I am new C#. I make a SOAP request and in the SOAP response, I need to access repeating nodes 'ABC'. This is how my SOAP Response looks like:
<?xml version="1.0" encoding="UTF-8"?>
<env:Envelope xmlns:env="http://schemas.xmlsoap.org/soap/envelope/">
<env:Header>
<work:WorkContext xmlns:work="http://example.com/soap/workarea/">sdhjasdajsdhj=</work:WorkContext>
</env:Header>
<env:Body>
<ReadABCResponse xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns="http://xmlns.xyz.com/abc/a6/AB/XYZ/V1">
<ABC xmlns="http://xmlns.xyz.example/abc/a6/AB/XYZ/V1">
<asd xmlns="http://xmlns.example.com/abc/a6/AB/XYZ/V1" xsi:nil="true"/>
<xyz xmlns="http://xmlns.example.com/abc/a6/AB/XYZ/V1" xsi:nil="true"/>
</ABC>
<ABC xmlns="http://xmlns.example.com/abc/a6/AB/XYZ/V1">
<asd xmlns="http://xmlns.example.com/abc/a6/AB/XYZ/V1" xsi:nil="true"/>
<xyz xmlns="http://xmlns.example.com/abc/a6/AB/XYZ/V1" xsi:nil="true"/>
</ABC>
</ReadABCResponse>
</env:Body>
</env:Envelope>
My code is as below:
XmlDocument responseDoc = new XmlDocument();
responseDoc.LoadXml(responseString); //responseString is set to above SOAP response.
XmlNamespaceManager nsmgr = new XmlNamespaceManager(responseDoc.NameTable);
nsmgr.AddNamespace("env", "http://schemas.xmlsoap.org/soap/envelope/");
nsmgr.AddNamespace("work", "http://example.com/soap/workarea/");
nsmgr.AddNamespace("xsi", "http://www.w3.org/2001/XMLSchema-instance");
nsmgr.AddNamespace("", "http://xmlns.example.com/abc/a6/AB/XYZ/V1");
XmlNodeList lst = responseDoc.SelectNodes("/env:Envelope/env:Body/ReadABCResponse/ABC", nsmgr);
Console.WriteLine("Count " + lst.Count);
// and then iterate over the repeating ABC nodes to do some work.
However value of Count is always printed as 0. I have tried different combinations of the xpath path in "SelectNodes" method including "//ABC" - which I thought should give me all the repeating 'ABC' nodes but it does not.
What is wrong with my code. please can someone highlight and help me!
I have looked around on this site but cant figure out what is wrong with this code.
The following shows how to use XDocument to read data from the XML.
Test.xml:
<?xml version="1.0" encoding="UTF-8"?>
<env:Envelope xmlns:env="http://schemas.xmlsoap.org/soap/envelope/">
<env:Header>
<work:WorkContext xmlns:work="http://example.com/soap/workarea/">sdhjasdajsdhj=</work:WorkContext>
</env:Header>
<env:Body>
<ReadABCResponse xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns="http://xmlns.xyz.com/abc/a6/AB/XYZ/V1">
<ABC xmlns="http://xmlns.xyz.example/abc/a6/AB/XYZ/V1">
<asd xmlns="http://xmlns.example.com/abc/a6/AB/XYZ/V1" xsi:nil="true">asd data 1</asd>
<xyz xmlns="http://xmlns.example.com/abc/a6/AB/XYZ/V1" xsi:nil="true">xyz data 1</xyz>
</ABC>
<ABC xmlns="http://xmlns.example.com/abc/a6/AB/XYZ/V1">
<asd xmlns="http://xmlns.example.com/abc/a6/AB/XYZ/V1" xsi:nil="true">asd data 2</asd>
<xyz xmlns="http://xmlns.example.com/abc/a6/AB/XYZ/V1" xsi:nil="true">xyz data 2</xyz>
</ABC>
</ReadABCResponse>
</env:Body>
</env:Envelope>
Add the following using statements:
using System.Xml;
using System.Xml.Linq;
using System.Diagnostics;
Create a class (name: ABC.cs)
public class ABC
{
public string Asd { get; set; }
public string Xyz { get; set; }
}
Option 1:
private void GetABC()
{
//ToDo: replace with your XML data
string xmlText = "your XML data...";
//parse XML
XDocument doc = XDocument.Parse(xmlText);
//create new instance
List<ABC> abcs = new List<ABC>();
foreach (XElement elem in doc.Descendants().Where(x => x.Name.LocalName == "ABC"))
{
