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I cannot find any elaboration on why the Date property of the DateTime object is defaulted to midnight. I know that it is, through my own work as well as MSDN, but I am trying to understand the reasoning behind this. I cannot find any articles elaborating on why this is so.
Edit: To elaborate on some of the points being asked in comments.
string a = "2014-10-22 09:00 PM";
DateTime d = DateTime.Parse(a);
In this example I would have assumed it would default to 21:00:00.000- again I know it does not.
DateTime.Date means the day, the same way DateTime.Today returns the current date's DateTime at midnight (as opposed to DateTime.Now). So what do you expect it to return instead? A DateTime is a struct which always contains a time even if it's set to 0:00:00.
So every DateTime has a time component. It's the same as if you'd say: give me an hour without minutes. Every hour can also be represented by 60 minutes. By using dt.Date you say explicitly that you want that DateTime "without" time which means midnight and is a shortcut for new DateTime(dt.Year,dt.Month,dt.Day).
As far as I'm aware, aside from being the start of the date, it's there so you can ignore the Time part of the DateTime.
I'm sure there's better, more detailed explanations (and I'm sure someone, somewhere will come along and mention the use of NodaTime - possibly Jon Skeet himself - and it's Date class)
Because it's got to be set to something, and midnight (ie all zeros) is as good a value as any!
Seriously though, it makes sense at you've asked for a date, and 00:00:00 is the start of that date. There's no Date type in the framework, the designers overloaded DateTime to cover both, and midnight was chosen as the time in the day.
In C#
DateTime dateAndTime = DateTime.Now;
gives the current date and time. I need only the current time. If I use string, it is possible like:
string time=DateTime.Now.ToString("hh:mm:ss");
Is it possible to get only the time portion of DateTime without going through a string?
You can get the current time in a TimeSpan by accessing TimeOfDay, like this:
TimeSpan time = DateTime.Now.TimeOfDay;
Now time will represent the amount of time that passed since midnight.
There is no out-of-the-box type that holds just a time. You could use TimeSpan, and even the .NET framework does at parts (for example DateTime.TimeOfDay), however I think that TimeSpan is really serving a different purpose.
TimeSpan, to quote MSDN, simply "measures a time interval". That could easily be longer than the hours, minutes, seconds, etc. that make up a day (i.e. 24 hours in sum). And indeed the TimeSpan structure provides for that, having properties like Days, for example.
Thus, I think TimeSpan is not a very good fit to represent the time of day (which I assume you mean when saying "current time").
That brings us to another problem. What exactly is the "current time"? As I said, I assume that you mean the current time as in "the current time of day". But current time could also mean the current (elapsed) time since some particular point in time in the past.
Granted, all that can get pretty theoretic or even rhetoric and does not really help you.
I would just use DateTime. Where you actually care about the "time" value, just only use the time portion (like you have shown, you known about, with your ToString example). Although, depending on what you need the time for, you might resort to the DateTime.TimeOfDay property instead of simply formatting it as a string (unless of course that is what you need).
Finally, you could also resort to third party libraries like Node Time, that do provide types for time only (like LocalTime).
string time = string.Format("{0:hh-mm-ss-tt}", DateTime.Now);
I've got something like this DateTime.Now.ToString("dd.MM.yy"); In my code, And I need to add 1 week to it, like 5.4.2012 to become 12.4.2012 I tried to convert it to int and then add it up, but there is a problem when it's up to 30.
Can you tell me some clever way how to do it?
You want to leave it as a DateTime until you are ready to convert it to a string.
DateTime.Now.AddDays(7).ToString("dd.MM.yy");
First, always keep the data in it's native type until you are ready to either display it or serialize it (for example, to JSON or to save in a file). You wouldn't convert two int variables to strings before adding or multiplying them, so don't do it with dates either.
Staying in the native type has a few advantages, such as storing the DateTime internally as 8 bytes, which is smaller than most of the string formats. But the biggest advantage is that the .NET Framework gives you a bunch of built in methods for performing date and time calculations, as well as parsing datetime values from a source string. The full list can be found here.
So your answer becomes:
Get the current timestamp from DateTime.Now. Use DateTime.Now.Date if you'd rather use midnight than the current time.
Use AddDays(7) to calculate one week later. Note that this method automatically takes into account rolling over to the next month or year, if applicable. Leap days are also factored in for you.
Convert the result to a string using your desired format
// Current local server time + 7 days
DateTime.Now.AddDays(7).ToString("dd.MM.yy");
// Midnight + 7 days
DateTime.Now.Date.AddDays(7).ToString("dd.MM.yy");
And there are plenty of other methods in the framework to help with:
Internationalization
UTC and timezones (though you might want to check out NodaTime for more advanced applications)
Operator overloading for some basic math calcs
The TimeSpan class for working with time intervals
Any reason you can't use the AddDays method as in
DateTime.Now.AddDays(7)
In our C# project we have the need for representing a date without a time.
I know of the existence of the DateTime, however, it incorporates a time of day as well.
I want to make explicit that certain variables and method-arguments are date-based.
Hence I can't use the DateTime.Date property
What are the standard approaches to this problem?
