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Not getting string in xml formatted form?

I am trying to create a xml document of following format:
<![CDATA[<Caption xmlns="http:happy.x.xsd" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://www.happybus.tv/yy/happybus.xsd">
<TemplateID>xxxxx</TemplateID>
<CaptionOptions>
<CaptionField>
<Field>xxx</Field>
<Text>xxx</Text>
</CaptionField>
<CaptionField>
<Field>xxxx</Field>
<Text>""</Text>
</CaptionField>
</CaptionOptions>
</Caption>]]>
Here is the code that I wrote
XmlDocument xml2 = new XmlDocument();
XmlElement e = xml2.CreateElement("Caption");
e.InnerText ="Hello";
XmlElement template = xml2.CreateElement("TemplateID");
template.InnerText = "#TemplateID";
XmlElement captionOptions = xml2.CreateElement("CaptionOptions");
XmlElement captionField = xml2.CreateElement("CaptionField");
XmlElement fieldId = xml2.CreateElement("FieldID");
fieldId.InnerText = "#FieldID";
XmlElement textstring = xml2.CreateElement("TextString");
textstring.InnerText = "#TextString";
captionField.AppendChild(fieldId);
captionField.AppendChild(textstring);
captionOptions.AppendChild(captionField);
e.AppendChild(template);
e.AppendChild(captionOptions);
xml2.AppendChild(e);
StringWriter string_writer2 = new StringWriter();
XmlTextWriter xml_text_writer2 = new XmlTextWriter(string_writer2);
xml_text_writer2.Formatting = Formatting.Indented;
xml2.WriteTo(xml_text_writer2); // xml is your XmlDocument
string formattedXml2 = string_writer2.ToString();
Console.Write(formattedXml2);
I have tried a similar example with different XML doc but it clearly work, I even tried debugging but it is not getting formatted.

Have you tried using the XDocument and related classes? I find they make manual construction of xml easier and more intuitive since the code looks very similar to the xml. The ToString method seems to output the xml formatted the way you want:
void Main()
{
var xDoc = new XDocument
(
new XElement("Parent",
new XElement("TemplateID", "xxxxx"),
new XElement("CaptionOptions",
new XElement("CaptionField",
new XElement("Field", "xxx"),
new XElement("Text", "xxx")
),
new XElement("CaptionField",
new XElement("Field", "xxxx"),
new XElement("Text", "")
)
)
)
);
Console.WriteLine(xDoc.ToString());
//To enclose the xml in a CDATA, you could use:
var cData = new XCData(xDoc.ToString());
Console.WriteLine(cData.ToString());
}

