Executing another Application with selected file using a button (C# Programming) - c#

To start, I'm a newbie with C# Programming and I've tried googling for solutions about my problem but it seems that i cannot find one, or simply too unlucky or too blind to spot one. I'm using Microsoft Visual Studio 2005.
Anyways. I was assigned to modify/create an automated test environment input application. The said application already has a function to run/start a CANoe program with a pre-defined file or if it's already running, stop the program.
private void button1_Click(object sender, EventArgs e)
{
// Execute CANoe(Obtain CANoe application objectg)
mApp = new CANoe.Application();
mMsr = (CANoe.Measurement)mApp.Measurement;
try
{
mApp.Open("C:\\Users\\uidr3024\\Downloads\\SRLCam4T0_Validation_ControlTool\\cfg\\SVT_SRLCam4T0_025B.cfg", true, true);
}
catch (System.Exception ex)
{
System.Console.WriteLine(ex.Message);
}
}
private void button2_Click(object sender, EventArgs e)
{
// Finish CANoe
if (mApp != null) {
mApp.Quit();
}
// Release the object
fnReleaseComObject(mMsr);
fnReleaseComObject(mApp);
}
What I wanted to do now is to have an OpenFileDialog box that will show a selection of files and user will be able to browse and select any file to start the CANoe program with the selected file and not just the file path that's been input in the code along the "mApp.Open()" syntax. I've tried this:
private void button5_Click_1(object sender, EventArgs e)
{
OpenFileDialog openFileDialog1 = new OpenFileDialog();
openFileDialog1.InitialDirectory = #"C:\Users\uidr3024\Downloads\SRLCam4T0_Validation_ControlTool\cfg";
openFileDialog1.Title = "Browse Configuration Files";
openFileDialog1.CheckFileExists = true;
openFileDialog1.CheckPathExists = true;
openFileDialog1.Filter = "CANalyzer/CANoe Configuration (*.cfg)|*.cfg |All files (*.*)|*.*";
openFileDialog1.FilterIndex = 1;
openFileDialog1.RestoreDirectory = true;
if (openFileDialog1.ShowDialog() == DialogResult.OK)
{
textBox1.Text = openFileDialog1.FileName;
}
}
I've tried this code that I often see in the Web and in the Tutorials but I don't know how to incorporate it with the button for running the CANoe program so that when user clicks the Open button from the Dialog Box, the file path would be shown in the textbox(optional) and/or when the user then clicks the Start CANoe, CANoe program would start with the selected .cfg file.
Am I making any sense here? Or am I doing the right thing here?
Btw, I found these... And I'm using a CANoe library for these, ofc.
#region "***** CANoe Object definition *****"
private CANoe.Application mApp = null; // CANoe Application CANoeƒAƒvƒŠƒP[ƒVƒ‡ƒ“
private CANoe.Measurement mMsr = null; // CANoe Mesurement function CANoe‘ª’è‹#”\
private CANoe.Variable mSysVar = null; // System variable ƒVƒXƒeƒ€•Ï”
private CANoe.Variable mSysVar_start = null; // System variable ƒVƒXƒeƒ€•Ï”
#endregion

I think you have done most of the hard work, unless I've missed something I think you just need something like this in your button1_Click method:
if( textBox1.Text != String.Empty && System.IO.File.Exists(textBox1.Text) )
{
// The textbox has a filename in it, use it
mApp.Open(textBox1.Text, true, true);
}
else
{
// The user hasn't selected a config file, launch with default
mApp.Open("C:\\Users\\uidr3024\\Downloads\\SRLCam4T0_Validation_ControlTool\\cfg\\SVT_SRLCam4T0_025B.cfg", true, true);
}

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FileDialog select target file?

So!
A user right clicks any file on their computer and a custom made option opens up my program, on Form_load I ask the user to choose a file however, I want that file to be the file they opened the program with.
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How could I achieve this?
When your program is associated with any file extension, Windows will pass the file name via command line parameter, so you can examine them:
private void Form1_Load(object sender, System.EventArgs e) {
String[] data = Environment.GetCommandLineArgs();
// 0th parameter is executable itself, we want the 1st parameter
if (data.Length > 1)
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else
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If you asking about 'Send to' menu in Windows context menu -> You should put your application in special folder as described here: How-to geek: Customize the Send To Menu in Windows 10, 8, 7, or Vista and you will receive the full path including file name as first parameter in args in function Main()

OpenFileDialog and UnauthorizedAccessException

I'm developing a tool that processes an .fbx model and user input into a single file for use in a game. The code for when the user presses the "Import Model" button is as follows, and is similar for every button:
private void E_ImportModelButton_Click_1(object sender, EventArgs e)
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ofd.Filter = "FBX Model (.fbx)|*.fbx";
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The problem is, whenever I click OK, an UnauthorizedAccessException occurs. I have tried importing files from C:\Users\Owner\Downloads as well as C:\Users\Owner\Desktop and the C:\ drive itself, but it still occurs. What could I add to this code to gain access to these (and other) folders?
You are trying to read from directory via the method intended to read from a file:
string s = Path.GetDirectoryName(ofd.FileName);
E_model = File.ReadAllBytes(s);
Replace it with:
E_model = File.ReadAllBytes(ofd.FileName);
You can't ready the directory, you have to read a file:
string s = Path.GetDirectoryName(ofd.FileName);
E_model = File.ReadAllBytes(s);
Try adding the file name here

