How to open notepad in c# by button - c#

I am new to programming and stuck on a little thing. I have a button on my Windows application and I want to open Notepad when I click the button. I used all the available codes from internet starting from process.start() to even envirnoment.path but the button doesn't show the Notepad. Here is what I have already tried.
private void btnNotepad_Click(object sender, EventArgs e)
{
string notepadPath = Path.Combine(Environment.GetFolderPath(Environment.SpecialFolder.SystemX86), "notepad.exe");
System.Diagnostics.Process.Start(notepadPath);
}
Or simply:
system.diagnostics.process.start(#"notepad.exe");
Also did this:
string theData = txtbxRepeat.Text;
FileStream aFile = new FileStream("myTextFile.txt", FileMode.OpenOrCreate);
StreamWriter sw = new StreamWriter(aFile);
txtbxRepeat.Text = theData;
sw.WriteLine(theData);
sw.Close();
Please help me in this.

You are heading in the correct direction with the first and 2nd code snippet. However, you need to specify the full path to the notepad++ exe.
private void button1_Click(object sender, EventArgs e)
{
System.Diagnostics.Process.Start(Path.Combine(Environment.GetFolderPath(Environment.SpecialFolder.ProgramFilesX86), "Notepad++", #"notepad++.exe"));
}
However, keep in mind the user may have installed notepad++ in a different directory (for example they don't have an x86 directory).
UPDATED: updated to include environment paths rather than hard-coded path.

Related

File.WriteAllText() statement in C# not creating a file

I am still only just learning C# in Visual Studio and I am trying to make a simple text encryption application. My problem at the moment is that when I use the command:
File.WriteAllText(name, inputTextBox.Text);
(Where name is the name of the file chosen in a SaveFileDialog and inputTextBox.Text is the text in a textbox on the main form)
however the file is never actually created. I even tried to build the application and run it as administrator but nothing happened.
What's even weirder is when I opened File Explorer, in the Quick Access section where it shows recent files, all the files that were supposed to be created show up there but don't exist when I click "Open File Location" and if I just try to open them, notepad just tells me the file doesn't exist.
The files are also not in my recycle bin or anything.
Here's the rest of my code in case it's something wrong with that:
public Form1()
{
InitializeComponent();
}
private void saveButton_Click(object sender, EventArgs e)
{
saveDialog.ShowDialog();
}
private void saveDialog_FileOk(object sender, CancelEventArgs e)
{
string name = saveDialog.FileName;
File.WriteAllText(name, inputTextBox.Text);
}
And in case you're wondering saveDialog is already an element in my form so there's no problem with that.
Since in your posted code the initialization of the SaveFileDialog is missing, and you say in your comment that the Debugger doesn't halt in the event body I take the long shot to assume that the event is not registered appropriately.
Try to make sure that your class (minimally) looks like the following example:
public partial class Form1 : Form
{
SaveFileDialog saveDialog;
public Form1()
{
InitializeComponent();
// create instance of SaveFileDialog
saveDialog = new SaveFileDialog();
// registration of the event
saveDialog.FileOk += SaveDialog_FileOk;
}
private void saveButton_Click(object sender, EventArgs e)
{
saveDialog.ShowDialog();
}
private void saveDialog_FileOk(object sender, CancelEventArgs e)
{
string name = saveDialog.FileName;
File.WriteAllText(name, inputTextBox.Text);
}
}
If your problem still remains, then I will remove my answer

Writing Something to a File then loading it again

Okay so i wanted to know how i would take something that is in a textBox, then i press a button, the contents of the textBox will be saved to a file location, then when i load the .exe back up, the contents will reappear in the textBox.
This is what i have so far
private void button3_Click(object sender, EventArgs e)
{
File.WriteAllText(#"C:\Application.txt", textBox1.Text);
}
^To Write it to a file location, I have tried this multiple times but it doesnt seem to want to make the file on my C:.
private void Form1_Load(object sender, EventArgs e)
{
try
{
textBox1.Text = File.ReadAllText(#"C:\Application.txt", Encoding.ASCII);
}
catch
{
}
^To Load the file then inject it back into the textbox it came from
Any and all help is appreciated,
Thanks.
You likely get an exception when trying to write to your C drive because it requires administrative access. Try running Visual Studio as Administrator (therefor the app will run as admin when kicked off from VS) or try writing to another location. Your code is all fine. The Encoding.ASCII bit is unnecessary though and I recommend removing it (more than likely that's not the encoding you will write the file in).
Trying to write directly to the C: drive can cause problems.
Try writing to a location that you definitely have write access to. You could use the ApplicationData directory (for application files unique to the current user), or use SpecialFolder.MyDocuments if you prefer.
private string applicationFilePath = Path.Combine(Environment.GetFolderPath(
Environment.SpecialFolder.ApplicationData), "Application.txt");
private void button3_Click(object sender, EventArgs e)
{
File.WriteAllText(applicationFilePath, textBox1.Text);
}
private void Form1_Load(object sender, EventArgs e)
{
textBox1.Text = File.ReadAllText(applicationFilePath, Encoding.ASCII);
}
I would do something like this:
using System.IO;
private void button3_Click(object sender, EventArgs e)
{
using (var stream = new FileStream(#"C:\Application.txt", FileMode.Create))
using (var writer = new StreamWriter(stream, Encoding.ASCII))
writer.Write(textBox1.Text);
}
private void Form1_Load(object sender, EventArgs e)
{
using (var stream = new FileStream(#"C:\Application.txt", FileMode.Open))
using (var reader = new StreamReader(stream, Encoding.ASCII))
textBox1.Text = reader.ReadToEnd();
}
I think this method gives you more control on your content. Try to explore the contents of FileMode enum, and make sure to add your using System.IO; directive.
Be careful not to confuse the using statement with the using directive.
Also, always remember to dispose/close your stream when done to ensure that the data has been flushed and that the file is no longer in use by your application. Here, the using statement does the job of disposing when the stream is no longer in use.
EDIT: As mentioned by the other posts, writing to the C: directory causes problems on newer operating systems due to Admininstrative Access restrictions. Make sure to write to different drives/folders that you definitely have access to.
// Current User
Path.Combine(Environment.GetFolderPath(Environment.SpecialFolder.ApplicationData), "Application.txt");
// All users
Path.Combine(Environment.GetFolderPath(Environment.SpecialFolder.CommonApplicationData), "Application.txt");

