I've C# project and it has Resources folder. This folder has some of txt files. This files have various file names.
I'm taking file names from any source as string variable. For example I have fileName string variable and test.txt file in Resources folder:
string fileName = "test.txt";
When I want to access this file as like below, I can:
WpfApplication.Properties.test.txt;
But, When I want to access it by this code, I can't.
WpfApplication.Properties.fileName;
I want to use fileName string variable and access this text file.
What can I do to access it?
Thanks in advance.
Edit :
I change form of this question:
I've string variable assigned any text file name. For example; I have a.txt, b.txt, c.txt, d.txt, etc.. I'm taking this file name as string variable (fileName) via some loops. So, I took "c.txt" string. And, I can access this file by code in below:
textName = "c.txt";
fileName = "../../Resources\\" + textName;
However, when I build this project as Setup Project and install .exe file to any PC, there is no "Resources" folder in application's folder. So,
../../Resources\
is unavailable.
How can I access Resources folder from exe file's folder?
You need to add a Resource File to your project wich has the extension .resx/.aspx.resx. You will then be able to double click on this file and edit the required resources/resource strings. To do this right click on Project node in Solution Explorer > Add > New Item > Resource File. Let us assume you have added a file called ResourceStrings.resx to the Properties folder and added a resource string with key name MyResourceString, to access these strings you would do
string s = Properties.ResourceStrings.MyResourceString;
I hope this helps.
I would strongly recommend you taking a look at: http://msdn.microsoft.com/en-us/library/aa970494.aspx
If your text files have build action set as Resource you can locate them in code like:
(assuming the file name is fileName and its located in Resources folder)
Uri uri = new Uri(string.Format("Resources/{0}", fileName), UriKind.Relative);
System.Windows.Resources.StreamResourceInfo info = Application.GetResourceStream(uri);
Then you can access info.Stream to get access to your file.
Related
I have this code:
Stream stream = new StreamReader("~/quartz.xml").BaseStream;
Q1:What is the "~" symbol specify path in C#?
Q2:How to get the "~" directory in C# service project?
Q3:Does it mean the bin exe directory or project name directory?
The quartz.xml file in my Windows service project located in two position:
D:\jsptpd\Code\jsptpdJobScheduler\jsptpdJobScheduler\bin\Debug
D:\jsptpd\Code\jsptpdJobScheduler\jsptpdJobScheduler
Sure the path will change everytime!So get the relative path is better.
Just omit it entirely:
Stream stream = new StreamReader("quartz.xml").BaseStream;
The default directory is the .exe's directory.
Per the OP's edit to the question:
Go to View > Solution Explorer. Right-click the file in question, then choose Properties. Change the Copy To Output Directory option to Copy Always. Then use the code above.
if we use(../quartz.xml):
the StreamReader read path is(not the file actual path):
C:\Windows\quartz.xml
if we use(quartz.xml):
the StreamReader read path is(not the file actual path):
C:\Windows\system32\quartz.xml
This is the way to find the file relative path:
string assemblyFilePath = Assembly.GetExecutingAssembly().Location;
string assemblyDirPath = Path.GetDirectoryName(assemblyFilePath);
string configFilePath = assemblyDirPath + "\\quartz.xml";
Stream stream = new StreamReader(configFilePath).BaseStream;
So the path is(you can specify either of two):
D:\jsptpd\Code\jsptpdJobScheduler\jsptpdJobScheduler\bin\Debug\quartz.xml
I'm developing a winform application. It has a reference to a dll library. I want to use a function 'PDFImage' in this library. This function is used to put images into a PDF documnent. The function 'PDFimage' has an argument 'FileName' of type String which takes the file location of the image.
Now I have to put the image as a separate file with the .exe file created after the project is built. This is not convenient for me. What I do now is I mention the file name of the image as the function parameter like 'Flower.jpg'. And I have kept the image in the \bin\debug folder.
I don't want to do it like this as this needs the image file to be placed seperately with the executable file.
What I am trying to do is as follows:
I added the image files to the Resources folder as existing item. Now, to call the function PDFImage, I need to pass the file name as argument. How can I do this?
I have the source code of dll with me. Is it better to modify the source code as required and create another dll rather than what I am doing now?
See if this helps;
string apppath = Application.StartupPath;
string resname = #"\Resource.bmp";
string localfile = "";
localfile = apppath + resname;//Create the path to this executable.
//Btw we are going to use the "Save" method of Bitmap class.It
//takes an absolute path as input and saves the file there.
