I've got a program which is linked to a Microsoft Access database and what I want to do is to display data from a data column, for example, customerName from the table customerDetails into a label. The drag and drop feature from the data sources panel puts the data into text boxes by default however, I want mine in labels. I've looked around but I couldn't find anything directly referencing how to put data into different controls like labels so any help is appreciated!
One way is to change the default control type for your fields in Data Sources window. Since you are already using that method, simply go to Data Sources window, expand your table and select required field(s). Then select a different control type (Label in your case) from the list.
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through C # I am creating a program that manages ambulances, I am trying to create a list with the events and active missions, this data must be taken from a mysql database, I have tried to see many "tutorials", but none explained what I needed, how do you think I can do something like this?
image here
in addition to displaying the data, if I click twice it should open the event or mission to me depending on where I click, (the icons are also buttons that should only be visible if there is a data)
just a tip! I'm not asking you to write the code for me!!!
EDIT:
I managed to get the data from mysql, that you know is it possible to place the data in specific columns?
Program
Code
It is difficult to guide you through such unspecific question, but I'll try some hints.
You said you have data from MySQL
Fill a DataTable (another way is to use BindingSource)
Assign DataTable as a DataSource of your DataGridView grid.
You can edit columns in the DataGridView using UI in VS, or you can do it programatically. First is easier, just note that if you at any stage provide Nothing as a data source, you'll loose column headers.
For event fired on DataGridViewRow, click on the grid in Designer, click on events in the Properties pane, find DatagridviewRow_DoubleClick and double click the line, to create associated method
FIll in the code into the even method. Use DataGridView.SelectedRows(0) to get selected row and it's index. If you want to "open it" create a modal dialog or what you want for displaying the content.
I am new here and startig to learn C#. Before I programed in C and Windows.Forms in VBA.
Now I have a Project where I receive serial port data from a device, that sends the contents of various C-structs (some nested). I want to display these Datasets in Windows.Forms each labeled, edit the values and send it back to the device. So it can easily copy the received data into its structures.
Now I don't know an easy way to get the structured data inside a c#-byte-list into various text boxes(?) that have describing labels to it. I would like to design the layout in Form Designer, so not want to create the controls dynamically. But maybe this is the best way?
Does someone know a good strategy / a best suited control to achieve this?
Thanks in advance.
You could use a DataGridView with control buttons inside each row or external buttons that handle selected row(s). In order to see and change the details a corresponding dialog form comes in handy in which I would implement a hex editor with the byte/hex values on the left and the readable value on the right.
To display the byte data just convert it to a hexadecimal string so you can display it in one column inside the DataGridView.
For the nesting part, you could either implement child elements inside the DataGridView itself (you need to either code this yourself or use some 3rd party extensions like this or Telerik, e.g., which also has the possibility of including button columns) or open a conditional dialog form which again shows a DataGridView for the child elements and so on (so you would open the same form as child form ad infinitum).
Thereby you are as flexible as possible and do not rely on fixed text box elements which you have to add or extend on further information.
I have a number of images stored in a Blob type field inside a MySQL InnoDB database along with other information pertaining to those images stored in another fields.
As you know the Banded Grid View distributed in DevExpress version 11.2, with the help of Banded Grid Columns, is capable of rendering several types of data, most notably images.
So far I'm able to create every control and load any kind of data required, including the images, using the common MySqlDataReader and DataSet approach, through the Grid Control DataSource property, that owns the BandedGridView.
However as you know, when you load a Blob field from MySQL you are returned a byte array with the content of the file, in this case the image in question.
I was hoping DevExpress would recognize the binary data and realize it was a image file, and automatically render the image in all the rows under the Column assigned to handle the database Image field, however it did not and now that I think of it, it was probably far fetched hope.
Instead of rendering the image, each row of the column shows a simple string output referencing what type of object the field contains. In this case since its a binary representation of a file, it outputs System.Byte[].
