + "All files (*.*)|*.*";
thisDialog.FilterIndex = 1;
thisDialog.RestoreDirectory = false;
thisDialog.Multiselect = true; // Allow the user to select multiple files
thisDialog.Title = "Please Select Source File";
thisDialog.FileName = lastPath;
List<string> list = new List<string>();
if (thisDialog.ShowDialog() == DialogResult.OK)
{
foreach (String file in thisDialog.FileNames)
{
try
{
if ((myStream = thisDialog.OpenFile()) != null)
{
using (myStream)
{
listBoxFiles.Items.Add(file);
}
}
}
catch (Exception ex)
{
MessageBox.Show("Error: Could not read file from disk. Original error: " + ex.Message);
}
}
}
}
Save the last directory used in a global variable like this:
private string _lastPath = string.Empty;
then after the file selection initialize it:
if(thisDialog.Filenames.Length > 0)
_lastPath = Path.GetDirectoryName(thisDialog.Filenames[0]);
when you reopen the dialog set the InitialDirectory with this check:
thisDialog.InitialDirectory = (_lastPath.Length > 0 ? _lastPath: "c:\\");
and remove the thisDialog.FileName = lastPath;
EDIT --- UPDATE OF YOUR CODE ---
// This at the global level of your form
private string _lastPath = string.Empty;**
private void btnAdd_Click(object sender, EventArgs e)
{
System.IO.Stream myStream;
OpenFileDialog thisDialog = new OpenFileDialog();
thisDialog.InitialDirectory = (_lastPath.Length > 0 ? _lastPath: "c:\\");
thisDialog.Filter = "(*.snoop, *.pcap, *.cap, *.net)|*.snoop; *.pcap; *.cap; *.net|" + "All files (*.*)|*.*";
thisDialog.FilterIndex = 1;
thisDialog.RestoreDirectory = false;
thisDialog.Multiselect = true; // Allow the user to select multiple files
thisDialog.Title = "Please Select Source File";
thisDialog.FileName = lastPath;
List<string> list = new List<string>();
if (thisDialog.ShowDialog() == DialogResult.OK)
{
if(thisDialog.Filenames.Length > 0)
_lastPath = Path.GetDirectoryName(thisDialog.Filenames[0]);
foreach (String file in thisDialog.FileNames)
{
try
{
if ((myStream = thisDialog.OpenFile()) != null)
{
using (myStream)
{
listBoxFiles.Items.Add(file);
}
}
}
catch (Exception ex)
{
MessageBox.Show("Error: Could not read file from disk. Original error: " + ex.Message);
}
}
}
}
You can use a Visual Studio have the last path value for every execution of the application.
Only have to go to Project Properties->Configuration and add a value descriptor.
Example:
Name = LastPath; Type = string; Scope = User; Value = "Default path";
And then after you rebuild yout application, you can set this property this way:
Settings.Default.LastPath = LastPathSelected;
later, you can retrieve the value with:
thisDialog.InitialDirectory = Settings.Default.LastPath;
thisDialog.InitialDirectory = Path.GetDirectoryName(lastPath);
Yes, you can use the OpenFileDialog.InitialDirectory property. Note: you are setting the directory and not the file. So be sure to remove the filename from the path.
more info here
remove this line and you have the last path
thisDialog.InitialDirectory = "c:\\";