//create new instance
ABC abc = new ABC();
foreach (XElement elemChild in elem.Descendants())
{
//Debug.WriteLine($"{elemChild.Name}: '{elemChild.Value?.ToString()}'");
if (elemChild.Name.LocalName == "asd")
abc.Asd = elemChild.Value?.ToString();
else if (elemChild.Name.LocalName == "xyz")
abc.Xyz = elemChild.Value?.ToString();
}
//add to List
abcs.Add(abc);
}
foreach (ABC abc in abcs)
{
Debug.WriteLine($"ABC: '{abc.Asd}' XYZ: '{abc.Xyz}'");
}
}
Option 2:
private void GetABC()
{
//ToDo: replace with your XML data
string xmlText = "your XML data...";
//parse XML
XDocument doc = XDocument.Parse(xmlText);
//get namespace
XNamespace nsABC = doc.Descendants().Where(x => x.Name.LocalName == "ABC").FirstOrDefault().GetDefaultNamespace();
List<ABC> abcs = doc.Descendants().Where(x => x.Name.LocalName == "ABC").Select(x2 => new ABC()
{
Asd = (string)x2.Element(nsABC + "asd"),
Xyz = (string)x2.Element(nsABC + "xyz")
}).ToList();
foreach (ABC abc in abcs)
{
Debug.WriteLine($"ABC: '{abc.Asd}' XYZ: '{abc.Xyz}'");
}
}
Resources:
XDocument
How to Read SOAP XML Response in VB.NET
You can also do this: copy the xml and paste it in Visual studio using Paste special -> Paste Xml as classes. Now you will have an Envelope class and you can deserialize the xml like in this example:https://learn.microsoft.com/en-us/dotnet/api/system.xml.serialization.xmlserializer.deserialize?view=net-7.0.
Soap messages can be quite complex and it would be easier to work with objects which you can modify and eventually serialize back if needed.
Thanks for your response guys but I managed to solve it. In the namsspace manager, I made the following change
nsmgr.AddNamespace("x", "http://xmlns.example.com/abc/a6/AB/XYZ/V1");
and when listing the ABC nodes, I made the following change i.e. to prefix ABC with x:
XmlNodeList lst = responseDoc.SelectNodes("//x:ABC", nsmgr);
Rest of the code remains as it is and now I can loop through all the ABC nodes.
Related
I need some help on how to get values of English and studentId from this XML. Maybe it needs some special parsing I can't figure out at the moment.
<?xml version="1.0" encoding="utf-8"?>
<soap:Envelope xmlns:soap="http://schemas.xmlsoap.org/soap/envelope/" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema">
<soap:Body>
<processResponse xmlns="http://tempuri.org/">
<processResult>
<xml version="1.0" encoding="UTF-8"?>
<returnedResponse>
<English>94</English>
<Remarks>Excellent</Remarks>
<studentId>tst005</studentId>
<Department>6</Department>
</returnedResponse>
</processResult>
</processResponse>
</soap:Body>
</soap:Envelope>
I have tried the following code:
XmlDocument xdr = new XmlDocument();
xdr.LoadXml(thexml);
XmlNodeList nodelist = xdr.SelectNodes("//processResponse/processResult/returnedResponse");
foreach (XmlNode node in nodelist)
{
string eng = node.SelectSingleNode("English").InnerText;
Response.Write("eng");
}
Do you get an error with invalid XML or does your SelectNodes not find anything?
How about this path
XmlNodeList nodelist = xdr.SelectNodes("/*/*/*/processResponse/processResult/returnedResponse");
You can try with SelectSingleNode, just like this.
var English= xdr.DocumentElement.SelectSingleNode("English").InnerText;
var studentId = xdr.DocumentElement.SelectSingleNode("studentId").InnerText;
1) XML ist invalid at line 6 -> because it does not have a closing tag. If you cannot edit the Service and strip the xml header or encode the resulting xml, you have to strip the line 6 in you consumercode.
2) You have to define the Namespaces!
