Prevent user from browsing elsewhere in an OpenFileDialog - c#

What I need to do is prevent users from browsing anywhere else then where I declare them to browse.
for example I have: ofd.InitialDirectory = Location; on button click.
Location for example being C:\Users\Chris\Pictures.
The thing is that I know that some users will try be clever and might go selecting things outside that folder I declare. Is there any way to prevent that from happening?
Possible workaround:
Just an if statement checking if the location of the selected file starts with the same Location I start them off in.
OpenFileDialog ofd = new OpenFileDialog();
private void button1_Click(object sender, EventArgs e)
{
string newPath = #"C:\Users\Chris\Pictures";
ofd.InitialDirectory = Location;
if (ofd.ShowDialog() == DialogResult.OK)
{
if (ofd.FileName.Contains(Location))
{
textBox1.Text = ofd.FileName;
}
else
{
MessageBox.Show("Please select a file that is located in the specified location (" + Location + ")"
, "Alert", MessageBoxButtons.OK, MessageBoxIcon.Error);
}
}
}

You can't prevent users from navigating to another folder, you have to build an own OpenFileDialog if you want to do that. You can prevent though that the file isn't accepted.
You have to handle the FileOk event for that. You can check if the parent directory is the one you want it to be.
Something like this:
private void openFileDialog1_FileOk(object sender, System.ComponentModel.CancelEventArgs e)
{
string[] files = openFileDialog1.FileNames;
foreach (string file in files )
{
if (Path.GetDirectoryName(file) != yourRequiredPath)
{
e.Cancel = true;
break;
}
}
}

This is not possible.
You can't restrict users to prevent them to browse elsewhere where you don't wish to.
One possible way to fix this is to write your custom open dialog box with custom validations.

If you really want to prevent navigation in the file dialog the only way to do it would be to use the Common Item Dialog, provided by COM1, and give it an IFileDialogEvents and implement the OnFolderChanging event. To allow navigation, return S_OK and to deny navigation return something else.
1 "Provided by COM" as in the component object model, not some third party.

Related

Using textbox to gather user's destination path for exporting a CSV in C# Windows application?

I'm looking for an option that allows a user to input their destination folder (Usually copy/Paste) into a text box on a Windows Application, and append the file's name with a specific name. However, I'm stuck as to how to accomplish this.
//Exporting to CSV.
string folderPath = MessageBox.Show(textBox1_TextChanged);
File.WriteAllText(folderPath + "DIR_" + (DateTime.Now.ToShortDateString()) + ".csv", csv);
So it can look like: C:/DIR_9132017.csv, or Documents/DIR_9132017.csv, depending on what the user inputs into the textbox. I have nothing in my textbox code section at the moment, if that also gives a clearer picture about the situation.
Any help will be greatly appreciated. Thank you!
You can either use FolderBrowserDialog or can just copy/paste the path and create the directory.
Using FolderBrowserDialog
Step1 : Create Browse button (so that the user can choose the directory)
Step2 : Create Export button (Place the code to write the file here)
private void browseButton_Click(object sender, EventArgs e)
{
if (folderBrowserDialog1.ShowDialog() == DialogResult.OK)
{
var folderPath = folderBrowserDialog1.SelectedPath;
textBox1.Text = folderPath;
}
}
private void exportToCsvButton_Click(object sender, EventArgs e)
{
var path = textBox1.Text;
var file = Directory.CreateDirectory(path);
var filename = "DIR_" + (DateTime.Now.ToShortDateString()) + ".csv";
File.WriteAllText(Path.Combine(path, "test.csv"), "content");
}
Using Copy/Paste
Step1 : Create Export button (User copy pastes the path. System create the directory and writes the file)
private void exportToCsvButton_Click(object sender, EventArgs e)
{
var path = textBox1.Text;
var file = Directory.CreateDirectory(path);
var filename = "DIR_" + (DateTime.Now.ToShortDateString()) + ".csv";
File.WriteAllText(Path.Combine(path, "test.csv"), "content");
}
You would use a FolderBrowserDialog for that. After adding it to your form, you can use it like this:
public void ChooseFolder()
{
if (folderBrowserDialog1.ShowDialog() == DialogResult.OK)
{
folderPath = folderBrowserDialog1.SelectedPath;
}
}
Source: https://msdn.microsoft.com/en-us/library/aa984305(v=vs.71).aspx
You haven't specified whether it's WinForms or WPF, so I'm using WPF, but is should be the same in WinForms.
To select the folder, you could use FolderBrowseDialog as follows. This code should be placed inside a button or some other similar control's Click event.
if (folderBrowse.ShowDialog() == DialogResult.OK)
{
txtPath.Text = folderBrowse.SelectedPath;
}
txtPath being a TextBox your selected path displayed in. You can substitute it with a simple string variable if you don't want to use a TextBox.
And if you want the user to be able to drag-drop a folder into a TextBox, you can create a TextBox control, and in it's PreviewDragOver and Drop events, you can do the following.
private void txtPath_PreviewDragOver(object sender, DragEventArgs e)
{
e.Handled = true;
}
private void txtPath_Drop(object sender, DragEventArgs e)
{
string[] files = (string[])e.Data.GetData(DataFormats.FileDrop);
if (files != null && files.Length != 0)
txtPath.Text = files[0];
}
Using both above in combination user has the ability to either select the folder he/she wants by clicking a button, drag-and-drop a folder into the TextBox, or copy-paste the folder path into the TextBox.

