I need some help on how to get values of English and studentId from this XML. Maybe it needs some special parsing I can't figure out at the moment.
<?xml version="1.0" encoding="utf-8"?>
<soap:Envelope xmlns:soap="http://schemas.xmlsoap.org/soap/envelope/" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema">
<soap:Body>
<processResponse xmlns="http://tempuri.org/">
<processResult>
<xml version="1.0" encoding="UTF-8"?>
<returnedResponse>
<English>94</English>
<Remarks>Excellent</Remarks>
<studentId>tst005</studentId>
<Department>6</Department>
</returnedResponse>
</processResult>
</processResponse>
</soap:Body>
</soap:Envelope>
I have tried the following code:
XmlDocument xdr = new XmlDocument();
xdr.LoadXml(thexml);
XmlNodeList nodelist = xdr.SelectNodes("//processResponse/processResult/returnedResponse");
foreach (XmlNode node in nodelist)
{
string eng = node.SelectSingleNode("English").InnerText;
Response.Write("eng");
}
Do you get an error with invalid XML or does your SelectNodes not find anything?
How about this path
XmlNodeList nodelist = xdr.SelectNodes("/*/*/*/processResponse/processResult/returnedResponse");
You can try with SelectSingleNode, just like this.
var English= xdr.DocumentElement.SelectSingleNode("English").InnerText;
var studentId = xdr.DocumentElement.SelectSingleNode("studentId").InnerText;
1) XML ist invalid at line 6 -> because it does not have a closing tag. If you cannot edit the Service and strip the xml header or encode the resulting xml, you have to strip the line 6 in you consumercode.
2) You have to define the Namespaces!
Btw: I highly recommend using (Linq2XML) XDocument. Your code could look like this:
XDocument xdr = XDocument.Parse(...);
var nodes = xdr.XPathSelectElements("//*[name()='returnedResponse']");
Try this
XmlDocument doc = new XmlDocument();
doc.LoadXml(xmlString);
XmlNodeList nList = doc.GetElementsByTagName("returnedResponse");
foreach (XmlNode node in nList)
{
XElement xelement = XElement.Parse(node.OuterXml);
var Descendents = xelement.Descendants();
foreach (var item in Descendents)
{
//you'll get each of your descendents here
}
}
Related
I'm really just trying to create a custom xml document for simple configuration processing.
XmlDocument xDoc = new XmlDocument();
string[] NodeArray = { "Fruits|Fruit", "Vegetables|Veggie"};
foreach (string node in NodeArray)
{
XmlNode xmlNode = xDoc.CreateNode(XmlNodeType.Element,node.Split('|')[0],null);
//xmlNode.Value = node.Split('|')[0];
xmlNode.InnerText = node.Split('|')[1];
xDoc.DocumentElement.AppendChild(xmlNode);
}
What i'm trying to get is this.
<?xml version="1.0" encoding="ISO-8859-1"?>
<Fruits>Fruit</Fruits>
<Vegetables>Veggie</Vegetables>
i get not set to value of an object at xDoc.DocumentElement.AppendChild(xmlNode);
Unfortunately, You can't make that XML structure.
All XML documents must have a single root node. You can't have more.
Try something like this
XmlDocument xDoc = new XmlDocument();
xDoc.AppendChild( xDoc.CreateElement("root"));
string[] NodeArray = { "Fruits|Fruit", "Vegetables|Veggie" };
foreach (string node in NodeArray)
{
XmlNode xmlNode = xDoc.CreateNode(XmlNodeType.Element, node.Split('|')[0], null);
//xmlNode.Value = node.Split('|')[0];
xmlNode.InnerText = node.Split('|')[1];
xDoc.DocumentElement.AppendChild(xmlNode);
}
It is not possible to have that XML structure as XML MUST have a single root element. You may want to try:
<?xml version="1.0" encoding="ISO-8859-1"?>
<items>
<Fruits>Fruit</Fruits>
<Vegetables>Veggie</Vegetables>
</items>
I am trying to find a node in my xml file but getting the error ( see title)?