Prevent user from browsing elsewhere in an OpenFileDialog

What I need to do is prevent users from browsing anywhere else then where I declare them to browse.
for example I have: ofd.InitialDirectory = Location; on button click.
Location for example being C:\Users\Chris\Pictures.
The thing is that I know that some users will try be clever and might go selecting things outside that folder I declare. Is there any way to prevent that from happening?
Possible workaround:
Just an if statement checking if the location of the selected file starts with the same Location I start them off in.
OpenFileDialog ofd = new OpenFileDialog();
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string newPath = #"C:\Users\Chris\Pictures";
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textBox1.Text = ofd.FileName;
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, "Alert", MessageBoxButtons.OK, MessageBoxIcon.Error);
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You can't prevent users from navigating to another folder, you have to build an own OpenFileDialog if you want to do that. You can prevent though that the file isn't accepted.
You have to handle the FileOk event for that. You can check if the parent directory is the one you want it to be.
Something like this:
private void openFileDialog1_FileOk(object sender, System.ComponentModel.CancelEventArgs e)
{
string[] files = openFileDialog1.FileNames;
foreach (string file in files )
{
if (Path.GetDirectoryName(file) != yourRequiredPath)
{
e.Cancel = true;
break;
}
}
}
This is not possible.
You can't restrict users to prevent them to browse elsewhere where you don't wish to.
One possible way to fix this is to write your custom open dialog box with custom validations.
If you really want to prevent navigation in the file dialog the only way to do it would be to use the Common Item Dialog, provided by COM1, and give it an IFileDialogEvents and implement the OnFolderChanging event. To allow navigation, return S_OK and to deny navigation return something else.
1 "Provided by COM" as in the component object model, not some third party.

Enabling textbox on button click event

How can i add the mechanism in my downloader for the case although many threads on SO deals either with php etc and not upto the need.
I have a browse button at the front of a textbox where i get's the user entered Path on local drive to fix the location for downloading but i have already hardcoded one for system drive.I want textbox button to be disabled unless user clciks browse button and then new path can be entered for downloading after then.
How can i go?
A quick example:
private void browseButton_Click(object sender, EventArgs e)
{
var saveFileDialog = new System.Windows.Forms.SaveFileDialog();
var selectedPath= saveFileDialog.ShowDialog();
if (selectedPath == System.Windows.Forms.DialogResult.OK)
{
_savePath = saveFileDialog.FileName;
textBox1.Enabled = true;
textBox1.Text = _savePath;
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C# After using OpenFileDialog, a MessageBox doesn't open on top

Our primary database application has a feature that exports either an Excel workbook or an Access mdb for specified work orders. Those files are then sent to our subcontractors to populate with the required data. I am building an application that connects to the files and displays the data for review prior to being imported into the primary database. Simple enough, right? Here’s my problem: the application opens a OpenFileDialog box for the user to select the file that will be the datasource for the session. That works perfectly. If I open a MessageBox after it, that box open up behind any other open windows. After that, they respond correctly. I only expect to be using MessageBoxes for error handling, but the problem is perplexing. Has anyone encountered this problem?
The MessageBoxes in the code are only to verify that the path is correct and to solve this problem; but, here’s my code:
private void SubContractedData_Load(object sender, EventArgs e)
{
string FilePath;
string ext;
OpenFileDialog ofd = new OpenFileDialog();
ofd.Filter = "Microsoft Access Databases |*.mdb|Excel Workbooks|*.xls";
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ofd.InitialDirectory = ElementConfig.TransferOutPath();
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ext = FilePath.Substring((FilePath.Length - 3));
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MessageBox.Show(FilePath);
AccessImport(FilePath);
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While it isn't advisable to use MessageBoxes to debug your code, I think the immediate problem is that you are doing this in the form's load event.
Try it like this:
protected override void OnShown(EventArgs e) {
base.OnShown(e);
// your code
}
Your problem is definitely the fact that you're trying to do this while loading the Form, because the form isn't yet displayed.
Another alternative would be moving this functionality out of the Load event and give the user a button to push or something like that.
In other words:
private void SubContractedData_Load(object sender, EventArgs e)
{
// unless you're doing something else, you could remove this method
}
Add a button that handles this functionality:
private void SelectDataSourceClick(object sender, EventArgs e)
{
OpenFileDialog ofd = new OpenFileDialog();
ofd.Filter = "Microsoft Access Databases |*.*|Excel Workbooks|*.xls";
ofd.Title = "Select the data source";
ofd.InitialDirectory = ElementConfig.TransferOutPath();
if (ofd.ShowDialog() == DialogResult.OK)
{
var FilePath = ofd.FileName.ToString();
var ext = Path.GetExtension(FilePath).ToLower();
switch (ext)
{
case ".xls":
MessageBox.Show(FilePath);
AccessImport(FilePath);
break;
case ".mdb":
MessageBox.Show(FilePath);
AccessImport(FilePath);
break;
default:
MessageBox.Show("Extension not recognized " + ext);
break;
}
}
else
{
System.Windows.Forms.Application.Exit();
}
}

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