//We accesed the Image resource through Properties.Resources.Settings and called Save method
//of Bitmap class.This saves the resource as a local file in the same folder as this executable.
Properties.Resources.Image.Save(localfile);
MessageBox.Show("The path to the local file is : " + Environment.NewLine + localfile + Environment.NewLine +
"Go and check the folder where this executable is.",
this.Text, MessageBoxButtons.OK, MessageBoxIcon.Information);
//localfile is the path you need to pass to some function like this;
//SomeClass.Somefunction(localfile);
Hope this helps and here is a sample if you need.
All you can do with that is get the resource, save it to a file (temporary one may be) and then pass the filename to the function. Most function that take a file in .net also take a stream, so if you have control of both sides, I'd do that and then you don't have to mess about with the file system.
So, basically I've created this program and it's copying the selected file to the the company's named folder in the Roaming AppData folder, which isn't so bad. I mean, the setup now isn't so bad but I would like to have more control over it.
string fullFileName = item.FileName;
string fileNameWithExt = Path.GetFileName(fullFileName);
string destPath = Path.Combine(Application.UserAppDataPath, fileNameWithExt);
File.Copy(item.FileName, destPath);
At the beginning of the program it checks to see if the custom AppData folder is there.
public void checkADfolder()
{
string folder = Environment.GetFolderPath(Environment.SpecialFolder.ApplicationData);
string specificFolder = Path.Combine(folder, ".program");
if (!Directory.Exists(specificFolder))
Directory.CreateDirectory(specificFolder);
}
I want the files to go to the AppData folder .program instead of the folder with the Application company name.
Also, I am running into an issue with this. When a user selects a file, and then closes the program and opens the program again and happens to select the same file, it gives an error because the file already exists. I need to have it overwrite all other files when the same file is selected.
Screw it, I'll also ask this to why I am here.
I need the user selected file to replace another file in the AppData folder and rename the user selected file.
Basically. User selects file. File name is "user.txt". Now it's in Roaming > .program > user.txt
I need that file to replace a file let's say it's called "guest.txt". It's in Roaming > .user > guest.txt
I need to copy and rename "user.txt" to "guest.txt" then replace "guest.txt" in the .user folder.
I hope that explains everything well enough.
I figured I would put everything into one post instead of making multiple.
I've searched but can not seem to find any answers :/
To overwrite the file you simply need to use the method here:
File.Copy Method (String, String, Boolean);
To overwrite your other file, simply call the function again like so:
File.Copy(#".\Roaming\program\user.txt", #".\Roaming\user\guest.txt", true);
In my app I have a WebBrowser element.
I would like to load a local file in it.
I have some questions:
Where to place the HTML file (so that it will also be installed if a user executes the setup)
how to reference the file? (e.g. my guess is the user's installation folder would not always be the same)
EDIT
I've added the HTML file to my project.
And I have set it up so that it gets copied to output folder.
When I check it it is present when run: \bin\Debug\Documentation\index.html
However when I do the following I get a 'Page cannot be displayed' error in the webbrowser element.
I use the following code to try to display the HTML file in the Webbrowser.
webBrowser1.Navigate(#".\Documentation\index.html");
Do a right click->properties on the file in Visual Studio.
Set the Copy to Output Directory to Copy always.
Then you will be able to reference your files by using a path such as #".\my_html.html"
Copy to Output Directory will put the file in the same folder as your binary dlls when the project is built. This works with any content file, even if its in a sub folder.
If you use a sub folder, that too will be copied in to the bin folder so your path would then be #".\my_subfolder\my_html.html"
In order to create a URI you can use locally (instead of served via the web), you'll need to use the file protocol, using the base directory of your binary - note: this will only work if you set the Copy to Ouptut Directory as above or the path will not be correct.
This is what you need:
string curDir = Directory.GetCurrentDirectory();
this.webBrowser1.Url = new Uri(String.Format("file:///{0}/my_html.html", curDir));
You'll have to change the variables and names of course.
quite late but it's the first hit i found from google
Instead of using the current directory or getting the assembly, just use the Application.ExecutablePath property:
//using System.IO;
string applicationDirectory = Path.GetDirectoryName(Application.ExecutablePath);
string myFile = Path.Combine(applicationDirectory, "Sample.html");
webMain.Url = new Uri("file:///" + myFile);
Note that the file:/// scheme does not work on the compact framework, at least it doesn't with 5.0.
