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Can't retrieve new value from GridView template field

I am having trouble retrieving the new value that is entered in a textbox template field in my GridView.
Here is my markup:
<asp:TemplateField HeaderText="username" SortExpression="username">
<ItemTemplate>
<asp:Label ID="Label2" runat="server" Text='<%# Bind("username") %>'></asp:Label>
</ItemTemplate>
<EditItemTemplate>
<asp:TextBox ID="txtUserName" runat="server" Text='<%# Bind("username") %>'></asp:TextBox>
</EditItemTemplate>
</asp:TemplateField>
And here is how I'm trying to retrieve the new value, inside the RowCommand event handler of my GridView:
string userName = ((TextBox)grdUserList.Rows[rowIndex].FindControl("txtUserName")).Text;
I get the old value instead of the newly typed value when I execute this code.
Does anyone know what I am missing? Thanks in advance.

I just found out the solution for my problem. I searched and found out that the GridView is being refreshed before the retrieving process begins because I was rebinding the GridView on the Page_Load method. I fixed the problem by not rebinding the gridview when it is a post back (or at least not before I have made the changes) using the IsPostback method. Thanks for everyone's reply :)

You are retrieving new value in wrong GridView event. You have to add OnRowUpdating="grdUserList_RowUpdating" event in your GridView control and then retrieve new TextBox value.
OnRowUpdating event in code-behind:
protected void grdUserList_RowUpdating(object sender, GridViewUpdateEventArgs e)
{
string userName = ((TextBox)grdUserList.Rows[e.RowIndex].FindControl("txtUserName")).Text;
// Write your update query and logic over here.
}
You can take a reference from here for additional knowledge.
Please let me know if you have any questions.

use this code in gridview
<Columns>
<asp:TemplateField HeaderText="SrNo">
<EditItemTemplate>
<asp:TextBox ID="txtsrno" runat="server" Text='<%#Eval("SrNo") %>'>
</asp:TextBox>
</EditItemTemplate>
<ItemTemplate>
<asp:Label ID="lblsrno" runat="server" Text='<%#Eval("SrNo") %>'>
</asp:Label>
</ItemTemplate>
</asp:TemplateField>
</Columns>

How to select a cell in datagrid onClick in ASP.net C#

I am importing a column in datatable to my grid. Now I want navigate to a new page on selecting a cell in grid by fetching the selected value. I have tried this by including bound field in my grid like
<asp:GridView ID="GDV_1" runat="server" EnableModelValidation="true" AutoGenerateColumns="false" OnSelectedIndexChanged="GDV_1_SelectedIndexChanged" AutoGenerateSelectButton="false" DataKeyNames="SROID">
<Columns>
<asp:BoundField DataField="SRONameinEnglish" HtmlEncode="False" DataFormatString="<a target='_blank' href='Test.aspx?code={0}>ClickHere</a>" />
</Columns>
</asp:GridView>
Doing this way my requirement is achieved but the all cells are displaying Common text Click here instead of showing data from Database.
Please give your suggestion on how to get the value from database into cell and make it clickable. I don't want to use Select button. Please find my current output.
This is my current output I want my data from DB instead of ClickHere.

You can use TemplateField
<asp:TemplateField HeaderText="Name">
<ItemTemplate>
<asp:LinkButton runat="server" ID="lnk<%# Eval("SRONameinEnglish")%>"><%# Eval("SRONameinEnglish")%></asp:LinkButton>
</ItemTemplate>
</asp:TemplateField>
and click of LinkButton put your code to navigate anywhere.

In your case you are binding boundfield with static a tag which have href attribute so your not able to change text on that boundfield from your database.To get your approach you should
use TemplateField and bind data with text attribute using eval keyword as below example.
Try it:
<asp:TemplateField HeaderText="Name">
<ItemTemplate>
<asp:HyperLink ID="HyperLink1" runat="server" Text='<%# Eval("name") %>' />
</ItemTemplate>
</asp:TemplateField>
OR
you can also bind link with your hyperlink using NavigateUrl property of hyperlink as below example.
<asp:TemplateField HeaderText="Name">
<ItemTemplate>
<asp:HyperLink id="HyperLink2" NavigateUrl='<%#Eval("YourUrl") %>' Text='<%#Eval("name") %>' runat="server"/>
</ItemTemplate>
</asp:TemplateField>
I hope it will helpful to you.

