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Can I store an Ini file in a Resources file?

I have a Windows Forms application, .Net Framework 4.6.1, and I want to store some DB connection data in an Ini file.
I then wanted to store it in the Resources file of the project (so I don't have to copy/paste the file in the Debug and Release folder manually, etc.) as a normal file, but when I tried to compile the program and read the Ini data with ini-parser, the following exception showed up: System.ArgumentException: 'Invalid characters in path access'.
I'm using Properties.Resources where I read the Ini file, so I guessed there would be no problem with the path. Could it be a problem with the Ini file itself?
The content of the Ini file is the following:
[Db]
host = (anIP)
port = (aPort)
db = (aDbName)
user = (aDbUser)
password = (aDbUserPwd)
And my method for reading the data:
public static void ParseIniData()
{
var parser = new FileIniDataParser();
IniData data = parser.ReadFile(Properties.Resources.dbc);
mysqlHost = data["Db"]["host"];
mysqlPort = data["Db"]["port"];
mysqlDb = data["Db"]["db"];
mysqlUser = data["Db"]["user"];
mysqlPwd = data["Db"]["password"];
}

I finally could do it using what #KlausGütter told me in the comments (thanks!).
Instead of using the FileIniDataParser you have to use the StreamIniDataParser, and get the Stream with Assembly.GetManifestResourceStream.
I found this a bit tricky, because using this method you need to set the Build Action in the file you want to read to Embedded Resource.
This file is then added as an embedded resource in compile time and you can retrieve its stream.
So my method ended up the following way:
public static void ParseIniData()
{
var parser = new StreamIniDataParser();
dbcReader = new StreamReader(_Assembly.GetManifestResourceStream("NewsEditor.Resources.dbc.ini"));
IniData data = parser.ReadData(dbcReader);
mysqlHost = data["Db"]["host"];
mysqlPort = data["Db"]["port"];
mysqlDb = data["Db"]["db"];
mysqlUser = data["Db"]["user"];
mysqlPwd = data["Db"]["password"];
}
where _Assembly is a private static attribute: private static Assembly _Assembly = Assembly.GetExecutingAssembly();. This gets you the assembly that's being executed when running the code (you could also use this code directly in the method, but I used the Assembly on another method in my class, so I decided to set an attribute... DRY I guess).

How can I create a database file with SQLite-net?

I am using SQLite-net nuget package in my UWP application. I want to create a local database file to use as such:
var s = new SQLiteConnection("myDbSQLite.db3", SQLiteOpenFlags.Create);
But it throws the error:
Could not open database file:
C:\Path\MyProject\bin\x86\Debug\AppX\myDbSQLite.db3 (Misuse)
I see in other posts they suggest to use SQLiteConnection.CreateFile("MyDatabase.sqlite"); but I don't see that method?
EDIT
The code
FileStream fs = File.Create(path);
Throws the exception:
UnauthorizedAccessException access to the path is denied
So I think this is a permission issue I am having with UWP. Is there something in the capabilities that I need to set?

Check your permissions on the folder, and also try using this for the constructor
_database = new SQLiteAsyncConnection(
"myDbSQLite.db3",
SQLiteOpenFlags.Create |
SQLiteOpenFlags.FullMutex |
SQLiteOpenFlags.ReadWrite );

Because creating a file in UWP must be done with the UWP API, if you're going to use this nuget library, you have to accommodate by creating it yourself first:
// Create the empty file; replace if exists.
Windows.Storage.StorageFolder storageFolder = Windows.Storage.ApplicationData.Current.LocalFolder;
storageFolder.CreateFileAsync("myDbSQLite.db3", Windows.Storage.CreationCollisionOption.ReplaceExisting);
My UWP app is actually part of a Xamarin.Forms app that is using shared code, so if your app is solely UWP there's probably a better library, such as this one that Codexer referred.

You should use a folder wher you have write-access to. So please try the following code:
String path = Environment.GetFolderPath(Environment.SpecialFolder.MyDocuments);
string dbFile = Path.Combine( path, "myDbSQLite.db3");
var s = new SQLiteConnection( dbFile, SQLiteOpenFlags.Create);

This worked for me:
var databasePath = Path.Combine(GetLocalFileDirectory(), "MyData.db");
try
{
// Create the empty file; replace if exists.
db = new SQLiteAsyncConnection(databasePath,
SQLiteOpenFlags.Create |
SQLiteOpenFlags.FullMutex |
SQLiteOpenFlags.ReadWrite);
}
catch(Exception ex)
{
throw new Exception(ex.Message);
}
public string GetLocalFileDirectory()
{
var docFolder = FileSystem.AppDataDirectory
var libFolder = Path.Combine(docFolder, "Databases");
if (!Directory.Exists(libFolder))
{
Directory.CreateDirectory(libFolder);
}
return libFolder;
}

error : Value of 'null' is not valid for 'stream'

I have opened Resources.resx file of a WinForms application project and copied images there. I am using the code shown below to get an image from the resources, but getting following error:
Value of 'null' is not valid for 'stream'.
The error occurs in this line:
btn.BackgroundImage = new Bitmap(
System.Reflection.Assembly.GetEntryAssembly().GetManifestResourceStream(test));
Relevant code:
private void genericButton_event(object sender, EventArgs e)
{
var btn = (Button)sender;
string test = "StudentModule.Properties.Resources" + btn.Name + ".png";
//Getting the error here:
btn.BackgroundImage = new Bitmap(System
.Reflection
.Assembly
.GetEntryAssembly()
.GetManifestResourceStream(test));
}
The value of test is "StudentModule.Properties.ResourcesbtnAbout.png", but I think it should be: "StudentModule.Properties.Resources.btnAbout.png". I tried this line also but it's not working:
string test = "StudentModule.Properties.Resources." + btn.Name + ".png";
What is the mistake I am doing here?