Executing another Application with selected file using a button (C# Programming)

To start, I'm a newbie with C# Programming and I've tried googling for solutions about my problem but it seems that i cannot find one, or simply too unlucky or too blind to spot one. I'm using Microsoft Visual Studio 2005.
Anyways. I was assigned to modify/create an automated test environment input application. The said application already has a function to run/start a CANoe program with a pre-defined file or if it's already running, stop the program.
private void button1_Click(object sender, EventArgs e)
{
// Execute CANoe(Obtain CANoe application objectg)
mApp = new CANoe.Application();
mMsr = (CANoe.Measurement)mApp.Measurement;
try
{
mApp.Open("C:\\Users\\uidr3024\\Downloads\\SRLCam4T0_Validation_ControlTool\\cfg\\SVT_SRLCam4T0_025B.cfg", true, true);
}
catch (System.Exception ex)
{
System.Console.WriteLine(ex.Message);
}
}
private void button2_Click(object sender, EventArgs e)
{
// Finish CANoe
if (mApp != null) {
mApp.Quit();
}
// Release the object
fnReleaseComObject(mMsr);
fnReleaseComObject(mApp);
}
What I wanted to do now is to have an OpenFileDialog box that will show a selection of files and user will be able to browse and select any file to start the CANoe program with the selected file and not just the file path that's been input in the code along the "mApp.Open()" syntax. I've tried this:
private void button5_Click_1(object sender, EventArgs e)
{
OpenFileDialog openFileDialog1 = new OpenFileDialog();
openFileDialog1.InitialDirectory = #"C:\Users\uidr3024\Downloads\SRLCam4T0_Validation_ControlTool\cfg";
openFileDialog1.Title = "Browse Configuration Files";
openFileDialog1.CheckFileExists = true;
openFileDialog1.CheckPathExists = true;
openFileDialog1.Filter = "CANalyzer/CANoe Configuration (*.cfg)|*.cfg |All files (*.*)|*.*";
openFileDialog1.FilterIndex = 1;
openFileDialog1.RestoreDirectory = true;
if (openFileDialog1.ShowDialog() == DialogResult.OK)
{
textBox1.Text = openFileDialog1.FileName;
}
}
I've tried this code that I often see in the Web and in the Tutorials but I don't know how to incorporate it with the button for running the CANoe program so that when user clicks the Open button from the Dialog Box, the file path would be shown in the textbox(optional) and/or when the user then clicks the Start CANoe, CANoe program would start with the selected .cfg file.
Am I making any sense here? Or am I doing the right thing here?
Btw, I found these... And I'm using a CANoe library for these, ofc.
#region "***** CANoe Object definition *****"
private CANoe.Application mApp = null; // CANoe Application CANoeƒAƒvƒŠƒP[ƒVƒ‡ƒ“
private CANoe.Measurement mMsr = null; // CANoe Mesurement function CANoe‘ª’è‹#”\
private CANoe.Variable mSysVar = null; // System variable ƒVƒXƒeƒ€•Ï”
private CANoe.Variable mSysVar_start = null; // System variable ƒVƒXƒeƒ€•Ï”
#endregion
I think you have done most of the hard work, unless I've missed something I think you just need something like this in your button1_Click method:
if( textBox1.Text != String.Empty && System.IO.File.Exists(textBox1.Text) )
{
// The textbox has a filename in it, use it
mApp.Open(textBox1.Text, true, true);
}
else
{
// The user hasn't selected a config file, launch with default
mApp.Open("C:\\Users\\uidr3024\\Downloads\\SRLCam4T0_Validation_ControlTool\\cfg\\SVT_SRLCam4T0_025B.cfg", true, true);
}

Enabling textbox on button click event

How can i add the mechanism in my downloader for the case although many threads on SO deals either with php etc and not upto the need.
I have a browse button at the front of a textbox where i get's the user entered Path on local drive to fix the location for downloading but i have already hardcoded one for system drive.I want textbox button to be disabled unless user clciks browse button and then new path can be entered for downloading after then.
How can i go?
A quick example:
private void browseButton_Click(object sender, EventArgs e)
{
var saveFileDialog = new System.Windows.Forms.SaveFileDialog();
var selectedPath= saveFileDialog.ShowDialog();
if (selectedPath == System.Windows.Forms.DialogResult.OK)
{
_savePath = saveFileDialog.FileName;
textBox1.Enabled = true;
textBox1.Text = _savePath;
}
}