Btw: I highly recommend using (Linq2XML) XDocument. Your code could look like this:
XDocument xdr = XDocument.Parse(...);
var nodes = xdr.XPathSelectElements("//*[name()='returnedResponse']");
Try this
XmlDocument doc = new XmlDocument();
doc.LoadXml(xmlString);
XmlNodeList nList = doc.GetElementsByTagName("returnedResponse");
foreach (XmlNode node in nList)
{
XElement xelement = XElement.Parse(node.OuterXml);
var Descendents = xelement.Descendants();
foreach (var item in Descendents)
{
//you'll get each of your descendents here
}
}
<?xml version="1.0" encoding="UTF-8"?>
<Envelope xmlns:xsd="http://www.w3.org/2001/XMLSchema">
<Message>
<MessageID>1</MessageID>
<Product>
<SKU>33333-01</SKU>
</Product>
</Message>
</Envelope>
I've tried googling but whether I'm just not providing the correct search criteria I don't know.
I want to be able to search the XML file based on the MessageID and then grab the SKU.
I then want to search another XML file based on the SKU and remove that message completely.
<?xml version="1.0" encoding="UTF-8"?>
<Envelope xmlns:xsd="http://www.w3.org/2001/XMLSchema">
<Message>
<MessageID>1</MessageID>
<Inventory>
<SKU>33333-01</SKU>
<Quantity>1</Quantity>
</Inventory>
</Message>
<Message>
<MessageID>2</MessageID>
<Inventory>
<SKU>22222-01</SKU>
<Quantity>1</Quantity>
</Inventory>
</Message>
</Envelope>
Meaning the XML above becomes:
<?xml version="1.0" encoding="UTF-8"?>
<Envelope xmlns:xsd="http://www.w3.org/2001/XMLSchema">
<Message>
<MessageID>2</MessageID>
<Inventory>
<SKU>22222-01</SKU>
<Quantity>1</Quantity>
</Inventory>
</Message>
</Envelope>
To confirm I cannot confirm that the MessageID will be the same over different XML files.
Thanks in advance for any help.
My questions:
How do I search through XML files?
How do I then grab another Nodes details
Can I remove a complete from an XML file based on a search?
You can use XmlDocument to load your XML document. Then, you can use XPath for searching any nodes.
XmlDocument document = new XmlDocument();
document.Load("C:\fileOnTheDisk.xml");
// or
document.LoadXml("<a>someXmlString</a>");
// Returns single element or null if not found
var singleNode = document.SelectSingleNode("Envelope/Message[MessageID = '1']");
// Returns a NodeList
var nodesList = document.SelectNodes("Envelope/Message[MessageID = '1']");
Read more about XPath at w3schools.com.
Here is a good XPath Tester.
For example, you can use the following XPath to find nodes in your document by ID:
XmlDocument document = new XmlDocument();
document.Load("C:\doc.xml");
var node = document.SelectSingleNode("Envelope/Message[MessageID = '1']");
var sku = node.SelectSingleNode("Inventory/SKU").InnerText;
Console.WriteLine("{0} node has SKU = {1}", 1, sku);
Or you can output all SKUs:
foreach (XmlNode node in document.SelectNodes("Envelope/Message"))
{
Console.WriteLine("{0} node has SKU = {1}",
node.SelectSingleNode("MessageID").InnerText,
node.SelectSingleNode("Inventory/SKU").InnerText);
}
It will produce:
1 node has SKU = 33333-01
2 node has SKU = 22222-01
Note that there are possible NullReferenceExceptions if nodes are not present.
You can simply remove it using RemoveChild() method of its parent.
XmlDocument document = new XmlDocument();
document.Load("C:\doc.xml");
var node = document.SelectSingleNode("Envelope/Message[MessageID = '1']");
node.ParentNode.RemoveChild(node);
document.Save("C:\docNew.xml"); // will be without Message 1
You can use Linq to XML to do this:
var doc= XDocument.Load("input.xml");//path of your xml file in which you want to search based on message id.
var searchNode= doc.Descendants("MessageID").FirstOrDefault(d => d.Value == "1");// It will search message node where its value is 1 and get first of it
if(searchNode!=null)
{
var SKU=searchNode.Parent.Descendants("SKU").FirstOrDefault();
if(SKU!=null)
{
var searchDoc=XDocument.Load("search.xml");//path of xml file where you want to search based on SKU value.
var nodes =searchDoc.Descendants("SKU").Where(d=>d.Value==SKU.Value).Select(d=>d.Parent.Parent).ToList();
nodes.ForEach(node=>node.Remove());
searchDoc.Save("output.xml");//path of output file
}
}
I'd recommend you did this using LINQ to XML - it's much nicer to work with than the old XmlDocument API.