How to set font-size of text box in bounded fields of grid view template fields?

In ASP.NET 2.0 web application, there is a gridview and user wanted to change the font size of contents of that grid view. Below is Gridview definition and server side code to set the font-size of contents of gridview. Everything is fine except, textboxes in bounded fields of gridview. The font size does not applied on them.
GridView :
<asp:TemplateField HeaderText="Display Name" HeaderStyle-HorizontalAlign="Left" ItemStyle-HorizontalAlign="Left">
<ItemTemplate>
<asp:TextBox ID="TextBox1" runat="server" Width="100px" Text='<%# Bind("DisplayName") %>' OnTextChanged="TextBox_TextChanged" />
<asp:HiddenField ID="HiddenField1" runat="server" Value='<%# Eval("DisplayName") %>' />
</ItemTemplate>
</asp:TemplateField>
ServerSide Code:
ObjPListSetting.Style["font-size"] = sTextSize + "px";
where, sTextSize is target value (i.e. 12, 14, 16).
Why is that so? Anyone can help in this regard.

In the OnRowDataBound event hander do something like this.
TextBox txtTextBox1 = RowObject.FindControl("TextBox1");
txtTextBox1.Style["font-size"] = sTextSize + "px";
This is a dummy code. Just check how you get the rowobject in below link.
http://msdn.microsoft.com/en-us/library/system.web.ui.webcontrols.gridview.rowdatabound.aspx

Grid View Format By Row

I'm wondering if it is possible to format a Grid View like the pattern below
Usual Grid View:
Name Address Age Gender <--- Fields Name
Example Example Example Example <--- Values
What I want to look like
"Fields" "Values"
Name Example
Address Example
Age Example
Gender Example
Any thought will be highly appreciated

you should look into using a repeater.

I think that GridView was simply not meant to be used that way. Usually, you will display several items in it and if those items are too many you will end up with the horizontal scrolling mistake (also, some nice arguments here).
If you are showing only one record, you should use a DetailsView control, which:
Displays the values of a single record from a data source in a table,
where each data row represents a field of the record. The DetailsView
control allows you to edit, delete, and insert records.

I got an Answer using this Codes:
<asp:GridView ID="GridView1" runat="server" DataSourceID="SqlDataSource1" AutoGenerateColumns="False" >
<Columns>
<asp:TemplateField HeaderText="">
<ItemTemplate>
Name: <asp:Label ID="Label1" runat="server" Text='<%# Eval("Name") %>'></asp:Label><br />
Address: <asp:Label ID="Label2" runat="server" Text='<%# Eval("Address") %>'></asp:Label><br />
Postcode: <asp:Label ID="Label3" runat="server" Text='<%# Eval("Postcode") %>'></asp:Label><br />
</ItemTemplate>
</asp:TemplateField>
</Columns>
</asp:GridView>

Multiple Column Dropdown in Details View control

I have created a dropdown list in a DetailsView control
I want to make that dropdown have multiple columns. Is that possible? If So how?
I've done a lot of searching and cant seem to find the solution.
Below is the code for my dropdown template:
<asp:TemplateField HeaderText="Division" SortExpression="fDivisionID">
<EditItemTemplate>
<asp:DropDownList
ID="DivisionDropDownList"
runat="server"
DataSourceID="DivisionSqlDataSource"
DataTextField="DivisionName"
DataValueField="DivisionID"
Text='<%# Bind("fDivisionID") %>'>
</asp:DropDownList>
</EditItemTemplate>
<ItemTemplate>
<asp:Label ID="Label1" runat="server" Text='<%# Bind("DivisionName") %>'></asp:Label>
</ItemTemplate>
</asp:TemplateField>
How do I add another column to that.. such as "Location"..
Thanks in advance

There are I think three ways actually.
Add two columns in your Select statement when fetching from database like below. or from here
Select Column1 + ' ' + Column2 From Yourtable
You can use third party controls.
Jquery Also supports this feature Here