GetManifestResourceStream() returns null when the stream could not be found. Which will then bomb the Bitmap constructor.
So the string you used is wrong. It isn't clear exactly how you embedded the resource. Do strongly favor using the resource designer, Project + Resources tab. Click the arrow on the Add Resource button, choose "Add Existing File" and select the file. You can then use the ResourceManager to get the bitmap:
var imageName = "Chrysanthemum";
btn.BackgroundImage = (Bitmap)Properties.Resources.ResourceManager.GetObject(imageName);
Note how the resource name is just the plain resource name as it appears in the resource designer.

Accessing Resources in a C# WPF Application (Same Assembly)

(Before I jump into the nitty-gritty, I want to set the context: I'm trying to load a WPF frame with the contents of an .html file that I'm including in my project as a resource.)
I create a new WPF Application; I add a new folder called 'foofiles' to the project, and I add a couple of files (page1.foo and page2.foo) to that folder.
For each newly added .foo file, I right-click on it, go to "Properties," and set the Build Action to 'Resource,' and the Copy To Output Directory to "Copy always."
I want to be able to access those files both in XAML:
<Frame x:Name="bar" Source="/foofiles/page1.foo"/>
And in procedural code:
private void someFunc()
{
bar.Source = new Uri("/foofiles/page1.foo");
}
But I just can't figure out why this doesn't work -- I get a "Format of the URI could not be determined."
In the code-behind, I tried doing this:
private void someFunc()
{
bar.Source = new Uri("pack://application:,,,/foofiles/page1.foo");
}
which didn't throw an exception, but my main window crashed.
In my thinking, if I add a file of any type to my project, and if I mark it as "Resource" in "Build Action," I should be able to use that file per my examples above. Also, I would like to use that file like this:
private void someOtherFunc()
{
System.IO.StreamReader reader = new System.IO.StreamReader("/foofiles/page1.foo");
string bar = reader.ReadToEnd();
}
Any help would be appreciated... thanks in advance!

Try adding the component-part to your Pack URI like this
pack://application:,,,/AssemblyName;component/ResourceName
where AssemblyName is the name of your assembly. So for your case, the following statement should work:
bar.Source = new Uri("pack://application:,,,/AssemblyName;component/foofiles/page1.foo");
More practically, try the relative pack uri notation:
bar.Source = new Uri("AssemblyName;component/foofiles/page1.foo", UriKind.Relative));
For stream reading resources use
var streamResourceInfo = Application.GetResourceStream(uri);
using (var stream = streamResourceInfo.Stream)
{
// do fancy stuff with stream
}

A problem with Relative Path Resolution when setting an Image Source

I have built a small WPF application that allows users to upload documents and then select one to display.
The following is the code for the file copy.
public static void MoveFile( string directory, string subdirectory)
{
var open = new OpenFileDialog {Multiselect = false, Filter = "AllFiles|*.*"};
var newLocation = CreateNewDirectory( directory, subdirectory, open.FileName);
if ((bool) open.ShowDialog())
CopyFile(open.FileName, newLocation);
else
"You must select a file to upload".Show();
}
private static void CopyFile( string oldPath, string newPath)
{
if(!File.Exists(newPath))
File.Copy(oldPath, newPath);
else
string.Format("The file {0} already exists in the current directory.", Path.GetFileName(newPath)).Show();
}
The file is copied without incident. However, when the user tries to select a file they just copied to display, A file not found exception. After debugging, I've found that the UriSource for the dynamic image is resolving the relative path 'Files{selected file}' to the directory that was just browsed by the file select in the above code instead of the Application directory as it seems like it should.
This problem only occurs when a newly copied file is selected. If you restart the application and select the new file it works fine.
Here's the code that dynamically sets the Image source:
//Cover = XAML Image
Cover.Source(string.Format(#"Files\{0}\{1}", item.ItemID, item.CoverImage), "carton.ico");
...
public static void Source( this Image image, string filePath, string alternateFilePath)
{
try
{image.Source = GetSource(filePath);}
catch(Exception)
{image.Source = GetSource(alternateFilePath);}
}
private static BitmapImage GetSource(string filePath)
{
var source = new BitmapImage();
source.BeginInit();
source.UriSource = new Uri( filePath, UriKind.Relative);
//Without this option, the image never finishes loading if you change the source dynamically.
source.CacheOption = BitmapCacheOption.OnLoad;
source.EndInit();
return source;
}
I'm stumped. Any thought's would be appreciated.

Although I don't have a direct answer, you should use caution for such allowing people to upload files. I was at a seminar where they had good vs bad hackers to simulate real life exploits. One was such that files were allowed to be uploaded. They uploaded malicious asp.net files and called the files directly as they new where the images were ultimately presented to the users, and were able to eventually take over a system. You may want to verify somehow what TYPES of files are being allowed and maybe have stored in a non-exeucting directory of your web server.

It turns out I was missing an option in the constructor of my openfiledialogue. The dialogue was changing the current directory which was causing the relative paths to resolve incorrectly.
If you replace the open file with the following:
var open = new OpenFileDialog{ Multiselect = true, Filter = "AllFiles|*.*", RestoreDirectory = true};
The issue is resolved.