We Keep Coding

Copy file from path in ListBox to a specific folder

I am trying to copy a files that i selected from a OpenFileDialog and saved their path into a ListBox.
From the path into the ListBox, I want it to copy it into a specific folder.
So far, it is copying the entire source folder into the destination folder.
My code:
private void button1_Click(object sender, EventArgs e)
{
System.IO.Stream myStream;
OpenFileDialog thisDialog = new OpenFileDialog();
thisDialog.InitialDirectory = "c:\\";
thisDialog.Filter = "All files (*.*)|*.*";
thisDialog.FilterIndex = 2;
thisDialog.RestoreDirectory = true;
thisDialog.Multiselect = true;
thisDialog.Title = "Please Select Attachments!";
if (thisDialog.ShowDialog() == DialogResult.OK)
{
foreach (String file in thisDialog.FileNames)
{
try
{
if ((myStream = thisDialog.OpenFile()) != null)
{
using (myStream)
{
listBox1.Items.Add(file);
}
}
}
catch (Exception ex)
{
MessageBox.Show("Error: Could not read file from disk. Original error: " + ex.Message);
}
}
}
else
{
//do nothing
}
//after selecting the files into the openfile dialog proceed to action the below.
foreach (object item in listBox1.Items)
{
//MessageBox.Show(string.Format("{0}!", listBox1.ToString()));
MessageBox.Show(item.ToString());
string sourceFolder = item.ToString();
string destinationFolder = #"c:\\testing";
//DirectoryInfo directory = new DirectoryInfo(sourceFolder);
DirectoryInfo directoryName = new DirectoryInfo( Path.GetDirectoryName(sourceFolder));
FileInfo[] files = directoryName.GetFiles();
foreach (var file in files)
{
string destinationPath = Path.Combine(destinationFolder, file.Name);
File.Copy(file.FullName, destinationPath);
}
}
}
Any help is mostly welcome. Thanks.

You are reading the whole source directory as many times as many files you selected in the file picker, but you already have the full path of your files in your ListBox, you can simply iterate them over and copy them to the destination like:
string destinationFolder = #"c:\testing";
foreach (var item in listBox1.Items)
{
string sourcePath = item.ToString();
string fileName = Path.GetFileName(sourcePath);
string destinationPath = Path.Combine(destinationFolder, fileName);
File.Copy(sourcePath, destinationPath);
}

C# FilePath Problems WinForms

I am trying to output the file address of an item selected in a combobox. But i keep getting the Directory address of the project and not the item itself. Please help. Here is my Code:
private void comboBox1_SelectedIndexChanged_1(object sender, EventArgs e)
{
if (availableSoftDropBox.SelectedItem.Equals("Choose Your Own..."))
{
if (openFileDialog1.ShowDialog() == DialogResult.OK)
txtFlashFile.Text = openFileDialog1.FileName;
}
else
{
string fileName;
fileName = Path.GetFullPath((string)availableSoftDropBox.SelectedItem);
string fullPath = #"C:\Program Files (x86)\yeet-n . master\yeet-
master\src\yeet\System\Products\" + (fileName);
txtFlashFile.Text = fullPath;

I'm not quite sure what you want to achieve, but using FileInfo instead of Path.GetFullPath might help.
private void comboBox1_SelectedIndexChanged_1(object sender, EventArgs e)
{
const string fullPath = #"C:\Program Files (x86)\yeet-n . master\yeet-
master\src\yeet\System\Products\";
string selection = (string)availableSoftDropBox.SelectedItem;
var fileInfo = new FileInfo(fullPath + selection);
string text = fileInfo.FullName;
if (selection.Equals("Choose Your Own..."))
{
if (openFileDialog1.ShowDialog() == DialogResult.OK)
{
text = openFileDialog1.FileName;
}
}
txtFlashFile.Text = text;
}

The process cannot access the file because it is being used by another process.c#

I am trying to copy one image from one location to another location using File.Copy() function but it gives the process can not access exception,any one can please help on this bellow is the code block.I have attached screenshot for exception.
private void btnUpload_Click(object sender, EventArgs e)
{
string SourcePath;
string RootDrive;
string DestPath;
string fileName;
fileName = "";
try
{
OpenFileDialog ofd = new OpenFileDialog();
ofd.Title = "Select Image to Upload";
ofd.Filter = "Jpg|*.jpg|Jpge|*.jpge|Gif|*.gif";
ofd.FileName = null;
if (ofd.ShowDialog() != DialogResult.Cancel)
{
fileName = ofd.FileName;
}
ofd.Dispose();
DestPath = Directory.GetCurrentDirectory() + #"\Uploads\PropertyImages\";
string destFile = System.IO.Path.Combine(DestPath, fileName);
if (!System.IO.Directory.Exists(DestPath))
{
System.IO.Directory.CreateDirectory(DestPath);
}
System.IO.File.Copy(fileName, destFile, true);
}
catch (Exception ae)
{
MessageBox.Show(ae.Message, "Upload Error", MessageBoxButtons.OK, MessageBoxIcon.Error);
}

It's probably because you are attempting to copy the file to itself. The call to Combine(), as you have it, is just returning fileName. Change the following line:
string destFile = System.IO.Path.Combine(DestPath, fileName);
to
string destFile = System.IO.Path.Combine(DestPath, System.IO.Path.GetFileName(fileName));

How to get file path from OpenFileDialog and FolderBrowserDialog?