browse folder and get user input to create a new file

I want to create a file in a directory selected by the user and named it by the user input.
I tried FolderBrowserDialog but it didn't prompt me to give a file name:
FolderBrowserDialog fbd = new FolderBrowserDialog();
DialogResult result = fbd.ShowDialog();
string path = fbd.SelectedPath;
//string FileName; then concatenate it with the path to create a new file
how can I do that?
You want to create a new file in a folder, so you should:
ask the user to select a folder (with FolderBrowserDialog)
offer the user a way to type a file name, with an input field (separate from the folder dialog)
Then you concat those 2 infos to get your full file name.
Or you can use SaveFileDialog and check if the file already exists when the user has selected a file (with a File.Exists...). There is a property for displaying an alert when the file does not exists, but not on the other side.
So when you got the DialogResult, use File.Exists and you can alert the user.
Sample for this solution:
In this sample (I hope without errors, cannot test right now):
- I open the saveFileDialog on a button called SaveButton with the SaveButton_Click click method
- I have a SaveFileDialog component on my form, called saveFileDialog1. On this component, the event FileOK is associated to my saveFileDialog1_FileOk method
private void SaveButton_Click(object sender, EventArgs e)
{
// Set your default directory
saveFileDialog1.InitialDirectory = #"C:\";
// Set the title of your dialog
saveFileDialog1.Title = "Save file";
// Do not display an alert when the user uses a non existing file
saveFileDialog1.CheckFileExists = false;
// Default extension, in this sample txt.
saveFileDialog1.DefaultExt = "txt";
if (saveFileDialog1.ShowDialog() == DialogResult.OK)
{
// DO WHAT YOU WANT WHEN THE FILE AS BEEN CHOSEN
}
}
// This method handles the FileOK event. It checks if the file already exists
private void saveFileDialog1_FileOk(object sender, System.ComponentModel.CancelEventArgs e)
{
if (File.Exists(saveFileDialog1.FileName))
{
// The file already exists, the user must select an other file
MessageBox.Show("Please select a new file, not an existing one");
e.Cancel = true;
}
}

C# After using OpenFileDialog, a MessageBox doesn't open on top

Our primary database application has a feature that exports either an Excel workbook or an Access mdb for specified work orders. Those files are then sent to our subcontractors to populate with the required data. I am building an application that connects to the files and displays the data for review prior to being imported into the primary database. Simple enough, right? Here’s my problem: the application opens a OpenFileDialog box for the user to select the file that will be the datasource for the session. That works perfectly. If I open a MessageBox after it, that box open up behind any other open windows. After that, they respond correctly. I only expect to be using MessageBoxes for error handling, but the problem is perplexing. Has anyone encountered this problem?
The MessageBoxes in the code are only to verify that the path is correct and to solve this problem; but, here’s my code:
private void SubContractedData_Load(object sender, EventArgs e)
{
string FilePath;
string ext;
OpenFileDialog ofd = new OpenFileDialog();
ofd.Filter = "Microsoft Access Databases |*.mdb|Excel Workbooks|*.xls";
ofd.Title = "Select the data source";
ofd.InitialDirectory = ElementConfig.TransferOutPath();
if (ofd.ShowDialog() == DialogResult.OK)
{
FilePath = ofd.FileName.ToString();
ext = FilePath.Substring((FilePath.Length - 3));
if (ext == "xls")
{
MessageBox.Show(FilePath);
AccessImport(FilePath);
}
else if (ext == "mdb")
{
MessageBox.Show(FilePath);
AccessImport(FilePath);
}
}
else
{
System.Windows.Forms.Application.Exit();
}
}
While it isn't advisable to use MessageBoxes to debug your code, I think the immediate problem is that you are doing this in the form's load event.
Try it like this:
protected override void OnShown(EventArgs e) {
base.OnShown(e);
// your code
}
Your problem is definitely the fact that you're trying to do this while loading the Form, because the form isn't yet displayed.
Another alternative would be moving this functionality out of the Load event and give the user a button to push or something like that.
In other words:
private void SubContractedData_Load(object sender, EventArgs e)
{
// unless you're doing something else, you could remove this method
}
Add a button that handles this functionality:
private void SelectDataSourceClick(object sender, EventArgs e)
{
OpenFileDialog ofd = new OpenFileDialog();
ofd.Filter = "Microsoft Access Databases |*.*|Excel Workbooks|*.xls";
ofd.Title = "Select the data source";
ofd.InitialDirectory = ElementConfig.TransferOutPath();
if (ofd.ShowDialog() == DialogResult.OK)
{
var FilePath = ofd.FileName.ToString();
var ext = Path.GetExtension(FilePath).ToLower();
switch (ext)
{
case ".xls":
MessageBox.Show(FilePath);
AccessImport(FilePath);
break;
case ".mdb":
MessageBox.Show(FilePath);
AccessImport(FilePath);
break;
default:
MessageBox.Show("Extension not recognized " + ext);
break;
}
}
else
{
System.Windows.Forms.Application.Exit();
}
}

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