Creating XML document with Two root nodes

I want to create XML with two root nodes, like this
<?xml version="1.0" encoding="IBM437"?>
<header1>
<header2>
<fracc>6004</fracc>
<txncode>HTH</txncode>
<reason>testing</reason>
<timeout>20</timeout>
<rdate>2/3/2015 12:00:00 AM</rdate>
<rtime>6/18/2015 1:20:00 PM</rtime>
<seqno>5</seqno>
<prefix>8</prefix>
<msgtype>trr</msgtype>
<sendto>trr</sendto>
<replyto>trr</replyto>
</header2>
</header1>
My code is like this, I'm unable to add two root elements with my code, it's a must to use XmlDocument class.
XmlDocument xmlDoc = new XmlDocument();
XmlNode rootNode = xmlDoc.CreateElement("header" );
xmlDoc.AppendChild(rootNode);
XmlNode accountNode = xmlDoc.CreateElement("fracc");
accountNode.InnerText = Infracc;
rootNode.AppendChild(accountNode);
XmlNode txnNode = xmlDoc.CreateElement("txncode");
txnNode.InnerText = Intxncode;
rootNode.AppendChild(txnNode);
XmlNode reasonNode = xmlDoc.CreateElement("reason");
reasonNode.InnerText = Inreason;
rootNode.AppendChild(reasonNode);
XmlNode timeoutNode = xmlDoc.CreateElement("timeout");
timeoutNode.InnerText = Intimeout.ToString();
rootNode.AppendChild(timeoutNode);
XmlNode rdateNode = xmlDoc.CreateElement("rdate");
rdateNode.InnerText = Indate.ToString();
rootNode.AppendChild(rdateNode);
XmlNode rtimeNode = xmlDoc.CreateElement("rtime");
rtimeNode.InnerText = Intime.ToString();
rootNode.AppendChild(rtimeNode);
XmlNode seqnoNode = xmlDoc.CreateElement("seqno");
seqnoNode.InnerText = Inseqno.ToString();
rootNode.AppendChild(seqnoNode);
XmlNode prefixNode = xmlDoc.CreateElement("prefix");
prefixNode.InnerText = Inprefix.ToString();
rootNode.AppendChild(prefixNode);
XmlNode msgtypeNode = xmlDoc.CreateElement("msgtype");
msgtypeNode.InnerText = Inmsgtype;
rootNode.AppendChild(msgtypeNode);
XmlNode sendtoNode = xmlDoc.CreateElement("sendto");
sendtoNode.InnerText = Insendto;
rootNode.AppendChild(sendtoNode);
XmlNode replytoNode = xmlDoc.CreateElement("replyto");
replytoNode.InnerText = Inreplyto;
rootNode.AppendChild(replytoNode);
xmlDoc.Save("boc.xml");
xmlDoc.Load("boc.xml");
xmlDoc.Save(Console.Out);
return xmlDoc;
and my output is this
<?xml version="1.0" encoding="IBM437"?>
<header>
<fracc>6004</fracc>
<txncode>ttt</txncode>
<reason>testing</reason>
<timeout>20</timeout>
<rdate>2/3/2015 12:00:00 AM</rdate>
<rtime>6/18/2015 1:20:00 PM</rtime>
<seqno>5</seqno>
<prefix>8</prefix>
<msgtype>tt</msgtype>
<sendto>t</sendto>
<replyto>t</replyto>
</header>
Please help me to add two root nodes.

You are not adding 2 root elements.
Change your lines of code
XmlDocument xmlDoc = new XmlDocument();
XmlNode rootNode = xmlDoc.CreateElement("header" );
xmlDoc.AppendChild(rootNode);
like below -
XmlDocument xmlDoc = new XmlDocument();
XmlNode rootNode1 = xmlDoc.CreateElement("header1");
xmlDoc.AppendChild(rootNode1);
XmlNode rootNode = xmlDoc.CreateElement("header2");
rootNode1.AppendChild(rootNode);

Based on your sample output, it's clear that <header1> is the root element and <header2> is inside <header1>, so all you need to do is append <header2> inside <header1> and append the rest of the elements inside <header2>. This code should work
XmlDocument xmlDoc = new XmlDocument();
XmlNode rootNode = xmlDoc.CreateElement("header1");
xmlDoc.AppendChild(rootNode);
XmlNode rootNode2 = xmlDoc.CreateElement("header2");
rootNode.AppendChild(rootNode2);
XmlNode accountNode = xmlDoc.CreateElement("fracc");
accountNode.InnerText = Infracc;
rootNode2.AppendChild(accountNode);
XmlNode txnNode = xmlDoc.CreateElement("txncode");
txnNode.InnerText = Intxncode;
rootNode2.AppendChild(txnNode);
XmlNode reasonNode = xmlDoc.CreateElement("reason");
reasonNode.InnerText = Inreason;
rootNode2.AppendChild(reasonNode);
XmlNode timeoutNode = xmlDoc.CreateElement("timeout");
timeoutNode.InnerText = Intimeout.ToString();
rootNode2.AppendChild(timeoutNode);
XmlNode rdateNode = xmlDoc.CreateElement("rdate");
rdateNode.InnerText = Indate.ToString();
rootNode2.AppendChild(rdateNode);
XmlNode rtimeNode = xmlDoc.CreateElement("rtime");
rtimeNode.InnerText = Intime.ToString();
rootNode2.AppendChild(rtimeNode);
XmlNode seqnoNode = xmlDoc.CreateElement("seqno");
seqnoNode.InnerText = Inseqno.ToString();
rootNode2.AppendChild(seqnoNode);
XmlNode prefixNode = xmlDoc.CreateElement("prefix");
prefixNode.InnerText = Inprefix.ToString();
rootNode2.AppendChild(prefixNode);
XmlNode msgtypeNode = xmlDoc.CreateElement("msgtype");
msgtypeNode.InnerText = Inmsgtype;
rootNode2.AppendChild(msgtypeNode);
XmlNode sendtoNode = xmlDoc.CreateElement("sendto");
sendtoNode.InnerText = Insendto;
rootNode2.AppendChild(sendtoNode);
XmlNode replytoNode = xmlDoc.CreateElement("replyto");
replytoNode.InnerText = Inreplyto;
rootNode2.AppendChild(replytoNode);
xmlDoc.Save("boc.xml");
xmlDoc.Load("boc.xml");
xmlDoc.Save(Console.Out);
return xmlDoc;
Working fiddle: https://dotnetfiddle.net/EevsJq