I've search the DevExpress documentation and generally on the web, nothing clear was found that could solve my problem. There is a example of my desired result packed along with DevExpress, the solution named "GridMainDemo" under the WinForms -> XtraGrid section. Once your running the demo, change into Alternate Views and into Banded Grid View, then just click on any row under the picture column, and you will see a clear example of my desired result.
Of course I've looked into the source of that demo, however I cannot say that clarification and explanation was a clear aim of the DevExpress team that built such demo, and unfortunately I didn't had much time to look at it deeply. However from what I've seen this demo differs from the point that the images are stored locally as files, and already properly reference in some sort of repository, which doesn't help much with my problem.
To finish my question, sorry for the long reading, just wanted to give a clear idea of what my aim is, what stands in the way, and how all things are set in order to find a way to reach my aim.
Now to cut a long story short. A simple example of how to load a image from a MySQL Blob field into a column in a Banded Grid View and have it rendered after load or when the user clicks the field cell, would be ideal and with it I would be able to understand and do the necessary code so that my View also renders my images.
My biggest thanks with this, really.
Note: Unfortunately, using local or even remote stored files is not
a option. The images must be kept within the confinements of the
database.
It wasn't so hard after all, and seems hope was well place and DevExpress did most of the work.
So, to help those who have a similar question, here is what you have to do, so you can have a certain column showing a image stored in a Blob type field.
Assuming you already loaded the data to your grid and it's being displayed correctly with the exception of the image of course.
First: You must declare a RepositoryItemImageEdit type object, that will simply implement a ImageEdit type control in the cell, which when trying to edit the cell value it will show your image, the goal of this question. If your goal differs on that point simply read the note after this answer afterwards.
Second: You must add the previously last declared object to your GridControl.RepositoryItems collection property. You can easily accomplish it using the Add method.
Third: Now you must define what type of control will be used to render the data for you Image column, for that you simple reference the BandedGridColumn.ColumnEdit property to be equal to the object you just added before.
Example
/* Create your columns, bands etc manually or
have it done automatically after loading the data.*/
...
// Load the data from the database to your gridControl
...
// Step one
RepositoryItemImageEdit imageControl = new RepositoryItemImageEdit();
// Step two
gridControl.RepositoryItems.Add(imageControl);
// Step three
/* view is the View assigned to your grid control
where your data and columns are being shown.*/
// Assuming your database blob field is named `Image`
view.Columns["Image"].ColumnEdit = imageControl;
If your data was loaded correctly and your columns assigned properly to their respective fields then this should render a small icon on each cell of your Image column and once your click or focus on it, a ImageEdit control will be rendered and show your image.
Note:
There are other controls besides ImageEdit capable of rendering images, for those others you will have to find
theirRepositoryItem based implementation.
Also, your Image column must be editable, otherwise this approach won't
work. Bare in mind that allowing edition at the column level will not work if it is denied at the View level through the OptionsBehavior.Editable property.
I will mark my answer as the correct one since no one else provided any insight on how to solve my problem, however you are welcome to post any other working approaches to this problem. Thank you.
I'm quite new to C# (coming from a Java background) and I'm working on a Form to quickly manage different data (e.g. Users, Domains, Computers) along with providing utilities that use the data.
To avoid confusion the following is a summary of the example data structure;
<User>
<Name>joe</Name>
<Domain>europa</Domain>
</User>
<Domain>
<Name>europa<Name>
<Domain>
<Domain>
<Name>group</Name>
</Domain>
<Computer>
<Name>localhost</Name>
</Computer>
In my Form I have tab pages for each data, each containing a DataGridView (containing a column for each member) to allow for simple management. I'm using a single DataSet which reads the data from an XML file (using a schema) when the Form Load event is fired. After reading the data I am setting the tables as the DataSource of their respective DataGridView using the code;
userDataGridView.DataSource = dataSet.Tables["User"];
domainDataGridView.DataSource = dataSet.Tables["Domain"];
computerDataGridView.DataSource = dataSet.Tables["Computer"];
This is working properly for the Domain and Computer DataGridViews as they only have single text columns which are mapped to the Name properties. However, the Domain column of for the User DataGridView is a combo box and I need that to contain all the possible Domains (e.g. europa, group) as well as the selected Domain being bound to User.Domain (also, the User.Domain being initially selected).
