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How does use XamlReader to load from a Xaml file from within the assembly?

I've found several posts across stackoverflow and the rest of the internet regarding how to load Xaml from a static file: they recommend creating a XmlReader or StreamReader pointing to a file found on the file system, but the .xaml document I would like to read from is going to be compiled with the rest of the assembly, so it won't have a meaningful file Uri. I do not want to copy this document around wherever the assembly goes. Is there a way to read from a .xaml document that has been compiled into the assembly?
I also know that I can simply read from a very long string literal inside the code itself, but I'd rather not do that - the UIElement produced from the Xaml should be easily edited, and I gain this by editing it in a Xaml file.
To illustrate what I'm hoping for, here's an example:
private void LoadUIElementFromCompiledXaml()
{
XmlReader xmlReader = new XmlReader("*Uri for .xaml document within my assembly*");
UIElement elementLoaded = (UIElement)XamlReader.Load(xmlReader);
}
I apologize in advance if the answer is blatantly obvious.

Before you can load Xaml from an assembly as an embedded resource, there is a bit of setup you must do. I'll walk you through an example, then from there you can customize it to suite your needs.
Create folder in your project. Name it XAML.
Add a XAML file to the XAML folder. Lets call it Sample.xaml.
Right-click on Sample.Xaml and choose properties. Set the value for Build Action to "Embedded Resource".
Right-click on the project and choose properties. Take note of the Default namespace value. We will use this as part of the path. For this example lets assume it is "MyNamespace.
Your code to load the Xaml resource would look something like this:
string defaultNamespace = "MyNamespace";
string folderName = "XAML";
string fileName = "Sample.xaml";
string path = String.Format("{0}.{1}.{2}", defaultNamespace, folderName, fileName);
using (Stream stream = System.Reflection.Assembly.GetExecutingAssembly().GetManifestResourceStream(path))
{
object root = XamlReader.Load(stream);
}
As you can see the path to the resource is made up of the default namespace of the project, the folder path to the file, and the file name. If the folder path has multiple levels use dots as folder separator in place of back slashes. For example Xaml\Subfolder would be Xaml.Subfolder.

How get file from a directory using relative path?

I am pretty new in C# and I am finding some difficulties trying to retrieve a jpg file that is into a directory of my project.
I have the following situation:
I have a Solution that is named MySolution, inside this solution there are some projects including a project named PdfReport. Inside this project there is a folder named Shared and inside this folder there is an header.jpg file.
Now if I want to obtain the list of all files that are inside the Shared directory (that as explained is a directory inside my project) I can do something like this:
string[] filePaths = Directory.GetFiles(#"C:\Develop\EarlyWarning\public\Implementazione\Ver2\PdfReport\Shared\");
and this work fine but I don't want use absolute path but I'd rather use a relative path relative to the PdfReport project.
I am searching a solution to do that but, untill now, I can't found it. Can you help me to do that?

Provided your application's Executable Path is "C:\Develop\EarlyWarning\public\Implementazione\Ver2", you can access the PdfReport\Shared folder as
string exePath = System.IO.Path.GetDirectoryName(Application.ExecutablePath);
string sharedPath = Path.Combine(exePath, "PdfReport\\Shared\\");
string[] filePaths = Directory.GetFiles(sharedPath);

Try to get the current folder by using this
Server.MapPath(".");
In a non ASP.NET application but WinForms or Console or WPF application you should use
AppDomain.CurrentDomain.BaseDirectory

If you want root relative, you can do this (assuming C:\Develop\EarlyWarning is site root)
string[] filePaths = Directory.GetFiles(Server.MapPath("~/public/Implementazione/Ver2/PdfReport/Shared"));
Or if you want plain relative,
//assuming you're in the public folder
string[] filePathes = Directory.GetFiles(Server.MapPath("/Implementazione/Ver2/PdfReport/Shared"));
Root relative is usually best in my experience, in case you move the code around.