XmlDocument - SelectSingleNode with namespace

This is my code:
XmlTextReader reader = new XmlTextReader(xmlPath);
XmlDocument xmlDoc = new XmlDocument();
xmlDoc.Load(reader);
XmlNode root = xmlDoc.DocumentElement;
XmlNode node = root.SelectSingleNode("marketingid");
XML that works:
<confirmsubmit>
<marketingid>-1</marketingid>
</confirmsubmit>
XML that doesn't work:
<confirmsubmit xmlns="http:....">
<marketingid>-1</marketingid>
</confirmsubmit>
What is the way to deal with the xmlns attribute and how can i parse it?
Is it has anything to do with namespace?
EDIT:
This is the code that works:
XmlTextReader reader = new XmlTextReader(xmlPath);
XmlDocument xmlDoc = new XmlDocument();
xmlDoc.Load(reader);
XmlNamespaceManager nsmgr = new XmlNamespaceManager(xmlDoc.NameTable);
nsmgr.AddNamespace("ns", xmlDoc.DocumentElement.NamespaceURI);
XmlNode book = xmlDoc.SelectSingleNode("/ns:confirmsubmit/ns:marketingid", nsmgr);
This all XPath is more complicated than seems, I would recommand to begginers like my to read: http://www.w3schools.com/xpath/xpath_syntax.asp

You need to add a XmlNamespaceManager instance in the game, as shown in this example from the documentation:
public class Sample
{
public static void Main()
{
XmlDocument doc = new XmlDocument();
doc.Load("booksort.xml");
//Create an XmlNamespaceManager for resolving namespaces.
XmlNamespaceManager nsmgr = new XmlNamespaceManager(doc.NameTable);
nsmgr.AddNamespace("bk", "urn:samples");
//Select and display the value of all the ISBN attributes.
XmlNodeList nodeList;
XmlElement root = doc.DocumentElement;
nodeList = root.SelectNodes("/bookstore/book/#bk:ISBN", nsmgr);
foreach (XmlNode isbn in nodeList){
Console.WriteLine(isbn.Value);
}
}
}

Here is how to do it from LINQ to XML. Short and simple
const string xml = #"<confirmsubmit xmlns='http:....'>
<marketingid>-1</marketingid>
</confirmsubmit>";
XElement element = XElement.Parse(xml);
var requestedElement = element.Elements().FirstOrDefault(x => x.Name.LocalName.Equals("marketingid"));

xmlns attribute is used at XHTML and defines namespace for a document. You can parse it like:
XDocument xdoc = XDocument.Load(xmlPath);
var attrib = xdoc.Root.Attribute("xmlns").Value;