My main question is how I achieve the above but I also have some additional questions hopefully someone can answer;
I'm assuming that changes made to a DataGridView are immediately persisted in the underlying XML file as I am reading it from the build's output directory. Is this correct or is additional configuration/process required?
During my attempts at getting this to work I tried to use a DataRelation as follows;
DataRelation dataRelation = new DataRelation("Domain users",
dataSet.Tables["Domain"].Columns["Domain"],
dataSet.Tables["User"].Columns["Domain"]);
dataSet.Relations.Add(dataRelation);
How exactly do DataRelations work and what effect do/can they have?
In case it helps you understand/explain I am using the SharpDevelop IDE for working on this application.
Thanks in advance.
As you have already found out, the DataGridView is very powerful and does most of the work in an automagically way. Unfortunately you run into problems if these defaults doesn't match your preferences (like using a ComboBox for a text property).
To get the DataGridViewComboBoxColumn into the proper place you can do this programmatically within your code or (if possible) do it with the designer (in Visual Studio don't know if SharpDevelop supports it).
Using the (Visual Studio) Designer
For this scenario it is necessary that the structure of the data is known at design time by providing a class holding all (or more) informations as simple properties (like a person class with properties name, age, etc.). If this is available you can add a BindingSource to your control and click in the properties window at the button next to the DataSource property. Select Add Project Data Source and select Object and select your desired object.
Now you have a binding source configured with a specific type of DataSource. Next select your DataGridView and change the DataSource property to the recently created binding source.
After this the DataGridView will automatically be populated with a column for each property. Now you can easily step into the Columns property and change the behaviour and type of each column as you like.
To connect your concrete data with the DataGridView just apply your table to the binding source.
Doing the same at runtime
If you have Visual Studio and followed the above steps you can afterwards easily take a look into the Designer.cs file to find how Visual Studio did all the stuff. There is nothing you can't do also manually. So if you need to just do it.
Simply create a DataGridViewComboBoxColumn, set the DataPropertyName and HeaderText and you've got a good starting point. Get the IndexOf() the column you want to replace, remove it and Insert() your freshly created column at the position you want.
Before the Grid can show some data (in the ComboBoxColumn) you need to provide a list with the possible values. For this purpose the comboBoxColumn has a DataSource property on itself where you can provide the desired values. With the simplest scenario you just provide an ICollection<string>, but you can also give something more complex like List<KeyValuePair<Enum, string>>. If that's the case you should also set the properties ValueMember and DisplayMember to tell the ComboBox which properties of the objects should be used to populate the list.
Maybe with these informations given you should take a look at the MSDN article about the DataGridViewComboBoxColumn and study the example. This should give you some additional hints on how to set it up properly.
I have this program in which I am trying to store a collection of values into a list and session
Example:
valueCollection = (List<Values>)Session["Value"];
I want to do the front end in a way which will show a table with each row showing a label and textbox. This would be too simple to do obviously but I want it to show 4 rows of the table by default and then the user can select "add another" this will then add another row onto the table with a label and textbox exactly similar to the 4 default. Everytime the user selects "add another" the table increments by 1.
How do you do something like that, or is there an easy way?
Here is a screenshot to explain it better:
http://img828.imageshack.us/img828/9986/idead.png
The basic idea is that you bind a control to your data and provide GUI controls to allow users to add/edit/delete records. Once the records are modified you re-bind the control to see the changes.
Take a look at the Databound controls in the .Net Framework. For a quick first pass you could use a ListView - a control which provides built-in functionality to automatically generate and mange the add/edit/delete GUI elements.
In 'real world' usage, storing big datasets isn't a great idea as more users = more sessions and each session uses server resources. You should really be getting/storing your data in a database or perhaps an XML file.
HTH