Why is there no Date class in C#?
Does anyone have a nice implementation using a struct and maybe some extensionmethods on DateTime and maybe implementing some operators such as == and <, > ?
Allow me to add an update to this classic question:
DateOnly (and TimeOnly) types have been added to .NET 6, starting with Preview 4. See my other answer here.
Jon Skeet's Noda Time library is now quite mature, and has a date-only type called LocalDate. (Local in this case just means local to someone, not necessarily local to the computer where the code is running.)
I've studied this problem significantly, so I'll also share several reasons for the necessity of these types:
There is a logical discrepancy between a date-only, and a date-at-midnight value.
Not every local day has a midnight in every time zone. Example: Brazil's spring-forward daylight saving time transition moves the clock from 11:59:59 to 01:00:00.
A date-time always refers to a specific time within the day, while a date-only may refer to the beginning of the day, the end of the day, or the entire range of the day.
Attaching a time to a date can lead to the date changing as the value is passed from one environment to another, if time zones are not watched very carefully. This commonly occurs in JavaScript (whose Date object is really a date+time), but can easily happen in .NET also, or in the serialization as data is passed between JavaScript and .NET.
Serializing a DateTime with XML or JSON (and others) will always include the time, even if it's not important. This is very confusing, especially considering things like birth dates and anniversaries, where the time is irrelevant.
Architecturally, DateTime is a DDD value-object, but it violates the Single Responsibly Principle in several ways:
It is designed as a date+time type, but often is used as date-only (ignoring the time), or time-of-day-only (ignoring the date). (TimeSpan is also often used for time-of-day, but that's another topic.)
The DateTimeKind value attached to the .Kind property splits the single type into three, The Unspecified kind is really the original intent of the structure, and should be used that way. The Utc kind aligns the value specifically with UTC, and the Local kind aligns the value with the environment's local time zone.
The problem with having a separate flag for kind is that every time you consume a DateTime, you are supposed to check .Kind to decide what behavior to take. The framework methods all do this, but others often forget. This is truly a SRP violation, as the type now has two different reasons to change (the value, and the kind).
The two of these lead to API usages that compile, but are often nonsensical, or have strange edge cases caused by side effects. Consider:
// nonsensical, caused by mixing types
DateTime dt = DateTime.Today - TimeSpan.FromHours(3); // when on today??
// strange edge cases, caused by impact of Kind
var london = TimeZoneInfo.FindSystemTimeZoneById("GMT Standard Time");
var paris = TimeZoneInfo.FindSystemTimeZoneById("Romance Standard Time");
var dt = new DateTime(2016, 3, 27, 2, 0, 0); // unspecified kind
var delta = paris.GetUtcOffset(dt) - london.GetUtcOffset(dt); // side effect!
Console.WriteLine(delta.TotalHours); // 0, when should be 1 !!!
In summary, while a DateTime can be used for a date-only, it should only do so when when every place that uses it is very careful to ignore the time, and is also very careful not to try to convert to and from UTC or other time zones.
I suspect there is no dedicate pure Date class because you already have DateTime which can handle it. Having Date would lead to duplication and confusion.
If you want the standard approach look at the DateTime.Date property which gives just the date portion of a DateTime with the time value set to 12:00:00 midnight (00:00:00).
I've emailed refsrcfeedback#microsoft.com and that's their answer
Marcos, this is not a good place to ask questions like these. Try http://stackoverflow.com
Short answer is that you need a model to represent a point in time, and DateTime does that, it’s the most useful scenario in practice. The fact that humans use two concepts (date and time) to mark points in time is arbitrary and not useful to separate.
Only decouple where it is warranted, don’t do things just for the sake of doing things blindly. Think of it this way: what problem do you have that is solved by splitting DateTime into Date and Time? And what problems will you get that you don’t have now? Hint: if you look at DateTime usages across the .NET framework: http://referencesource.microsoft.com/#mscorlib/system/datetime.cs#df6b1eba7461813b#references
You will see that most are being returned from a method. If we didn’t have a single concept like DateTime, you would have to use out parameters or Tuples to return a pair of Date and Time.
HTH,
Kirill Osenkov
In my email I'd questioned if it was because DateTime uses TimeZoneInfo to get the time of the machine - in Now propriety. So I'd say it's because "the business rules" are "too coupled", they confimed that to me.
I created a simple Date struct for times when you need a simple date without worrying about time portion, timezones, local vs. utc, etc.
https://github.com/claycephus/csharp-date
System.DateOnly and System.TimeOnly types were recently added to .NET 6, and are available in the daily builds.
They were included with the .NET 6 Preview 4 release.
See https://github.com/dotnet/runtime/issues/49036
They are in the .NET source code here:
https://github.com/dotnet/runtime/blob/main/src/libraries/System.Private.CoreLib/src/System/DateOnly.cs
https://github.com/dotnet/runtime/blob/main/src/libraries/System.Private.CoreLib/src/System/TimeOnly.cs
I've blogged about them here.