xml nodes editing based on an xmlElement

I have tried two ways but they both didnt work..
the first way::
string filepath = Server.MapPath[this is not a link]("XMLFile2.xml");
XmlDocument xdoc = new XmlDocument();
xdoc.Load(filepath);
XmlNode root = xdoc.DocumentElement;
XmlNode idNode = root.SelectSingleNode("/students/student/id");
if (idNode.Value == 9.ToString())
{
var nodeOfStudent = xdoc.SelectNodes("/students/student[#id='9']");
nodeOfStudent[1].InnerXml = TextBox_firstname.Text;
nodeOfStudent[2].InnerXml = TextBox_lastname.Text;
nodeOfStudent[3].InnerXml = TextBox_dob.Text;
nodeOfStudent[4].InnerXml = TextBox_class.Text;
nodeOfStudent[5].InnerXml = TextBox_section.Text;
nodeOfStudent[6].InnerXml = TextBox_telephone.Text;
}
the second way::
string filepath = Server.MapPath("XMLFile2.xml");
XmlDocument xdoc = new XmlDocument();
xdoc.Load(filepath);
XmlNode root = xdoc.DocumentElement;
XmlNode idNode = root.SelectSingleNode("/students/student/id");
xdoc.SelectSingleNode("/students/student[#id='10']/firstname").InnerXml = TextBox_firstname.Text;
xdoc.DocumentElement.AppendChild(firstname);
xdoc.SelectSingleNode("/students/student[#id='10']/lastname").InnerXml = TextBox_firstname.Text;
xdoc.SelectSingleNode("/students/student[#id='10']/dob").InnerXml = TextBox_firstname.Text;
xdoc.SelectSingleNode("/students/student[#id='10']/class").InnerXml = TextBox_firstname.Text;
xdoc.SelectSingleNode("/students/student[#id='10']/section").InnerXml = TextBox_firstname.Text;
xdoc.SelectSingleNode("/students/student[#id='10']/telephone").InnerXml = TextBox_firstname.Text;
xdoc.Save(filepath);
is there something wrong i dont see...
my xml file looks like this::
<students>
<student>
<id>1</id>
<first_name>ahmad</first_name>
<last_name>hani</last_name>
<DOB>12/5/1998</DOB>
<class>sixth</class>
<section>A</section>
<telephone>06555632</telephone>
</student>
</students>
and i used a query string to load the values from a gridView located in another page using "QueryString"....
thanks in advance.

You can easily do this with Linq to xml:
int id = 9;
XDocument xdoc = XDocument.Load(filepath);
var student = xdoc.Descendants("student")
.Where(s => (int)s.Element("id") == id)
.SingleOrDefault();
if (student != null)
{
student.Element("first_name").Value = TextBox_firstname.Text;
student.Element("last_name").Value = TextBox_lastname.Text;
student.Element("DOB").Value = TextBox_dob.Text;
student.Element("class").Value = TextBox_class.Text;
// etc
}
xdoc.Save(filepath);

SqlDataReader not producing XML document

I am trying to dynamically create a XML for a webservice but when I test the service I get the following error
XML Parsing Error: no element found
Location: http://stuiis.cms.gre.ac.uk/dd615/aspweb/WatCoursework/Service.asmx/getMusicdetailsSql
Line Number 1, Column 39:
--------------------------------------^
// Make a new XML document in memory.
XmlDocument doc = new XmlDocument();
// Fill this document with a root element
// named <Inventory>.
XmlElement musicInformation = doc.CreateElement("musicInformation");
using (SqlDataReader oDr = myCommand.ExecuteReader())
{
while (oDr.Read())
{
// Now, make a sub element named <Car> with
// an ID attribute.
XmlElement musicdetails = doc.CreateElement("musicdetails");
musicdetails.SetAttribute("m_id", oDr["m_id"].ToString());
// Build the data within the <Car> element.
XmlElement p_id = doc.CreateElement("p_id");
p_id.InnerText = oDr["p_id"].ToString();
XmlElement artistname = doc.CreateElement("artistname");
artistname.InnerText = oDr["artistname"].ToString();
XmlElement recordname = doc.CreateElement("recordname");
recordname.InnerText = oDr["recordname"].ToString();
XmlElement recordtype = doc.CreateElement("recordtype");
recordtype.InnerText = oDr["recordtype"].ToString();
XmlElement format = doc.CreateElement("format");
format.InnerText = oDr["format"].ToString();
XmlElement price = doc.CreateElement("price");
price.InnerText = oDr["price"].ToString();
musicdetails.AppendChild(p_id);
musicdetails.AppendChild(artistname);
musicdetails.AppendChild(recordname);
musicdetails.AppendChild(recordtype);
musicdetails.AppendChild(format);
musicdetails.AppendChild(price);
musicInformation.AppendChild(musicdetails);
}
return doc;
}

I think you forgot to add the musicInformation to the document:
}
doc.AppendChild(musicInformation);
return doc;
}