Hey there i started learning C# a few days ago and I'm trying to make a program that copies and pastes files (and replaces if needed) to a selected directory but I don't know how to get the directory and file paths from the openfiledialog and folderbrowserdialog
what am I doing wrong?
Here's the code:
namespace filereplacer
{
public partial class Form1 : Form
{
public Form1()
{
InitializeComponent();
}
private void direc_Click(object sender, EventArgs e)
{
string folderPath = "";
FolderBrowserDialog directchoosedlg = new FolderBrowserDialog();
if (directchoosedlg.ShowDialog() == DialogResult.OK)
{
folderPath = directchoosedlg.SelectedPath;
}
}
private void choof_Click(object sender, EventArgs e)
{
OpenFileDialog choofdlog = new OpenFileDialog();
choofdlog.Filter = "All Files (*.*)|*.*";
choofdlog.FilterIndex = 1;
choofdlog.Multiselect = true;
choofdlog.ShowDialog();
}
private void replacebtn_Click(object sender, EventArgs e)
{
// This is where i'm having trouble
}
public static void ReplaceFile(string FileToMoveAndDelete, string FileToReplace, string BackupOfFileToReplace)
{
File.Replace(FileToMoveAndDelete, FileToReplace, BackupOfFileToReplace, false);
}
}

For OpenFileDialog:
OpenFileDialog choofdlog = new OpenFileDialog();
choofdlog.Filter = "All Files (*.*)|*.*";
choofdlog.FilterIndex = 1;
choofdlog.Multiselect = true;
if (choofdlog.ShowDialog() == DialogResult.OK)
{
string sFileName = choofdlog.FileName;
string[] arrAllFiles = choofdlog.FileNames; //used when Multiselect = true
}
For FolderBrowserDialog:
FolderBrowserDialog fbd = new FolderBrowserDialog();
fbd.Description = "Custom Description";
if (fbd.ShowDialog() == DialogResult.OK)
{
string sSelectedPath = fbd.SelectedPath;
}
To access selected folder and selected file name you can declare both string at class level.
namespace filereplacer
{
public partial class Form1 : Form
{
string sSelectedFile;
string sSelectedFolder;
public Form1()
{
InitializeComponent();
}
private void direc_Click(object sender, EventArgs e)
{
FolderBrowserDialog fbd = new FolderBrowserDialog();
//fbd.Description = "Custom Description"; //not mandatory
if (fbd.ShowDialog() == DialogResult.OK)
sSelectedFolder = fbd.SelectedPath;
else
sSelectedFolder = string.Empty;
}
private void choof_Click(object sender, EventArgs e)
{
OpenFileDialog choofdlog = new OpenFileDialog();
choofdlog.Filter = "All Files (*.*)|*.*";
choofdlog.FilterIndex = 1;
choofdlog.Multiselect = true;
if (choofdlog.ShowDialog() == DialogResult.OK)
sSelectedFile = choofdlog.FileName;
else
sSelectedFile = string.Empty;
}
private void replacebtn_Click(object sender, EventArgs e)
{
if(sSelectedFolder != string.Empty && sSelectedFile != string.Empty)
{
//use selected folder path and file path
}
}
....
}
NOTE:
As you have kept choofdlog.Multiselect=true;, that means in the OpenFileDialog() you are able to select multiple files (by pressing ctrl key and left mouse click for selection).
In that case you could get all selected files in string[]:
At Class Level:
string[] arrAllFiles;
Locate this line (when Multiselect=true this line gives first file only):
sSelectedFile = choofdlog.FileName;
To get all files use this:
arrAllFiles = choofdlog.FileNames; //this line gives array of all selected files

Use the Path class from System.IO. It contains useful calls for manipulating file paths, including GetDirectoryName which does what you want, returning the directory portion of the file path.
Usage is simple.
string directoryPath = System.IO.Path.GetDirectoryName(choofdlog.FileName);

you can store the Path into string variable like
string s = choofdlog.FileName;