You can right click on your file header.jpg, choose Properties, and select for example the option Copy always on the property "Copy to Output Directory".
Then a method like this, in any class that belongs to project PdfReport:
public string[] ReadFiles()
{
return Directory.GetFiles("Shared");
}
will work well.
Alternatively, if you have files that never change at runtime and you want to have access to them inside the assembly you also can embed: http://support.microsoft.com/kb/319292/en-us

Access to Resources

I've C# project and it has Resources folder. This folder has some of txt files. This files have various file names.
I'm taking file names from any source as string variable. For example I have fileName string variable and test.txt file in Resources folder:
string fileName = "test.txt";
When I want to access this file as like below, I can:
WpfApplication.Properties.test.txt;
But, When I want to access it by this code, I can't.
WpfApplication.Properties.fileName;
I want to use fileName string variable and access this text file.
What can I do to access it?
Thanks in advance.
Edit :
I change form of this question:
I've string variable assigned any text file name. For example; I have a.txt, b.txt, c.txt, d.txt, etc.. I'm taking this file name as string variable (fileName) via some loops. So, I took "c.txt" string. And, I can access this file by code in below:
textName = "c.txt";
fileName = "../../Resources\\" + textName;
However, when I build this project as Setup Project and install .exe file to any PC, there is no "Resources" folder in application's folder. So,
../../Resources\
is unavailable.
How can I access Resources folder from exe file's folder?

You need to add a Resource File to your project wich has the extension .resx/.aspx.resx. You will then be able to double click on this file and edit the required resources/resource strings. To do this right click on Project node in Solution Explorer > Add > New Item > Resource File. Let us assume you have added a file called ResourceStrings.resx to the Properties folder and added a resource string with key name MyResourceString, to access these strings you would do
string s = Properties.ResourceStrings.MyResourceString;
I hope this helps.

I would strongly recommend you taking a look at: http://msdn.microsoft.com/en-us/library/aa970494.aspx
If your text files have build action set as Resource you can locate them in code like:
(assuming the file name is fileName and its located in Resources folder)
Uri uri = new Uri(string.Format("Resources/{0}", fileName), UriKind.Relative);
System.Windows.Resources.StreamResourceInfo info = Application.GetResourceStream(uri);
Then you can access info.Stream to get access to your file.

Load local HTML file in a C# WebBrowser

In my app I have a WebBrowser element.
I would like to load a local file in it.
I have some questions:
Where to place the HTML file (so that it will also be installed if a user executes the setup)
how to reference the file? (e.g. my guess is the user's installation folder would not always be the same)
EDIT
I've added the HTML file to my project.
And I have set it up so that it gets copied to output folder.
When I check it it is present when run: \bin\Debug\Documentation\index.html
However when I do the following I get a 'Page cannot be displayed' error in the webbrowser element.
I use the following code to try to display the HTML file in the Webbrowser.
webBrowser1.Navigate(#".\Documentation\index.html");

Do a right click->properties on the file in Visual Studio.
Set the Copy to Output Directory to Copy always.
Then you will be able to reference your files by using a path such as #".\my_html.html"
Copy to Output Directory will put the file in the same folder as your binary dlls when the project is built. This works with any content file, even if its in a sub folder.
If you use a sub folder, that too will be copied in to the bin folder so your path would then be #".\my_subfolder\my_html.html"
In order to create a URI you can use locally (instead of served via the web), you'll need to use the file protocol, using the base directory of your binary - note: this will only work if you set the Copy to Ouptut Directory as above or the path will not be correct.
This is what you need:
string curDir = Directory.GetCurrentDirectory();
this.webBrowser1.Url = new Uri(String.Format("file:///{0}/my_html.html", curDir));
You'll have to change the variables and names of course.

quite late but it's the first hit i found from google
Instead of using the current directory or getting the assembly, just use the Application.ExecutablePath property:
//using System.IO;
string applicationDirectory = Path.GetDirectoryName(Application.ExecutablePath);
string myFile = Path.Combine(applicationDirectory, "Sample.html");
webMain.Url = new Uri("file:///" + myFile);

Note that the file:/// scheme does not work on the compact framework, at least it doesn't with 5.0.
You will need to use the following:
string appDir = Path.GetDirectoryName(
Assembly.GetExecutingAssembly().GetName().CodeBase);
webBrowser1.Url = new Uri(Path.Combine(appDir, #"Documentation\index.html"));

Place it in the Applications setup folder or in a separte folder beneath
Reference it relative to the current directory when your app runs.

