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asp grid view hyperlink field not working

I have a logLink column in my database.
I have my hyperlink field in gridView as below :
<asp:HyperLinkField DataNavigateUrlFields="logLink" DataTextField="logLink" DataNavigateUrlFormatString="{0}" Text="Link" ControlStyle-CssClass="hlink" HeaderText="LOG LINK" ItemStyle-Width="6%" ItemStyle-Font-Underline="true" />
But this link is not clickable.
I want the values in the log link column of my db to come here.
Does anyone know how to solve this ?

try this.
<asp:TemplateField>
<ItemTemplate>
<asp:HyperLink ID="lnk" runat="server" Target="_blank" Text='<%# Eval("yourText") %>'
NavigateUrl='<%# Eval("logLink") %>'></asp:HyperLink>
</ItemTemplate>
</asp:TemplateField>

How to select a cell in datagrid onClick in ASP.net C#

I am importing a column in datatable to my grid. Now I want navigate to a new page on selecting a cell in grid by fetching the selected value. I have tried this by including bound field in my grid like
<asp:GridView ID="GDV_1" runat="server" EnableModelValidation="true" AutoGenerateColumns="false" OnSelectedIndexChanged="GDV_1_SelectedIndexChanged" AutoGenerateSelectButton="false" DataKeyNames="SROID">
<Columns>
<asp:BoundField DataField="SRONameinEnglish" HtmlEncode="False" DataFormatString="<a target='_blank' href='Test.aspx?code={0}>ClickHere</a>" />
</Columns>
</asp:GridView>
Doing this way my requirement is achieved but the all cells are displaying Common text Click here instead of showing data from Database.
Please give your suggestion on how to get the value from database into cell and make it clickable. I don't want to use Select button. Please find my current output.
This is my current output I want my data from DB instead of ClickHere.

You can use TemplateField
<asp:TemplateField HeaderText="Name">
<ItemTemplate>
<asp:LinkButton runat="server" ID="lnk<%# Eval("SRONameinEnglish")%>"><%# Eval("SRONameinEnglish")%></asp:LinkButton>
</ItemTemplate>
</asp:TemplateField>
and click of LinkButton put your code to navigate anywhere.

In your case you are binding boundfield with static a tag which have href attribute so your not able to change text on that boundfield from your database.To get your approach you should
use TemplateField and bind data with text attribute using eval keyword as below example.
Try it:
<asp:TemplateField HeaderText="Name">
<ItemTemplate>
<asp:HyperLink ID="HyperLink1" runat="server" Text='<%# Eval("name") %>' />
</ItemTemplate>
</asp:TemplateField>
OR
you can also bind link with your hyperlink using NavigateUrl property of hyperlink as below example.
<asp:TemplateField HeaderText="Name">
<ItemTemplate>
<asp:HyperLink id="HyperLink2" NavigateUrl='<%#Eval("YourUrl") %>' Text='<%#Eval("name") %>' runat="server"/>
</ItemTemplate>
</asp:TemplateField>
I hope it will helpful to you.

how to add a link button in the grid view by visual studio?

I want to add a link button in grid view that will navigate to the next form in the website. but i want to know how to insert that button into the grid view column? please help me..

You can add Link buttons in the Item template of a gridview.
<asp:TemplateField>
<ItemTemplate>
<asp:LinkButton ID="Link" runat="server" PostBackUrl="MyNextPage.aspx">Edit</asp:LinkButton>
</ItemTemplate>
</asp:TemplateField>

<Columns>
<asp:TemplateField>
<HeaderTemplate>
// TEXT FOR COLUMN NAME
</HeaderTemplate>
<ItemTemplate>
// ADD LINK BUTTON HERE.
</ItemTemplate>
</asp:TemplateField>
</Columns>
Add this inside grid view.

try this
<asp:GridView ID="GridView1" runat="server">
<Columns>
<asp:ButtonField ButtonType="Link" HeaderText="LinkButton"/>
</Columns>
</asp:GridView>

Make Sure your GridViews datasource is bound. Set Auto-Generate Columns to false.
Open GridViewTask , add new column with Hyperlink Field proper name and path . You are done.

How to set focus on last row of grid

I need to set focus on the last row of the grid after a grid row updation takes place. Can anyone help me out on this?
Below is my gridview,
<asp:GridView ID="grdViewForComment" runat="server" OnRowDataBound="Row_DataBound" AutoGenerateColumns="false">
<Columns>
<asp:TemplateField HeaderText="Advanced search">
<ItemTemplate>
</ItemTemplate>
</asp:TemplateField>
</Columns>
</asp:GridView>

Check adding below code
grdViewForComment.Rows[19].Focus(); // RowIndex here.
grdViewForComment.Rows.Count-1

GridView trouble in .Net

i think this maybe an easy one...
I have a Gridview, bound to a dataSource with this query:
select userid, name, phone from users
I need to change the content of the Name cell to a link, like so:
User's Name
so OnRowDataBound i'm doing this:
e.Row.Cells[1].Text = "" + e.Row.Cells[1].Text + "";
It all works fine this way. My problem is that i don't want to display the UserId column in the Gridview, but when i attribute it (asp attribute or server-side) Visible="false" to the BoundField UserId, i can't capture it's value to build the Name Cell.
Thanx for your help

Make your gridView to use template items instead of simple grivdiew column.
<asp:TemplateField HeaderText="FirstName" SortExpression="FirstName">
<EditItemTemplate>
<asp:TextBox ID="TextBox1" runat="server" Text='<%# Bind("FirstName")%>'>
</asp:TextBox>
</EditItemTemplate>
<ItemTemplate>
<asp:Label ID="Label1" runat="server" Text='<%# Bind("FirstName") %>'>
</asp:Label>
</ItemTemplate>
</asp:TemplateField>
You can find a nice intro Here

Agree with Jani, this should be done with a template field. If you really need to do it the other way, see Can data be kept in a dynamically bound GridView's invisible fields?.

you can set the visibility on the onrowdatabound event