For all the examples, you can parse your XML string xml to an XDocument like so:
var doc = XDocument.Parse(xml);
1. How do I search through XML files?
You can get the SKU for a specific message ID by querying your document:
var sku = (string)doc.Descendants("Message")
.Where(e => (int)e.Element("MessageID") == 1)
.SelectMany(e => e.Descendants("SKU"))
.Single();
2. How do I then grab another Nodes details?
You can get the Message element with a specified SKU using a another query:
var message = doc.Descendants("SKU")
.Where(sku => (string)sku == "33333-01")
.SelectMany(e => e.Ancestors("Message"))
.Single();
3. Can I remove a complete element from an XML file based on a search?
Using your result from step 2, you can simple call Remove:
message.Remove();
Alternatively, you can combine the query from step 2 and simply execute a command to remove any messages that have a specific SKU:
doc.Descendants("SKU")
.Where(sku => (string)sku == "33333-01")
.SelectMany(e => e.Ancestors("Message"))
.Remove();
I tried to answer all your questions:
using System.Xml.XPath;
using System.Xml.Linq;
XDocument xdoc1 = XDocument.Load("xml1.xml");
XDocument xdoc2 = XDocument.Load("xml2.xml");
string sku = String.Empty;
string searchedID = "2";
//1.searching through an xml file based on path
foreach (XElement message in xdoc1.XPathSelectElements("Envelope/Message"))
{
if (message.Element("MessageID").Value.Equals(searchedID))
{
//2.grabbing another node's details
sku = message.XPathSelectElement("Inventory/SKU").Value;
}
}
foreach (XElement message in xdoc2.XPathSelectElements("Envelope/Message"))
{
if (message.XPathSelectElement("Inventory/SKU") != null && message.XPathSelectElement("Inventory/SKU").Value.Equals(sku))
{
//removing a node
message.Remove();
}
}
xdoc2.Save("xml2_del.xml");
}
For example :
I have the following XML,
<?xml version="1.0" encoding="utf-8"?>
<TEST>
<Name>TESTRUN</Name>
<SyncByte>ff</SyncByte>
<SOM>53</SOM>
<PDADD>7e</PDADD>
<LENLSB>08</LENLSB>
</Test>
I would like to get the values from the tags "SyncByte", "SOM", "PADD" and "LENLSB" into a single array. Is there an option within XML to accomplish this?
P.S. There are close to 20+ tags in the XML and not all tags contain values all the time. Hence if there is a single command to get all the values of the XML, then it would be great.
With Linq to Xml:
var xml = #"<?xml version=""1.0"" encoding=""utf-8""?>
<Test>
<Name>TESTRUN</Name>
<SyncByte>ff</SyncByte>
<SOM>53</SOM>
<PDADD>7e</PDADD>
<LENLSB>08</LENLSB>
</Test>";
var doc = XDocument.Parse(xml);
string[] values = doc.Root.Descendants().Select(x => x.Value).ToArray();
First:
your xml formate is wrong , it should be:
<?xml version="1.0" encoding="utf-8"?>
<TEST>
<Name>TESTRUN</Name>
<SyncByte>ff</SyncByte>
<SOM>53</SOM>
<PDADD>7e</PDADD>
<LENLSB>08</LENLSB>
</TEST> <!--END Tag should same as TEST -->
Then you can query them like this:
var xml=XDocument.Load("d:\\test.xml");
var list=xml.Descendants("TEST")
.Select(x=>new
{
SyncByte=x.Element("SyncByte")==null?"":x.Element("SyncByte").Value,
SOM=x.Element("SOM")==null?"":x.Element("SOM").Value,
LENLSB=x.Element("LENLSB")==null?"":x.Element("LENLSB").Value
});
You can get the child of any parent node through 'XmlElement.ChildNodes' and store it in collection.
for eg :
static int Main(string[] args)
{
string strFilename = "Input.xml";
XmlDocument xmlDoc = new XmlDocument();
if (File.Exists(strFilename))
{
xmlDoc.Load(strFilename);
XmlElement elm = xmlDoc.DocumentElement;
XmlNodeList lstVideos = elm.ChildNodes;
for (int i = 0; i < lstVideos.Count; i++)
Console.WriteLine("{0}",lstVideos[i].InnerText );
}
else
Console.WriteLine("The file {0} could not be located",
strFilename);
Console.WriteLine();
return 0;
}
I have to read an XML document and insert the values into a List<T> of my objects.