If you need to run date comparisons then use
yourdatetime.Date;
If you are displaying to the screen use
yourdatetime.ToShortDateString();
Allow me to speculate: Maybe it is because until SQL Server 2008 there was no Date datatype in SQL so it would be hard so store it in SQL server?? And it is after all a Microsoft Product?
Who knows why it's that way. There are lots of bad design decisions in the .NET framework. However, I think this is a pretty minor one. You can always ignore the time part, so even if some code does decide to have a DateTime refer to more than just the date, the code that cares should only ever look at the date part. Alternatively, you could create a new type that represents just a date and use functions in DateTime to do the heavy lifting (calculations).
Why? We can only speculate and it doesn't do much to help solve engineering problems. A good guess is that DateTime contains all the functionality that such a struct would have.
If it really matters to you, just wrap DateTime in your own immutable struct that only exposes the date (or look at the DateTime.Date property).
In addition to Robert's answer you also have the DateTime.ToShortDateString method. Also, if you really wanted a Date object you could always use the Adapter pattern and wrap the DateTime object exposing only what you want (i.e. month, day, year).
There is always the DateTime.Date property which cuts off the time part of the DateTime. Maybe you can encapsulate or wrap DateTime in your own Date type.
And for the question why, well, I guess you'll have to ask Anders Heljsberg.
Yeah, also System.DateTime is sealed. I've seen some folks play games with this by creating a custom class just to get the string value of the time as mentioned by earlier posts, stuff like:
class CustomDate
{
public DateTime Date { get; set; }
public bool IsTimeOnly { get; private set; }
public CustomDate(bool isTimeOnly)
{
this.IsTimeOnly = isTimeOnly;
}
public string GetValue()
{
if (IsTimeOnly)
{
return Date.ToShortTimeString();
}
else
{
return Date.ToString();
}
}
}
This is maybe unnecessary, since you could easily just extract GetShortTimeString from a plain old DateTime type without a new class
Because in order to know the date, you have to know the system time (in ticks), which includes the time - so why throw away that information?
DateTime has a Date property if you don't care at all about the time.
If you use the Date or Today properties to get only the date portion from the DateTime object.
DateTime today = DateTime.Today;
DateTime yesterday = DateTime.Now.AddDays(-1).Date;
Then you will get the date component only with the time component set to midnight.
In C# if I want to parse a datetime, but some times I just have either a date and not a time component or no date but a time component, how would I do this? Usually when you leave out the time component, it automatically assumes that the time is 12:00AM. But I don't want this. If the time component is missing then I just want the DateTime to store a date only and the leave the time component off.
The value of a DateTime internally is just an UInt64 (ulong in C#) that stores the number of ticks since some date in the past, so whether you like it or not, the time component will always be there.
If you only need to display certain parts, just use any of the format strings (examples are for "en-us" culture):
DateTime.Now.ToString("d"); // 5/26/2009
DateTime.Now.ToString("t"); // 4:56 PM
The complete reference: http://msdn.microsoft.com/en-us/library/az4se3k1.aspx
It's not possible to have a DateTime without a time component. You could store a boolean flag along with it in a struct to store data about existence of that component. However, there's no way to use the automatic parsing routine to distinguish between a DateTime string with a time specified as 12:00 PM and a nonexistent one.
If it really bugs you you can always create a wrapper class that can hide the time portions of the datetime class.
No you will have the time component no matter what. The best you can do is access the Date property on your DateTime object if you really have to.
http://msdn.microsoft.com/en-us/library/system.datetime.date.aspx
DateTime by definition stores a date and a time such that it cannot just represent one of them without representing the other. If you only want the date (or only the time), parse out the information you need and discard the rest of it.
As mentioned before DateTime will always have a Date and a Time part of it if you only want a single part use the way described by the others
DateTime date = DateTime.Parse("2009-11-30);
date.Year; = 2009
date.Month; = 11
date.Day; = 30
date.Hour; = 0
and so on
The thing you must be aware is that all of these methods will only return an integer.
If you want to know all the possible ways to parse a string John Sheehan has put together a great Cheat Sheet wit all possible ways to parse and manipulate dates, and other strings for that matter.
You could have a class that stores a DateTime and determines if the time was ever set or if just the date was set and return values accordingly.
Use
DateTime date = new DateTime();
date = DateTime.Parse("1/1/2001");
to set the date, then use
date.ToShortDateString();
or
date.Year;
date.Month;
date.Day;
to get what you need. Hope that helps!
A DateTime object is always stores a date + a time, not just one. You can always choose to work only with the date part, i.e. only use properties like Year, Month, DayOfWeek. But underneath there will aways be some stored time.
It is very dangerous to assume that the date portion of a DateTime is necessarily the date you are expecting. As pointed-out, DateTime always includes and considers the time aspect, even when you don't see it.
This is a big problem when you have data stored in different time-zones (and particularly if knowledge of that offset is not also kept, because it is assumed that what is being stored is a Date, not a date-with-time).
You may store a birthdate as '01/01/2000 00:00:00' during Summer-Time, which then is stored in UCT as '31/12/1999 23:00:00'. When you then read that birth-date later, the date portion is now a day early.
Best to create your own type. Strange that Microsoft didn't think it worth having a Date type.