Show dialog on first start of application

Is there an easy way to show an dialog when the program is started for the first time (and only the first time), for some kind of instruction or specifying settings?
You could save it as a bool in your settings and you should check at load event of first form.
Your settings file should have a setting that I called "FirstRun" do this with following steps:
Right click your Project
Click "Properties"
Click "Settings" tabpage(probably on the left)
Add setting like I did as seen in image above
Note: The Scope can be changed to "Application", if that is your application's need, since you didn't mention in your question.
Your Settings file should look like image below:
public void Form1_Load(object sender, EventArgs e)
{
if((bool)Properties.Settings.Default["FirstRun"] == true)
{
//First application run
//Update setting
Properties.Settings.Default["FirstRun"] = false;
//Save setting
Properties.Settings.Default.Save();
//Create new instance of Dialog you want to show
FirstDialogForm fdf = new FirstDialogForm();
//Show the dialog
fdf.ShowDialog();
}
else
{
//Not first time of running application.
}
}
Note: wrote this from my phone, so I couldn't compile to test
Edit: Checked code and added image from desktop.
You can have bool value in your settings file which is a "user setting" which means you can change it to true save it for this specific user.
When your application starts just check that value. If it's false show your dialog and change it to true and it will stay true.
public void Form_Load(object sender, EventArgs e)
{
if(Settings.Default.ShowDialog)
{
Settings.Default.ShowDialog = false;
Settings.Default.Save();
// show first disalog
}
// rest of code if needed
}
Here's an MSDN link on user settings:
http://msdn.microsoft.com/en-us/library/bb397750(v=vs.110).aspx
Ok, so I assume you're creating WinForms application. First of all, locate the Load event in your main Form event lists (or simply double click your Form in Designer panel). The following method stub will pop up:
public void Form1_Load(object sender, EventArgs e)
{
}
And modify it like this:
public void Form1_Load(object sender, EventArgs e)
{
MessageBox.Show("Your message here");
}

Windows Forms FolderBrowserDialog hangs the application

With winforms, when I right click on a folder or try to delete a folder within the FolderBrowserDialog the window becomes irresponsive and I've to force-close it.
Here's the code:
private void btnOpenFileDialog_Click(object sender, EventArgs e)
{
folderBrowserDialog1.SelectedPath = txtBoxLog.Text;
folderBrowserDialog1.RootFolder = Environment.SpecialFolder.MyComputer;
if (folderBrowserDialog1.ShowDialog()==DialogResult.OK)
{
txtBoxLog.Text = folderBrowserDialog1.SelectedPath;
}
}
The problem was system wide, so the control was correctly behaving in an incorrect way (irony).

Using button click to open helpProvider c#

Just a quick question but is it possible to open a helpProvider?
All I want is open a CHM help file when I click a button in addition to the F1 key?
If it’s not possibly anyone know of a work around?
Thanks Peter
I think you mean a Windows Forms Application.
There is a Windows Forms Control called HelpProvider that does it for you.
System.Windows.Forms.HelpProvider hlpProvider = new System.Windows.Forms.HelpProvider();
hlpProvider.SetShowHelp(this, true);
// Help file
hlpProvider.HelpNamespace = "helpFile.chm";
You can open your help file with
Process proc = new Process();
proc.StartInfo.FileName = "helpFile.cfm";
proc.Start();
private void MainMenu_Load(object sender, EventArgs e)
{
helpProvider1.HelpNamespace = Application.StartupPath + "\\filename.chm";
helpProvider1.SetShowHelp(this, true);
}
private void HelpText_Click(object sender, EventArgs e)
{
Help.ShowHelp(this, helpProvider1.HelpNamespace);
}
Good luck ^_^

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