To get the full file path of a selected file or files, then you need to use FileName property for one file or FileNames property for multiple files.
var file = choofdlog.FileName; // for one file
or for multiple files
var files = choofdlog.FileNames; // for multiple files.
To get the directory of the file, you can use Path.GetDirectoryName
Here is Jon Keet's answer to a similar question about getting directories from path

Create this class as Extension:
public static class Extensiones
{
public static string FolderName(this OpenFileDialog ofd)
{
string resp = "";
resp = ofd.FileName.Substring(0, 3);
var final = ofd.FileName.Substring(3);
var info = final.Split('\\');
for (int i = 0; i < info.Length - 1; i++)
{
resp += info[i] + "\\";
}
return resp;
}
}
Then, you could use in this way:
//ofdSource is an OpenFileDialog
if (ofdSource.ShowDialog(this) == DialogResult.OK)
{
MessageBox.Show(ofdSource.FolderName());
}

Your choofdlog holds a FileName and FileNames (for multi-selection) containing the file paths, after the ShowDialog() returns.

A primitive quick fix that works.
If you only use OpenFileDialog, you can capture the FileName, SafeFileName, then subtract to get folder path:
exampleFileName = ofd.SafeFileName;
exampleFileNameFull = ofd.FileName;
exampleFileNameFolder = ofd.FileNameFull.Replace(ofd.FileName, "");

I am sorry if i am late to reply here but i just thought i should throw in a much simpler solution for the OpenDialog.
OpenDialog ofd = new OpenDialog();
var fullPathIncludingFileName = ofd.Filename; //returns the full path including the filename
var fullPathExcludingFileName = ofd.Filename.Replace(ofd.SafeFileName, "");//will remove the filename from the full path
I have not yet used a FolderBrowserDialog before so i will trust my fellow coders's take on this. I hope this helps.

String fn = openFileDialog1.SafeFileName;
String path = openFileDialog1.FileName.ToString().Replace(fn, "");

Find a file in my directory

I need to get the path of a file which is in a specific directory.The user selects a csv file from a OpenFileDialog. If the csv file has field that ends at .txt then take the path of that file and put it in a pathfile variable. The new file has to be placed, by the user, in the same directory as the csv file.
EDIT: How do I put the path of the file in a variable ?
EDIT2: The file could be placed everywhere, for example: C://george.csv. So I want to take a txt from the directory c:// .Or if the file is here: C://Documents/anna.csv. The text has to be C://Documents/textfile.txt.
EDIT3: The csv file that the user has opened is at c://Documents/gonow.csv
The file gonow.csv is : one, two, tree, four, textfile.txt, five, six, seven.
When a field has extension .txt then the program has to go and cath the path. In this case the path is c://Documents/textfile.txt.
private void button3_Click(object sender, EventArgs e)
{
string filename = "";
DialogResult result = openFileDialog2.ShowDialog();
if (result == DialogResult.OK)
{
filename = openFileDialog2.FileName;
textBox3.Text = filename;
System.IO.StreamReader file2 = new System.IO.StreamReader(textBox3.Text);
}
}
private void button2_Click(object sender, EventArgs e)
{
if (Path.GetExtension(colB[j]) == ".csv")
textBox2.Text += " comma separated, in line " + j + "" + Environment.NewLine;
}

Try
string path = Path.GetDirectoryName(filename);
EDITED according to your EDIT3:
Use this function to open your csv file and get new complete filename.
private string GetFilename(string csvFilename)
{
string path = Path.GetDirectoryName(csvFilename);
string[] lines = File.ReadAllLines(csvFilename);
foreach (string line in lines)
{
string[] items = line.Split(',');
string txt = items.First(item => item.ToLower().Trim().EndsWith(".txt"));
if (!String.IsNullOrEmpty(txt))
return Path.Combine(path, txt);
}
return "";
}

iF you need to put the txt file (the generated file) in the same folder as that of the CSV file, you can store the path of the CSV file and create the txt file in theat folder.
To do this you may like to have a variable like this:
private void button3_Click(object sender, EventArgs e)
{
string filename = "";
string FolderPath;
DialogResult result = openFileDialog2.ShowDialog();
if (result == DialogResult.OK)
{
filename = openFileDialog2.FileName;
FolderPath = Path.GetDirectoryName(filename);
textBox3.Text = filename;
System.IO.StreamReader file2 = new System.IO.StreamReader(textBox3.Text);
}
}
private void button2_Click(object sender, EventArgs e)
{
if (Path.GetExtension(colB[j]) == ".csv")
textBox2.Text += " comma separated, in line " + j + "" + Environment.NewLine;
}
The FolderPAth variable holds the path to the folder. You can create the txt file in this folder. This means that the txt file is in the same folder as of the csv file. If you need to access this in a different method, you may declare it in relevant scope.