what i try to do is a simple math operation in my project but something works wrong because i get always 0. So my question is:
how can i do this math operations using mvc razor?
what i try is this:
#{
decimal a = 2 / 4; //--> result 0,5
int b = a * 100 //--> 50
}
the problem is that the first result of the variable a give me 0,5 and i need this value in decimal,
but then i wanted to multiplicate it with 100 that gives me the 50 of datatype int.
hmm, but i can´t figured it out how to do that..
can someone give me a hand with this pls??
You are performing Integer division which gives you Zero here yYou need to convert one of the value into decimal while performing division.
Try This:
decimal a = 2.0M / 4;
int b = Convert.ToInt32(a * 100);
The following works:
decimal a = 2m / 4m; //--> result 0,5
int b = (int)(a * 100m);
Related
This simple calculation is returning zero, I can't figure it out:
decimal share = (18 / 58) * 100;
You are working with integers here. Try using decimals for all the numbers in your calculation.
decimal share = (18m / 58m) * 100m;
18 / 58 is an integer division, which results in 0.
If you want decimal division, you need to use decimal literals:
decimal share = (18m / 58m) * 100m;
Since some people are linking to this from pretty much any thread where the calculation result is a 0, I am adding this as a solution as not all the other answers apply to case scenarios.
The concept of needing to do calculations on various types in order to obtain that type as a result applies, however above only shows 'decimal' and uses it's short form such as 18m as one of the variables to be calculated.
// declare and define initial variables.
int x = 0;
int y = 100;
// set the value of 'x'
x = 44;
// Results in 0 as the whole number 44 over the whole number 100 is a
// fraction less than 1, and thus is 0.
Console.WriteLine( (x / y).ToString() );
// Results in 0 as the whole number 44 over the whole number 100 is a
// fraction less than 1, and thus is 0. The conversion to double happens
// after the calculation has been completed, so technically this results
// in 0.0
Console.WriteLine( ((double)(x / y)).ToString() );
// Results in 0.44 as the variables are cast prior to calculating
// into double which allows for fractions less than 1.
Console.WriteLine( ((double)x / (double)y).ToString() );
Because the numbers are integers and you perform integer division.
18 / 58 is 0 in integer division.
Whenever I encounter such situations, I just upcast the numerator.
double x = 12.0 / 23409;
decimal y = 12m / 24309;
Console.WriteLine($"x = {x} y = {y}");
double res= (firstIntVar * 100f / secondIntVar) / 100f;
when dividing numbers I use double or decimal , else I am getting 0 , with this code even if firstIntVar && secondIntVar are int it will return the expected answer
decimal share = (18 * 100)/58;
Solved: working perfectly with me
int a = 375;
int b = 699;
decimal ab = (decimal)a / b * 100;
This simple calculation is returning zero, I can't figure it out:
decimal share = (18 / 58) * 100;
You are working with integers here. Try using decimals for all the numbers in your calculation.
decimal share = (18m / 58m) * 100m;
18 / 58 is an integer division, which results in 0.
If you want decimal division, you need to use decimal literals:
decimal share = (18m / 58m) * 100m;
Since some people are linking to this from pretty much any thread where the calculation result is a 0, I am adding this as a solution as not all the other answers apply to case scenarios.
The concept of needing to do calculations on various types in order to obtain that type as a result applies, however above only shows 'decimal' and uses it's short form such as 18m as one of the variables to be calculated.
// declare and define initial variables.
int x = 0;
int y = 100;
// set the value of 'x'
x = 44;
// Results in 0 as the whole number 44 over the whole number 100 is a
// fraction less than 1, and thus is 0.
Console.WriteLine( (x / y).ToString() );
// Results in 0 as the whole number 44 over the whole number 100 is a
// fraction less than 1, and thus is 0. The conversion to double happens
// after the calculation has been completed, so technically this results
// in 0.0
Console.WriteLine( ((double)(x / y)).ToString() );
// Results in 0.44 as the variables are cast prior to calculating
// into double which allows for fractions less than 1.
Console.WriteLine( ((double)x / (double)y).ToString() );
Because the numbers are integers and you perform integer division.
18 / 58 is 0 in integer division.
Whenever I encounter such situations, I just upcast the numerator.
double x = 12.0 / 23409;
decimal y = 12m / 24309;
Console.WriteLine($"x = {x} y = {y}");
double res= (firstIntVar * 100f / secondIntVar) / 100f;
when dividing numbers I use double or decimal , else I am getting 0 , with this code even if firstIntVar && secondIntVar are int it will return the expected answer
decimal share = (18 * 100)/58;
Solved: working perfectly with me
int a = 375;
int b = 699;
decimal ab = (decimal)a / b * 100;
This simple calculation is returning zero, I can't figure it out:
decimal share = (18 / 58) * 100;
You are working with integers here. Try using decimals for all the numbers in your calculation.
decimal share = (18m / 58m) * 100m;
18 / 58 is an integer division, which results in 0.