// instantiate XmlDocument and load XML from file
XmlDocument doc = new XmlDocument();
doc.Load(#"C:\temp\test2.xml");
var node = doc.SelectSingleNode("/Offers/Offer/ID=[text()='1']");
var test = node;
xml
<?xml version="1.0" encoding="utf-8"?>
<Offers>
<Offer>
<Model>AAAA</Model>
<ID>1</ID>
<Name>First offer</Name>
</Offer>
<Offer>
<Model>BBBB</Model>
<ID>2</ID>
<Name>Second offer</Name>
</Offer>
</Offers>
Remove the = after ID:
var node = doc.SelectSingleNode("/Offers/Offer/ID=[text()='1']");
becomes:
var node = doc.SelectSingleNode("/Offers/Offer/ID[text()='1']");
The XML (fragment):
<?xml version="1.0" encoding="utf-8"?>
<soap:Envelope xmlns:soap="http://schemas.xmlsoap.org/soap/envelope/" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema">
<soap:Body>
<GetXMLResponse xmlns="http://sitecore.net/visual/">
<GetXMLResult>
<sitecore xmlns="">
<status>ok</status>
The code (fragment):
XmlNamespaceManager nsManager = new XmlNamespaceManager(template.NameTable);
nsManager.AddNamespace("soap", "http://schemas.xmlsoap.org/soap/envelope/");
nsManager.PushScope();
XmlNode sitecoreRoot = template.SelectSingleNode("/soap:Envelope/soap:Body/*[namespace-uri()='http://sitecore.net/visual/' and local-name()='GetXMLResponse']", nsManager);
string status = sitecoreRoot.SelectSingleNode("/GetXMLResult/sitecore/status").Value;
sitecoreRoot element returns the correct node. However the XPath to get the status always returns null, even though the siteCoreRoot.OuterXMl property shows the element is present.
The only thing I can think of is the line:
<sitecore xmlns="">
is throwing off the XPath
TIA
XmlNamespaceManager ns = new XmlNamespaceManager(cd.NameTable);
ns.AddNamespace("sp", "http://schemas.xmlsoap.org/soap/envelope/");
ns.AddNamespace("sc", "http://sitecore.net/visual/");
XmlNode sitecoreRoot = cd.SelectSingleNode("//sp:Envelope/sp:Body/sc:GetXMLResponse/sc:GetXMLResult/sitecore/status", ns);
var status = sitecoreRoot.InnerText;
May help you?
If you just want the status node, you can try this xml library and the following XPath.
XElement root = XElement.Load(file); // or .Parse(string)
XElement status = root.XPathElement("//status");
The library handles doing the namespace for you.
I am doing some practice code with the XmlTextReader. I have written some very basic XML as shown here:
<?xml version="1.0" encoding="utf-8" standalone="yes"?>
<task name="mixed_sprite_task_test">
<sprite>
<type>animatedSprite</type>
<id>0</id>
<name>animatedSprite</name>
<fileName>iyezoz</fileName>
<startingPositionX>200</startingPositionX>
<startingPositionY>200</startingPositionY>
<sheetSizeX>12</sheetSizeX>
<sheetSizeY>35</sheetSizeY>
<startingFrameX>0</startingFrameX>
<startingFrameY>0</startingFrameY>
<startingState>standing</startingState>
<movementSpeed>15</movementSpeed>
<frameDelay>0.055</frameDelay>
</sprite>
<sprite>
<type>staticSprite</type>
<id>0</id>
<name>staticSprite</name>
<fileName>Super_Mario_63</fileName>
<startingPositionX>0</startingPositionX>
<startingPositionY>0</startingPositionY>
</sprite>
<sprite>
<type>simpleSprite</type>
<id>0</id>
<name>simpleSprite</name>
<fileName>imgres</fileName>
<startingPositionX>100</startingPositionX>
<startingPositionY>100</startingPositionY>
<movementSpeed>15</movementSpeed>
</sprite>
</task>
This file shows that I have a task. In the task I have 3 sprites.
In my code I want to loop through each sprite and collect the information.