Somewhere, nearby the assembly you're going to run.
Use reflection to get path to your executing assembly, then do some magic to locate your HTML file.
Like this:
var myAssembly = System.Reflection.Assembly.GetEntryAssembly();
var myAssemblyLocation = System.IO.Path.GetDirectoryName(a.Location);
var myHtmlPath = Path.Combine(myAssemblyLocation, "my.html");

What worked for me was
<WebBrowser Source="pack://siteoforigin:,,,/StartPage.html" />
from here. I copied StartPage.html to the same output directory as the xaml-file and it loaded it from that relative path.

Windows 10 uwp application.
Try this:
webview.Navigate(new Uri("ms-appx-web:///index.html"));

Update on #ghostJago answer above
for me it worked as the following lines in VS2017
string curDir = Directory.GetCurrentDirectory();
this.webBrowser1.Navigate(new Uri(String.Format("file:///{0}/my_html.html", curDir)));

I have been trying different answers from here, but managed to derive something working, here it is:
1- Added the page in a folder i created at project level named WebPagesHelper
2- To have the page printed by webBrowser Control,
string curDirectory = Path.GetDirectoryName(Assembly.GetExecutingAssembly().GetName().CodeBase);
var uri = new Uri(curDirectory);
string myFile = Path.Combine(uri.AbsolutePath, #"WebPagesHelper\index.html");
Uri new_uri = new Uri(myFile);
i had to get the assembly path, create a first uri to get an absolute path without the 'file://' attached, next i combined this absolute path with a relative path to the page in its folder, then made another URI from the result.
Then pass this to webBrowser URL property webBrowser.URL = new_uri;

Open a text file with WPF

There is a text file that I have created in my project root folder. Now, I am trying to use Process.Start() method to externally launch that text file.
The problem I have got here is that the file path is incorrect and Process.Start() can't find this text file. My code is as follows:
Process.Start("Textfile.txt");
So how should I correctly reference to that text file? Can I use the relative path instead of the absolute path? Thanks.
Edit:
If I change above code to this, would it work?
string path = Assembly.GetExecutingAssembly().Location;
Process.Start(path + "/ReadMe.txt");

Windows needs to know where to find the file, so you need somehow specify that:
Either using absolute path:
Process.Start("C:\\1.txt");
Or set current directory:
Environment.CurrentDirectory = "C:\\";
Process.Start("1.txt");
Normally CurrentDirectory is set to the location of the executable.
[Edit]
If the file is in the same directory where executable is you can use the code like this:
var directory = Path.GetDirectoryName(Assembly.GetEntryAssembly().Location);
var file = Path.Combine(directory, "1.txt");
Process.Start(file);

The way you are doing this is fine. This will find the text file that is in the same directory as your exe and it will open it with the default application (probably notepad.exe). Here are more examples of how to do this:
http://www.dotnetperls.com/process-start
However, if you want to put a path in, you have to use the full path. You can build the full path while only caring about the relative path using the method listed in this post:
http://social.msdn.microsoft.com/Forums/en-US/vbgeneral/thread/e763ae8c-1284-43fe-9e55-4b36f8780f1c
It would look something like this:
string pathPrefix;
if(System.Diagnostics.Debugger.IsAttached())
{
pathPrefix = System.IO.Path.GetFullPath(Application.StartupPath + "\..\..\resources\");
}
else
{
pathPrefix = Application.StartupPath + "\resources\";
}
Process.Start(pathPrefix + "Textfile.txt");
This is for opening a file in a folder you add to your project called resources. If you want it in your project root, just drop off the resources folder in the above two strings and you will be good to go.

You'll need to know the current directory if you want to use a relative path.
System.Envrionment.CurrentDirectory
You could append that to your path with Path
System.IO.Path.Combine(System.Envrionment.CurrentDirectory, "Textfile.txt")

Try using Application.StartupPath path as default path may point to current directory.
This scenario has been explained on following links..
Environment.CurrentDirectory in C#.NET
http://start-coding.blogspot.com/2008/12/applicationstartuppath.html

On a windows box:
Start notepad with the file's location immediately following it. WIN
process.start("notepad C:\Full\Directory\To\File\FileName.txt");