This simple calculation is returning zero, I can't figure it out:
decimal share = (18 / 58) * 100;
You are working with integers here. Try using decimals for all the numbers in your calculation.
decimal share = (18m / 58m) * 100m;
18 / 58 is an integer division, which results in 0.
If you want decimal division, you need to use decimal literals:
decimal share = (18m / 58m) * 100m;
Since some people are linking to this from pretty much any thread where the calculation result is a 0, I am adding this as a solution as not all the other answers apply to case scenarios.
The concept of needing to do calculations on various types in order to obtain that type as a result applies, however above only shows 'decimal' and uses it's short form such as 18m as one of the variables to be calculated.
// declare and define initial variables.
int x = 0;
int y = 100;
// set the value of 'x'
x = 44;
// Results in 0 as the whole number 44 over the whole number 100 is a
// fraction less than 1, and thus is 0.
Console.WriteLine( (x / y).ToString() );
// Results in 0 as the whole number 44 over the whole number 100 is a
// fraction less than 1, and thus is 0. The conversion to double happens
// after the calculation has been completed, so technically this results
// in 0.0
Console.WriteLine( ((double)(x / y)).ToString() );
// Results in 0.44 as the variables are cast prior to calculating
// into double which allows for fractions less than 1.
Console.WriteLine( ((double)x / (double)y).ToString() );
Because the numbers are integers and you perform integer division.
18 / 58 is 0 in integer division.
Whenever I encounter such situations, I just upcast the numerator.
double x = 12.0 / 23409;
decimal y = 12m / 24309;
Console.WriteLine($"x = {x} y = {y}");
double res= (firstIntVar * 100f / secondIntVar) / 100f;
when dividing numbers I use double or decimal , else I am getting 0 , with this code even if firstIntVar && secondIntVar are int it will return the expected answer
decimal share = (18 * 100)/58;
Solved: working perfectly with me
int a = 375;
int b = 699;
decimal ab = (decimal)a / b * 100;
Related
This simple calculation is returning zero, I can't figure it out:
decimal share = (18 / 58) * 100;
You are working with integers here. Try using decimals for all the numbers in your calculation.
decimal share = (18m / 58m) * 100m;
18 / 58 is an integer division, which results in 0.
If you want decimal division, you need to use decimal literals:
decimal share = (18m / 58m) * 100m;
Since some people are linking to this from pretty much any thread where the calculation result is a 0, I am adding this as a solution as not all the other answers apply to case scenarios.
The concept of needing to do calculations on various types in order to obtain that type as a result applies, however above only shows 'decimal' and uses it's short form such as 18m as one of the variables to be calculated.
// declare and define initial variables.
int x = 0;
int y = 100;
// set the value of 'x'
x = 44;
// Results in 0 as the whole number 44 over the whole number 100 is a
// fraction less than 1, and thus is 0.
Console.WriteLine( (x / y).ToString() );
// Results in 0 as the whole number 44 over the whole number 100 is a
// fraction less than 1, and thus is 0. The conversion to double happens
// after the calculation has been completed, so technically this results
// in 0.0
Console.WriteLine( ((double)(x / y)).ToString() );
// Results in 0.44 as the variables are cast prior to calculating
// into double which allows for fractions less than 1.
Console.WriteLine( ((double)x / (double)y).ToString() );
Because the numbers are integers and you perform integer division.
18 / 58 is 0 in integer division.
Whenever I encounter such situations, I just upcast the numerator.
double x = 12.0 / 23409;
decimal y = 12m / 24309;
Console.WriteLine($"x = {x} y = {y}");
double res= (firstIntVar * 100f / secondIntVar) / 100f;
when dividing numbers I use double or decimal , else I am getting 0 , with this code even if firstIntVar && secondIntVar are int it will return the expected answer
decimal share = (18 * 100)/58;
Solved: working perfectly with me
int a = 375;
int b = 699;
decimal ab = (decimal)a / b * 100;
I'm very new with C#.
I don't understand why is x = 1 and not 1.4.
Can please somebody explain me this?
double x = (double)(12 / 5 - 3 % 2);
Console.WriteLine(x);
Because this is NOT about double.
You are integer-executing
(12 / 5 - 3 % 2);
and THEN casting to double. If you want this to be about double, then make sure at least one of the numbers is a double. In your case just mark the literals as double.
(12d / 5d - 3d % 2d);
is all doubles. As long as one is a double, the operation happens as double - but your original case makes all the calculations, THEN casts to double. So they happen as integer.
You're doing integer math and then converting to double. 12 / 5 = 2, 3 % 2 = 1, and 2 - 1 = 1.
Welcome to stackoverflow! :)
The problem is that you are operating all int, and afterwards converting them to double.
You need to make sure that you are operating with doubles from the beginning.
Try out the code in here: https://dotnetfiddle.net/xaQjKL
using System;
public class Program
{
public static void Main()
{
// Doubles from the beggining
double d_twelve = 12.0;
double d_five = 5.0;
double x = (double)(d_twelve / d_five);
Console.WriteLine($"Using all doubles: {x}");
// First split two int, then convert the result to double
int i_twelve = 12;
int i_five = 5;
x = (double)(i_twelve / i_five);
Console.WriteLine($"Using ints, and converting at the end to double: {x}");
// And now your code:
x = (double)(12 / 5 - 3 % 2);
Console.WriteLine($"Your original code: {x}");
// And now your code fixed (notice the 12 => 12.0):
x = (double)(12.0 / 5 - 3 % 2);
Console.WriteLine($"Changing 12 by 12.0: {x}");
}
}
You are doing operations with integers and then casting he result to a double.
double x = (12d / 5d - 3d % 2d);
Console.WriteLine(x);
Adding d after a number will make it a double while adding f will make it a float.
https://learn.microsoft.com/en-us/dotnet/csharp/language-reference/builtin-types/floating-point-numeric-types#real-literals
Because you use integer values inside the parenthesis, and the expression is calculated using integer math before being cast to double.