Class (Result)
+Result
-username
-dob
-answer1
-answer2
-uuid
Below is the XML format structure
<?xml version="1.0" encoding="UTF-8" standalone="yes"?>
<export exportDate="2012-11-07T12:03:52.823+11:00">
<survey type="USER" completion="2012-11-07T11:46:52.754+11:00" reference="2012-11-07T11:30:34.680+11:00" year="2012" uuid="226f2aa3-46e6-46ab-8995-7d52eb21d5f4">
<user xsi:type="USER" created="2012-11-07T11:09:30.409+11:00" dob="08/06/1988" surname="Billy" name="Bob" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"/>
<subject created="2012-11-07T11:09:30.409+11:00" dob="08/06/1988" surname="Billy" name="Bob"/>
<version released="1970-01-01T10:00:02.012+10:00" version="1"/>
<result group="2" rawscore="2.4" metric="1"/>
<result group="2" rawscore="2.0" metric="2"/>
<answer score="1" question="6"/>
<answer score="2" question="7"/>
</survey>
</export>
My current progress
I was previously using XmlDocument as I have in the past but now that Im working with Linq im sure this can be done in just a few lines. I dont like the look of the code below, if anyway has some tips please help.
thankyou
List<Result> results = new List<Result>();
XmlDocument doc = new XmlDocument();
doc.Load(filename);
XmlNodeList objects = doc.GetElementsByTagName("survey");
foreach (XmlNode o in objects)
{
Result result = new Result();
if (o.Attributes["type"].Value == "USER" || o.Attributes["type"].Value == "ADMIN")
{
result.surveycompleted = o.Attributes["completion"].Value;
XmlNodeList usernodes = o.SelectNodes("user");
....
if (usernodes.Count > 0)
{}
else
{
Use LINQ2XML:
XElement doc=XElement.Load(filename);
List<Result> lstSurvey=doc.DescendantsAndSelf("Survey").Select(x=>
new Result
{
uuid=x.Element("Survey").Attribute("uuid").Value,
username=x.Element("user").Attribute("name").Value,
dob=x.Element("user").Attribute("dob").Value,
answer1=x.Elements("answer").First().Value,
answer2=x.Elements("answer").Skip(1).First().Value
}
).ToList<Result>();
I would like to filter with high performance XML elements from an XML document.
Take for instance this XML file with contacts:
<?xml version="1.0" encoding="ISO-8859-1"?>
<?xml-stylesheet type="text/xsl" href="asistentes.xslt"?>
<contactlist evento="Cena Navidad 2010" empresa="company">
<contact type="1" id="1">
<name>Name1</name>
<email>xxxx#zzzz.es</email>
<confirmado>SI</confirmado>
</contact>
<contact type="1" id="2">
<name>Name2</name>
<email>xxxxxxxxx#zzzze.es</email>
<confirmado>Sin confirmar</confirmado>
</contact>
</contaclist>
My current code to filter from this XML document:
using System;
using System.Xml.Linq;
class Test
{
static void Main()
{
string xml = #" the xml above";
XDocument doc = XDocument.Parse(xml);
foreach (XElement element in doc.Descendants("contact")) {
Console.WriteLine(element);
var id = element.Attribute("id").Value;
var valor = element.Descendants("confirmado").ToList()[0].Value;
var email = element.Descendants("email").ToList()[0].Value;
var name = element.Descendants("name").ToList()[0].Value;
if (valor.ToString() == "SI") { }
}
}
}
What would be the best way to optimize this code to filter on <confirmado> element content?
var doc = XDocument.Parse(xml);
var query = from contact in doc.Root.Elements("contact")
let confirmado = (string)contact.Element("confirmado")
where confirmado == "SI"
select new
{
Id = (int)contact.Attribute("id"),
Name = (string)contact.Element("name"),
Email = (string)contact.Element("email"),
Valor = confirmado
};
foreach (var contact in query)
{
...
}
Points of interest:
doc.Root.Elements("contact") selects only the <contact> elements in the document root, instead of searching the whole document for <contact> elements.
The XElement.Element method returns the first child element with the given name. No need to convert the child elements to a list and take the first element.
The XElement and XAttribute classes provide a wide selection of convenient conversion operators.
You could use LINQ:
foreach (XElement element in doc.Descendants("contact").Where(c => c.Element("confirmado").Value == "SI"))