You will need to use the following:
string appDir = Path.GetDirectoryName(
Assembly.GetExecutingAssembly().GetName().CodeBase);
webBrowser1.Url = new Uri(Path.Combine(appDir, #"Documentation\index.html"));
Place it in the Applications setup folder or in a separte folder beneath
Reference it relative to the current directory when your app runs.
Somewhere, nearby the assembly you're going to run.
Use reflection to get path to your executing assembly, then do some magic to locate your HTML file.
Like this:
var myAssembly = System.Reflection.Assembly.GetEntryAssembly();
var myAssemblyLocation = System.IO.Path.GetDirectoryName(a.Location);
var myHtmlPath = Path.Combine(myAssemblyLocation, "my.html");
What worked for me was
<WebBrowser Source="pack://siteoforigin:,,,/StartPage.html" />
from here. I copied StartPage.html to the same output directory as the xaml-file and it loaded it from that relative path.
Windows 10 uwp application.
Try this:
webview.Navigate(new Uri("ms-appx-web:///index.html"));
Update on #ghostJago answer above
for me it worked as the following lines in VS2017
string curDir = Directory.GetCurrentDirectory();
this.webBrowser1.Navigate(new Uri(String.Format("file:///{0}/my_html.html", curDir)));
I have been trying different answers from here, but managed to derive something working, here it is:
1- Added the page in a folder i created at project level named WebPagesHelper
2- To have the page printed by webBrowser Control,
string curDirectory = Path.GetDirectoryName(Assembly.GetExecutingAssembly().GetName().CodeBase);
var uri = new Uri(curDirectory);
string myFile = Path.Combine(uri.AbsolutePath, #"WebPagesHelper\index.html");
Uri new_uri = new Uri(myFile);
i had to get the assembly path, create a first uri to get an absolute path without the 'file://' attached, next i combined this absolute path with a relative path to the page in its folder, then made another URI from the result.
Then pass this to webBrowser URL property webBrowser.URL = new_uri;
There is a text file that I have created in my project root folder. Now, I am trying to use Process.Start() method to externally launch that text file.
The problem I have got here is that the file path is incorrect and Process.Start() can't find this text file. My code is as follows:
Process.Start("Textfile.txt");
So how should I correctly reference to that text file? Can I use the relative path instead of the absolute path? Thanks.
Edit:
If I change above code to this, would it work?
string path = Assembly.GetExecutingAssembly().Location;
Process.Start(path + "/ReadMe.txt");
Windows needs to know where to find the file, so you need somehow specify that:
Either using absolute path:
Process.Start("C:\\1.txt");
Or set current directory:
Environment.CurrentDirectory = "C:\\";
Process.Start("1.txt");
Normally CurrentDirectory is set to the location of the executable.
[Edit]
If the file is in the same directory where executable is you can use the code like this:
var directory = Path.GetDirectoryName(Assembly.GetEntryAssembly().Location);
var file = Path.Combine(directory, "1.txt");
Process.Start(file);
The way you are doing this is fine. This will find the text file that is in the same directory as your exe and it will open it with the default application (probably notepad.exe). Here are more examples of how to do this:
http://www.dotnetperls.com/process-start
However, if you want to put a path in, you have to use the full path. You can build the full path while only caring about the relative path using the method listed in this post:
http://social.msdn.microsoft.com/Forums/en-US/vbgeneral/thread/e763ae8c-1284-43fe-9e55-4b36f8780f1c
It would look something like this:
string pathPrefix;
if(System.Diagnostics.Debugger.IsAttached())
{
pathPrefix = System.IO.Path.GetFullPath(Application.StartupPath + "\..\..\resources\");
}
else
{
pathPrefix = Application.StartupPath + "\resources\";
}
Process.Start(pathPrefix + "Textfile.txt");
This is for opening a file in a folder you add to your project called resources. If you want it in your project root, just drop off the resources folder in the above two strings and you will be good to go.
You'll need to know the current directory if you want to use a relative path.
System.Envrionment.CurrentDirectory
You could append that to your path with Path
System.IO.Path.Combine(System.Envrionment.CurrentDirectory, "Textfile.txt")
Try using Application.StartupPath path as default path may point to current directory.
This scenario has been explained on following links..
Environment.CurrentDirectory in C#.NET
http://start-coding.blogspot.com/2008/12/applicationstartuppath.html
On a windows box:
Start notepad with the file's location immediately following it. WIN
process.start("notepad C:\Full\Directory\To\File\FileName.txt");