You can use a double value for the first value and it should be enough:
> double x = (12d / 5) - (3 % 2);
> Console.WriteLine(x);
1.4
This simple calculation is returning zero, I can't figure it out:
decimal share = (18 / 58) * 100;
You are working with integers here. Try using decimals for all the numbers in your calculation.
decimal share = (18m / 58m) * 100m;
18 / 58 is an integer division, which results in 0.
If you want decimal division, you need to use decimal literals:
decimal share = (18m / 58m) * 100m;
Since some people are linking to this from pretty much any thread where the calculation result is a 0, I am adding this as a solution as not all the other answers apply to case scenarios.
The concept of needing to do calculations on various types in order to obtain that type as a result applies, however above only shows 'decimal' and uses it's short form such as 18m as one of the variables to be calculated.
// declare and define initial variables.
int x = 0;
int y = 100;
// set the value of 'x'
x = 44;
// Results in 0 as the whole number 44 over the whole number 100 is a
// fraction less than 1, and thus is 0.
Console.WriteLine( (x / y).ToString() );
// Results in 0 as the whole number 44 over the whole number 100 is a
// fraction less than 1, and thus is 0. The conversion to double happens
// after the calculation has been completed, so technically this results
// in 0.0
Console.WriteLine( ((double)(x / y)).ToString() );
// Results in 0.44 as the variables are cast prior to calculating
// into double which allows for fractions less than 1.
Console.WriteLine( ((double)x / (double)y).ToString() );
Because the numbers are integers and you perform integer division.
18 / 58 is 0 in integer division.
Whenever I encounter such situations, I just upcast the numerator.
double x = 12.0 / 23409;
decimal y = 12m / 24309;
Console.WriteLine($"x = {x} y = {y}");
double res= (firstIntVar * 100f / secondIntVar) / 100f;
when dividing numbers I use double or decimal , else I am getting 0 , with this code even if firstIntVar && secondIntVar are int it will return the expected answer
decimal share = (18 * 100)/58;
Solved: working perfectly with me
int a = 375;
int b = 699;
decimal ab = (decimal)a / b * 100;
I'm counting the results of my database.
If it's lower then 50, i want to divide them by 2.
Example:
if(CountResults < 50)
{
//CountResults = 39
int divided = CountResults / 2; //Results in 19
}
What i want:
if(CountResults < 50)
{
//CountResults = 39
int divided = CountResults / 2; //Results in 19,5
Math.Round(divided, 0);
}
I want to be able to round it upwards and down.
So i get the result 19.5 twice. Once i want it to be 19, and once to be 20..
How do i achieve this?
It's not clear how you are going to use your code twice, but if you want to divide integer into two integer parts just subtract first result from totals:
if(CountResults < 50)
{
//CountResults = 39
int divided1 = CountResults / 2; // 19
int divided2 = CountResults - divided1; // 20
}
First result will use integer division and it will give you result rounded towards zero (19 in your case). Further reading: C# Specification 7.7.2 Division Operator
Second result will give you rest which will be either equal to first result (if there was no rounding), or it will be equal to division rounded from zero (20 in your case).
The rounding part can be accomplished using these 2 nice methods:
Math.Floor brings it to the floor
Math.Celing lifts it to the celing ;)
The calculation part is a little more tricky. This statement:
int divided = CountResults / 2; //Results in 19,5
cannot really be true, or let's say it does not matter what is behind the comma because when it is assigned to the variable int devided it will loose this information and no rounding is anymore required.
When you want a result of type double (meaning e.g. 19,5 ) and you want to round that result, you need at least one of the parameters of the calculation to be of type double double!
Example
double var1 = 39;
int res_low = (int)Math.Floor(var1 / 2);
int res_high = (int)Math.Ceiling(var1 / 2);
note that writing 2 is implicitly seen by the compiler as int and writing 2.0 is implicitly seen as double. So this would yield the same result:
int var2 = 39;
int res_low2 = (int)Math.Floor(var2 / 2.0);
int res_high2 = (int)Math.Ceiling(var2 / 2.0);
I am facing a problem in dividing numbers in c#.
See my code in C# for division
double openRate = 0,
long a=542;
long b=4795;
openRate =(a/b)*100
This gives 11.303.. in my calculator .
But c# gives me 0.0
What could be reason?
When you write
long a = 542;
long b = 4795;
Since because a / b is calculated as an integral value; any fractional part was dropped. So a / b is equal 0 at this point not 0,113...
From elemantary school math;
0 * 100 = 0
Your calculator use probably floating division so actually it calculates this like;
double openRate = 0;
long a = 542;
long b = 4795;
openRate =((double)a / b) * 100; // 11.303...
a and b are integers and get divided using the operator/ of long, resulting in an integral division.
542 / 4795 = 0.113
After this they got multiplied with 100, which is an integer, either.
0 * 100 = 0
Last but not least the (still integral) result get's converted into an double. What you want to write is something like this:
openRate = ((double)a / (double)b) * 100.0;