If you want decimal division, you need to use decimal literals:
decimal share = (18m / 58m) * 100m;
Since some people are linking to this from pretty much any thread where the calculation result is a 0, I am adding this as a solution as not all the other answers apply to case scenarios.
The concept of needing to do calculations on various types in order to obtain that type as a result applies, however above only shows 'decimal' and uses it's short form such as 18m as one of the variables to be calculated.
// declare and define initial variables.
int x = 0;
int y = 100;
// set the value of 'x'
x = 44;
// Results in 0 as the whole number 44 over the whole number 100 is a
// fraction less than 1, and thus is 0.
Console.WriteLine( (x / y).ToString() );
// Results in 0 as the whole number 44 over the whole number 100 is a
// fraction less than 1, and thus is 0. The conversion to double happens
// after the calculation has been completed, so technically this results
// in 0.0
Console.WriteLine( ((double)(x / y)).ToString() );
// Results in 0.44 as the variables are cast prior to calculating
// into double which allows for fractions less than 1.
Console.WriteLine( ((double)x / (double)y).ToString() );
Because the numbers are integers and you perform integer division.
18 / 58 is 0 in integer division.
Whenever I encounter such situations, I just upcast the numerator.
double x = 12.0 / 23409;
decimal y = 12m / 24309;
Console.WriteLine($"x = {x} y = {y}");
double res= (firstIntVar * 100f / secondIntVar) / 100f;
when dividing numbers I use double or decimal , else I am getting 0 , with this code even if firstIntVar && secondIntVar are int it will return the expected answer
decimal share = (18 * 100)/58;
Solved: working perfectly with me
int a = 375;
int b = 699;
decimal ab = (decimal)a / b * 100;
In my C# application I want to implement a simple calculation. I got this code:
private void button1_Click(object sender, EventArgs e)
{
int percentField;
int priceField;
int result;
percentField = int.Parse(txtPercentNew.Text);
priceField = int.Parse(txtPriceNew.Text);
result = priceField / 100 * percentField;
MessageBox.Show(result.ToString());
}
But the problem is the MessageBox displays me 0. I can't figure out why.
Can someone please give me a hint what I am doing wrong?
Your variables are integers, which means that / performs integer division. Unless priceField is at least equal to 100 you will always get 0 as the result.
You can correct the problem by casting priceField to a floating point type before dividing:
(double)priceField / 100 * percentField;
However, this will not work while result is of type int because the compiler wants to protect you from inadvertent rounding errors. So you either have to cast back to an integer (losing precision due to rounding):
result = (int)((double)priceField / 100 * percentField);
or else make result be a double as well.
You are using integers instead of floating point numbers.
As a consequence, rounding off occurs during calculation.
Use float or double instead of int.
Probably your priceField is less then 100 and since you doing integer division, it creates 0 as a result.
From / Operator (C# Reference)
When you divide two integers, the result is always an integer. For
example, the result of 7 / 3 is 2. To determine the remainder of 7 /
3, use the remainder operator (%). To obtain a quotient as a rational
number or fraction, give the dividend or divisor type float or type
double. You can assign the type implicitly if you express the dividend
or divisor as a decimal by putting a digit to the right side of the
decimal point, as the following example shows.
Just cast one of your variables to floating point type like;
result = priceField / 100d * percentField;
or
result = (double)priceField / 100 * percentField;
You are working with only integers, try
double result;
result = priceField / (double)100 * percentField;
In your code, you are dividing by 100. Which means every int you are going to divide less than 100 will result in a value between [0 - 1]. When implicitly casting to an int, the result will be floored. Therefor, a 0.1 will become 0 - a 0.9 will become 0 - ...
try cast to double, because you're working with integers it results in 0.
example here
The problem is you're using int for each value.
Change result to a double and try this:
result = (double)priceField / 100 * percentField;
It should work; however, if you want to do this properly I recommend you read about MidpointRounding.
I am facing a problem in dividing numbers in c#.
See my code in C# for division
double openRate = 0,
long a=542;
long b=4795;
openRate =(a/b)*100
This gives 11.303.. in my calculator .
But c# gives me 0.0
What could be reason?
When you write
long a = 542;
long b = 4795;
Since because a / b is calculated as an integral value; any fractional part was dropped. So a / b is equal 0 at this point not 0,113...
From elemantary school math;
0 * 100 = 0
Your calculator use probably floating division so actually it calculates this like;
double openRate = 0;
long a = 542;
long b = 4795;
openRate =((double)a / b) * 100; // 11.303...
a and b are integers and get divided using the operator/ of long, resulting in an integral division.
542 / 4795 = 0.113
After this they got multiplied with 100, which is an integer, either.
0 * 100 = 0
Last but not least the (still integral) result get's converted into an double. What you want to write is something like this:
openRate = ((double)a / (double)b) * 100.0;