I can get the data from the first sprite with no issue. Is there a certain way to loop through an xml with attributes of the same name?
Thank-you!
I prefer Linq2Xml.
var xDoc = XDocument.Parse(xmlstring); //or XDocument.Load(filename);
var sprites = xDoc.Descendants("sprite")
.Select(s=>s.Elements()
.ToDictionary(e=>e.Name.LocalName,e=>(string)e))
.ToList();
You can use it as
var type = sprites[0]["type"];
or can take a safe action
string delay;
if (sprites[1].TryGetValue("frameDelay", out delay))
{
Console.WriteLine(delay);
}
You can select all the nodes named "sprite"
var myXml = new XmlDocument();
myXml.Load(myDocument);
XmlNode rootElement = myXml.DocumentElement;
foreach (XmlNode item in rootElement.SelectNodes(#"/task/sprite"))
{
// do stuff with node
}
I am trying to get the values for faultcode, faultstring, and OrderNumber from the SOAP below
<SOAP:Envelope xmlns:SOAP="http://schemas.xmlsoap.org/soap/envelope/">
<SOAP:Body>
<faultcode>1234</faultcode>
<faultstring>SaveOrder:SetrsOrderMain:Cannot change OrderDate if GLPeriod is closed, new OrderDate is 3/2/2010:Ln:1053</faultstring>
<detail>
<SOAP:Envelope xmlns:SOAP="http://schemas.xmlsoap.org/soap/envelope/">
<SOAP:Body UserGUID="test">
<m:SaveOrder xmlns:m="http://www.test.com/software/schema/" UserGUID="test">
<Order OrderNumber="1234-1234-123" Caller="" OrderStatus="A" xmlns="http://www.test.com/software/schema/">
Here is my code in C#
XDocument doc = XDocument.Load(HttpContext.Current.Server.MapPath("XMLexample.xml"));
var errorDetail = new EcourierErrorDetail
{
FaultCode = from fc in doc.Descendants("faultcode")
select fc.Value,
FaultString = from fs in c.Descendants("faultstring")
select fs.Value,
OrderNumber = from o in
doc.Descendants("detail").Elements("Order").Attributes("OrderNumber")
select o.Value
};
return errorDetail;
I am able to get the values for both faultcode and faultstring but not the OrderNumber. I am getting "Enumeration yielded no results." Can anyone help? Thanks.
Yes, you're ignoring the XML namespace when selecting:
<SOAP:Envelope xmlns:SOAP="http://schemas.xmlsoap.org/soap/envelope/">
.....
<m:SaveOrder xmlns:m="http://www.test.com/software/schema/" UserGUID="test">
<Order OrderNumber="1234-1234-123" Caller="" OrderStatus="A" xmlns="http://www.test.com/software/schema/">
The <Order> tag is inside the <m:SaveOrder> tag which uses the XML namespace prefixed by the m: prefix.
Also, you're trying to select the "detail" and then you skip to the "Order" node directly (using .Elements()) - you missed the <m:SaveOrder> node in between.
You need to take that into account when selecting:
XDocument doc = XDocument.Load(HttpContext.Current.Server.MapPath("XMLexample.xml"));
XNamespace xmlns = "http://www.test.com/software/schema/";
var orderNode = doc.Descendants(xmlns + "SaveOrder").Elements(xmlns + "Order");
var value = from o in orderNode.Attributes("OrderNumber")
select o.Value;
Does that give you a result??
A clean solution could be using System.Xml.XPath. Here is where I found the example
This is how to use it in this case:
XmlDocument xmlDoc = new XmlDocument();
xmlDoc.LoadXml(result);
XmlNamespaceManager xmlnsManager = new XmlNamespaceManager(xmlDoc.NameTable);
xmlnsManager.AddNamespace("soap", "http://schemas.xmlsoap.org/soap/envelope/");
xmlnsManager.AddNamespace("m", "http://www.test.com/software/schema/");
var orderNode = xmlDoc.SelectSingleNode("//m:Order", xmlnsManager);
var value = orderNode.Attributes["OrderNumber"].Value;